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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 4 B, D# f1 ?. v2 Q7 Y5 @5 X5 N. K
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    解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    4 a: q6 u9 s. t0 z9 s. }, }
    ( X. k, n6 v1 E; H- k 关键要素
    + s. L$ m% Q( ~% C- U1. **基线条件(Base Case)**9 u, Z7 f; G( V4 U$ c% N
       - 递归终止的条件,防止无限循环
    / @& E% S- Y# E& R- L   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    ) W4 P2 y( j$ @# A$ M# F0 Y5 v
    2. **递归条件(Recursive Case)**  A5 ]4 y: {5 A; K, I) b
       - 将原问题分解为更小的子问题. m7 M' C9 O0 @$ j5 \4 h2 z
       - 例如:n! = n × (n-1)!
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    ; B1 T1 P8 h$ i  O 经典示例:计算阶乘6 W0 a+ k/ V7 j6 C6 q. a( h
    python- c% R5 f/ P% g
    def factorial(n):
    , X9 c$ A* q' z7 S/ Q7 l0 O& M    if n == 0:        # 基线条件! {9 i! G/ h& x- @. I/ J
            return 1" _' G3 N2 ^5 ~
        else:             # 递归条件
    8 q* f0 E# d6 p$ r# g        return n * factorial(n-1)- S. n& {& e7 m. n
    执行过程(以计算 3! 为例):  J0 C: n: v3 `  n) {
    factorial(3)0 X* ^, e$ A: X  H6 `
    3 * factorial(2)- E3 f0 m/ g' j2 e7 |7 S
    3 * (2 * factorial(1))
    ! l2 G$ y2 y6 E4 x3 * (2 * (1 * factorial(0)))
    ! r' u+ e/ n8 d7 z, N3 * (2 * (1 * 1)) = 6: q) |& H9 S3 W  |* M5 W9 l
    ; Q( O, \$ q6 D/ G% G% F" r
    递归思维要点
    / Y9 U7 T4 @% Q9 s* t9 ~/ O% [1. **信任递归**:假设子问题已经解决,专注当前层逻辑) h: q( \  x2 E2 |( D# B
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间); N9 g& P# t' W& B* s
    3. **递推过程**:不断向下分解问题(递)/ F5 {" |+ I0 D; a4 J  W
    4. **回溯过程**:组合子问题结果返回(归)
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    注意事项
    ' ]5 \6 P/ `8 a1 {1 A必须要有终止条件; B* D# S- g5 A- G8 X
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)2 y" e4 K! {. R4 w! E
    某些问题用递归更直观(如树遍历),但效率可能不如迭代  P- V/ N4 `: A. z5 l; x. ~( a
    尾递归优化可以提升效率(但Python不支持)
    : D* `& }7 {4 s, y9 q3 {- x& Y) t
    , j; ~' ]' G- ?8 [2 K3 g: o. X 递归 vs 迭代
    2 K& O/ m* P* U1 q- z& H|          | 递归                          | 迭代               |
    9 C8 _3 }1 c) C9 a, i' \|----------|-----------------------------|------------------|. C3 r' N1 m+ R- Y
    | 实现方式    | 函数自调用                        | 循环结构            |+ L( s% M% D6 r
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ; c7 y0 {; R; t$ l1 {9 r| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |! V" {' @. u/ k
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |6 C: s- }/ h( x" ]8 d
    - y# w! ^* f& W9 o
    经典递归应用场景
    + W1 J: Y# w( {8 F' a" k1. 文件系统遍历(目录树结构)
    ' C; Y3 ~1 h2 `) e2. 快速排序/归并排序算法
    / E* u& Q0 D% P- q3. 汉诺塔问题! u# }; @6 H; H& R  ^
    4. 二叉树遍历(前序/中序/后序)
    ( V  z; y. r  T4 L: U( Z0 o, V7 F# U, k5. 生成所有可能的组合(回溯算法)
    2 U8 ?. v: \9 S" o( B5 f
    0 c! H- H. j8 i9 k5 }+ J( }# ]试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 07:17
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,) {% K3 l, l+ C) I4 D7 l6 k
    我推理机的核心算法应该是二叉树遍历的变种。2 Q7 S  M+ V8 W/ }4 g/ S* r7 _
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    * p1 C) `' u1 |5 V5 uKey Idea of Recursion
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    & D+ Q0 V8 f8 d. GA recursive function solves a problem by:
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    % b( O# e$ q- q, m0 T6 b' e    Breaking the problem into smaller instances of the same problem.
    9 ]* [5 W, V6 {3 [# p% W0 r! a- ^% L/ i! `  s1 C# f( ]
        Solving the smallest instance directly (base case).: M/ _! G8 d; F/ a# Q1 F
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        Combining the results of smaller instances to solve the larger problem.
    , t* E$ W( B* I; E4 p; H+ g/ f7 r$ H/ h/ I+ p6 U- |
    Components of a Recursive Function( {: \" ]2 `2 e

