设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2605|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    ( G0 E8 L1 q2 S
    & \+ A8 L7 G; T解释的不错" y4 A7 X* `0 D; _: ]
    , V$ D& M0 _% V' `: I5 v& E
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    ; n! `- y9 t) V# I, j/ b" M: H$ ^0 i/ v- Y( Z& r
    关键要素! x% U, [! d2 i" Z
    1. **基线条件(Base Case)**; m+ k& ?; y' X- ^& K, y
       - 递归终止的条件,防止无限循环3 n+ b) ?' p1 Q3 d
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    $ t8 o! ]3 ]' h) T7 p' r# j8 ~# m- B8 }
    2. **递归条件(Recursive Case)**
      n9 G; A4 ^# o, e" J# w, {   - 将原问题分解为更小的子问题
    - u0 S( d7 p  S) l8 R   - 例如:n! = n × (n-1)!! h: A; i4 i' v) a4 s1 N

    8 r' t. G: m; y3 l% X6 b 经典示例:计算阶乘
    % _% j0 V* [# v" f( s) Y3 S# cpython
    4 o7 k' F: C% ?! F+ ~4 X) x. Ydef factorial(n):* T: t! B. i; {7 p* U
        if n == 0:        # 基线条件
    " O# k+ T! H* ^+ t        return 1
    " E' C' }, x& T) u$ `9 v    else:             # 递归条件
    & h* \7 R: G& n: v        return n * factorial(n-1)1 i4 g! K$ R% Z) q
    执行过程(以计算 3! 为例):
    ; p5 ^+ S) [0 ?) wfactorial(3), d# h) H! V8 E" g% j4 O
    3 * factorial(2)
    / c) l9 E6 E  X2 m3 * (2 * factorial(1))
    1 r& ^1 I+ t* O. {3 * (2 * (1 * factorial(0)))) u( l3 h0 j2 z8 d% H
    3 * (2 * (1 * 1)) = 6
    $ X" ?# Y& R& w! |" d; c
    # D" [$ g( o! u  O: Z 递归思维要点, J, }5 v# r8 m* Z  Z
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑+ P1 b7 D. V* F5 V
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)1 {6 N; Z$ m% J! s. d: I/ X
    3. **递推过程**:不断向下分解问题(递)( {3 u$ _. M/ \; U6 V5 p  |
    4. **回溯过程**:组合子问题结果返回(归)
    : s4 D0 L+ f8 I% A6 j# F+ W$ [4 @
    注意事项: s- V/ I8 M- q
    必须要有终止条件5 q2 v& i8 K# |
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)5 ]( U9 O% }$ Q7 T" ~% ?8 U
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    , o/ p. ]! w  g! }/ W4 n尾递归优化可以提升效率(但Python不支持): a' f- G; J* n* U

