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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 " V, |  P, q% H. R. Q% V1 E
    ! A+ }: q7 A$ H8 Q( j
    解释的不错4 o5 |0 l' F# L1 N% x8 Z4 M# d$ @

    ' o( H2 `9 V& m$ J5 ]1 i$ D2 C+ m' y4 I7 m递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。5 s4 _) a! W4 S+ K0 q

    % W$ u6 k9 I9 U- K4 _ 关键要素6 X( f- g8 C% B: N! R9 X
    1. **基线条件(Base Case)**7 M5 S# U" P, t1 \9 ^4 Y  \
       - 递归终止的条件,防止无限循环
    : C# N: @% Q% @4 s/ |% ?/ J   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1) v, d6 `; [/ K# O5 }- R

    ! q+ X* z, s* s' c) x4 Q* X4 h2. **递归条件(Recursive Case)**( V$ S. z8 b; W
       - 将原问题分解为更小的子问题- m3 V! j) h# m% l% \
       - 例如:n! = n × (n-1)!* Y# e4 \" R4 h: O2 c  V

    4 O5 j2 x, g5 b7 X/ G# B 经典示例:计算阶乘, z+ s, W/ T7 f+ @# O8 z
    python2 s. R) m  i. i7 }: A1 U, F
    def factorial(n):
      p5 |9 U0 N( I7 L1 n$ Y  v    if n == 0:        # 基线条件! r! k! P. p% J0 w6 Y
            return 17 m& Y" I" T6 G- {7 k7 g
        else:             # 递归条件7 B" U* b/ @3 V) z# i
            return n * factorial(n-1)+ j( f% X- `) Z  t6 x/ U8 x
    执行过程(以计算 3! 为例):( Q/ m% W$ e9 }0 V2 R
    factorial(3)
    2 v5 A6 G. l; Y: |/ S' r. c3 * factorial(2)" Z8 B/ z; p# ~, G  r. Q
    3 * (2 * factorial(1))
    * v/ J9 Q3 Q/ G9 R7 h& z+ a+ ~3 * (2 * (1 * factorial(0)))5 E( a: v- y9 f6 Y+ ^
    3 * (2 * (1 * 1)) = 6$ b7 U! M# o: ^$ J$ F* }
    1 |/ X) s# K  M1 p
    递归思维要点
    / P: w1 L! n. u# Y1. **信任递归**:假设子问题已经解决,专注当前层逻辑. m. z7 [9 E8 h
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    / ?9 i9 h) I" ^- x$ j3. **递推过程**:不断向下分解问题(递)
    ; ?8 [+ `& b" m' c4. **回溯过程**:组合子问题结果返回(归)6 Y8 r9 F* c5 `; t4 m$ o4 r5 Y
    1 F5 i! X5 D/ D9 f) C( b
    注意事项6 ~2 M6 W2 O) O/ N# ~
    必须要有终止条件
    ! r! F% u. y0 n4 C$ c/ \1 y递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    , E5 z9 D# [  l2 n  a* k3 D某些问题用递归更直观(如树遍历),但效率可能不如迭代6 [: e! \  _  M0 a
    尾递归优化可以提升效率(但Python不支持)
    1 F6 Q2 ?2 ^! g' l; j
    6 n* G; C6 o+ G6 @0 b9 J% M 递归 vs 迭代+ @& V+ Z! D' G5 U
    |          | 递归                          | 迭代               |
    5 |7 ?9 W6 V7 G) r" ~, R/ D. k0 x|----------|-----------------------------|------------------|8 ~) y6 h, G) [! }
    | 实现方式    | 函数自调用                        | 循环结构            |
    . P3 z  Y. [4 a* M5 n* K| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    : m) u/ g% i4 n- v  q4 R. y% ^| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    1 v* i8 b4 O5 g( w3 s5 Z! U| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    * ~( |% U" [4 A% X- u. O2 X6 e) ^) @7 x4 {
    经典递归应用场景
    2 `! [5 ~/ M9 p* A% z" E' H* [1. 文件系统遍历(目录树结构)
    + Z4 {4 A; S" V* i; Q2. 快速排序/归并排序算法
    7 U+ Q% Y: x5 |/ F3 w- G7 W3. 汉诺塔问题1 \, W5 H! w! K! c1 {: q" K7 H, w+ S
    4. 二叉树遍历(前序/中序/后序)
    ; K3 I  W# R4 d5. 生成所有可能的组合(回溯算法)
    ! P+ z! x2 `! |6 U+ _1 P- c; V+ T1 d$ S  k8 [2 _; M
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
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    昨天 08:41
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,+ c6 l9 h  C" o2 e
    我推理机的核心算法应该是二叉树遍历的变种。
