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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    . ~5 T# A* X  Z9 E8 q" |1 g3 k& ]8 l, {
    解释的不错
    4 \1 r8 @( F6 d! ^. w+ `# G5 _% |& J9 z: D# J. K, K
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。; G% C9 F) a4 p1 n7 u; Q
    0 C/ ^0 P$ y( O- D: H9 E
    关键要素
    + v- G5 S$ {5 \9 g1. **基线条件(Base Case)**
    0 W3 E* ?; {6 R! L# H' @   - 递归终止的条件,防止无限循环
    5 Z7 I: o# e9 v4 B   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    & h' V( K/ c8 F+ y4 M
    1 ^: I8 C' ~+ t" D1 P& Y2. **递归条件(Recursive Case)**# H' i4 X; V5 R- ^* |# `# Z
       - 将原问题分解为更小的子问题
    & h+ |& c7 b  T! O( F( g   - 例如:n! = n × (n-1)!& K4 E4 X! ]7 r0 v

    6 z+ h* p9 P* g8 e6 ~1 n7 o 经典示例:计算阶乘- s+ ^& D. t! i) A/ N
    python
    " Z0 M# r" D6 |3 c$ Wdef factorial(n):
    , c2 ]7 n8 C# J5 R6 |* D    if n == 0:        # 基线条件
    # F& }+ }5 p9 l& l        return 1. N8 }$ S9 E; ~, Z7 i
        else:             # 递归条件
      V; V; \0 U3 v" T2 S        return n * factorial(n-1): s& B( x, M5 v
    执行过程(以计算 3! 为例):$ \- \7 ~/ C1 K! w6 p
    factorial(3)
    9 C" ]  O; x. l% G7 \8 S6 ]. \) \3 * factorial(2)4 s' j0 F/ a$ C3 i$ W& t
    3 * (2 * factorial(1))
    ( o! U2 ^7 c6 e9 c3 * (2 * (1 * factorial(0)))8 Q0 k8 k! s& A7 L; _4 s
    3 * (2 * (1 * 1)) = 6" _  C; u1 T6 L% L0 x7 ?

    " j* b/ F" T  h1 A 递归思维要点
    0 a$ U# l! L; [+ o9 A, \: S1. **信任递归**:假设子问题已经解决,专注当前层逻辑/ X" Y; I/ Z# U" ]
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    4 P. y2 M3 ~" k( a; g" y! T. _8 H3. **递推过程**:不断向下分解问题(递), `# \. |5 B8 v3 y3 i8 [
    4. **回溯过程**:组合子问题结果返回(归)
    3 `- B7 d& s# U3 C& g
    0 {- P8 K( Y; @8 t! f- V: r: T 注意事项
    , B& N: d) t% d0 C必须要有终止条件8 N% s6 R% n. p
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    , j9 X/ K: I& x$ ~+ N& ^某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ' \. o3 f$ I7 o6 ~" W3 G( k( E尾递归优化可以提升效率(但Python不支持), r- ^% g; T% m. b$ u: [3 Y
      u$ X- C# X. k  T/ l
    递归 vs 迭代4 n* ^3 y+ N. N9 q
    |          | 递归                          | 迭代               |
    1 C4 Y, q+ D* B|----------|-----------------------------|------------------|
    5 c6 t( {/ v0 O| 实现方式    | 函数自调用                        | 循环结构            |7 F* J' P- u5 o4 P7 _1 s4 s! }4 C& G6 t
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |) L/ ?( V0 i) }7 y& K
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |9 }9 d- M8 J* j' P, ~( h) F
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |( B" B* A, @# @6 V5 K- Y
    . a5 ?5 F/ i% P( Z1 Y/ p) a/ z
    经典递归应用场景
    : a! {! V! V/ ^  l1. 文件系统遍历(目录树结构)2 x* s6 P3 c" `" j9 W  n
    2. 快速排序/归并排序算法: Y  @" |' i: K
    3. 汉诺塔问题# v/ c2 Q5 X4 G
    4. 二叉树遍历(前序/中序/后序)  t# s8 s. x+ x
    5. 生成所有可能的组合(回溯算法), W. Y# W# ]3 F: A

