设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2376|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    & J4 T: g; y  f+ f! ~2 t5 w% V) c" \; y
    解释的不错
    % Q# v6 N; d- F' n1 w( C" Y
    * }" @: ]* Y3 J- Y$ l  L- N递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。. F+ j2 R  z4 B% y+ W) a) ?( V  s
    $ p7 x! U0 N8 S
    关键要素: t0 z8 c6 A' N" ?5 i* V" }# f
    1. **基线条件(Base Case)**
    $ [! i8 l9 u/ U* G( C0 [0 W7 t   - 递归终止的条件,防止无限循环
    7 {  Q7 O8 k' L6 r7 d   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1" e/ ?2 S  J4 r2 ]9 u

    ) @* Y3 w0 z9 l9 |9 G4 j0 H$ d2. **递归条件(Recursive Case)**) N8 I& W0 o! x( b: ~5 b- U# d
       - 将原问题分解为更小的子问题
      ]0 `5 M% B( P, ]6 E% @   - 例如:n! = n × (n-1)!3 ?: z3 }! W! N( S, \
    . m6 c8 Z, X/ X2 p0 S3 F6 {
    经典示例:计算阶乘
    / y  \. Z7 F4 [( m6 f( T* \4 q0 h9 E# h/ ppython6 P  I8 a/ \$ y$ _# ^
    def factorial(n):. {3 t' y. l/ r8 C5 c& n7 ~
        if n == 0:        # 基线条件0 s0 j1 w- q+ S. z. @
            return 1
    : u! }/ F  i9 o& P- [    else:             # 递归条件
    & I$ t  u7 t7 c  W        return n * factorial(n-1)/ P8 P/ g6 F6 x! R+ ^1 A* ?
    执行过程(以计算 3! 为例):( ^' D, A% j# q0 ~; e, s; a' I
    factorial(3)( B" X  q8 b8 E  V  T& Y' _3 D
    3 * factorial(2)# C! W+ a1 |& p
    3 * (2 * factorial(1))) W$ T1 E2 _1 M. \" F$ b1 Z
    3 * (2 * (1 * factorial(0)))
    8 |7 k" ]- Y9 D" m3 * (2 * (1 * 1)) = 6
    8 t0 u, {# _9 u- V3 u' d/ A9 {$ N: |' }
    递归思维要点
    4 z6 Y, Z7 U9 n7 v( V: x7 D# H) H' d1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    5 a5 Q+ N2 r8 V& B' N8 W2. **栈结构**:每次调用都会创建新的栈帧(内存空间)! c) @0 {( D& n- @* O
    3. **递推过程**:不断向下分解问题(递)# D( s( j+ e1 _9 W8 c
    4. **回溯过程**:组合子问题结果返回(归)- o* K; c; s4 K* Y  I, l

      T: [4 o! Z9 r6 W' N 注意事项
    ; Y$ c( d& l& [% Q( x必须要有终止条件$ D. j2 x4 W$ [- ^3 J: s
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)2 i) p' z# {! l9 Y1 L, x) X3 N
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ! V9 S9 O7 x* `2 Z/ \尾递归优化可以提升效率(但Python不支持)! j9 @( `( U2 }; z0 {' l8 H
    ; L2 a! }# b( A6 ~5 E+ d1 O
    递归 vs 迭代
    7 i& d$ O$ Z5 G' I7 K& v* e|          | 递归                          | 迭代               |
    / W7 J8 H# m4 N0 {+ n" W|----------|-----------------------------|------------------|; \, [& ?0 t- D/ _( i& f& [/ Y) e
    | 实现方式    | 函数自调用                        | 循环结构            |
    5 o: R4 e! u9 [* v5 S1 o4 s# f% }| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |' ~. j3 W- j: n/ G  r
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |" C  n* P) i% U) G( m
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |7 ?! P# L+ Z, I! _* f+ D# C( o

