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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 $ W9 ^( h6 z) i: ?( C

    / a4 c2 l. G) f% l0 G解释的不错
    6 T: |$ O. y' c$ G% A$ R. S4 w- w8 l" C9 B; t0 ]8 `. Z. x- {5 H
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    5 T3 ]) p, W- R! I1 Y
    1 J1 h+ i7 P# B; @- v+ E 关键要素
    # J5 J: s9 V$ m$ `; H( Q2 X8 T1. **基线条件(Base Case)**; d; f. i3 b3 z: k. o. {1 Y3 P
       - 递归终止的条件,防止无限循环
    # j1 A; x) x# `1 u$ M   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    ( G2 _2 z7 }- H" R4 ~) R/ V+ P- B+ Y+ c
    2 B0 b& R2 d# G5 x( u- O2. **递归条件(Recursive Case)**
    9 E: G* D8 q9 {0 W' k9 n0 T   - 将原问题分解为更小的子问题
    4 J5 K$ Z0 Q0 `$ s/ I   - 例如:n! = n × (n-1)!; k- e- g3 P) Y  t

    & D, ~& i2 i6 B. ]; I) R 经典示例:计算阶乘/ n& h0 p- q$ _3 x
    python
    1 H' Y% X) j7 P- wdef factorial(n):
    1 L1 B7 h6 x) Q2 o6 O, b8 X( B    if n == 0:        # 基线条件! I! N9 j3 k% D0 A/ z6 Z* [
            return 19 s( d( Q5 z2 U# P# O* C) T4 `" J
        else:             # 递归条件; d+ d( o5 p2 _  k- [3 i( K
            return n * factorial(n-1)
    2 q& S4 C# r, M执行过程(以计算 3! 为例):
    . u0 _7 ~8 X& kfactorial(3)7 W, V2 F8 G1 z' P: [* A+ B1 U! t
    3 * factorial(2)
    ! |( R  Y: A, ^/ B! Z( r/ h8 e3 * (2 * factorial(1))
    ( w' y: r/ ]5 Y0 `7 ~( s3 * (2 * (1 * factorial(0)))) p4 F; e3 _8 ?0 ~; x; e! r
    3 * (2 * (1 * 1)) = 67 `9 c. m+ `2 v+ w0 j" y" f) ~

    9 D$ e9 t  J1 ~! g1 e% s$ z 递归思维要点9 y1 c5 ^; Z$ }- f" h
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑" s( g" k) G, }
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)4 f5 v5 c& a2 d9 k
    3. **递推过程**:不断向下分解问题(递)3 Y% U: a2 R+ f3 u0 ]  g
    4. **回溯过程**:组合子问题结果返回(归)
    - p# c, v5 g5 \: t0 k
    8 {) S0 s! B) Y6 {8 f 注意事项  U0 r! T  W7 B1 u1 H4 }6 M. |
    必须要有终止条件0 P/ P$ I. s3 J2 J8 U+ _& h* D
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    6 N0 ]6 ^. I% k1 W某些问题用递归更直观(如树遍历),但效率可能不如迭代( T/ [6 c) @$ X8 y3 K3 u
    尾递归优化可以提升效率(但Python不支持)% d# _7 `2 b+ X. s$ ^
    4 n8 `% |# F; G8 j4 j( S, H8 d. V
    递归 vs 迭代
    4 L3 M# z9 C5 h- [1 I1 [$ R" o4 h|          | 递归                          | 迭代               |
    + F( B# {1 A4 `3 c2 V0 r3 W8 q! Y|----------|-----------------------------|------------------|
    % ^4 v& i! l" P+ y# S$ m/ @| 实现方式    | 函数自调用                        | 循环结构            |
    + e+ J$ \' ^3 m| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |5 b$ Y+ g/ e2 `$ V7 O
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ) C3 z! G% j0 ~% n| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    & }5 Q9 _$ q4 q+ O( x$ R- p) t' [( I/ p# ]7 R5 Y* H
    经典递归应用场景
    . ^" i, I6 A! L- H* S0 O1. 文件系统遍历(目录树结构)+ q$ u5 T3 u2 O% K$ d% _
    2. 快速排序/归并排序算法* U. h! x# V9 O/ k" S, N, I$ b0 e/ V- k
    3. 汉诺塔问题
    7 |- D6 l! R" H! T6 q4. 二叉树遍历(前序/中序/后序)) Y# F  T: G/ g
    5. 生成所有可能的组合(回溯算法)
    * _/ e- y+ [/ [: |" a3 V; }# B* J2 I# ?6 J3 Q) z: b( c3 r
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,. W- c" d" x" P# I; `: ^- O& O
    我推理机的核心算法应该是二叉树遍历的变种。
    . Y( Y. |; {9 H  p另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:/ j' [% m8 k) m) ?- Y
    Key Idea of Recursion; p. M% r, @. L) P+ {' B6 G
    8 Z- f) ~- W* Q
    A recursive function solves a problem by:- Z- v: b. z) T  |$ G
    6 c8 K2 p/ ?) S1 S! }; e2 @/ z0 k
        Breaking the problem into smaller instances of the same problem.& r2 U6 M/ Q6 z

