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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ; Y- i+ m  J8 M3 O$ ^" s
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    解释的不错2 X- T8 x# c: q
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。4 W7 U6 i; n# L7 {( e: A) y/ @
    % \9 T( ^9 M# V0 a' R# y$ Y
    关键要素
    ' L4 q4 d9 \( ?5 S1. **基线条件(Base Case)**
    ' }; v+ B. d) `   - 递归终止的条件,防止无限循环% I! }+ E( {/ l8 b2 G) P  p9 G
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    6 U0 a. P0 O  m% h* }7 N( X
    $ X3 O0 v5 ]. W# I1 m  C2. **递归条件(Recursive Case)**# A) H" ]- f8 H& Q3 [& w
       - 将原问题分解为更小的子问题
    $ U: |! }, I9 ~" y0 J, v  {   - 例如:n! = n × (n-1)!
    ( O. F3 L" Q) A! V* s3 }! \5 B# j. v8 {. G' {1 F! X2 m2 R
    经典示例:计算阶乘' P5 V9 b+ X; `$ n& i+ k7 u
    python  t) [# p& s* n% R
    def factorial(n):  T) ]7 W5 [* D
        if n == 0:        # 基线条件: T4 @  a$ Q1 o
            return 1) p" @: ~- O  x9 {! {  l
        else:             # 递归条件
    1 A. L1 \; ?0 Q1 i8 s4 ^# P0 K& n% N        return n * factorial(n-1)
    5 Y) ]9 b; d! j. L执行过程(以计算 3! 为例):
    1 o5 B/ }) m2 O2 Q5 k* Qfactorial(3)
    $ W% B2 K, X1 }" m0 ^. y. w3 * factorial(2)
    - a# H: ?4 r+ P- C1 z& V  V3 * (2 * factorial(1))
    ! I' I8 r* c' I& S+ k# u: g3 * (2 * (1 * factorial(0))), H. j( f! @6 B7 p" N
    3 * (2 * (1 * 1)) = 6
    ( q' ?; c, Q8 \: _% K9 s$ j. Y) J# J: R. ~4 u$ Q/ \& D
    递归思维要点
    , p& f7 P4 E7 `6 A1. **信任递归**:假设子问题已经解决,专注当前层逻辑; G" w' f- q; a) h$ J8 n, q
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)3 J7 K0 f8 j7 A/ ]7 @5 k, Z' L
    3. **递推过程**:不断向下分解问题(递)* r3 l2 N. y# I- \) z1 t7 q
    4. **回溯过程**:组合子问题结果返回(归)7 G; ~# Y; {- @

    - u: A. U& V1 w- g 注意事项
    ( g- x8 E* [- a& g9 |5 F& J! E& p必须要有终止条件
    , u: @4 v* z: t- V2 o递归深度过大可能导致栈溢出(Python默认递归深度约1000层), o5 a9 a) C6 A' Z: E/ ?
    某些问题用递归更直观(如树遍历),但效率可能不如迭代  C$ J; R4 g9 c. Q; Z  R
    尾递归优化可以提升效率(但Python不支持)
    ' D3 D, _3 }" A7 S4 X; ]# @1 j
    ; y1 }2 N% K2 a) z0 I  R- m  o: h 递归 vs 迭代+ C; T/ T) B9 l, Y/ K) S7 t
    |          | 递归                          | 迭代               |
    4 F" U8 |7 M2 j7 y|----------|-----------------------------|------------------|9 i0 g8 {, z; T' {: I
    | 实现方式    | 函数自调用                        | 循环结构            |
    / C5 X3 J3 K8 i! {& a| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    * A3 j$ b; A7 k5 A; D. @$ n9 x& q| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    : f. \. a& x: Y" f: s- @% G| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |) J" d! y6 V* m' K0 ?& r8 k
    7 B2 @7 ]6 h. M1 e9 ?0 ]4 e
    经典递归应用场景
    3 ~7 h. U# [- q! W3 Y3 X# U# A1. 文件系统遍历(目录树结构)) D+ k! S) D. _+ q- [2 z
    2. 快速排序/归并排序算法
    * @( A% N, h  ^' P5 o' X3. 汉诺塔问题9 m# Z8 D' U& Q9 Y7 G3 h
    4. 二叉树遍历(前序/中序/后序)% \- k! c: f7 B1 ~+ f7 N, I
    5. 生成所有可能的组合(回溯算法)
    8 [5 \# S% N! I( p4 @. A& P9 w9 C
    0 R2 C% Q+ n' T( V$ B( O试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,' v3 F* u5 X0 d" c( @7 t" z, Y
    我推理机的核心算法应该是二叉树遍历的变种。
    9 h. {$ W! u8 @2 O$ s, A9 @) d5 C/ U另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    ( j# ?  k2 J) bKey Idea of Recursion
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    A recursive function solves a problem by:
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    0 b2 h" \* y/ J" h) [    Breaking the problem into smaller instances of the same problem.5 K  w! T! R% s% `; G& s- q% U4 H. e
    , l7 H- p$ `0 y# ~0 j- S
        Solving the smallest instance directly (base case).
    + ~. @5 n8 r% a- R9 r% s$ R) X" T9 F1 v3 A
        Combining the results of smaller instances to solve the larger problem.
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    4 W5 A( w4 h/ q; @9 t2 cComponents of a Recursive Function
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        Base Case:  G( e$ k2 l& l" B8 c$ E0 q6 c

