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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    # ^0 T1 z( E; ]! Z+ w/ I6 d( m' y! U! ?/ M! q
    解释的不错1 A. D% Y$ D9 ]4 X5 y7 z' n

    : W  {# i% p! S, p' ]* G% d递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。+ Q7 q5 r7 O# H5 y. L/ V2 b
    3 P& l0 K4 p& Q: l9 n' p
    关键要素
    * Q+ f; W; B, E" J, m4 Y. c1. **基线条件(Base Case)**8 `! }: a) g/ C/ X7 x
       - 递归终止的条件,防止无限循环6 f9 I7 i( T$ I% G/ V
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 18 q. r2 y( a/ W4 ?( V! e, A/ Z2 u% @
    - w& u* L& `5 u$ n! A
    2. **递归条件(Recursive Case)**; N- z& l0 p; x* p
       - 将原问题分解为更小的子问题
    1 J* ^) d6 l) w5 r   - 例如:n! = n × (n-1)!2 d" y; Y2 _# x5 H7 E) ]
    ' |, n3 C' L6 W% U5 j4 o$ e
    经典示例:计算阶乘. p1 y' ]3 G% N. `
    python5 d9 u8 y0 |3 U1 r( L
    def factorial(n):7 {8 b% {/ F" b3 W" u. L6 c( u% r
        if n == 0:        # 基线条件# }% s$ `0 m5 h  Z& j; f
            return 1
    ' F+ H* A# M$ ]8 }    else:             # 递归条件
    1 r  P0 w& f6 T5 z        return n * factorial(n-1)
    1 Q! C9 M/ h2 `执行过程(以计算 3! 为例):
    3 H& @' O' X6 n/ Y2 k5 k/ w. }8 afactorial(3)1 }; N) H( d( C- Q9 P
    3 * factorial(2)
    ' P  j1 v. T4 K3 * (2 * factorial(1))
    " l2 v! m+ E1 g% u3 * (2 * (1 * factorial(0)))
    ' H. M8 J' P) K3 * (2 * (1 * 1)) = 6
    " E7 x$ B6 Q1 J7 }0 k& \* r& U" i+ Q6 q1 h( [
    递归思维要点
    7 n. B2 D8 w+ N. \0 a; M2 n" C% L1. **信任递归**:假设子问题已经解决,专注当前层逻辑" D+ G7 S6 h( C9 W! C* h1 M
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    . C$ M4 K) @% s  ?3. **递推过程**:不断向下分解问题(递)# K. H" D: l' g0 q' j* R% h
    4. **回溯过程**:组合子问题结果返回(归)
    5 L" O. Z/ z5 R. a1 V: b* g" u- |
    注意事项
    ; i% z( q- M% M# L( L0 }) R必须要有终止条件( e" G5 O- A" V; P! ]
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)( ?8 W3 b5 y& X8 @
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ! C6 Q. E) j/ e尾递归优化可以提升效率(但Python不支持)
    - `& Q2 i6 W! v$ m
    1 a) I$ @/ Q3 ?; { 递归 vs 迭代( d. ?9 d1 d! C) J: G
    |          | 递归                          | 迭代               |* U. w7 R3 v6 |# g' Y8 A  q
    |----------|-----------------------------|------------------|6 ~# {- V# J' V" p
    | 实现方式    | 函数自调用                        | 循环结构            |+ [. `# m9 G) x- T! [2 G
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |9 L- A  P6 l" _8 t8 W  x* Q' n# ?7 w
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    + Q& E% }7 B7 R1 G/ z, J" N/ }( h0 @7 L| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    - X8 B: T9 X. W" U
    7 t) L* z: v& I2 q- ^" A6 S& d9 L 经典递归应用场景* k. i/ n$ d/ |" I. c
    1. 文件系统遍历(目录树结构)
    9 ~( g9 J9 b) K7 b# |2. 快速排序/归并排序算法
    ( L0 @7 m* x# r) F- a) E3. 汉诺塔问题
    " Z  G2 ], d: x  |/ j4. 二叉树遍历(前序/中序/后序)) U# b" J4 H; d. E! P' |; n
    5. 生成所有可能的组合(回溯算法)
    0 z" `" @2 v! j4 C" y( ?  ]) g) v3 J# X
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    7 v7 u: A/ y. v1 L- z我推理机的核心算法应该是二叉树遍历的变种。
    7 ?& H4 c: F/ a, e  q+ E  r另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:2 T8 K, K* C3 J; ?9 T
    Key Idea of Recursion2 q- X  h1 z  f% K! F* |

