设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 3326|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    ' o; e: F7 V: z) _& u* y6 G, }# Q, R2 Y
    解释的不错/ @7 z! P! F5 j8 f

    1 i. H* r5 u1 V: Z  K1 M& c) e递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    * b# o0 M; p8 K9 s+ l% ?
    1 s# j/ l! Y! N" C/ X5 |+ B" H 关键要素
    - ]; ^, k( U# {& X- i% k7 _1. **基线条件(Base Case)**
    , u* _/ ^0 Q8 @& o   - 递归终止的条件,防止无限循环
    9 K9 f1 C! \3 {& k$ J' R   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1: P* }, S2 w1 x9 p* e4 q) O

    . }; ]# t) T* F0 y4 {. J& |' ?2 H2. **递归条件(Recursive Case)**
    , M2 E8 R8 B8 @. W   - 将原问题分解为更小的子问题2 d" h, `4 \2 I% c
       - 例如:n! = n × (n-1)!! I# K3 ?8 g% @& R& p
    ; n: J; j( ^. q. p0 l
    经典示例:计算阶乘
    6 k4 r8 n5 ^7 o  w9 }( Hpython7 f& S2 D: s9 Z$ k9 o+ K
    def factorial(n):+ k4 p; i- F5 J" V
        if n == 0:        # 基线条件
    ' n4 I/ [4 f3 J- H( S' u  S& [        return 1& l8 U! V/ `6 V
        else:             # 递归条件# A( b- H8 F% a6 V
            return n * factorial(n-1)8 I& S2 [% @; B! ~& U  l
    执行过程(以计算 3! 为例):' a6 d; k3 }2 W0 T
    factorial(3)
    , E  \3 B+ g! x$ F9 M5 n3 * factorial(2)
    8 V+ u' i8 t; e0 R3 r3 * (2 * factorial(1))
      r; R$ k4 ]2 F" C- S3 * (2 * (1 * factorial(0)))
    4 k7 F4 m) n0 P0 D$ H* y3 * (2 * (1 * 1)) = 6
      q% Q; i0 y) C7 m; U. @- E! d* O. |, p! G
    递归思维要点6 s2 Z: f& D, k8 }7 l: q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑; i- N" Q& }" S) P- W/ u" f5 O* R8 L( a, O
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ( m4 X: B. b4 _8 Z: H3. **递推过程**:不断向下分解问题(递)4 j! P0 {" Y- s- J$ z
    4. **回溯过程**:组合子问题结果返回(归)
    & Q" P6 m% r% n+ {" m, n& S1 J& p6 }( @2 n+ m
    注意事项# a4 T2 f7 w2 z; V- C# \
    必须要有终止条件
    2 l- |8 ~8 Q0 m- |5 S/ Q递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    4 y# R0 }( V% j7 l" b8 N. D, J某些问题用递归更直观(如树遍历),但效率可能不如迭代7 v) A. p- ?0 Z0 y( i* `
    尾递归优化可以提升效率(但Python不支持): |. m* s/ Y4 W1 v- n: b! Z
    9 O% G# H/ V! i, ]. m& g
    递归 vs 迭代* b! L% R% g; [! ~# V# F/ e
    |          | 递归                          | 迭代               |
    " H! _1 L4 \# K$ b# W. D- x|----------|-----------------------------|------------------|
    & _3 Y; f' s1 ~9 @: U/ X! Z| 实现方式    | 函数自调用                        | 循环结构            |  t, k; |: b* c, q, k
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    7 N4 f( n# U+ J7 q# [' h+ o| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ! R5 j! E- W% b, o| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    . {0 b8 z7 R0 r; \
    * ?; g6 n* W* w' G 经典递归应用场景
    ' [! Y) @0 h- d3 K* k- y( C% l) ?1. 文件系统遍历(目录树结构)9 R, v" v/ M$ M( y% u: o
    2. 快速排序/归并排序算法5 T* K" B# p6 m: t7 J. H
    3. 汉诺塔问题
    % B- C- H7 A& }6 P6 B8 U5 k- l4. 二叉树遍历(前序/中序/后序)6 p4 p. T) R" j) ]' ]! L
    5. 生成所有可能的组合(回溯算法)% A( K- J. n: C; H) C
    8 |: [. o/ D1 r* q+ _9 P
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    开心
    1 小时前
  • 签到天数: 3357 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,% J6 q" y4 W; N# c% W9 r. _8 A1 j
    我推理机的核心算法应该是二叉树遍历的变种。
    & N: ?+ T, H! c' j9 E$ j另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:. \+ p! u: @; _# P
    Key Idea of Recursion
    6 g# b  M8 b! T2 O- O: S, m! u! l" N3 R) z; |
    A recursive function solves a problem by:% \8 y3 t2 }; h3 g0 O+ c, Z
    ( X6 }2 O1 l; ]
        Breaking the problem into smaller instances of the same problem.
    6 ]! U* n9 ^( H
    ) s% T# P( D. _" Z4 @    Solving the smallest instance directly (base case).
    5 g7 v- t  F- x5 w. z  V! l
    " `# U) j6 d" M: k7 c. M    Combining the results of smaller instances to solve the larger problem.6 ]& E( ~; ~2 z+ E: g
    7 {( |8 c( R' R# e  i
    Components of a Recursive Function
    ) s+ Y4 C9 r' F2 g" r8 D
    % g3 i# {  O1 Z' K2 x) U& A0 q1 W    Base Case:
    ) O. `( ~0 |$ E6 N0 i5 D4 A* f' e
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.  n; W2 f( S  h( i# A
    1 ^# E( f) I. |# Z  G0 G6 V- M5 `
            It acts as the stopping condition to prevent infinite recursion.% \4 x+ W5 A/ V5 W3 u" G. I

