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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    9 [' @. O; X: f) V5 i1 b+ z& {+ N
    : ~! T1 |# u; E解释的不错8 E, F: t& {% K  |6 U

    $ ^6 \3 L% W' D% Q& Y0 i递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    + [" D- N* u+ s& A" N  Z
    / v  y3 Z. ]( s! _* ~ 关键要素
    : u7 [& j( s" \1. **基线条件(Base Case)**2 B- x9 F+ b: H! ^  R' o
       - 递归终止的条件,防止无限循环
    " X* G: I  a* u) B( j! r" ^, v   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    0 T# O4 Y8 E) F, b7 W( T- O2 q4 v* [+ d1 W7 w; [2 x' s9 P/ l
    2. **递归条件(Recursive Case)**
    0 p+ T: I" L: a/ p6 K: I* c; |   - 将原问题分解为更小的子问题
    - ~; K* R0 n+ g# a5 v   - 例如:n! = n × (n-1)!8 q7 j# [: T6 x
    $ h" N4 h( o. [1 e2 o; M) r8 M
    经典示例:计算阶乘+ k2 A! H8 g. o4 _5 @) Z# G
    python) e" K* v/ |8 H9 }/ X/ S  e
    def factorial(n):
    0 |9 c4 ]/ A6 D* J, q    if n == 0:        # 基线条件
    9 i  U) ]; o9 z8 K) P" K0 _+ l: o        return 1
    : w; [7 m3 I+ z  K" B4 A( k    else:             # 递归条件- i2 L5 z, d+ ]/ ~' e6 \
            return n * factorial(n-1)
    , _, y& e$ E) K: ^执行过程(以计算 3! 为例):
    - d; n' M5 {7 b& h) _) _4 g9 ]factorial(3)
    0 Y8 A8 \- _) C9 ~- d# O. F3 * factorial(2)
    " ^' o; g' n1 y, B7 v0 f& {3 * (2 * factorial(1))
    ' U8 s& @9 I  A3 * (2 * (1 * factorial(0)))5 S/ H' H2 h& W* u# Y; A5 j8 z6 p
    3 * (2 * (1 * 1)) = 6" ?! l4 I/ y* P/ j' w
    1 }+ }$ R) B1 q1 |. x/ F
    递归思维要点
    ( E$ X' c5 _2 ~' I1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    9 a( }- g) w/ P  A7 g2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    5 ^0 K+ l" g% B8 N3. **递推过程**:不断向下分解问题(递)
    % `! ]5 a" N1 @! c, H6 j+ R5 S3 T) S4. **回溯过程**:组合子问题结果返回(归)
    $ V# [6 s8 J0 [' ?* ]' W: o
    $ V# }3 J. j1 C 注意事项% G( n" h4 A- ]4 a
    必须要有终止条件
    ( {1 M/ x0 n2 v; `( G$ H递归深度过大可能导致栈溢出(Python默认递归深度约1000层)* A4 f+ U( F: R) r5 d
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    & Z8 Z  q1 H: Y( g尾递归优化可以提升效率(但Python不支持)
    & y( w* H  n, x8 x% Y; W( l$ T/ S' [8 Y( y7 v* t) p4 Q$ a
    递归 vs 迭代5 ]  X* _7 T0 j; I; x( d  M. c5 |. L
    |          | 递归                          | 迭代               |
    , `0 n) p% R, d6 q|----------|-----------------------------|------------------|6 k) d- e/ L. \9 i  O# U5 r1 c$ X
    | 实现方式    | 函数自调用                        | 循环结构            |
    # R3 L' ^9 d2 j4 g' X, a/ Y% Q* t| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |+ c6 ]: r% \& ]2 y) I
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |5 P7 G" U" C& b1 H
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |" z4 A0 e; e; a

    + K, C( R9 F9 e( A  A# Z* C 经典递归应用场景
    : d/ Q+ Q. q: u0 R, k/ n$ w1. 文件系统遍历(目录树结构)
    4 E- P" a! ]+ i) M2. 快速排序/归并排序算法
      z  _1 C" {4 t% A! n3. 汉诺塔问题
    9 r2 L: V% e. Z1 m' V: A! y8 ~) {4. 二叉树遍历(前序/中序/后序)
    8 I. s  q" ^' }2 g+ z- i5. 生成所有可能的组合(回溯算法)
    * j. m9 v, `0 A" ?- _' w' T
    9 Y. R1 l, @. O& _试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    13 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,7 [' p, F+ _5 {+ `; h
    我推理机的核心算法应该是二叉树遍历的变种。4 g# O$ y6 }! G0 f4 b1 n! d
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:. ~, i4 C4 x3 @& I1 x7 J! ]+ _
    Key Idea of Recursion& i) |# y* F8 r" P$ V+ E