    " m/ Y: g1 r! [: p7 }9 [A recursive function solves a problem by:
    $ d! J( `. W. G7 P
    7 N* \# Z5 F/ F    Breaking the problem into smaller instances of the same problem.
    " D: }! v: u" l, i/ Z7 X- o
    2 o; k: X5 K- ?3 y    Solving the smallest instance directly (base case).
    # g( W7 x, i3 i& R) e
    4 A2 p+ l% I$ G    Combining the results of smaller instances to solve the larger problem.
    " R$ \4 h7 n; d- z' o$ Q% S8 g2 O5 i; r
    Components of a Recursive Function* q! y8 N+ J" _* f% I% v& z4 t

    ( ]- q3 J6 f* I  F( F    Base Case:4 w' I! d  \+ u1 ?5 ~& _4 q! b3 ^
    " ]+ v- M2 {' b, \" d- X" w
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.+ r# G: u( J: m7 `* y3 ~
    . a# I6 M3 F) {3 \
            It acts as the stopping condition to prevent infinite recursion.! G$ v  a' Z+ {. z7 w
    / _; B2 K* P! R( T+ S
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.$ \" F  z- }( I5 S
    ; P) D5 P% \( y& N  P
        Recursive Case:
    8 u8 q7 J8 ]2 n6 G+ t
    0 R  _5 E/ n9 C1 ^/ I  q        This is where the function calls itself with a smaller or simpler version of the problem.5 m& y7 W! Q: O9 X) f

    " H; }; D2 ~! v) H8 l        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    & \1 v" ]6 R" T  S) F2 a0 y
    ) J: f4 C, j% C% l+ o! P& d/ qExample: Factorial Calculation6 y! w& I/ P( f8 \3 S7 [, P" J" F
    : U. g1 Z6 Q$ p# R. b
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:) ]; W( q  X5 D' U
    2 R$ F7 {- W% A* M# [( L
        Base case: 0! = 1
    $ W- w8 f$ }2 G3 S8 i/ w3 H8 f
    ) }) ^" f5 J' d. E& G/ H    Recursive case: n! = n * (n-1)!9 X# }) B, J8 g8 g  N, c0 ?

    9 @6 K# p  C2 bHere’s how it looks in code (Python):! i. J/ X5 T/ ^9 c$ E5 G3 N5 B
    python
    0 n" i9 }/ f# `, `+ {) {
      r+ |$ u5 e. F
    / V0 I7 V1 l& \' A* O$ ]def factorial(n):: z- l1 e8 Z; m2 ]
        # Base case# h5 R3 Y4 B  N& F. m! D% l7 f5 I9 q
        if n == 0:, m6 [" t+ c0 d* T! o
            return 1
    * _# \, n. F- T, b* |    # Recursive case
    6 X4 n- X3 u# M% N+ k- k: l+ T    else:/ g8 ^3 D) s/ l4 x: @
            return n * factorial(n - 1)
    9 x# G, r( u) R1 {/ x" n9 A
    % q6 E) V; J( y; D* R3 O# Example usage
    " q# U/ ?! ?1 E! _$ Tprint(factorial(5))  # Output: 120% O: t  O- `' N! r

    4 h0 V, C5 v  Q3 X+ E0 T/ HHow Recursion Works& n5 v: Z5 A7 [6 E. h( x
    # u* V! b9 |) }
        The function keeps calling itself with smaller inputs until it reaches the base case.# g# ~6 A4 S& Q5 B5 q8 i5 O! G
    : Z9 {& R3 a0 p9 H: c3 o; l9 s2 f
        Once the base case is reached, the function starts returning values back up the call stack.
    , Z! }9 \1 t: R
    5 ~) l' p0 O- u9 c    These returned values are combined to produce the final result.
    , {% v! j+ `# N& k( |/ _) F: q/ J
    8 \) b. `0 z4 i, R+ `+ w0 bFor factorial(5):
    9 ^4 t& F# |' f; l2 ]2 N- |8 C' R1 S! F7 u; p" x" H& u
    6 I' k! ?+ H) B* t  H
    factorial(5) = 5 * factorial(4)
    ( y; O# H% `) F) d5 j# Mfactorial(4) = 4 * factorial(3)
    9 S% A5 l- e# ~1 J! y, \factorial(3) = 3 * factorial(2)3 H2 K( p9 F0 Z# P' o$ [
    factorial(2) = 2 * factorial(1)* ?& S7 m( f1 d+ x
    factorial(1) = 1 * factorial(0)4 I: ]$ `" L8 q  I' E( @! Q
    factorial(0) = 1  # Base case# w8 o# T$ v  i1 f0 W: A
    8 X  k. f' M$ ^; j$ g
    Then, the results are combined:
    * ^9 H/ S" D" A9 T: c6 U! Z# q7 R( |4 H# B6 U