    2 n4 p! \0 w0 L2 K/ S% l. e! W    Solving the smallest instance directly (base case).
    / g: @* e$ Y0 W: o, u: F7 T/ n' W/ s1 u
        Combining the results of smaller instances to solve the larger problem.( {% m! M" ]4 o: y5 k* F
    3 l* u1 F+ g* u2 }1 a/ m* L* D  ~
    Components of a Recursive Function* C" ~0 S9 o5 W! {! P5 a
    & J/ |# e" n7 `" k+ h- N) x- u& g
        Base Case:
    / d# I5 {+ |* e/ y$ y, K. `  N
    - ?# p0 F/ _9 }2 c" _0 P( t3 [        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
      v# U9 ~( d/ ]$ i# @+ I
    ) D, [) r, G5 J( _3 S  q, M; C0 ~        It acts as the stopping condition to prevent infinite recursion.
    7 h, }* D$ ]. o
    ( d# \9 I4 _9 x' k        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.1 I- d* H" o* W% T" K& d2 W9 c

    4 t! c8 z5 Q, C+ l8 N. x5 l9 \    Recursive Case:
    ! f4 f5 A) g* x8 k; i9 B8 @1 r) Y  d
    ) C  \% f6 i& S, m  f7 m' K        This is where the function calls itself with a smaller or simpler version of the problem.5 p* d& ?% D9 g5 `
    7 r* L$ z0 S8 ^0 `) f$ [  J
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).% ?" d6 t' _# e# ^5 @+ j, e' e
    ' r4 O6 S1 ]9 b- S% G" L  c
    Example: Factorial Calculation7 U- m0 l0 K2 g2 D7 E
    1 R/ R& @8 v2 U2 J0 B$ p9 Y- t8 |
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:, h! I' t. I3 I. f; _/ i  s
    : U3 j0 F6 m% K: M. y- r
        Base case: 0! = 1, L6 I- ~( z# h7 {3 F, F! f

      m9 o' {1 \* T8 e( \. F- Z/ Q    Recursive case: n! = n * (n-1)!7 I1 D& Z( d* e. h8 w

    : Q+ s( p/ w$ Q( N/ J3 ?+ FHere’s how it looks in code (Python):& }9 N( _/ F$ w1 i8 a* I
    python
    8 S- _' X+ X2 F2 ]8 ?4 S, g' V: T2 r4 I  G" I0 x

    , S) A! O+ e, H2 Bdef factorial(n):
    # j9 a) D! ~' K4 f* q# ]    # Base case9 }) j% L3 S( P0 s2 `
        if n == 0:8 M5 Z$ h* ^( {5 `# D) v
            return 1
    4 N- z( b9 Y* j' w6 ^% t, L0 L    # Recursive case6 p4 f2 a; Y$ g6 K
        else:
    0 E3 i, q- ]9 g$ W        return n * factorial(n - 1)" S  T' o+ P. L$ }$ B
    ! b& B2 \: ~! ?, z1 V
    # Example usage# E  J. u. ]7 a6 U  M9 g7 M
    print(factorial(5))  # Output: 120
    ) s1 k8 I( [: z7 N# |
    " d  r7 _4 x* O; aHow Recursion Works
    ' ^+ T7 A6 L2 U# @( n! K3 a. f5 I
    . ?6 Y+ [# {  E7 S$ E8 W/ J$ H  U    The function keeps calling itself with smaller inputs until it reaches the base case.2 ~: F8 S* v! H) E

