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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    1 }# f) E. ^4 j. r9 s3 X, @0 E
    ' |1 L1 @( v5 O0 p+ b解释的不错% _+ [5 D  |- Z$ c2 i  D7 s! M

    ( f9 o( q8 _; z$ r, r1 v4 q递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。  S! D4 _, E! f7 c. B
    - U5 m$ O, K- ~2 p8 i
    关键要素
    - M1 B, t' F7 _4 p( |1. **基线条件(Base Case)**0 l/ D: g3 h2 D# x0 S: K0 j
       - 递归终止的条件,防止无限循环
    $ i( r, p. v. n3 B5 L   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1+ \6 I. [. U9 t+ {4 [) s% q

    ) A  o+ M0 u, h2. **递归条件(Recursive Case)**
    8 q" Q( V1 O0 o; {) D5 {& F   - 将原问题分解为更小的子问题  r; _0 j) a! f* d3 r1 A1 S
       - 例如:n! = n × (n-1)!# C8 ?% s& e- L7 M3 G- l2 I
    4 A, \* H7 S4 ?: D/ }. G* I
    经典示例:计算阶乘. s, G3 D4 u; V
    python
    # @4 \+ K( A2 d+ f2 G" bdef factorial(n):
    $ X. d  |( ^/ m: Q% |/ ~9 R    if n == 0:        # 基线条件8 E3 `3 S- W: u. r- @! [3 E: O) u5 E
            return 12 W' o0 t* Y- G
        else:             # 递归条件2 O5 v) P$ d. w+ q; z) Y6 w. T/ K
            return n * factorial(n-1)
    1 }* t7 C, c: E% m" @  i; ]执行过程(以计算 3! 为例):
    5 Y/ Z, _5 m2 U$ K* A0 u  T+ {factorial(3)
    " A5 J- b9 m8 ^$ i4 L3 * factorial(2)
    6 x- L5 n0 C5 J* k5 C; \/ E3 * (2 * factorial(1))- t( T1 P1 Y7 [! B% n1 _
    3 * (2 * (1 * factorial(0)))
    5 L+ U2 V1 s: a" t6 U/ \! }3 * (2 * (1 * 1)) = 63 z5 x, I  G+ a" J
    3 v7 P9 W& n, @' A
    递归思维要点; S$ H$ h  X- a' q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    / v3 X3 f! `0 I) H! h: f2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    % t" Y  g0 O5 _% p. S  a3. **递推过程**:不断向下分解问题(递)
    1 c, p* ]  ]% h3 R3 v9 u9 J  w( P) T4. **回溯过程**:组合子问题结果返回(归)% c4 Y" U0 G( V/ X
    ; |; ?' U& v3 c' N1 O- _! ?, b
    注意事项
    3 [/ f. s, |9 \  q' B% ]必须要有终止条件
    ) u) t' Y! }  y递归深度过大可能导致栈溢出(Python默认递归深度约1000层)$ i5 E) I: R/ s1 t; v1 ^
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    * c2 Y: \* x8 G7 R8 ~% M; Z0 u尾递归优化可以提升效率(但Python不支持): F6 g: `, U" q7 Q, M7 |" b8 t- \) u

    ' J: s  s9 o; I( J% b/ I. M: ? 递归 vs 迭代$ L/ w% O: v( l& g8 `' V6 |; m
    |          | 递归                          | 迭代               |1 ~7 J& K+ `! a! N9 w# d1 E
    |----------|-----------------------------|------------------|
    & Q# K3 [) E6 v( U  g9 U, c- R5 }| 实现方式    | 函数自调用                        | 循环结构            |
    & k2 {. p! c3 h' P| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |' `( m8 }$ S' i0 k1 C, ]1 _
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |2 ~+ C3 P" B0 u$ J0 O. o8 K
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    6 c# g% U$ c% F1 [' C6 ?/ U" a( W9 i# `1 F4 \- @
    经典递归应用场景# v6 c5 p0 w2 C8 r- w" ^0 O$ M! _
    1. 文件系统遍历(目录树结构)( _2 r8 C( ?( Z7 o$ C$ G$ T; j- }
    2. 快速排序/归并排序算法
    & g/ Q, P7 |3 X  O3. 汉诺塔问题# y* k( V! x$ I2 Q( w
    4. 二叉树遍历(前序/中序/后序)
    0 T4 t( d& Y1 O) `3 e( j5. 生成所有可能的组合(回溯算法)
    6 V4 {9 H7 n, S3 M+ w0 o, P! ]5 u8 U. R2 \7 o" [( K
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
    郁闷
    3 天前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,0 B0 Z8 k+ P$ t7 s. S- r2 N# l
    我推理机的核心算法应该是二叉树遍历的变种。
    # `9 L! Y7 S/ |" v另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:7 E# ]2 W& Q2 t$ e
    Key Idea of Recursion4 g9 W+ \& C$ i' R$ x1 ^
    5 O: P5 f4 w! H# ]6 x" G
    A recursive function solves a problem by:/ b& E1 V8 ^; G0 f7 Z