    ) @5 L6 ]+ w! k) S        This is the simplest, smallest instance of the problem that can be solved directly without further recursion./ ]  E4 Q2 F' j: n

    6 ^  @1 a2 u( Y9 v) ^# a        It acts as the stopping condition to prevent infinite recursion.0 Y/ K5 X0 J* l2 X5 q  F4 ^

    , z# Z2 u# U, F( V2 T+ ]1 j        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    0 V3 ?- U' V2 V/ ]/ B- T
    , D. X2 j( N+ `+ q+ U  o    Recursive Case:$ G9 w: c+ x: e4 V

    2 f/ j) M5 V- b: a5 }& G        This is where the function calls itself with a smaller or simpler version of the problem.9 x5 l1 Q2 }* b* w6 C

    ' T3 L+ R) I( ~        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    ; f1 u+ Y. b+ A" ]. F; G) UExample: Factorial Calculation
    ( A' }+ P4 @. s, x9 t' M0 q% L) q% g' L
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:+ D  e5 f$ l; t

    7 Z6 r1 z; ~( a& d' {1 |    Base case: 0! = 1$ E; x1 _4 i9 E3 r* }9 k0 c2 r

    4 e7 h. Q+ u- K& A+ X( M5 ~0 ]    Recursive case: n! = n * (n-1)!
    8 ]: g. m/ I- W) y8 ]! Y7 Y
    7 K" l4 ~& i  b: t5 B6 @Here’s how it looks in code (Python):
    5 ^6 l) r$ T( X% g" `: Vpython& q/ g! H5 ^, R1 k; Z
    1 e/ a- ?7 s9 V* W

    # f0 f5 q: h9 p0 M5 E7 H$ Mdef factorial(n):
    . Y( Z6 A3 V) P  R1 X    # Base case
    , p3 q9 m; j9 P3 {    if n == 0:
    + s7 {7 Y( ^* j  H: }        return 1" Q1 h/ R, f1 L6 h. w$ D6 e5 k
        # Recursive case
    ( ~- G' t0 U$ j# I2 }* g. D: b. x    else:# {* s, U# V$ a* b
            return n * factorial(n - 1)
    ( g3 N: \( s  i: k: ?: \; ]% C) ^
    8 K3 R3 ^) n$ e# Example usage) h; m2 D- u6 J$ Q) M
    print(factorial(5))  # Output: 120( V+ t1 j1 j. D$ h

