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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 9 h) I" Z( n. i' P* q" S
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    解释的不错& ~% d) i' w0 `6 p! E6 ~" d( K4 p
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    ! K; o2 I2 z8 V5 w' D0 s0 B5 r5 [+ ]1 ^, U
    关键要素
    8 n! M$ E8 r- e" T( r$ t, l- O9 n1. **基线条件(Base Case)**
    7 b' b, [8 L- X# c   - 递归终止的条件,防止无限循环) y% m% v$ f* G! w
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    9 b5 C1 }; Y' \$ z# e' e. i4 v' w5 i7 M
    2. **递归条件(Recursive Case)**
    . G, s. F, h/ G# O, y. Q   - 将原问题分解为更小的子问题3 T4 w: I% ~" v! m) S& }" ~0 Y
       - 例如:n! = n × (n-1)!
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    经典示例:计算阶乘# X, Q# _4 q3 e$ y
    python* Y8 w0 ~( _5 I) g4 }  i; W
    def factorial(n):
    $ L, {$ H/ U2 A/ E- e. S    if n == 0:        # 基线条件
    % g/ `* P* p' X: P6 W        return 1, y1 Y& v' K! N6 V1 |8 S
        else:             # 递归条件
    6 @4 {5 L5 A- [' R4 @3 c        return n * factorial(n-1). ~! Q8 B! \) e" j
    执行过程(以计算 3! 为例):$ q# W6 ?! h) }- K0 y& ~
    factorial(3)& \2 [4 g1 ^2 v; p  k( S
    3 * factorial(2); L6 x" f" [1 V9 G+ O
    3 * (2 * factorial(1))0 R0 e7 s9 z* Q0 w6 G
    3 * (2 * (1 * factorial(0)))
    * X; X- p) m7 J( j& m8 S3 * (2 * (1 * 1)) = 63 A9 T3 D" D8 r4 s( ~1 L

    - [( `( W# o9 K) ?* o0 I8 G 递归思维要点7 T( u- f4 J+ r, p  L; c7 `0 M
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑% j: F( F% T  V9 L( ?
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
      P  A* l# R, H+ H9 [' F/ d/ g' ^1 d; _3. **递推过程**:不断向下分解问题(递)+ I6 T* c3 C) n; Y3 Y8 `
    4. **回溯过程**:组合子问题结果返回(归)- c1 y( c; [5 {8 i* J

    ) }( F6 G. l( k 注意事项
    ( i7 K! M, s7 s/ h5 H必须要有终止条件
    9 ^' M$ L; t) _* I2 m! z( L递归深度过大可能导致栈溢出(Python默认递归深度约1000层)3 z8 E0 m4 S: i6 @
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    0 L+ J' ~3 T; M. i' _尾递归优化可以提升效率(但Python不支持)
    - u) i4 ~/ q- }! L2 f4 y7 X
    4 }; c7 I! k% ], p3 q7 V! `# {/ v 递归 vs 迭代/ R- c3 P6 q* S" P5 S  M; c
    |          | 递归                          | 迭代               |- s1 b2 r% W, O" `
    |----------|-----------------------------|------------------|* v" x! S# P8 M; d4 L3 S( ]0 r
    | 实现方式    | 函数自调用                        | 循环结构            |6 w7 M: z/ w" Y9 J8 x: g3 X+ x. |9 [
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    " a/ O0 X4 b( d' @; ]  j0 `7 A! C| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |+ k* x9 ~7 ]$ w; E/ P
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |- V' F- R8 W& \/ \, y3 q

    , k) i) G/ I- |9 f$ N) i9 O 经典递归应用场景
    0 a9 U/ R! L$ {1. 文件系统遍历(目录树结构)' J! Y& s. Z7 J1 v
    2. 快速排序/归并排序算法
    ) L5 ~0 H5 v3 r) B0 X+ R4 {3. 汉诺塔问题
    * ?% v4 o8 ~1 ]1 w4. 二叉树遍历(前序/中序/后序)' f" y, @4 B4 v4 b8 h+ P
    5. 生成所有可能的组合(回溯算法)
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    % ~1 W) V7 {7 d: s" y( i0 J6 j试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    9 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    ( a! N# X' j+ H. D我推理机的核心算法应该是二叉树遍历的变种。
    1 a2 T+ }! R) n" `& }另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:" w- E4 ]9 a$ `# m
    Key Idea of Recursion; t# I4 n6 Q) D
    7 a5 x& u8 Y1 |1 o* m1 Z, b& _2 |
    A recursive function solves a problem by:
    " U: S5 P9 K, v- e. o/ ?. t5 c  K5 }' a- F3 y) R
        Breaking the problem into smaller instances of the same problem.5 D7 n7 P8 [# m% e

