|
|
本帖最后由 Menuett 于 2013-12-22 15:59 编辑 3 C e8 Y# l: t- ~3 J' o
煮酒正熟 发表于 2013-12-20 12:05 ' q9 D- D4 X( f* O
基本可以说是显著的。总的来说,在商界做统计学分析,95%信心水平是用得最多的,当95%上不显著时,都会去 ...
# n1 h4 a1 `8 \! j: \8 @8 o. ?, x4 }! i4 l7 E
这个其实是一种binomial response,应该用Contigency Table或者Logisitic Regression(In case there are cofactors)来做。只记比率丢弃了Number of trial的信息(6841和1217个客户)。
9 u9 l/ D6 M& _6 R$ A5 q _9 _4 E& j! ^/ E/ b/ k
结果p=0.5731。 远远不显著。要在alpha level 0.05的水平上检验出76.42%和75.62%的区别,即使实验组和对照组各自样本大小相同,各自尚需44735个样本(At power level 80%)。see: Statistical Methods for Rates and Proportions by Joseph L. Fleiss (1981)) l1 O; p0 j- i& t1 y0 P
* q) M5 r y9 b9 B9 R# ~0 g
R example:
' H0 t; M# B [7 w9 ?
* N$ H: {2 B0 E> M<-as.table(rbind(c(1668,5173),c(287,930)))" ^ j- d" {& I0 P y8 S+ |
> chisq.test(M)/ m9 U4 Y# S3 U& s# I7 F- k4 n9 a. Q
! s" z$ X U; p3 s7 a
Pearson's Chi-squared test with Yates' continuity correction9 D8 {7 |4 x* D: D& t
, J6 B0 j' N/ c8 a% c1 C
data: M6 K* L/ f7 m, I8 p4 S- K* D3 c
X-squared = 0.3175, df = 1, p-value = 0.5731
5 p/ Q% j4 a: ~ l3 n% G( b6 N! J, S6 A' f5 F) ^
Python example:9 P; S7 |8 m' Z9 \4 I3 z# x
# M& i+ W# O2 n>>> from scipy import stats* p8 ?# D `' o I
>>> stats.chi2_contingency([[6841-5173,5173],[1217-930,930]])
* T0 U2 i$ G6 x(0.31748297614660292, 0.57312422493552839, 1, array([[ 1659.73628692, 5181.26371308],
- T: b# h4 |5 p, A* `1 @7 u [ 295.26371308, 921.73628692]])) |
|