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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 , S  i: x9 p* t3 A& C) Q

    4 X" `* a9 I4 B3 W. N; d解释的不错
    # `# Y& z1 ^1 K4 T, Y& ]
    8 C  H" h1 `# m7 Y1 Q5 S递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。3 Q% O/ x+ V, y- l" Y% {$ Z& [0 }
    & |* U5 `* \! ~5 D! e+ e
    关键要素
    ! @6 Y( E9 O3 }6 h, b% s1. **基线条件(Base Case)**
    0 ?6 v$ K& r9 k+ J7 H& v   - 递归终止的条件,防止无限循环
    " @' K8 \- `/ v4 d2 o7 {6 G9 F   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 14 @. O$ C: K2 q  e9 ~6 q" O

    " p" K( W/ c# ^: j0 |3 X2. **递归条件(Recursive Case)**' n  d  e0 C7 }5 v. A$ ^. e8 w
       - 将原问题分解为更小的子问题. T6 ]! Q2 Y2 |' h5 U/ n3 X! ^
       - 例如:n! = n × (n-1)!, F: x% Z0 v& E, `2 m; F; f
    - Z- W: o! X/ I& B5 ?
    经典示例:计算阶乘; H$ I" d# \4 X" V" M
    python& G3 n; C- p9 x* {) b
    def factorial(n):
    9 B) S0 i: b2 c/ T' s% G    if n == 0:        # 基线条件: v; X" a6 K8 j, O9 O, f3 S
            return 1
    ; U* x& I2 k" ^. |  k    else:             # 递归条件
    1 [( T5 S/ N, x4 m4 d; I        return n * factorial(n-1)- L3 h: d; I) |% A3 `9 k
    执行过程(以计算 3! 为例):$ \& a, s$ K( [. N2 b
    factorial(3): t4 K; q+ U0 q; }' L' K
    3 * factorial(2), |  z' f: P5 k$ p
    3 * (2 * factorial(1))
    ) f$ `. z: V( i$ M6 m( V3 * (2 * (1 * factorial(0)))
    6 H6 i# s* B1 C9 z4 C+ t3 * (2 * (1 * 1)) = 6& s7 M$ c. ?" s, N% @  q/ ~4 `

    - l( Y+ b2 ]: V5 }; E2 b, L 递归思维要点
    5 Q, b% I; e# ]9 h1. **信任递归**:假设子问题已经解决,专注当前层逻辑: q/ {. q. m. u% a) I  H
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ' |4 R% G1 G# I, u* ~; A: y- W1 p3. **递推过程**:不断向下分解问题(递)
    & C+ Y7 p7 b1 b# A* u& @% Q: K4. **回溯过程**:组合子问题结果返回(归)6 i& N. f9 |2 |: G) C, m) Z( w