    9 l8 ]0 X8 D6 J: V另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:! `) O  R/ r6 a2 ~2 r+ H7 w5 g
    Key Idea of Recursion1 o4 r6 Y/ f2 j$ W" _( V; C
    - T! r; N. c7 Y: L
    A recursive function solves a problem by:: x1 v( E, K0 D8 ]; b- U
      F, i8 z. {5 h4 l
        Breaking the problem into smaller instances of the same problem.
    ) U! S; e" J6 x  Z1 H' C. I; R2 g. D0 j% ~+ e; D# V1 Q
        Solving the smallest instance directly (base case).
    ! Z2 b/ c: L- \" H7 @) P) U5 t7 g5 d( l
    , i; ?% f" a: N/ x1 P% o% U1 \    Combining the results of smaller instances to solve the larger problem.
    $ X( J- r9 i! l/ Y1 D
    1 G% }( o4 T0 WComponents of a Recursive Function4 Q' Z0 n  A" b# x9 A0 G' w
    # i3 N2 Q' `$ u  b7 ^6 H5 |
        Base Case:
    6 }% J3 ~* R# ?
    9 g1 p2 n) P7 k# _* g        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    $ }! N0 ^  g3 A7 R$ D) h# a4 L2 }
    9 n! c9 l$ G: i( J% P        It acts as the stopping condition to prevent infinite recursion.
    % Y: l/ i5 Q8 ~: n/ y  m" f4 K- g  i# j) F' x+ P
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.0 e2 s5 x' C8 u. ?& G+ w
    6 A$ Z9 ^7 k# y: S0 U
        Recursive Case:
    8 c) x+ G0 r( Z0 \0 t" c% A6 `+ }% @7 t
            This is where the function calls itself with a smaller or simpler version of the problem.& J) ^0 x3 N1 s; T* O5 g
    9 s$ w& [% P; J/ ~/ N$ s& Q0 p
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).# Q5 f/ B8 i3 g! k3 f3 ?% a
    - I9 y2 v9 v! f/ }- Y; g
    Example: Factorial Calculation
    , y8 F1 ]5 Q. Q! P9 _4 H2 m
    ) q  B& l% c8 F9 \+ w1 a8 S9 O6 B$ pThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    ' x% q1 y9 d( ~: K
    6 @0 r  u2 p4 ~  u* T- v- f8 e    Base case: 0! = 1
    . }) p% x4 O! T! {1 O
    % W. h' @' Y, c2 y    Recursive case: n! = n * (n-1)!
    4 {, [6 V+ ?" Y$ M# [# s
    5 C3 ?% K4 T6 u8 xHere’s how it looks in code (Python):1 V. v' G$ G9 m7 ~" t/ {
    python: F/ K& C; K5 N: s5 i: w
    ; T# }' Y" l* E9 T2 [
    4 z6 Q& Y- d6 a3 T- v" V, h* p2 L3 Y# X& {& c
    def factorial(n):
    " E' {' ]- p& g    # Base case
    / f3 c4 V1 x7 I& m    if n == 0:
    - a! L! u  c, X% k/ ?" s$ M2 i        return 1
    0 j0 Q( O/ b4 A( H    # Recursive case8 H9 G. W9 z4 y9 [5 t8 C
        else:/ x, @4 U! c9 U  F4 p6 m; o* ]
            return n * factorial(n - 1)
    " E1 X4 N$ `$ g* A+ k! y1 v3 D7 ~6 h
    # Example usage
    * v; N4 [1 S0 i2 J. ?/ r/ V9 Z7 ~print(factorial(5))  # Output: 120! w  z& m8 m. ~$ x7 C8 c
    0 I/ s& l. Z4 R' `, P
    How Recursion Works1 V8 V* ~" O2 Y8 `; `1 ?  j

    + U8 c. p( W& w. x- o4 I( Z" l; t    The function keeps calling itself with smaller inputs until it reaches the base case.
    ; t0 k) V3 t" h+ s
    ( Q) W% _- }+ ]/ a    Once the base case is reached, the function starts returning values back up the call stack.& r0 N0 b8 G/ i  }4 m9 Q

    1 Q2 S7 e# }/ N& P: b+ h    These returned values are combined to produce the final result.1 @) M6 M" B4 G/ ^
    5 }8 v9 `; l' @
    For factorial(5):; c3 m8 D0 K, _. v9 c( P8 ^# p# l- W
    5 N4 d7 Y3 o) u3 J: v3 \, c( |- c