    6 U+ `/ F  m, l' f4 ?; v! m6 O    Breaking the problem into smaller instances of the same problem.' h7 D8 G6 e  d, n$ g7 L5 U
    5 T0 X& g& p% @3 q, R
        Solving the smallest instance directly (base case).
    3 M3 M: B9 Y4 N8 m9 _
    , \* G  l# ]. c; R+ p: Y0 M    Combining the results of smaller instances to solve the larger problem.
    ) ~  D5 ?7 s' |1 J
    ! Y; h, g& T# u8 L8 D0 ], |Components of a Recursive Function
    ( W% }! h$ ]7 G6 M# Z+ p# P4 b0 I3 }5 U0 W4 g# P3 e- z% M- {% a
        Base Case:) P9 t/ B7 |3 b5 v) A8 s

    4 i! j) R- C4 |9 v+ W  G        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    9 M* `5 n0 T7 w9 B5 Z* y3 R( u' H' w0 O" ?$ }2 W, Y1 V7 T. M! k
            It acts as the stopping condition to prevent infinite recursion.
    % X7 a' W* s- `9 @$ T
    ' _7 j% Q2 J; u. @% m/ b( ]        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    # B9 }5 I9 T5 Z! A; o/ a5 T4 S; e$ x5 [3 [. g
        Recursive Case:
      W7 [6 f) @+ s1 K  h2 l0 v+ q. Q8 n4 U( M+ T
            This is where the function calls itself with a smaller or simpler version of the problem." V% x) t0 S$ K

      u$ d3 g7 @  z3 v6 C0 D8 ]& _        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    ( y/ B, X! B; j3 y% o7 S( }
    2 |+ w, t+ l# DExample: Factorial Calculation) H4 X% J0 [9 F0 }8 j8 K

    ( B0 X& J6 Q3 yThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:/ F0 C! U+ X, }8 w% w$ O9 L
    ! D* }6 a0 Y3 J( s
        Base case: 0! = 1! v# I( N" T! B+ p0 _5 L
    4 P  X8 I8 u7 u; }! i8 S2 O. t
        Recursive case: n! = n * (n-1)!
    / w  s' G8 }0 X0 W
    # C6 J8 |8 E9 V* g3 S" k+ N: K- uHere’s how it looks in code (Python):1 J0 p, L  ]' M
    python
    ) u  p* p) D. O9 v3 ~4 @; u! `  F6 u$ L4 t# l

    * c  A, `4 C- \" mdef factorial(n):
    : E2 O- U7 u, f$ Q: c$ Y# {. u    # Base case
    % @7 ?' g; q2 |% `! ~    if n == 0:  z( k/ K3 o% A( g8 R1 U
            return 13 W! z$ R/ `) j2 c
        # Recursive case
    - s9 ?% s5 }4 Q7 K5 T1 m5 K+ I    else:8 }/ F7 L6 O0 y7 F& I* D
            return n * factorial(n - 1)
    " ?. k( B; k# A2 _. r8 G* W! ]
    ! l2 {6 C- f* ~& ~# Example usage
    + G& e' o! I2 o+ `5 I* f& Z/ L- Q, Kprint(factorial(5))  # Output: 120
    ; X* Z* w$ l4 U8 n4 I* U
    ' J$ f4 R: @; D6 GHow Recursion Works
    7 Q% y* n9 B* E# x% b: u3 }/ k
    + |9 V1 k+ G: f& a) E3 S    The function keeps calling itself with smaller inputs until it reaches the base case.
    ) u$ r9 a) ]3 u( J
    + f, H' A7 O: q$ `7 _( k, R0 s: ]2 _    Once the base case is reached, the function starts returning values back up the call stack." D# u" i5 e9 U4 R

    4 d& @5 T3 v/ w+ g2 v. V* Z    These returned values are combined to produce the final result.
    % O3 d- h( O; e% G  z7 L$ A  \/ K! D, w& `4 u/ D7 l. @7 n
    For factorial(5):7 \5 [  m' A# n