    ( L  P+ n6 I4 V+ a1 q8 K    Solving the smallest instance directly (base case).
    3 |2 o. B- \6 `& \: U+ B4 N5 L
    # I+ W3 I: f5 }3 B* G0 G$ u$ s6 q    Combining the results of smaller instances to solve the larger problem.
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    Components of a Recursive Function# D2 \% M7 M( F. T

    2 M* Z; i- i/ l/ H9 i    Base Case:
    " p8 w% q: H3 y% U; S/ V3 ], X% I4 J& B( q. v* H
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    9 @% n+ m) ]6 F1 y; X
    6 y1 D" |2 V2 B1 ^: @        It acts as the stopping condition to prevent infinite recursion.2 |3 T, E% x( `2 I
    $ F& t. u( U# @) T6 O: {
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.1 P2 O% H4 \- x+ j. D" S
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        Recursive Case:
    " }& e/ Q+ R' d9 _, }
    - K) X) R' K+ t+ _        This is where the function calls itself with a smaller or simpler version of the problem.% R, x2 T# t. ^  H

    # o. z  `9 T. `: O" l        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    / {4 }' Y" r2 zExample: Factorial Calculation8 Y( Z: G8 B/ |) \) z
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    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:* Z& C/ P' B$ l9 Z% U# W4 v; Q

    & B9 O8 [" y% Q    Base case: 0! = 1
    + ?: w( u7 ]/ a5 M
    6 r- n  t" x* u4 ]0 [  I1 U    Recursive case: n! = n * (n-1)!
    8 a- y# j: G# B) ]: A5 q# S
    ; N) j3 x5 B. Y3 b0 d3 @" {, xHere’s how it looks in code (Python):2 e7 E8 y: z1 U& f% A+ j
    python9 {4 M, }7 I1 G! H' \7 o0 ?# y
    : Z5 ]. E3 H& S- L0 j& ~

    6 Q, c$ w5 c1 d1 q9 n$ O# O5 ], rdef factorial(n):
    / B$ \1 d/ E- F0 h& `    # Base case' T: [3 O. }. Z
        if n == 0:* H( N9 B, A' b" b7 l# E. P# c  C  O
            return 1
    ! [% a$ {$ O3 k. B8 o5 v    # Recursive case6 q" f% U9 D: e* N+ a+ O- M
        else:' s1 L6 M. _# o! ?) I/ ~' x
            return n * factorial(n - 1)
    : U3 a  Y2 x; D5 s! i
    / j. O) ^" f3 j& G# Example usage
    ! G2 e- P7 }8 E( o7 E; oprint(factorial(5))  # Output: 120" l. W6 G+ e0 m9 S& O, |
    ; F1 N7 A. Y) P6 N% l' B8 K3 G6 j
    How Recursion Works/ a# g0 r7 l  k9 U, l1 h

    - i! `3 d% @4 |- x$ G; r    The function keeps calling itself with smaller inputs until it reaches the base case.9 n- \$ W2 z9 x/ y6 ?
    $ g  _5 T1 V$ J- z
        Once the base case is reached, the function starts returning values back up the call stack." Q/ C& r- a* L5 ^+ a$ {8 @9 L8 B
    . b$ w8 J/ {& @+ y0 A  t5 r2 i
        These returned values are combined to produce the final result.
    ) \! f+ L+ U* S1 h0 Q' }
    . T8 z0 h" b: L/ w  wFor factorial(5):4 t+ s& z7 C/ v4 j/ x6 g. T6 W# Y