    - z7 Q, X& _6 Y: {' r, p  z5 ]    Once the base case is reached, the function starts returning values back up the call stack./ `, Y9 Z- n; J, L0 @, A
      g' ]- Z4 D8 m# R
        These returned values are combined to produce the final result.% K6 k$ f% D' z3 O$ r. P5 R& {: U
    + E$ Y2 `" i3 {
    For factorial(5):
    2 p( Q" J, T: H" c! o& f: F
    2 f$ f+ q0 D! y. X7 m5 S
    2 C7 h8 s( n3 jfactorial(5) = 5 * factorial(4)
    9 A, r# j# q( ]$ a: ?; ofactorial(4) = 4 * factorial(3)
    + I/ R. H- f: j/ u7 ^. ?8 Rfactorial(3) = 3 * factorial(2); q0 L* z: P1 U, c! K/ x
    factorial(2) = 2 * factorial(1)
    " b3 T' d  t7 r9 [factorial(1) = 1 * factorial(0)4 c( O, |7 j1 B
    factorial(0) = 1  # Base case
    ( J2 M1 O! F. N1 g* _
    ) n. f# c# \) x& I0 ^3 o2 D% |$ zThen, the results are combined:7 @& A" I% A+ Y1 k- K, m

    $ T9 H, ?# ^6 c  Z* l7 J: ^
    1 C! @. ?0 e/ t% c. ]7 H" N: _factorial(1) = 1 * 1 = 1. p2 W" i) `$ t$ i
    factorial(2) = 2 * 1 = 2
    , K: R1 P4 a; v5 p" Rfactorial(3) = 3 * 2 = 6
    * w4 x8 h, s$ Ffactorial(4) = 4 * 6 = 24
    9 ~- s+ h* b4 ^9 i+ V/ tfactorial(5) = 5 * 24 = 1205 w. n9 o9 Y) B# _8 n1 E) K8 L! T" }

    7 ]1 j; c: K+ u2 v' {! vAdvantages of Recursion8 w- n4 I! w( X$ S" j, u

    % r: `/ u) p6 ?: Y! b1 u5 m+ @$ \- W    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
      a, j' f& p' y* a: v9 j. L! j" j3 ~9 n% W! p) N% D
        Readability: Recursive code can be more readable and concise compared to iterative solutions.* u/ @/ H" v9 c3 j! ~3 j; k* J4 y

    2 @7 F. t% J1 ~* j9 q0 vDisadvantages of Recursion! `6 m; j5 l% E/ @0 L. s
    9 t, v4 K! ?: t3 y5 R
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.2 F: A  k$ N0 J

    & o, |2 P) o4 ]  x    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).$ _$ e# H# m" t4 f  Q. f& P( Q
    0 z' g3 [6 G& k0 M6 M/ X" I. [
    When to Use Recursion
    / z4 N! _" A" E2 y9 C& h- b; Q9 h( e: H. H
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ( s& ]3 U8 w( U2 Z" ]5 X0 |- H& E6 f
    - s4 B3 X' S4 x: k    Problems with a clear base case and recursive case.. O' {' ?" E& k

    . o& Z$ W2 C$ ~, `4 D/ T8 KExample: Fibonacci Sequence
    . L: l' ^! `; m* [, Z$ h) i7 K4 O" @7 m( Q! s' s
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    # Z0 M7 Y$ F, y4 ~3 I2 Q$ I9 N, j1 D
        Base case: fib(0) = 0, fib(1) = 1
    % E: d8 }8 f- J+ B6 a) t3 Y( s8 i% M& S; M6 w
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    ) @" C& U/ }! B+ O! R# D+ u4 O, @% ~# ^& V+ F
    python, y5 \1 @" e& X% J4 E/ ]
    # J' k& l% T& P  j2 L+ h
    4 C8 Q0 s# |8 I2 v
    def fibonacci(n):
    ) y+ t6 v6 F1 Z, x5 }2 ^    # Base cases' w% [% I5 f$ s& l( I4 ^6 V
        if n == 0:, O+ ~/ e9 o+ N
            return 0' v# j, ~2 X# r) D1 \/ m# q* {
        elif n == 1:# F# q! q$ x5 v/ p+ a! y: {
            return 1% ~0 Y+ _  s! r1 K$ H( {
        # Recursive case* u- t8 r5 Z$ X/ J! t
        else:% W* s1 m( m1 z- @- D: d
            return fibonacci(n - 1) + fibonacci(n - 2)1 E: t1 J# q) E- q$ n( f

    ; e, e4 m" ^/ ]# Example usage
    7 [# m8 z. g( S& e, Rprint(fibonacci(6))  # Output: 8
    9 S& e5 S! h9 I" g% V& I% e3 @8 P1 h# h9 ^1 p
    Tail Recursion1 C/ p3 c' S$ J" d
    * ?' l1 P4 y0 j! X# y3 }
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).$ b% d0 n2 u$ K, @8 O1 |" T
    6 @) }$ \2 @9 W% N
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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