    ( T: |' A! n% G/ C3 }) t1 d
    / X# [% X- M3 Z2 L( Cfactorial(5) = 5 * factorial(4)
    2 t) k6 ]% h& `5 pfactorial(4) = 4 * factorial(3)* {# k+ Y, V4 D$ s) e/ ?3 K
    factorial(3) = 3 * factorial(2)/ Y3 \6 |) Y( f+ z3 S
    factorial(2) = 2 * factorial(1)
    2 J2 g% v5 ~( w9 E: V0 `/ bfactorial(1) = 1 * factorial(0)
    8 g+ E' {' f. H+ I- o+ Qfactorial(0) = 1  # Base case7 _% m% U$ {  n! }/ `
    ; {: L! ]# X4 I! \5 i6 @+ i. B5 M  ~! ]
    Then, the results are combined:5 ~% b" X" q, v4 S/ X: S& M$ \
    3 H& q8 \6 x4 p

    7 Y" ?1 z  G3 \$ {factorial(1) = 1 * 1 = 1
    , _# }7 b! I& i6 K# N  O2 o1 H6 qfactorial(2) = 2 * 1 = 2
    & {$ ~8 f4 ]1 m- Y7 Tfactorial(3) = 3 * 2 = 6
    9 r4 W- \& x, W- f: I  d, d" Lfactorial(4) = 4 * 6 = 24* R( ~4 E5 i- |' X9 K& k! j. k
    factorial(5) = 5 * 24 = 120! c2 D3 Y) B% e$ A

    6 i6 ^% M) v3 V; T, @; @Advantages of Recursion
    8 C) ?8 i8 ]* M0 l1 `7 p# P2 v& @
      ^. \) I7 I: X    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).% V) F: y4 P! E3 f! u9 W2 {, S

    ' `" L, k6 |: _. @8 N. `    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    3 @' R9 v0 X; A2 N( w/ z% v
    ' l; k: v% [' S! F3 pDisadvantages of Recursion
    4 K  w6 O! H) i8 ^# p# e; u/ q! {/ V: N! l5 P- ^! U' i
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.; T: u* `- V5 H. r

    ' J7 Z0 M' |  k' B5 C  h    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).; |2 H0 Q) G! p7 p1 a+ f+ p
    + |# g" [. ?3 }/ s3 c$ x, O. ]
    When to Use Recursion
    . h5 k: \6 W" ?+ I; i: k; ?
    ) x/ s: l  \% z! g: v' \    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    % J' E" Z0 k* ]- s5 p$ w3 T3 Z( Y2 w6 R/ i/ F9 {0 n. \
        Problems with a clear base case and recursive case., K  c- q% P* t7 w" U
    6 f* h: A- b" s1 a
    Example: Fibonacci Sequence
    0 v+ T$ n# e! J- h6 ~$ x3 Z  ?% e  q! F( i, K
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:) a; B# l2 ]# I) D8 A, q% C0 o

    * M3 R4 n' `& D0 p; h    Base case: fib(0) = 0, fib(1) = 12 @6 M+ ~1 [$ f1 k) Z! m
    ( y$ Q9 x- L) E3 F/ u! k, E% R
        Recursive case: fib(n) = fib(n-1) + fib(n-2)0 [2 J  Y$ a3 x

    2 Y5 T3 z+ `7 M1 X" f. x+ r+ u" [: `7 Gpython9 I7 v7 \' y9 n4 H  a
    2 x: {3 q3 t* ~

    ; W: [8 e1 N, T9 U2 Idef fibonacci(n):
    $ t6 P9 _; Z* b4 C' v6 E; @    # Base cases
    , e6 ]7 ^0 z8 d/ A$ V6 n& y. b    if n == 0:2 z) N/ V) P7 r# q
            return 0
      t0 V/ v, l# d2 s+ w3 C    elif n == 1:
    4 T; ^  ~( O0 Q! A7 _0 \        return 1
    3 h, F- W. r1 ?% c" B- V5 u    # Recursive case$ G: f2 c! F( m) R! |7 u; }" H1 K$ ]
        else:9 C4 q( \* P& V5 T% m' h
            return fibonacci(n - 1) + fibonacci(n - 2)
    5 `0 Z# e; ]( o4 ?( O, S' X# i" C
    # Example usage, r8 G" D* r. r1 A4 x
    print(fibonacci(6))  # Output: 8- Q+ B( @. D  ~
    ( Q' k% {  `, U2 ]. Z. `* p% N) L/ e. ?
    Tail Recursion& }' {$ E: t$ J9 m) s- {8 X
    1 p+ p$ H9 R5 v
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).3 b% u" i6 a4 P& n1 |# Y

    1 e% [$ U4 ]9 o" g0 r" eIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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