    - t/ H4 z" i! B' ~! o试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    $ g2 C! @$ B3 b8 }+ L我推理机的核心算法应该是二叉树遍历的变种。
    2 @$ [% c; e5 b8 f另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:% c* P, D* a3 Q5 Y5 ?3 |
    Key Idea of Recursion) c: D8 n) k1 R9 V+ M3 z

    1 L2 P/ _! ?4 h, `, GA recursive function solves a problem by:% a' {4 d' A# X5 Z% P& r$ R

    4 k9 R, P3 E6 g; G    Breaking the problem into smaller instances of the same problem.; d  ]9 b" U* R; a' ~1 T

    3 C5 G* Y* b( @- Z    Solving the smallest instance directly (base case).
    % J7 t- \! R+ G2 j; F  H, m, m& E9 @! Q2 P% d' |# }7 D
        Combining the results of smaller instances to solve the larger problem.
    + c' v3 p1 m( Q* T, s  ~: w: u3 M6 ]- i2 }9 `4 g+ J
    Components of a Recursive Function
    . I, f9 P. H, C; ^
    , x4 j* j' |7 E+ M; ?) Q    Base Case:( j8 g5 X' r8 B2 n6 n

    ! _* e* T: ?  y" e6 }, @' a        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    , s) q  n; K8 X! d( O
    ) s7 h5 k& h- G5 M( G        It acts as the stopping condition to prevent infinite recursion.
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    ) {  z+ z% _4 M7 }$ G/ L* n) O        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.( f: s+ l) V  h2 L% l* L! V/ H
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        Recursive Case:. U" v5 G  f( ]$ j% K

    , R+ z" h& @. f        This is where the function calls itself with a smaller or simpler version of the problem.* |, ]0 |8 N/ O- _& z+ R

    6 L- Y& }0 G+ M% [! ~6 U        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).4 O' G( A# K& ?

    / s: }  @  B' L4 jExample: Factorial Calculation
    * [, |: b4 |  p4 \4 L7 [$ S( v7 f
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:" L7 `" a# k: ?, B* _
    * }) c& G3 r! |: `# j
        Base case: 0! = 1+ G7 H6 V: U# O- y# I3 v
    ; N! }' Q6 o) P2 Z) s6 J
        Recursive case: n! = n * (n-1)!5 C1 v* M2 K/ t2 V: P7 X2 [

    ; Z: L% t5 m- B! B7 xHere’s how it looks in code (Python):! {" @% [# k- p! E6 X8 C
    python
    : Y" f  [& B& z+ K7 q# a
    , ^/ r, F: @( e/ x  \8 [
    $ i# L2 P7 _4 Z" [def factorial(n):  _% C, x  m" M/ b  J
        # Base case
    0 y( a6 Z0 t, X7 @) v    if n == 0:6 p4 V2 F! G- P
            return 1
    * ]3 O5 G6 Y1 x# J  r    # Recursive case) p- M# ]& y, I- @! ?) l- t
        else:
    , u: p9 J3 W6 T* b) E        return n * factorial(n - 1)% G" v6 p; t, b* L2 p5 q
    3 A8 ]" ^& x" D- o/ `
    # Example usage
    1 |% i+ B, d& n, lprint(factorial(5))  # Output: 1204 l! |$ J! h8 {+ ?
    8 }/ T2 X$ g! k! C8 F  m
    How Recursion Works2 @6 G) z' l) M5 r6 U( n9 t

    5 X0 r/ ]$ f7 {, H% w! |! t    The function keeps calling itself with smaller inputs until it reaches the base case.
    0 G) Z4 A8 z$ i( G' J1 I9 s+ C# U3 M  Z4 X
        Once the base case is reached, the function starts returning values back up the call stack.9 f' m: R0 T1 W( Q

    7 r! a& k% C# j! m: Z3 e  G- \    These returned values are combined to produce the final result.
    0 i4 I- V' t% f6 s5 y' P- r
    5 U) w' R2 q: P6 j0 pFor factorial(5):% u( D: a6 X9 V! e( y