    , n* ^$ L1 K+ P* f$ \factorial(5) = 5 * factorial(4). z6 f5 {- }1 u! Q- c
    factorial(4) = 4 * factorial(3)
    $ Z" c" h) k" l' Zfactorial(3) = 3 * factorial(2)
    & s' ^( g+ v7 ~' ~+ o5 V2 ~. b  Bfactorial(2) = 2 * factorial(1)
    ) \3 `) x! _9 ?3 O; o& g5 ofactorial(1) = 1 * factorial(0)" [9 `# f" O7 {
    factorial(0) = 1  # Base case
    0 O3 d: P! q- `* C  ]5 f
    ( F5 W4 Y8 e' E! q# cThen, the results are combined:
    - r( z7 {! ~! @4 d
    * y% p. O+ f( Z9 u. \% R2 r, s5 t# _- j, j6 c
    factorial(1) = 1 * 1 = 17 e' j: y4 @) G
    factorial(2) = 2 * 1 = 2
    2 ]% L" s9 Q; n$ M2 gfactorial(3) = 3 * 2 = 6
    $ C& w5 f' p5 q6 |1 c7 y( Yfactorial(4) = 4 * 6 = 24
    * P7 T$ D: S; I! j1 V2 \factorial(5) = 5 * 24 = 1205 ^, s7 J  a3 J1 A7 H! t  e0 i
    8 X# _0 ^* M; h4 Q' [# J0 m# O
    Advantages of Recursion2 Y/ }$ m; V7 \1 }1 P. s+ Y$ E0 ^
    0 T8 k& ]  O% m8 g0 |+ o/ T7 g
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).- V  T9 O& T  d  O1 T' k
    : f2 Z9 h! c: C/ w
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    * z& q: R% w( F2 N6 m% y6 ?( T1 F) [
    Disadvantages of Recursion+ O  S8 o0 }( h* h

    : P. I. x5 Z5 ~% V; z5 s    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.& e) X0 E8 h2 S- G+ D  x
    & {5 P7 }' x' B$ H+ i
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).8 l' V% E$ l1 \( {) W3 t, r1 h7 r

    + u8 b$ r4 R6 j5 j$ W1 a# bWhen to Use Recursion$ w: b# X6 d5 ~$ q8 |
      _( q0 C  Q$ W* O; x
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort)." }% }, K# A+ K

    " @8 z4 i8 [2 e% x& S) v. i! d" d    Problems with a clear base case and recursive case./ [# b9 ^' l& S% g4 Z$ S

    ' y- J4 _; _8 o! ?/ mExample: Fibonacci Sequence
    4 D  a) V% p" ]2 {
    6 A, u) N% W0 J! [; zThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    3 m6 u" u! x4 |" ?6 ~# }9 d7 F- X% p
        Base case: fib(0) = 0, fib(1) = 1/ Y& U" B# }" K9 P, z7 @5 R* {

    % S/ W# b( k1 S: a$ t    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    1 U) h) S% e+ }
    9 |: f5 l2 G; Q( H0 q8 ~/ Fpython
    : n% x6 o6 Y# S# ]
    9 B8 d0 \  g2 I% Y1 X$ ~6 F: v' E: q; I& x' e0 T
    def fibonacci(n):
    ) S$ T: r8 g3 G+ v( Y: f. q    # Base cases
    ! S7 _1 m$ R4 t" m  r    if n == 0:2 U3 V. [5 ~) Y( Y
            return 0( |4 K9 Z2 R, ]
        elif n == 1:5 k$ M& A8 o# m  v2 p8 ?
            return 1. D' S* X. y/ @' n3 G, ?! J
        # Recursive case
    , g5 e9 B; S9 ]3 Z. z    else:
    " k1 o+ v: p: J  P- I" [4 V4 B        return fibonacci(n - 1) + fibonacci(n - 2)
    . o; ]1 Q3 S2 @* Y
    9 k  ~+ q% G3 L2 L$ @) W6 ^1 f5 Z! Y# Example usage* p1 x2 s- T/ }* V3 |& l
    print(fibonacci(6))  # Output: 8
    ( K* _% b& M9 q
    1 y+ U+ @: p9 `3 G6 UTail Recursion
    - a0 ~# o: a( l8 F
    $ t7 R# B0 b9 [2 o, NTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion)., Y9 [( C3 g, ^- U7 s

    $ Y' Z2 m7 U9 ~! B5 NIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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