    3 H$ H7 G2 ^3 n* [5 d        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    & Y; j( {1 k* D6 Z& A  ~7 i
    # Z+ }& ]4 u( F  \* u9 B    Recursive Case:
    6 x: v5 F& c, H; b; t3 k: u; n: h5 T6 D) y/ N
            This is where the function calls itself with a smaller or simpler version of the problem.
    # F- g, z7 \1 q5 V
    , F2 C5 s# H/ P1 x        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).8 e6 Z- K2 Z( d& `5 X

    ( Z. e9 F7 O1 w0 x" s- G; b$ {9 TExample: Factorial Calculation
    ( F6 [4 {6 B; A2 u1 ~6 J# p/ H# Z( Q0 \+ h: ^
    % P) v; X, I) vThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:( {- q( N8 r: t5 H# t+ v

    6 B5 \5 Y- r, S) L/ j' O    Base case: 0! = 1
    , n2 F+ n+ s. ?' Z+ K  c, Y$ v
    . y- h  ?) B, g! H( D$ e: G! g    Recursive case: n! = n * (n-1)!
    5 n2 q2 l% x3 _9 ]8 l- ~4 J
    : m1 C0 [1 b' g' Q0 U9 mHere’s how it looks in code (Python):
    9 d1 ~! S4 t$ Tpython# R. X% @) p! i
    ) ]0 e: Y- c' n+ B. u% ?

    ; `# z, z- Q$ Sdef factorial(n):' t' m) _" J  C! ?
        # Base case
    * t( O9 l: N8 \$ Y: `4 i    if n == 0:
    5 H2 G+ r! T9 ^5 [2 U        return 1
    * ^$ q2 U7 c* N) Y# f8 Z: E    # Recursive case# t$ K8 G+ ?! r
        else:
    + c" z  J: L7 r. {0 A        return n * factorial(n - 1)& W1 o0 M* n" z. z' U3 T

    ' f% m# D) J- r! }" \8 G+ O/ C) j# Example usage
    5 \" B0 x' |8 l1 w, Rprint(factorial(5))  # Output: 120
    & H% q0 y. m! L. Z4 @' `# t, w: u7 t
    How Recursion Works3 z4 L& h9 L! m
    / k: q+ d3 J2 i3 n
        The function keeps calling itself with smaller inputs until it reaches the base case.
    6 [* V7 m# J* B. W# r0 T, v9 i+ Z% T' B4 E5 o
        Once the base case is reached, the function starts returning values back up the call stack.
    # e1 Q. }+ ^- _0 z, X8 Q0 g$ s3 r% S& j
        These returned values are combined to produce the final result.' |# @1 i1 Q, z0 g( t
    3 f' u, D9 H5 `/ A
    For factorial(5):5 P8 q6 n0 m) r. X7 i
    & S9 c) n) {; F" |4 V' _