    0 O% `3 t' z0 |* A5 T5 U9 U1 GHow Recursion Works2 X8 R0 m& c- Z$ B+ I; R' R0 f+ {
    & C+ y  `/ O1 r5 w6 V% J+ j
        The function keeps calling itself with smaller inputs until it reaches the base case.! [1 m) B  l( D- k5 y: v( W
    : m5 J, B$ E# L7 `0 ^0 m
        Once the base case is reached, the function starts returning values back up the call stack.
    6 t8 `7 A: @7 l2 ]  q6 V* [# l% D% H2 [  \/ t' t- |
        These returned values are combined to produce the final result.
    ' W7 \, a# f3 G1 t# |2 F7 T% c0 E# f6 w+ g$ W
    For factorial(5):
    5 \3 i6 k; a! p: O2 h5 e+ `
    " Q" l0 V; }' s# V8 V+ O$ q) i; `3 ?9 |! [
    factorial(5) = 5 * factorial(4)
    : `  j/ E- m, H% Sfactorial(4) = 4 * factorial(3), V/ t+ h+ t$ r2 x
    factorial(3) = 3 * factorial(2)2 d: n% F9 v9 T; _' z
    factorial(2) = 2 * factorial(1)
    $ `) B  q" U& m& N/ p& I# X. _factorial(1) = 1 * factorial(0)
    ( z% v+ \' d! @( lfactorial(0) = 1  # Base case/ R; [& U- |' X* N& B3 V
    0 ?* w! O+ r" u
    Then, the results are combined:
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    : n# F$ g/ v' P  s
    factorial(1) = 1 * 1 = 1
    ! E# t2 W/ i9 a# ^factorial(2) = 2 * 1 = 2" Y- s3 ?- U, ?1 Z! H* I
    factorial(3) = 3 * 2 = 6
    * Y. a# j4 ]; u+ k; gfactorial(4) = 4 * 6 = 24- @8 k: z, Q3 U4 R
    factorial(5) = 5 * 24 = 120
    & `. q8 R- a  K7 A5 w
    . a# t1 {9 m3 c8 T3 J7 y9 {$ MAdvantages of Recursion
    1 x# U  v2 q# X' u( h2 ]" L% Z: f
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).$ a; |' Y2 [# i4 T* ?/ v* h- Q

    / K% t0 j: r8 @( ~& y9 t. d    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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    Disadvantages of Recursion
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    5 O" }6 c; Y8 \4 o7 X    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    6 c, s- K6 F; ?, X( }$ R
    & \" ^0 T( `' m- q- B    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    6 O, o: Z: v. b' E  W4 R) P6 ]4 D2 d3 B# O) R6 ]- W
    When to Use Recursion
    % n+ R' q5 O. F0 @6 f/ ^% ]. n) E6 L
    , r' A3 x5 V& v( b: P* V6 n    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    1 O; l" g2 l. O, g8 X; m# M' l+ ^' Y
    ' t0 v% p  \9 ^5 s9 O    Problems with a clear base case and recursive case." G+ {2 e/ T2 B3 q

    " K- y; y' E5 h  BExample: Fibonacci Sequence
    - x; V( r5 J$ R! u  Q2 e# L+ J
    ! w: P# ]- c! tThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:5 K) L1 x5 e- j# r

    8 G1 B$ H; |  U2 z    Base case: fib(0) = 0, fib(1) = 1% g- h2 U, v% q4 T/ j; ?
    ' g6 P. Q) y) `/ k. r/ u
        Recursive case: fib(n) = fib(n-1) + fib(n-2)$ X9 B3 @5 l. m9 A/ r' y# Y9 q* |
    $ V3 Y7 n3 n/ }4 D/ s& n
    python
    " j& R/ y  l0 k' W' v5 @, |/ Z$ C7 x0 s! f% {( ~1 K  z- @% t

    2 c/ A2 v3 |9 j3 h& Ndef fibonacci(n):
    - p: h7 z0 J5 r( _/ S2 f; w7 j    # Base cases( \' e0 s7 U/ r& j% V
        if n == 0:
    9 }' \2 d, i. z( J$ o        return 0
      I, V* V5 `* N9 t+ l    elif n == 1:
    , T8 V$ ~# b" i( e; q# |. x        return 1
    + z, |8 ^9 }# m5 m0 Y/ \    # Recursive case- x, H+ n" `) f: Z
        else:
    . Y/ [3 d0 A, G+ X, @. u: a' a        return fibonacci(n - 1) + fibonacci(n - 2)
    ! z3 x! [% p" e$ \/ k9 B! d( h! N7 S' L7 j* a% X  n
    # Example usage
    2 R( Z* u  P5 s; W: K3 S& v# Xprint(fibonacci(6))  # Output: 8% s2 R& s/ @2 R: R: E% u- l, S

    ' E0 k2 i$ {+ W6 [- |$ x% aTail Recursion
    ) A( s( h0 g% Q2 W- s0 M- W2 r+ c) I8 i* b# j
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).+ M+ R; Y: T0 ~, f# D
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    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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