    ( k; B' m0 P5 D+ n1 k4 l 经典递归应用场景5 o( `( i, x: l, z8 I- o
    1. 文件系统遍历(目录树结构)
    ! [: l# R/ z& f( ?2. 快速排序/归并排序算法
    % {& X+ f- L: ~9 Q7 N) c7 B$ O: o$ X3. 汉诺塔问题* z4 H! L$ S9 j* b9 m; C
    4. 二叉树遍历(前序/中序/后序); h+ P, w( j# p2 s
    5. 生成所有可能的组合(回溯算法)# [& g$ \2 L5 U( {3 g& U7 J
    3 X$ u& _! w+ O8 h. T
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    奋斗
    6 小时前
  • 签到天数: 3209 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    % b% a5 R' |9 n; |我推理机的核心算法应该是二叉树遍历的变种。3 A, M+ I( [+ U8 \7 b4 ]1 I3 X
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:$ G  i0 o3 n" D
    Key Idea of Recursion7 `  [7 P) r* k
    $ M' M' Y; Z1 l8 S
    A recursive function solves a problem by:! O+ _0 ~7 x7 B0 D( M
    1 u! H6 C3 F4 F. z: |1 g1 ^
        Breaking the problem into smaller instances of the same problem.
    % v( S$ V8 Q; Y! x. \  L2 F% u: u4 `$ O+ _4 z  s$ q
        Solving the smallest instance directly (base case).( J4 N0 |) i/ }. J9 u
    - ~2 k4 d5 U% s1 }# y! w; R5 x
        Combining the results of smaller instances to solve the larger problem.6 w/ @# j8 L. ~. Z8 ~

    3 x3 z2 ]8 S! p4 o2 ^1 `3 wComponents of a Recursive Function) q4 D$ R, C% Y, `( b
    / x8 U; c. y1 q
        Base Case:9 p( ^9 H8 \1 H( ~( M7 d
    ) _+ y: s1 B0 X$ k/ e
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    % L% @5 R  e: c6 u0 f
    / X- D4 @( T9 D  h' }        It acts as the stopping condition to prevent infinite recursion.
    6 k" H" O( C% h+ m: }. |- ~2 O
    % D1 g3 S* m9 m0 r- T1 z        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.; ]  X6 B2 F; D( H6 a5 A/ N) h
    1 `- U1 E$ S8 _  S9 n
        Recursive Case:6 n0 K; i" S8 C# k, `. k: p

    6 R3 l8 Q1 x8 O( z; H3 D$ E        This is where the function calls itself with a smaller or simpler version of the problem.1 I4 i& z6 O7 D9 K6 L5 @$ e* p8 j2 g

    ; B9 K, ~+ W$ f% }/ Q        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).4 h3 X6 _5 G/ L- K2 W

    2 h5 c2 A5 Y: @2 k' `! D4 QExample: Factorial Calculation( J  @; |) @* F3 M6 z
    . k5 E: T6 Q% d" @$ f9 i
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    , F+ \2 l7 q9 `  \9 O
    7 J$ W2 [3 f/ m; u# r2 f( Z    Base case: 0! = 1
    + d* V* S) l1 S
    ' z" \& X. ~0 i! u. {: K    Recursive case: n! = n * (n-1)!+ |) l( ~3 i( E, M; i' p  Y

    . o6 |. M+ {2 [& Y( HHere’s how it looks in code (Python):
    8 X# z+ q, b* g" N7 n6 Qpython
    $ Y- |. Y2 F3 `: b$ D5 x1 y: b( ?
    ) K. U, U- H+ G% S1 n/ |; V, u$ Q$ x$ X7 K* v' Q" e
    def factorial(n):
    4 H5 m; ?& e: |    # Base case6 i- n6 J( L* z  A, }% F& p
        if n == 0:
    $ _) i0 m* S% i4 t2 d/ D" C        return 1
    7 U. J, I8 E' z2 E- U2 x/ s4 H. w; f    # Recursive case
    2 K$ q4 P& q" {    else:0 Q( I4 j! D6 R& D$ ~: L
            return n * factorial(n - 1)
    3 V$ R) N6 W# c
    8 {9 `2 J9 r7 o% e9 }# A4 P( V. ^# Example usage4 y' y* C+ b$ Q/ `
    print(factorial(5))  # Output: 1207 W+ Q3 H; j8 x; x* J" ?( Z. f' z* c! Y3 j
    # d( m7 S3 J7 D. H0 a! `7 o
    How Recursion Works
    ( C8 ?4 C$ M. R2 L- N% C. G
      c. ]/ N0 ^6 [    The function keeps calling itself with smaller inputs until it reaches the base case.9 E; \1 Z1 f0 a4 ^  V# d1 w' X& A
    ) L4 k+ D& @( x5 f4 z3 u* W( k
        Once the base case is reached, the function starts returning values back up the call stack.2 p3 \2 p1 ~" E

    ! X; W1 ^1 D; b; z    These returned values are combined to produce the final result.: G' H: g' s! S8 {
    2 M0 n4 m4 s4 O& n, J$ {
    For factorial(5):
      z5 c; E/ Q. C; a" u' H* V8 q) R( n9 ?3 e* A: ]. v4 R