    # B4 H" p; N0 P* b2 u' o+ Y" h. w    Base Case:7 t1 j( d1 Q6 h- J' G- x4 g

    9 T5 A) G! T2 `8 Y4 N5 k        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.! n. j; t: o& D, [; o
    + F, Y0 M. |- ?* g5 I/ A
            It acts as the stopping condition to prevent infinite recursion.( ?. D# q! I( W

    $ s7 X4 |& V* h+ c( \6 z$ z        Example: In calculating the factorial of a number, the base case is factorial(0) = 1./ u' F( L& p8 {3 A

    , U) f2 {: R! j& b. Q9 [# X5 m1 C    Recursive Case:
    1 s( G5 Y. v& s" X, q) f3 r$ r* a) q/ }
            This is where the function calls itself with a smaller or simpler version of the problem.: _) A; H4 M- J

    4 K2 l9 _) z2 W2 g        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).% c4 t9 R- \9 o8 [# r9 p
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    Example: Factorial Calculation
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    , v- l$ P4 m3 f: w& JThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:) Y# T1 j- z, [* h! N  X! ^
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        Base case: 0! = 1
    ! e- B8 Z& j4 b9 U' L* X. c9 x; b% H- K' W( S$ |
        Recursive case: n! = n * (n-1)!0 J6 r: _- x/ o7 o. ]% z

    : ~5 H5 Z! }, x/ u( [- rHere’s how it looks in code (Python):
    5 _8 X' j. u& ?% Xpython
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    9 c! R0 W9 \# Q" ]" R3 \) G/ F1 `6 J+ d
    def factorial(n):
    . S% e; d/ F. e1 c. N2 I    # Base case6 ^" M. _0 L$ O- r  k9 o% O8 H
        if n == 0:/ U7 L( o6 ^( I  J% Y& x& n9 ?' ~
            return 1$ o6 A) J# b4 @; _* D' E7 G  b
        # Recursive case- i: D" T" N! m' A* M, y+ H
        else:
    # C1 P- t8 ^2 D7 J        return n * factorial(n - 1)
    / f+ Y4 m! C# E% ]. y: }3 a+ h( E5 \7 J+ R: }" [% J
    # Example usage& q1 K, W! h0 h
    print(factorial(5))  # Output: 120
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    How Recursion Works
    # O! o" z8 P! ?% W- J) d# |# Z5 f. V7 \- h5 f( w, Z: p8 [; x
        The function keeps calling itself with smaller inputs until it reaches the base case.* G% ]/ [: F; N+ g/ `( t
    7 D1 h( \' k+ [
        Once the base case is reached, the function starts returning values back up the call stack.
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        These returned values are combined to produce the final result.
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    For factorial(5):# k- ^' e0 |" X8 I  C1 B" E7 |