    & O8 i9 x/ \/ D- q8 t' F% Lfactorial(5) = 5 * factorial(4)
    ' Z$ `& I' A% S1 h  `& I" J, qfactorial(4) = 4 * factorial(3)' R+ i. L0 J$ ^/ ^6 y
    factorial(3) = 3 * factorial(2)
    2 X! w1 V/ ]% |8 sfactorial(2) = 2 * factorial(1)1 i  `; }9 v; J  O9 N9 n  n
    factorial(1) = 1 * factorial(0)
    3 j# y7 u$ ^$ l8 ofactorial(0) = 1  # Base case- ]4 I% T# Q- D  y* a3 H* |* A- q

    6 v5 k; N7 r8 }/ Q) R1 L: S1 ~Then, the results are combined:
    " m$ D( T1 l- z0 k7 c  I5 K/ V; T! J9 ?* l3 u( L6 O

    - s5 n: y5 w. |7 {* Wfactorial(1) = 1 * 1 = 13 ^( x: z% Z5 [) S. I
    factorial(2) = 2 * 1 = 2
    , {. ]6 Q8 H7 l; bfactorial(3) = 3 * 2 = 6
    $ w1 y! C/ r+ f# D) j4 Ffactorial(4) = 4 * 6 = 24- i. o: e5 L7 [2 r+ o+ e
    factorial(5) = 5 * 24 = 120
    1 ?0 A6 Q- d( [; ~4 `; g4 H5 L3 D4 X" {
    Advantages of Recursion. A3 l- v2 g& I' B5 x
    5 F" L# l0 `% A
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).5 a! J/ v, g% N; Y5 H! ]) Y2 f  b* F
    3 U  |) w  Z# s6 E. P% X) v  |
        Readability: Recursive code can be more readable and concise compared to iterative solutions.) z0 |5 O+ k6 X" p

    3 Q5 ^! q* J. ~) z( w3 f7 V  V% TDisadvantages of Recursion& q' M5 @1 V* f: [0 B' I4 a  d

    ' A  f: L: z1 w$ O* [    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.: `" D' X& l( f
    4 w  X8 n: ?& J  p
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).4 Z: N# D: w) ^* ^7 _* u: B

    & G9 q" J$ U* U) Y6 P; L  ~When to Use Recursion
    & j2 y4 P/ E" X6 B& K$ Q6 L( P, s/ s. v4 k
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).( o; W  Q9 N; u
    ' o/ @' \5 H; D  k8 s
        Problems with a clear base case and recursive case.3 e9 b" S0 ^4 G+ \2 Y! B5 Y  K* T
      Y9 Z- y1 ?. Y0 j- S
    Example: Fibonacci Sequence
    7 Y+ }; N( L& l# y8 w% Q  e8 {5 B
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    ) F0 @$ ~$ u$ l" W6 H9 u- x2 F- M! f* b& Q* x  A6 x" o
        Base case: fib(0) = 0, fib(1) = 1& N5 k& a2 P( b7 M  o+ c

    - @7 B: H4 }7 Q* [    Recursive case: fib(n) = fib(n-1) + fib(n-2)7 j3 i8 L& Y5 n1 J

    2 l  n: a; T- K7 t- e4 Z4 v1 ?python* O; j" G9 _: L, O
    3 [5 N) \5 V7 s) p6 d
    ' i% W$ {, W. @
    def fibonacci(n):, t: e. N9 Z5 L, G9 l
        # Base cases' j1 O/ n& P! P( V8 Y
        if n == 0:" d2 Z  O1 `/ Z5 m8 a8 `1 {0 T" `. z
            return 0) g- H2 X6 l& k* J0 @, |9 b0 O
        elif n == 1:5 f8 V. V% s7 H1 `% T- s: b% O: ^. z# m
            return 1
      w/ x* L4 x' j% }9 n5 l( [5 C, W    # Recursive case" S  f. k, i3 \- Z; ~
        else:
    6 q  h! x1 L0 `& w        return fibonacci(n - 1) + fibonacci(n - 2)
    7 m+ U8 k! z6 A* j- _
    3 U! X/ H  P- {4 X9 ?9 G! G; n# Example usage
    & i! v4 x" K2 o- F0 g% h+ cprint(fibonacci(6))  # Output: 8- L0 h8 j3 O" U: n, U
    . `9 \* _5 `6 k  g1 v) b
    Tail Recursion7 d( H$ y* I. w7 I, ^$ u  i

    3 t3 N. f: C  l5 JTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    6 H8 o+ X6 x) o; F. ?: x% @$ p. ~! j: p9 w8 ~" f% ?/ L  ?) S
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-9-21 08:27 , Processed in 0.061902 second(s), 20 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表