    ) Q: a. B5 E+ L7 Ofactorial(5) = 5 * factorial(4)9 n  z# b9 O9 Q- q1 b
    factorial(4) = 4 * factorial(3)/ v# q7 v% g/ ]' j
    factorial(3) = 3 * factorial(2)2 S3 e% r8 U6 C' i
    factorial(2) = 2 * factorial(1)
    4 Z4 M+ i4 G* ?$ rfactorial(1) = 1 * factorial(0)4 _/ S5 B) K5 @; C. v
    factorial(0) = 1  # Base case% S, R# }1 T  i! z: O0 T+ h
    7 Y! d, [  ^: j1 u8 x& E0 c- h" h
    Then, the results are combined:
    / [  y6 }4 ~+ n. j, |2 @3 {4 t1 r( b5 K0 j- J4 o6 h
    $ H4 i: X2 I$ g1 q8 s: }
    factorial(1) = 1 * 1 = 1
    * i( P% l, y7 J5 M# Xfactorial(2) = 2 * 1 = 2
    ; {% T" U, J* V) ~& @factorial(3) = 3 * 2 = 6
    ; I$ E8 Z3 F3 R9 R/ y* Pfactorial(4) = 4 * 6 = 24
    ! D4 Q; n/ p5 |1 K( w0 Y! Pfactorial(5) = 5 * 24 = 120; K3 g3 U  R/ J- c1 }. a. `
    " i0 H# w: t& K" F8 u) _8 N: y
    Advantages of Recursion
    ' \$ k+ m+ e4 c' t9 @" Z- }8 w  t) @6 J1 f* j
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).% Y9 L2 z# e8 t: O+ a" v
    2 b" A$ D- i" c  T* k- V7 l0 |
        Readability: Recursive code can be more readable and concise compared to iterative solutions.. f4 k1 O3 V- C" w! b# ^0 b2 k

    5 g5 U3 x" N: n, E3 A7 TDisadvantages of Recursion
    ( A  l' M$ K" E3 z( Z# L' k3 r8 _+ p- n) ]
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    ' T0 J4 j% H* E. {
    ! S& I5 [- h# h; e  w1 [8 p2 C    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    # i7 `9 l% E+ X
    ' Y* H/ x- V: X0 [& \When to Use Recursion0 {" ~, U/ B: p) h' c8 l
    ! A/ ^( o5 N% H
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).0 W4 e' a% g. E) o# b: Z1 G9 H. Y: v
    ( P; V+ m9 a0 ^$ `) a2 E
        Problems with a clear base case and recursive case.
    % d" {3 d' T+ Q5 x6 y# C8 C4 |7 E, }8 f) |+ B, L8 D
    Example: Fibonacci Sequence4 B7 @, b% X* w( j# s, o1 @% g/ w

    % T4 Z# Y6 X; n, EThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    * t5 e) [2 S1 u$ Q
    . W+ d) z5 e; \1 E) p4 [    Base case: fib(0) = 0, fib(1) = 1
    ; ?! v) z" C6 O7 Q
    5 J+ l8 H7 {# h" o/ i: r; f0 A    Recursive case: fib(n) = fib(n-1) + fib(n-2)% V  w* s2 j4 o& \
    - `, T( f. ]- q; D, h, y) p
    python
    & @% _. w/ l9 D+ H0 ^9 V6 J  {) p' h/ U, P7 f
    - s3 k; Q& ]) x  A8 @: I, }$ h, U# C
    def fibonacci(n):/ _3 {: r2 |! s1 s
        # Base cases. H5 b; M* J* H0 k& G3 U. i7 R5 W: }& s
        if n == 0:% U" y3 i$ L" E0 O
            return 0! J- u8 t, j3 ]  f- ^: K& j# H& s
        elif n == 1:
    6 K4 ]  a$ B; S4 E3 d$ D        return 1
    ' F* C* T1 q9 A' Y+ q    # Recursive case
    : ?2 H  |. z/ @' |& ~7 M/ u6 V# Q    else:: ~3 Q; j1 @1 _0 A/ r; ~
            return fibonacci(n - 1) + fibonacci(n - 2)
    ( K) f: p7 d9 C! N& b6 B4 N7 o3 _8 i! y/ N2 S! |0 Q( L- p% D) o) p
    # Example usage
    9 R( m9 K6 ^$ C) i" h/ d+ Gprint(fibonacci(6))  # Output: 89 H" x2 N5 n1 t+ u

    # x" g& k( `6 UTail Recursion9 l  l* q7 Q* f  W* z

    6 b3 O1 W$ O( b# g  \' ^Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).: j1 \2 ?$ N* W0 I+ }8 U( Y% ]

    9 v0 O- W* Y( _; h& Q& {- ?In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-3-30 13:05 , Processed in 0.069920 second(s), 20 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表