    / A" l9 R0 X% k' b- g) K0 k
    0 S6 s: n- [3 S! V7 p  Z  Bfactorial(5) = 5 * factorial(4)! |# X/ ]/ E, P* g
    factorial(4) = 4 * factorial(3)
    7 T  L6 G+ j* p! h+ f* I- V/ p5 Efactorial(3) = 3 * factorial(2)2 ^* c3 q0 u  T6 z, a* Z4 b
    factorial(2) = 2 * factorial(1)' Z; E$ O" v. \4 s- }" L
    factorial(1) = 1 * factorial(0); ]) K' n7 q. q! N3 f" }
    factorial(0) = 1  # Base case; w9 s4 I! w& o3 C6 i3 S

    0 Z) U0 m4 W! e. p, DThen, the results are combined:$ R, G9 c% ]7 h) G$ Y! g$ d4 i

    2 l( T, M# m9 F7 }6 F- {1 {8 w/ h! p; h& R% F: B4 y6 @
    factorial(1) = 1 * 1 = 1
    3 f4 I/ F5 q: E% s2 l; r- jfactorial(2) = 2 * 1 = 2  R4 ~* O# A9 g' S2 I; X
    factorial(3) = 3 * 2 = 6
    9 @+ ~, D$ P' `# \. f) _factorial(4) = 4 * 6 = 24+ O1 X. ^' i+ L( a9 V0 G3 j
    factorial(5) = 5 * 24 = 120
    % B% V6 y' i. a) D& E8 C+ F4 n/ s; F8 m( M: c5 T* J
    Advantages of Recursion
    : D3 P( L& K$ {& d* t% L8 {) ?
    4 N- Y. \; a# i1 K8 K4 o    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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        Readability: Recursive code can be more readable and concise compared to iterative solutions.
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    Disadvantages of Recursion1 p* O6 X+ e# E+ K$ ~- d
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        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.' `. |& Z7 `& m
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        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).& f, P$ S5 M. x2 L' s
    + i+ U! h2 T$ \! o$ Z. w7 S; N; `
    When to Use Recursion% R4 u3 e! U* P* O$ z, I0 y

    2 G6 ^- b" A0 e3 h" z    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    & a4 N4 {) z2 Y6 b6 ]) U0 F$ p( i$ Y5 X* o
        Problems with a clear base case and recursive case.; V  x- L- v- q/ E0 n) Z

    . u  g/ O1 t9 C7 r0 x# e$ V, G8 {Example: Fibonacci Sequence+ C( E$ g* i, h* R$ e0 b
    3 p5 S) O7 @! O4 Z( g
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:1 G* L# i" ^: m. A

    8 d; S$ J4 t( ^' ?+ R5 q# O' U    Base case: fib(0) = 0, fib(1) = 1
    ) N/ W6 G& c$ R, d! ~! V
    2 ^5 m" B, j4 T    Recursive case: fib(n) = fib(n-1) + fib(n-2)3 u: v  D+ \) A' }- Z
    8 C! {. K' j; t% [  D0 k
    python! c+ A4 ^6 d8 z# o1 ]

    ! T4 Z5 ]/ ]# v6 P: }* k" v8 A: \, Q* f" w" a! z" e
    def fibonacci(n):. D5 e* W, y6 r! F- V7 x- \/ `) c
        # Base cases
    . r# }, }$ H# j* D' u    if n == 0:# d8 s* g6 \# J7 G
            return 0
    # a& q$ L* |" \6 G    elif n == 1:' k$ I. T- T/ \6 q- Q7 ^# [2 h
            return 1
      v+ w, Y1 V2 [3 B6 {: E    # Recursive case
    : C( L' Q( k0 L- Z! \" u% b! f    else:
    - y+ `+ a8 [% N3 N; A' i; c        return fibonacci(n - 1) + fibonacci(n - 2)
    ) C; ~+ k6 p3 E2 U/ ^% K/ y- P6 w8 k" p
    # Example usage
    3 z6 [2 o8 B2 z8 c  N' W$ m4 Pprint(fibonacci(6))  # Output: 85 v# s* ^& J% p; ~

      W0 {& B5 k9 f3 B7 j! PTail Recursion" Q1 ^; G4 ]5 y* i  N
    9 C. n$ A: m; C
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    ! S1 z$ ]+ |# }( m( G1 X
      D- x( ?6 s) z/ T' i' ^5 ]In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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