    # y0 H- j6 o( V! jA recursive function solves a problem by:
    # p, M9 I; u& C) {8 I' E! M2 N3 h  D8 ?; L3 T0 ]
        Breaking the problem into smaller instances of the same problem.: A6 a$ h' H) j/ i- J) \5 p: r

    / h+ h/ n0 P$ B- S    Solving the smallest instance directly (base case).2 x/ U( o2 n  l4 Z9 t7 w. F

      u5 v9 a3 L0 u/ A0 u. l    Combining the results of smaller instances to solve the larger problem.7 I5 b2 j- B! C* ?# r. {6 ~

    8 j0 o7 h: `; x6 B: mComponents of a Recursive Function
    $ J8 h- A0 Z9 H/ p+ Z+ [2 f9 T
    ; K; B  b8 W6 I! b. H    Base Case:
    # m1 M+ X! K$ X3 w+ \$ j; {5 W* |% F4 d6 \% ?
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    " g8 g# ?8 v. z# [+ A! F5 u1 B6 w, r/ @) q
            It acts as the stopping condition to prevent infinite recursion.( n9 R. N8 y& Q
    ! p" t, M( B7 U
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1./ R% Y' L- y$ f. b

    0 f6 {  t% K3 ^9 [# B  t3 }    Recursive Case:
    " O! T- X- ~5 X4 i) }: c/ |6 r( q! o2 W% Q3 S+ H: l
            This is where the function calls itself with a smaller or simpler version of the problem.
    ) A; q  n, j# h) e4 E# R3 ?7 D7 P7 {7 ?, t
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    / J, R+ Y' g3 V1 a4 Y$ C  Q6 Q8 a, W# h5 O! }' q0 O
    Example: Factorial Calculation
    ' Q. P- v$ [% w9 Q/ i! M1 V" p' K4 Y9 Z. s7 F, @& @7 B: F
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:% F, h* K( P/ @7 Z4 V

    * |4 x: T' \. g) m1 t! h0 Z- B    Base case: 0! = 1
    / u, M0 Q" ^' w6 F6 d' _1 a, `- x
        Recursive case: n! = n * (n-1)!: b: n, X5 q$ u3 I1 L

    & N' _7 b+ B) S6 N+ I# v" W( vHere’s how it looks in code (Python):1 H8 A6 z4 A5 l9 ?* y' K
    python$ M& j0 ~% V3 j

    . j- t0 W& J) \& p- l/ v. E( e6 A% \3 t
    def factorial(n):
    4 e- O% _0 J7 C/ T0 G( e0 p$ S* X    # Base case) E/ q4 `3 S/ `: S7 G
        if n == 0:4 l* `1 E. F% h; A3 W
            return 1. {) Q( b( S; e8 D$ R6 c" c
        # Recursive case
    ' R. E- [* p# Y3 F9 _    else:
    0 J1 X/ U) t2 E( {7 b        return n * factorial(n - 1)$ B$ w1 o; T9 r9 R; M

    $ E8 p5 Y7 Q# s# b# Example usage# L5 e5 B$ g5 u  T" [6 c: [
    print(factorial(5))  # Output: 120! R6 H0 o, h: Q" h
    # c, p* V& V. @' l+ V* z1 B7 s
    How Recursion Works9 N0 J) F1 t8 |$ {  w- n$ y$ h

    , y6 h* k2 {* d, m% _' k    The function keeps calling itself with smaller inputs until it reaches the base case.  @% g8 E1 C- b
    % r# l5 @% o; Q5 }
        Once the base case is reached, the function starts returning values back up the call stack.
    0 r. B4 c+ K& Y- @2 P" }9 L9 F  w
    6 {$ \$ N  Q9 H. t! O. K    These returned values are combined to produce the final result.5 }6 E9 [, v& _/ U2 A

