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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 " A( s+ ^2 V- Z: O( [3 N$ x
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    解释的不错
    6 \$ O7 ^8 d( {1 @! d8 v3 D1 l
    5 C5 K6 u, |3 Z" G; {/ }递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    0 W; K+ ]2 I  J: k: H$ R. P% x: F! p/ V/ x+ U! \
    关键要素( a/ O3 r" r, b
    1. **基线条件(Base Case)**: ~1 }9 V; T7 a
       - 递归终止的条件,防止无限循环0 H& H, L% j3 y9 }) p# _, q
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 10 s6 i8 M, B2 P$ k6 B' Y" l, e
    $ T. }7 d4 |. C
    2. **递归条件(Recursive Case)**
    ( P% e/ c' {. f1 @5 H   - 将原问题分解为更小的子问题
    6 o) p0 Z& b4 J( v, n3 q- _9 {1 A4 ~' H   - 例如:n! = n × (n-1)!
    4 L' J1 ~& m/ q
    8 e- B1 i/ `( [% A; [6 i6 L 经典示例:计算阶乘6 q2 B3 O& @) A9 }. n+ f) N$ [
    python+ i  @5 r6 E* [  c7 o8 V# M
    def factorial(n):$ R9 P' b2 _6 B
        if n == 0:        # 基线条件
      X; ]! N3 ], x4 k        return 1( z& J5 a6 ]% k, F/ {+ \
        else:             # 递归条件$ n0 {  j7 n2 b% ]! ~
            return n * factorial(n-1)
      S9 I( g# d4 p* I$ Y执行过程(以计算 3! 为例):% e3 f' F: m, D
    factorial(3)# w* }( \2 |6 a- |: A) ^0 X
    3 * factorial(2)
    ; O$ H9 U4 I9 `4 H+ o! B3 * (2 * factorial(1)): ^- W) x1 v: J; ~5 c" C0 U
    3 * (2 * (1 * factorial(0)))
    + J+ Y$ a  n$ [# a6 R! _4 J3 * (2 * (1 * 1)) = 6
    & g% H( B/ J  B: U+ Y) t$ M2 Y, p7 y' h
    递归思维要点
    0 f$ {8 @  {6 m8 B, m7 E1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    9 q0 B: s- w6 A5 r( }2. **栈结构**:每次调用都会创建新的栈帧(内存空间)( T- S7 J# W0 K; _5 I7 D
    3. **递推过程**:不断向下分解问题(递)( {2 G2 Z* Q0 u7 f( T8 ?
    4. **回溯过程**:组合子问题结果返回(归)
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    ! d, i7 \& Q; `  C7 y( V. O% | 注意事项5 N0 ~1 E  w6 I' Z
    必须要有终止条件& W( `4 W* C& S+ [9 y. o  o" Q
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    / \" J; P# J) I* a( R+ b" ^某些问题用递归更直观(如树遍历),但效率可能不如迭代, Q( Q% h, H: ~& Z
    尾递归优化可以提升效率(但Python不支持)$ h; W: v/ T3 i# B. W) B4 Y

    : k- R* B: q) V9 S( N/ I 递归 vs 迭代
    6 m) G* i* n% [0 m- Q: E|          | 递归                          | 迭代               |! u$ d2 r- M% o) P7 Z
    |----------|-----------------------------|------------------|
    + h+ j' R1 B/ w0 p$ t8 X9 D  m6 y1 Y) x| 实现方式    | 函数自调用                        | 循环结构            |9 \$ v% m# ^/ Y. W
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ( r0 i" }/ P7 r' l| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |, ?( p5 i+ @6 @1 Z
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    # @1 K1 g; a, e5 C2 u* F, J; e- ^. X
    经典递归应用场景2 D, Y5 U# O- r3 X
    1. 文件系统遍历(目录树结构)2 X* S0 J# ?- N2 w( @# I
    2. 快速排序/归并排序算法
    ) u! L6 i  u3 {$ ?% k) C& B  {( k7 z* `3. 汉诺塔问题
    8 i  }+ O* _. I4. 二叉树遍历(前序/中序/后序)9 Y+ R  G$ k1 C3 N
    5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    前天 07:13
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,/ j8 J" }  B3 b" }) ]( `" [
    我推理机的核心算法应该是二叉树遍历的变种。% C7 q' Q! ?2 r, F
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    ( w7 Y1 a' v3 I! @  ~+ BKey Idea of Recursion; @; ?! i- d! |5 F- Y. U* W! m