    0 P6 |& F  O1 I# L4 O# K 递归 vs 迭代
    ! g. v+ D& T9 \5 j* G|          | 递归                          | 迭代               |, i+ ]! M/ d7 w$ n. u! q
    |----------|-----------------------------|------------------|
    " s# W5 e5 F0 e5 h1 a3 b| 实现方式    | 函数自调用                        | 循环结构            |
    $ f3 P0 v6 b$ s9 H5 y& C| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    % K! V! R. Z( n3 P1 b3 s5 b. X| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    # {- Z/ N, f  o3 v% t+ f| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |# K( Y5 Z# B! N
    9 t2 k5 C0 N4 M0 u) _( B5 @  j5 I' M
    经典递归应用场景& Q" E  k; ?1 l( j1 o8 R- u7 Y8 r) `: a/ Z
    1. 文件系统遍历(目录树结构)# F, Y" F! U5 V. X9 j
    2. 快速排序/归并排序算法# V* D' L5 d( P2 @1 P9 {/ Z
    3. 汉诺塔问题4 ?" V. B" Y2 \
    4. 二叉树遍历(前序/中序/后序). E' z8 H9 ^- q+ y
    5. 生成所有可能的组合(回溯算法)
    0 N& Q) F6 D1 p- r. m+ s
    5 @- @! d( j0 L% `# @! B试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    奋斗
    13 小时前
  • 签到天数: 3227 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    : R( G# Y' c0 F3 t我推理机的核心算法应该是二叉树遍历的变种。% H1 d* H1 v. j4 P  c8 S4 [7 X
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    ' |2 h8 g8 S& U% g/ e" T0 B9 bKey Idea of Recursion
    . {4 m) O7 t* H$ [5 C
      a- S! D: W$ _' U, O# u! YA recursive function solves a problem by:' @! [9 y2 n/ D* d" t% B3 G
    # w4 ~: k' n) `7 I7 p
        Breaking the problem into smaller instances of the same problem.
    & P. a! A* i2 ^3 X- m- z9 [1 j( H( Z+ J3 G; f
        Solving the smallest instance directly (base case).3 ]( F# Y% O! O- Y! J
    & S& ?  j2 T! N2 w3 ^
        Combining the results of smaller instances to solve the larger problem.: }, i" V% U* ~! w& I" S# d5 B' S
    7 m3 ~) f3 c1 m, G. Y+ `
    Components of a Recursive Function
    % l" r4 h9 m2 e% P
    / f, u0 w0 T- L7 \% M    Base Case:
    3 _4 L; E- r* `& D2 m' z1 ]
    3 p5 n  x' F4 \% v$ P        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.$ F- |8 n* {5 n: b5 k! o" h9 b' Q
    0 L' L- O- l3 Z+ h3 L
            It acts as the stopping condition to prevent infinite recursion.
    2 {" u/ M- |; w! Z" C; ]3 S0 ~* e8 A8 x* }9 A
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.! h9 `  q0 e1 {& p; U; _
    % G) w# H; j- x" e
        Recursive Case:& l* D% S+ B0 Y* ~8 I% J
    . T& t/ W: Y+ W
            This is where the function calls itself with a smaller or simpler version of the problem.
    / _9 B, B" Z, j& |9 A8 O! v' q# K7 @% b2 h  K3 D
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).* B2 E6 C' D2 f
    4 i" A" P; h* A
    Example: Factorial Calculation' b. o2 ]9 l3 v* W$ V4 B  a3 r0 a$ }3 A

    ' f( H" X$ C: z2 [) F3 ]+ Q% KThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:( M% Y; t/ [" ]3 \3 T- L6 H
    ' o8 ^" a: k5 p
        Base case: 0! = 1
    " ~3 K7 \9 J! C- e" I; J1 k0 `: g  e& j
        Recursive case: n! = n * (n-1)!* E$ G, m. n% B+ P( f' N
    7 _5 U% U' k6 k
    Here’s how it looks in code (Python):/ o! x8 Z! d$ X# d6 `2 n
    python
    9 S: M, G9 Q# [. G
    ( l0 m' }9 l) \9 z
    9 ]# P1 r6 [( F1 idef factorial(n):
    # s0 y, A2 u. H/ L6 p7 O+ ^7 }    # Base case/ Q( w" V: k7 R" f
        if n == 0:
    " e4 B, {' B, D2 [        return 1. A! s# ^9 H; G+ d0 b
        # Recursive case
    4 h) W% W$ o  x+ N5 O2 t& O, f* C    else:( B7 J- }5 B8 y
            return n * factorial(n - 1)) I: k6 Z+ Q7 v  {: ?/ K( Z# i
    6 _+ _. B6 t* R3 N- P
    # Example usage
    : |  {# @& a1 M4 ]0 n# s  bprint(factorial(5))  # Output: 120
    , w% S8 J& k3 H$ u9 \  ?
    # B8 o3 Z% n- q6 V; jHow Recursion Works
    0 P# ]6 Y+ W2 q: V. ~8 j" I0 e' J$ y
        The function keeps calling itself with smaller inputs until it reaches the base case.
    / _" T$ O' Q* c4 `: h
    ) m5 f( u2 t# ]. u    Once the base case is reached, the function starts returning values back up the call stack.
    $ w- V) u4 L" N& _; K' M' B6 K1 h1 ]* z* }' A
        These returned values are combined to produce the final result.
    2 x; S* P9 ]4 z5 }6 A8 M% M
    , S: a$ G" x- RFor factorial(5):
    2 t7 C$ K; \0 G" ?9 ]) m: Q$ X6 a5 z2 v$ r
    ! X4 e5 t& w7 ^5 R" p
    factorial(5) = 5 * factorial(4)
    : g$ o, x1 v2 M1 b8 }* {- efactorial(4) = 4 * factorial(3)2 L8 b0 W% h* q* S$ j: r# q
    factorial(3) = 3 * factorial(2)
    % Q9 W' J8 H: q' Z& Lfactorial(2) = 2 * factorial(1)% _1 t/ G3 r6 E) X4 a
    factorial(1) = 1 * factorial(0); [7 M5 ^  R- S. o. s( m" X
    factorial(0) = 1  # Base case
    * K3 V/ Z% N6 F7 i3 M# Z2 y8 Q2 q4 h0 I( d1 \% F0 u9 l2 N
    Then, the results are combined:: B9 B$ L9 J0 D- M