    ) Z  G0 F- [: T. h5 j+ {factorial(1) = 1 * 1 = 1% B  f, }1 l0 B' E  f1 b6 U
    factorial(2) = 2 * 1 = 22 q+ V$ m! ?9 a1 h! ?. H+ U5 W
    factorial(3) = 3 * 2 = 6
    2 @$ J: h# u2 F) D) x9 efactorial(4) = 4 * 6 = 24
    " g. K0 |+ q& O% T9 l0 Nfactorial(5) = 5 * 24 = 120& ~8 T0 c* X4 |; G. h* e5 U: F
    - x* l. d: z3 |+ @/ O4 ?
    Advantages of Recursion( F  L" u2 B! n! a+ I
    # v" @8 X- Z/ ^$ S7 V* U
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).! [7 F, k3 C$ w0 z" N

    9 H- v4 |5 j. I  c) y% j# f' z& Q( Q  |    Readability: Recursive code can be more readable and concise compared to iterative solutions.0 l' G6 T% D+ Y: }) O, q! B2 ^
    & d, q, f  l/ J! i% m  Q$ j
    Disadvantages of Recursion
    ( d3 l& o: i% Z6 F  M( R# f
    & Y' b. S! u6 h% U$ u" R    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.( i# j1 a' @' e0 h# r. I4 G
    1 u  W/ \) q: m; y4 T' V# {
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).$ ]2 D9 h! K4 B  e. C  V# ~3 x

    + h. M) C8 }; nWhen to Use Recursion
    4 s7 s+ \- k# _& L: w: ?+ l/ t/ R. k: Y9 z5 F, ]
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    $ Z. m2 y  f4 M$ D7 F* W7 ~0 ~
    % m" H2 y1 N- Q7 Q+ ?  H; b    Problems with a clear base case and recursive case.0 T) l2 }/ m# K% a2 e" q% ~

    % X7 G; J7 V$ g6 oExample: Fibonacci Sequence; h7 K3 a" V7 l
    & j- x9 a* Y! t: x4 D
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    / b/ c9 Y4 f" o6 F4 C2 [+ Z0 |) U( R* R7 d% z/ h, V
        Base case: fib(0) = 0, fib(1) = 15 h) U* ]6 r# Z* `

    , s; p# y; @& Q$ x% |, C7 z    Recursive case: fib(n) = fib(n-1) + fib(n-2)4 F$ r. T& N' ^( F7 Q1 y
    1 J  m* s; t! L+ ?8 M$ b2 ?+ X
    python. b# j* K* d. ~4 S; @) }
    ; q- [5 t# z5 i; h$ o: H' y' G

      G7 N* F' Z3 {def fibonacci(n):
    " x& O3 h* o1 l# D) F4 F! c* P: V    # Base cases
    4 A! o+ L$ a) Y) ?5 X, }9 T$ g    if n == 0:
    ; l' p# @8 G: @  ]8 q. x        return 0, Z  }& [2 A+ Q) U+ c
        elif n == 1:7 ^) j* E; n. h# l
            return 1
    2 {0 L& H. L, k, o- m    # Recursive case
    8 h" j" s0 l" A& L7 r    else:
    ' n4 n& |: M9 U9 {2 A        return fibonacci(n - 1) + fibonacci(n - 2)4 t; }& G9 d0 z% A5 K! t
    6 _6 M2 ?( [, r+ ~
    # Example usage) u6 r5 o( H9 V; ^6 W6 _
    print(fibonacci(6))  # Output: 8
    ( ~% |/ f4 H; V/ T* T6 N- i2 Y$ A: y, r" f4 Y% V- l
    Tail Recursion
    * i3 D8 N% h/ y5 h* u7 k
    8 [( D3 H" d1 g) ^" n( O3 m6 Y% N' W; KTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    " o- h  o; P1 Q/ E/ d" `; a1 F- j5 g% B/ q# x
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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