    , u) T/ R8 S8 ~, m; V- W6 K% ~/ ^/ U* B0 ?
    6 ~' z, T. {! i9 W4 mfactorial(5) = 5 * factorial(4)- z* z- ?/ g1 X6 O4 G
    factorial(4) = 4 * factorial(3)2 `  d/ n' A* M- P/ D/ O/ }; d8 w
    factorial(3) = 3 * factorial(2)
    1 r# U, `+ o" |- F3 F' H( ~factorial(2) = 2 * factorial(1)9 D  e! s" s5 H0 a
    factorial(1) = 1 * factorial(0)
    ( W6 m! m; S( A# k; }factorial(0) = 1  # Base case
    8 {, f6 s0 o$ h: N) w; U# r+ p; X+ E: T9 ~* q/ G+ _
    Then, the results are combined:
    # ?3 e. ~9 Z* {. j6 M- E  O8 v! \
    8 P: O( R3 b. |8 i5 V: J$ l
    factorial(1) = 1 * 1 = 1
    5 u: e, X+ f9 X6 v8 T9 `# L% ufactorial(2) = 2 * 1 = 2- h7 e% g, W# Z- _' S# c  L
    factorial(3) = 3 * 2 = 6. z. f$ Y( r) Y
    factorial(4) = 4 * 6 = 24
    . _0 p' {2 I* j- ~" X9 S4 u) ifactorial(5) = 5 * 24 = 120
    3 p2 t" Z* B& W) H) ~2 P* x
    3 v8 \/ u2 z; L9 D8 j8 E7 L+ G( k0 NAdvantages of Recursion
    . N$ @2 p8 d! U  q* k: `# \0 _: }% U
    : L( m  _% t" a2 |    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    ) J, M, D/ h( T5 @9 o
    0 _5 L( o% {/ G+ T    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    # f! ^& g6 T4 j! j" k# B1 r
    / V( I4 `% `( bDisadvantages of Recursion: |) N. O2 }" c. I- V
    4 {* V' T  e; y% \
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    6 t* S1 n/ S9 M2 u2 [; a! \/ d
    2 A) v/ h% Q" c2 F1 R/ }    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ( B- m. M% p# c5 G8 h& Q% n) d; ^' j9 O  E
    When to Use Recursion
    8 s6 ^2 [6 X! V4 J
    $ B# H- f7 Z* D: o7 F+ v    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).: n+ h$ o6 S0 n& q" K
    / }% d! ^6 _5 G" o* Z4 D+ P" _
        Problems with a clear base case and recursive case.+ d* T  i) l7 L; ^: b
    9 n) l$ |7 \# X- {
    Example: Fibonacci Sequence
    9 B1 B% }( d  u7 c$ }$ W* r) }! D
    4 r- O3 a! ]) J9 H2 W0 U/ }, UThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:+ |6 ]! @3 t2 b( c* d
    ) S# a  ]8 n' F. g; F( Y: \" X
        Base case: fib(0) = 0, fib(1) = 1* f8 k; ?3 ?" v* Y2 f$ O6 B

    , d$ u2 E( E  D9 b  n7 o& s    Recursive case: fib(n) = fib(n-1) + fib(n-2)+ c4 P  R- K. H. `( X/ ?1 N; `

    ; U# C6 I! f3 B7 _# q" M+ r. zpython: ~9 i  j7 H8 {
    ) h  h( I4 Z: e+ P1 J

    9 N5 ]4 M. u9 Y( A5 T3 C& t& Ddef fibonacci(n):
    6 l8 x" H( Y: y    # Base cases
    & m# P* E4 u" m% d7 c# @    if n == 0:5 _+ Q) u, w; M0 J# I' \
            return 0) A: m, k, j$ U
        elif n == 1:
    * H5 |0 Y* i* W) J) P% s3 I; @        return 14 e9 X, z7 c4 J: T
        # Recursive case
    2 v' V5 c4 O$ ~8 n7 K; G    else:
    6 Y6 Y2 v( |$ E        return fibonacci(n - 1) + fibonacci(n - 2)
    ! l" x' y6 A1 j" r- F* M' ~4 }+ V4 _5 E$ W- r2 N2 s! m
    # Example usage( Q5 T* M6 o* j0 z) P( `* R
    print(fibonacci(6))  # Output: 82 r: h; d9 I6 Z( s+ z- H
    ! o$ j9 u& z& \2 k
    Tail Recursion8 Y6 T! Y6 K7 @) x: b# E& C4 p. L% }

    , \' @2 h8 s/ t0 S3 O) Q: YTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).+ W0 g7 k' Y& u2 }4 {. d) n

    2 d! Y8 D7 Y5 a3 z, }7 ?: j6 GIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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