    / \. o: t& i& B; G* m, t% n8 B: j- s- H
    factorial(1) = 1 * 1 = 1
    / ~" ~. V/ L- D6 u) h4 Xfactorial(2) = 2 * 1 = 2- c3 x$ a: F7 p; S! W
    factorial(3) = 3 * 2 = 6
    9 Y/ Z* o/ d* n9 x1 A$ q$ j/ U( Ffactorial(4) = 4 * 6 = 24: Y1 l1 l; e; U
    factorial(5) = 5 * 24 = 120
    4 V4 l7 x* k/ |: C
    + V8 [6 S5 h9 _0 A* {% d# UAdvantages of Recursion
    8 m7 q, b0 Q4 e* X* h
    * r; p2 b4 s! ~+ k( m    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).. R( B, T9 n# o) X: p1 Q' B3 n

    1 E; m( T8 x! Y: J( G5 X) s    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    6 A$ L" r: y! c- y
    7 g( z0 g! f7 n) R& MDisadvantages of Recursion
    $ D& s9 g, J3 g& c* O: L( h! u1 u
    : n+ l! D: [" L6 `7 r4 p    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.3 A! d8 L# i9 F9 w4 x) N  m' b8 O
    & g) {  ?. R) z" |  ~& a
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    + U0 {6 [- ^( @9 Z0 B7 E! V1 E9 D3 Y( s. c& ?" D
    When to Use Recursion
    " I8 E% X; n% i
    ; j" N; x3 F. N7 D+ O    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    7 G; r4 c: A' g' V; Z) o" c' E9 L  k0 n! {; c4 h3 v' S
        Problems with a clear base case and recursive case.
    2 X# u1 T9 m5 V; q. w' j( ?3 L1 X) t+ i& f: a$ I- U9 p+ e
    Example: Fibonacci Sequence
      b. g' s+ z9 H* R* \3 Y5 ~: w3 y3 L5 M1 P7 k6 o; N) ~
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    4 H+ `: l# m0 _- \# N1 h' j0 p. b; q: ~
        Base case: fib(0) = 0, fib(1) = 17 `/ P5 W0 w/ }
    & Q' X' i8 I1 }
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    6 b" ]  E# l. s) v- r, N( I5 @# O# X  f6 S* y
    python- ]/ n' @1 h4 E* i

    * d% D, ^; M! A6 Z( e/ m
      K+ _0 M% K, I- C1 X" Vdef fibonacci(n):" y1 ]6 j4 e8 ?2 H% l8 `1 T
        # Base cases9 k" z( J) P9 d; d
        if n == 0:# l  P0 z& m3 @8 A% i9 c
            return 0
    ; ~5 m! E% t- g" x1 o' h2 I+ `    elif n == 1:  W* M, ], @! ]
            return 17 }2 L) A+ B7 i/ N1 C9 ], |8 N
        # Recursive case* m9 ]  `# s1 U; X
        else:) r7 X5 J$ K4 `) o8 p+ s
            return fibonacci(n - 1) + fibonacci(n - 2)
    ) o+ V# ^4 ?5 W" k% p5 j+ |& i. K" ~) t& f( }) X( [3 W( b
    # Example usage% Y+ y) p7 V1 j, L, b, i* [
    print(fibonacci(6))  # Output: 8$ f. G& N: A; t# {4 _
    0 s4 B3 g- S; N, D& f% J
    Tail Recursion. X4 b, @# g' a9 b3 I
    1 W- n# r) T6 R# s3 B6 p
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    3 [% k- u8 \( i; E8 [( W
    + i- F" T& O$ e! G! ]. xIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-4-30 19:25 , Processed in 0.061661 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表