    : L2 w7 W: h- N- P  `9 x, U8 JFor factorial(5):: {' d# V5 d/ E4 Q1 @. W4 S% q
    3 g- G% I1 N" z% R5 H
    . B9 d0 b  T  `( o5 u# l; M
    factorial(5) = 5 * factorial(4)( x+ b# v: Y% p; i3 t& ~& \. N
    factorial(4) = 4 * factorial(3)! w' }2 l- Q/ X( Z( l
    factorial(3) = 3 * factorial(2)+ Y+ P/ V+ l+ J( J# ]+ g% h
    factorial(2) = 2 * factorial(1)
    : G( i8 F- L0 a: A( t: Wfactorial(1) = 1 * factorial(0)* [' a/ h# P- {, q
    factorial(0) = 1  # Base case
    * M: m; W, B6 X7 h& e  k4 L. _$ S7 h# F6 W. I7 ?: r' c) s( M
    Then, the results are combined:) j6 d' @0 n3 X& I/ G! t

    1 u0 e9 m3 B! ^3 r; S
    . R4 F  I) n" c9 c# Ffactorial(1) = 1 * 1 = 14 J' @- v/ `) p! n
    factorial(2) = 2 * 1 = 2! N; R% W& H0 j  |, o; Y& H: o
    factorial(3) = 3 * 2 = 6
    7 U8 m( S0 o* v7 A8 lfactorial(4) = 4 * 6 = 246 {8 e* u$ _' ]; b6 u
    factorial(5) = 5 * 24 = 120
    " W7 K$ x% n  E/ j0 O, s. G' ^2 g' u. x; Q# Y* ]5 [
    Advantages of Recursion  m2 M' {8 R1 U! k# t" x+ |- g% p7 o
    0 F" ]* Y6 e3 z  _& C" n. q+ I
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    - Y2 W! P8 X& O7 f& N% Z# D7 L$ z* g6 i
        Readability: Recursive code can be more readable and concise compared to iterative solutions.- E+ ]3 G* [) i8 E* O# s

    6 U: t: X& Q& W$ @Disadvantages of Recursion8 j" L( y4 L3 S$ F7 h
    9 _  e* V( P7 n$ `
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    # Y; r9 s/ o, X. Z" }+ h( T5 h/ G) Q8 J7 ^  [
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).  a! a: U1 ]$ n) v) z. a4 D
    : A% f2 K  V& K" S
    When to Use Recursion5 v' {0 {! ~" M. ]2 u# ^# r7 X2 z9 D
      X1 C4 D# l5 E4 C' f' {; ]
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).& P) w8 V0 T& O! O
    " M  v* G* i: j6 W( E6 Y
        Problems with a clear base case and recursive case.
    ' d) i6 e( H" p) p
    4 V9 _1 o' V- Z9 v" b! lExample: Fibonacci Sequence% W* i3 Y+ L- B7 Q) {$ B  O

    & }5 [* c1 V0 F. E6 `4 F7 cThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:0 \) t9 q, M. u  X7 f

    , \; |' ^. K2 Q0 @# t    Base case: fib(0) = 0, fib(1) = 1' D9 n6 J; z/ L: [

    0 _9 L' G8 t  T: Z  L- {3 p4 b" M    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    8 g; E; E6 H7 G$ ~0 |
    # R% a3 ~! C" u" |. upython( O; f( W! ~1 Z* h6 v) N

    " ~: X3 }5 k- C1 ?4 H
    ! H/ m/ a2 j, t  J* fdef fibonacci(n):3 S* g5 W0 J6 K7 X; g
        # Base cases
    8 d) [+ |& b+ S    if n == 0:6 _; ]0 X8 I3 r. X: `
            return 0. r* v0 B& x. B7 x7 P/ s/ S: o- [, M
        elif n == 1:
    : y3 y" v# d# g* w' [        return 1
    7 U# I9 \! c' f: x' g    # Recursive case
    3 x+ E5 o: r% I- U) @    else:
    9 t0 s/ ?# L$ P9 c( R( k/ |3 E! d        return fibonacci(n - 1) + fibonacci(n - 2)
    1 f/ q2 |/ _( f) f1 ^6 Q& D3 m3 y+ X
    2 N- A) k* i8 V# Example usage+ E( E( L6 t7 S) a7 M1 h
    print(fibonacci(6))  # Output: 8
    : ~( K6 K/ I5 b+ _7 u. K
    : m" \7 \% G: d. M- E, q) g* aTail Recursion+ b( y1 o* D* X- V

    ; e7 w4 i. ^. M5 mTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    + I: V) U; N' O* a( y! ^- s9 d- d! B- t! ?2 K4 J, [
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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