    - }* n3 ^2 l) f* I/ j6 O 注意事项
    4 j' `1 g; r6 g: Z$ N; o- Q必须要有终止条件# k8 j) f, ]+ @8 ~! a: |
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)8 v0 d/ {( Z" y: `6 A$ n( \( P" s
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    0 {' {; V& H. J5 [# D/ w  f2 \" \. e  I尾递归优化可以提升效率(但Python不支持)
    ( \, f  h+ J1 X1 e6 N; N6 [7 ]0 p  M% i! t  S
    递归 vs 迭代8 H. w% H" f3 f# w1 O( N5 o
    |          | 递归                          | 迭代               |
    9 V% C& X  E/ m: J|----------|-----------------------------|------------------|( j6 {9 {& y& ~! M) A
    | 实现方式    | 函数自调用                        | 循环结构            |
    1 Y! T; M7 J" u- b: W| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |# X9 G* y! r- l" D2 T( P" A! ~) o  r; K
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    2 ]. ^8 u3 _6 R4 C  r: K( K& ~3 [, Q1 D| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
      V9 L% R& v6 W" Q" c% u# F7 Y+ z8 {7 s2 T% ~
    经典递归应用场景
    5 g# g. V9 Y, K6 g3 L. j: q1. 文件系统遍历(目录树结构)
    : S8 p* S( c% w; Y3 U" G2. 快速排序/归并排序算法9 Y+ R4 h6 N' y& V& L' J
    3. 汉诺塔问题- ]. l& P) T4 \9 Z# Y" U$ I0 {% Y
    4. 二叉树遍历(前序/中序/后序)' I. Y7 m3 [# P0 L; ^. J5 M
    5. 生成所有可能的组合(回溯算法)
    - Y: `. y  d/ {9 L: l
    $ d# V( q4 u5 j3 r试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,3 W( i2 u/ s$ R" F1 ^& f
    我推理机的核心算法应该是二叉树遍历的变种。
    / {" f9 F: s# q6 S. g+ W% T另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:6 `/ E" R# Y" e' t" t. f
    Key Idea of Recursion
    $ Q# o6 i1 v& s
    0 _6 F: u$ Y( k. H1 E  T0 w2 fA recursive function solves a problem by:8 |5 e( z5 v: n  [+ M* ?
    5 f! F- X1 L$ W( D8 C: f( y5 J
        Breaking the problem into smaller instances of the same problem.
    # ]7 t$ ?$ `' X+ O5 R0 z5 c* z* ?8 W! q  l' T
        Solving the smallest instance directly (base case).
    9 Y3 H8 `- ?; `+ Q  H1 h# A. y1 M  H8 x5 D2 D
        Combining the results of smaller instances to solve the larger problem.
    $ E1 l" r3 @) q
    4 S8 ~% r- C6 f1 b5 I  xComponents of a Recursive Function
    / U, q& e2 {: K5 p; D+ c. M
    / R4 C% G7 Z* m$ o8 ~- D    Base Case:
    5 x1 C* b; _$ U& }* a. y) K" w# J0 t( X* T% g5 F$ Z% q
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.6 |- ^8 L- J4 y. X  z5 V* C
    % u5 ^% h% I  ?4 ^
            It acts as the stopping condition to prevent infinite recursion.
    0 q' D( I) w# w
    5 F# d% f: g! Z7 z        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.; @( `& ^% c# Y% F/ L' ~

    $ x" o" D  s  g8 v1 ]! J    Recursive Case:
    $ K& K' \1 p0 p  c) S. p' T+ Y4 T8 i: g4 U4 ^  A: k5 u
            This is where the function calls itself with a smaller or simpler version of the problem.( D' ?! n1 u* i: i' M; ?
    . W) K& j" t' s3 K
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)., z, S0 C2 v6 _; h
    , H$ d; V% c& H- I
    Example: Factorial Calculation0 |  e- |' L- f- v1 U; q
    ) R8 [% S1 d6 C9 V- j
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    & o7 l$ O+ h0 [8 Y9 b# z" m4 A5 r& H: V" h1 _
        Base case: 0! = 15 o4 ?$ T8 l5 u

    : i6 ]4 A( W5 \% a' w    Recursive case: n! = n * (n-1)!
    ' y" p$ i7 g! G- L" h0 J" i. R+ I$ \$ z" r( y- x7 R3 z
    Here’s how it looks in code (Python):7 \" w9 N2 @- O1 c& {9 l6 ^
    python5 Q% ]' `7 [" x' a) m! n' X' M% ~

    " {8 v7 A0 \5 U5 m6 N' I" v  e) D. ^
      W. q+ Q# m1 X7 H- |( [def factorial(n):1 O7 M& C$ O# B5 U
        # Base case
    : m1 {( k: V  s# u    if n == 0:( J, e! ^9 x5 W6 z5 a6 S
            return 10 w4 y# `: r+ G/ B- o
        # Recursive case& f2 O* \* b0 f. j6 M% G
        else:
    & b3 _5 O2 ~! v- o        return n * factorial(n - 1)4 G' @) X% D' d* C  D: M! {! T
    0 Z. O  T$ k/ V: K, p
    # Example usage
    ! |& i6 x4 k. a$ lprint(factorial(5))  # Output: 120
    # S$ d! _( ?" F: m! U9 \3 z# ?4 T$ k( T% R8 u
    How Recursion Works8 ]# `# w) k6 J% z5 P' B
    $ p! o4 F' q% s" a- _9 E, s
        The function keeps calling itself with smaller inputs until it reaches the base case.& s9 n7 @7 n& n) f! P& a, k4 `! N
    0 t, v' T8 q6 S0 ~6 \
        Once the base case is reached, the function starts returning values back up the call stack.
      Q/ c- @( |2 t
    # Z$ `8 K+ H- `    These returned values are combined to produce the final result.
    $ W, h/ L+ ^" ^' g, D- p7 \8 N1 G8 v9 k5 }  t* n0 t
    For factorial(5):/ j, d) R" A4 X
    . V7 s1 P: Y9 {1 d0 K