    2 X) M+ C$ x5 H" B7 X2 Y+ s- _( A& R$ g0 Y% N# z) f# C2 H
    factorial(5) = 5 * factorial(4)1 F* s+ Z% T/ m# r: e" f
    factorial(4) = 4 * factorial(3)
    ' g7 f' n. W0 M5 v6 ]- }/ Gfactorial(3) = 3 * factorial(2)7 R  j5 y. [  g1 U: X
    factorial(2) = 2 * factorial(1)
    # {2 m0 q: _. ffactorial(1) = 1 * factorial(0)5 K1 g9 t: Q/ Q8 ^  ]
    factorial(0) = 1  # Base case
    3 |3 Y' v* O( n4 X8 U* E0 D
    9 p- D- i7 @! c5 X0 ?/ a4 ]7 M" MThen, the results are combined:
    9 R' |8 w& i( t6 P' u4 b& s, U- c0 S8 s9 C

    # S2 h/ r' ]0 T4 |2 h" O; |8 mfactorial(1) = 1 * 1 = 17 ~( R1 Q6 `# d$ J0 d
    factorial(2) = 2 * 1 = 2
    + u0 B5 `% |, D/ v1 Q, W2 B2 Nfactorial(3) = 3 * 2 = 6
    0 y6 n3 l8 x5 W4 h4 ^) Sfactorial(4) = 4 * 6 = 24
    0 j3 G4 |  N3 Pfactorial(5) = 5 * 24 = 120
    2 S& X* a& f+ h5 l# T( X2 T
      ^% L9 t/ Y' @* L  {/ cAdvantages of Recursion2 N3 k; v; J- |5 z2 n# o

    ! ]+ E1 O9 M0 E' B$ A2 u+ u1 ?/ Q3 E    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    ; e( y7 k! Q( I5 g: B1 r) `: }' D
    0 |# v: E3 p& [" M: c    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    4 H9 w1 F) r$ H! a- w. ]# F! W1 _+ @  R2 `/ t
    Disadvantages of Recursion
    6 a3 R* B  W2 P, v6 O' T( r, Z1 o6 O2 p- D
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.& E6 d; v$ a, N: f
    / O" C- C- l3 \( P) e
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    7 O7 _4 y; m; ]. ^7 P
    ) g( f. C9 @+ \; Y9 ]  pWhen to Use Recursion
    ' E2 H! s3 ]- b2 H% ?9 g) E9 S) H& @
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    0 W2 H) S1 w6 y/ y2 q, W! E, o3 g$ x( f! l$ i
        Problems with a clear base case and recursive case.
    ; C3 S/ S  x# ~& y' |! K6 \, p; n6 t7 ^0 a
    Example: Fibonacci Sequence
    & N* B# @: Q' C, ?% p7 B# F. q$ d4 i# F  L/ b' X
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    . Z% y8 H1 F5 D4 |. k/ |
    : v# |2 m3 u% D' {    Base case: fib(0) = 0, fib(1) = 1
    0 r( S" X4 d: s* q8 A/ {& l
    7 {' t4 ]5 M% _" Y    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    . W7 w  k; k( A" S% c2 `# a9 {" u0 r/ Z$ G. J7 @- _
    python8 ^' f+ F7 o- [+ c7 _$ H0 q, w% _

    % K/ v* z7 @( a' A* |6 g
    6 d% V$ u1 Q6 ?def fibonacci(n):* x, f% ?( P1 l- I: m# q
        # Base cases0 \, U* `. T/ T
        if n == 0:4 X" _  t0 ?9 l; R- o& b3 A% ^, G7 [
            return 0# D2 Q+ b4 v+ f- h! M
        elif n == 1:2 u! @8 n5 z  R# j& I3 B0 a
            return 1$ \$ T( b! Q( B: d# E
        # Recursive case
    6 Y5 }. K* Z1 _/ E2 q7 E7 b( H" `+ c/ A) R    else:
    : U& R( j  `# I9 W0 t* B3 i        return fibonacci(n - 1) + fibonacci(n - 2)) Q8 y0 y$ a6 A

    7 x0 ]' s: Y2 c0 j0 r- g' z# _# Example usage1 ]) D1 L& ]  J, `- h
    print(fibonacci(6))  # Output: 8
    , a7 t2 {8 }5 [# u% U5 V+ M7 r; d0 v+ K
    Tail Recursion' ^1 O+ n* }+ F$ n/ X# f0 c

    8 Q5 U4 e3 l/ ITail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    1 {+ T( j. y8 G/ ?) x0 [3 l9 O! Y7 y0 ?9 K$ E1 B* ?
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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