    8 m  |+ t' o! f& K: RA recursive function solves a problem by:
    - S. S$ `8 i/ v1 {7 g1 e) f% n. F
    - c0 n! }8 P, v6 ^& v) G" e    Breaking the problem into smaller instances of the same problem.
    / l8 W' z% U+ H- ]9 V( }; E5 O4 i! T: v' ?7 o# P, A
        Solving the smallest instance directly (base case).- _7 o' g9 [8 [. s/ s6 J3 q. N
    % d2 b9 E+ x2 e; `$ s
        Combining the results of smaller instances to solve the larger problem.
    # \( _" W0 W7 X- Q. x( G# V! ]1 I9 s1 @  o5 q
    Components of a Recursive Function
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        Base Case:
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    / \6 ?9 {2 v% s4 Q( q( e        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.6 C. l( L( S9 ?) ?0 K

    8 {) e) z+ A. Q/ u2 t! k* y/ z        It acts as the stopping condition to prevent infinite recursion.
    ! ^3 u* h# c& v/ h
    . q! Q  S8 `3 Y1 j        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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        Recursive Case:9 [/ f9 G* r. H; M1 z9 x4 Z- N

    1 g1 F& w% S/ F' t* G" f8 F        This is where the function calls itself with a smaller or simpler version of the problem." o% V) h6 {! Z
    # h) W: n) y: U9 j# U" W, R
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).8 |# \/ u, @: H( |4 l
    2 s6 ?4 d. ~4 H4 {' _, I
    Example: Factorial Calculation
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    # D4 z6 S3 [4 XThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    9 I4 f/ W2 C7 d4 ~0 `' x8 R
    + [8 S  T3 e5 U; }    Base case: 0! = 1
    & D4 j) B1 y7 ]* a' A% \) Y% d; G
    2 t1 G( T7 Y9 M; [0 m" L& P% q: U    Recursive case: n! = n * (n-1)!3 ?) p: l% E9 [2 r8 |/ a. F4 h
    & e( j$ b5 p' L/ j. R
    Here’s how it looks in code (Python):
    * n' ]2 Y: U5 {( N$ e3 Zpython1 `: V) `- }) Z* F5 a! s
    5 s' w2 B# F  b: u& |8 }
      w- x7 Z7 G( H- c" M& @( W0 V; Y
    def factorial(n):
    * P1 i- U5 f: j: O% i    # Base case! F' r+ T) U8 m
        if n == 0:
    ' F' q( m, z0 v        return 1, R0 Y" M& F$ |9 l' B
        # Recursive case
    1 ~* Z9 Y3 N" W. z4 ?% v    else:
      \! v. ]/ c$ [7 H        return n * factorial(n - 1)
    # h9 t6 u; J; k# E3 Q2 a1 q9 k/ t- _2 V  d9 K
    # Example usage5 M# `# D/ {. `) v$ J$ l
    print(factorial(5))  # Output: 120
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    ! Z& @& M5 W2 N3 G  oHow Recursion Works( D0 J0 @! ?! Z7 m) X6 O
    $ S* `9 K/ R" j/ e5 e
        The function keeps calling itself with smaller inputs until it reaches the base case.
    % P9 |( D& x2 Y$ `# G/ Q4 K3 }9 S$ B
    : a0 Y3 Z, [9 U7 K2 F6 r3 T    Once the base case is reached, the function starts returning values back up the call stack.5 C4 P/ B: H; c, X

    ' D$ c+ e) j, ?. X, e    These returned values are combined to produce the final result.. q, \2 T# h3 M
    4 I2 y7 z# S, C! v, O& S( [# q
    For factorial(5):
    4 P6 i4 I2 M! E' Z4 U+ Y2 U& S1 k4 [6 T) y5 q$ O
    & R( [: o, n% ?
    factorial(5) = 5 * factorial(4)
    : e+ ?, ?0 u5 n4 w5 \  ~factorial(4) = 4 * factorial(3)3 I) d: u9 Y) Z# F) x+ [3 e
    factorial(3) = 3 * factorial(2); {7 e8 d& n0 i" |
    factorial(2) = 2 * factorial(1)
    $ L  U( ^! _3 Y: N) ]/ I) A0 }factorial(1) = 1 * factorial(0)
    1 l5 P1 p- j3 }8 lfactorial(0) = 1  # Base case! H5 A0 o5 @7 i5 F& z' n

