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本帖最后由 Menuett 于 2013-12-22 15:59 编辑
- s/ E( K: y/ d煮酒正熟 发表于 2013-12-20 12:05 w0 J& K' N. p4 X$ o! u, s
基本可以说是显著的。总的来说,在商界做统计学分析,95%信心水平是用得最多的,当95%上不显著时,都会去 ... 9 I" x0 l: t, R- a
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这个其实是一种binomial response,应该用Contigency Table或者Logisitic Regression(In case there are cofactors)来做。只记比率丢弃了Number of trial的信息(6841和1217个客户)。 * d, ]9 h" M, ~: y
+ F9 J; `1 |, Y0 L* Z结果p=0.5731。 远远不显著。要在alpha level 0.05的水平上检验出76.42%和75.62%的区别,即使实验组和对照组各自样本大小相同,各自尚需44735个样本(At power level 80%)。see: Statistical Methods for Rates and Proportions by Joseph L. Fleiss (1981)! t6 a# g9 }5 [1 D
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R example: S% K) R, X5 v
! {, w% R: k$ V4 t4 D& v4 ~> M<-as.table(rbind(c(1668,5173),c(287,930)))+ t( \- b" G! s: f: F2 l+ ?& l. s2 z
> chisq.test(M)
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Pearson's Chi-squared test with Yates' continuity correction8 Z5 _* e0 v) X- g/ K
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data: M
, {& G+ a1 Y. {) \5 ^X-squared = 0.3175, df = 1, p-value = 0.5731
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m d) i. x0 W$ _4 s% _* APython example:
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8 b" D( |) L2 a5 f>>> from scipy import stats6 ~- i; j$ v( Y0 p
>>> stats.chi2_contingency([[6841-5173,5173],[1217-930,930]])* N4 x) Q0 l$ V
(0.31748297614660292, 0.57312422493552839, 1, array([[ 1659.73628692, 5181.26371308],* K, e/ e5 J& O4 o0 w
[ 295.26371308, 921.73628692]])) |
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