    . A1 d. O: W  e1 A6 R6 uThen, the results are combined:, ~1 F" N. S5 t

    " q6 l. m3 Y& g5 V2 I  a: d8 s5 m
    factorial(1) = 1 * 1 = 1
    % d3 E1 Y" C# h- sfactorial(2) = 2 * 1 = 2
    , g1 M. ]! c+ x+ J, W* hfactorial(3) = 3 * 2 = 6+ O# X" m# ^$ v- R
    factorial(4) = 4 * 6 = 24
    ( s0 o5 p$ [* b& Mfactorial(5) = 5 * 24 = 120
    2 A& a* g% B) m  m% I: q3 s( M+ X" t. S3 }+ R% b% j6 A, p
    Advantages of Recursion& {' G1 ^* j# f) u1 B
    2 Z9 ]; W$ Z- G3 P
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).* C* M) ?0 |. T( m
    # z- r3 o( K) f' y
        Readability: Recursive code can be more readable and concise compared to iterative solutions.3 q" ]) a1 n4 E% Q2 b3 i

    , B$ Q/ @+ f3 A' V% l/ iDisadvantages of Recursion
    # M" b7 j$ L- @3 \* n3 F5 i6 ?# N6 ]2 [* e. S# ~3 G/ Y9 @, M8 i
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.9 b9 n; H/ a; k2 R% K

    ! P* n2 K2 f% Q. u, F; h$ e% k    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    2 H! n! o+ c# O$ y" x0 c" ?, H8 V9 Q2 W
    When to Use Recursion
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        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    + N4 o! a* {: W& _' d, x0 Q6 h1 x) l0 a$ |/ P
        Problems with a clear base case and recursive case.5 p) ?* u* |4 b7 b; g5 ?

    9 R* `- D/ Z. V8 n7 X7 ]" uExample: Fibonacci Sequence2 ^, l5 V0 N, P; R6 j5 ~1 {* v

    ! N$ R( {* ]) s+ o$ z8 AThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    * ?1 V6 S, v( }5 z, I& u, B& {0 f
        Base case: fib(0) = 0, fib(1) = 1
    4 e" \/ h5 i0 k% F8 {9 D2 u- @+ z, e/ R# V
        Recursive case: fib(n) = fib(n-1) + fib(n-2): N4 e8 h% w; G9 [

    $ s6 K1 _& E4 q( P8 [+ O1 gpython% T/ ?, {' q* D6 |* R
    2 ~- L+ Q! f  @1 m/ i# A+ r) V- L

    + S& s% j( v* o. H( ]9 ]def fibonacci(n):( l+ d0 z9 |9 p/ F5 M0 L) L2 {8 d
        # Base cases
    3 B& `. n9 P- X7 Z9 q- w8 q    if n == 0:7 t+ P( k' K6 q4 C1 d6 V& z% `
            return 0  d4 r$ k  d( K  @3 |) j7 J
        elif n == 1:
    + Q* w# C  C% h        return 1" Q# a8 L* M8 k: e  @7 D
        # Recursive case1 s7 l5 W  P7 ~, |( ~, n. Y
        else:" u$ c+ B) T; q2 d
            return fibonacci(n - 1) + fibonacci(n - 2)3 N* a, p9 P! \8 L+ r
    0 Y# I/ o$ j" V4 _$ z
    # Example usage' O- [# I+ J+ R! l' {4 v; |; L) _
    print(fibonacci(6))  # Output: 8/ J  W, g2 n) V# C  F" C7 V/ m

    2 ?& E  j7 g: I* C$ |Tail Recursion
    4 }% G- \8 J8 \
    # P+ ?0 q1 W( J# [7 Y% A+ j$ ]Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ) P3 X' }; c& X" i) M4 [4 a( Z% J) s+ ?2 O! Y$ \8 P1 t& x
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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