    4 Q0 h3 Y& R4 N4 P9 I3 Ifactorial(5) = 5 * factorial(4)- h1 T3 l6 M) J+ ]8 U
    factorial(4) = 4 * factorial(3)5 }* C8 j; K7 \% o( s
    factorial(3) = 3 * factorial(2)# ]8 e1 [$ L0 I& S3 E
    factorial(2) = 2 * factorial(1)
    0 [4 a0 K6 `4 D! E& A+ ?1 jfactorial(1) = 1 * factorial(0)
    # P" K/ u7 k; u9 mfactorial(0) = 1  # Base case: D: A) `9 |$ U7 e. A: i9 J

    2 j/ @. @- W, QThen, the results are combined:
    0 c5 Y# u* m& W
    % P; n5 Q- \! @" z
    5 v1 b6 a; Q- J% H0 k. o; ?: K! qfactorial(1) = 1 * 1 = 1
    . ^4 ^3 @6 b' K2 e  zfactorial(2) = 2 * 1 = 2
    1 B9 U6 K4 s1 H1 E$ N$ Efactorial(3) = 3 * 2 = 6
    ' l/ G6 S, t, f9 B, B& @7 Nfactorial(4) = 4 * 6 = 24
    0 m$ O% @; X3 v( X0 b) W; N% {: dfactorial(5) = 5 * 24 = 120! u% \: F1 p' B, S
    6 D; o3 m. a. D$ C, i
    Advantages of Recursion) F- i5 s4 ?4 O$ K$ S* K6 Y2 W. q$ F, m
    5 m) j3 G1 K4 Q
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    # I. T' K* N/ ~0 f9 D5 _1 l
    2 d1 J* Z$ k) f8 `' F$ a& X    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    9 x2 L, y  @/ W4 p- M1 ^! u' L! o3 m2 {8 n( \* J9 n7 `( ?+ c; M
    Disadvantages of Recursion
    , ^3 l8 P2 p6 k$ A; t" o1 v# ?8 P* v  P# d. u: U* P& b
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.' o7 G; T4 S* J. g

    2 P; G) T' f+ w; x- G: _) f* ^    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ) Z# v% y; [4 W, c; d- Y1 P2 F* U8 ]& J7 h8 \- s& S
    When to Use Recursion9 ~) \& I) }" V7 f* T3 ^: q- t

    6 m0 Y! ~7 ?) T; a7 r( Z  z% k    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).+ h7 W7 V& R/ d3 J7 l& Z
    ) c1 X, E8 M- h$ s) U
        Problems with a clear base case and recursive case.. @+ `1 S6 S. \. O
    2 h0 `9 I) G' y* ?) d
    Example: Fibonacci Sequence- C5 R; z* A& t) z* _( O: }- z
    ( v0 `0 t5 |9 ~$ g  a
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:; P6 A( }! O; P7 v7 o1 D* ~

    5 [; _) P3 A/ _- g1 b- p    Base case: fib(0) = 0, fib(1) = 1
    ' k% X, _. H& n0 O: R6 f# F# o: q5 d$ [
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    9 a# q# f" v( t% p+ ?; |! Z5 ?( j6 o$ a0 f  n+ Z
    python
    + |) {0 p, D( R1 p: r
      A, t/ Z2 g/ Y4 C8 h1 }
    0 v, a" o5 e) B% Idef fibonacci(n):; f6 I( N2 ~& q/ `' b. ^2 b% s
        # Base cases
    9 K  d" y7 n. m7 `    if n == 0:
    3 h# f+ ]& i/ `8 ?- c; o  s        return 0( [) b, l' Q$ w( Z; w
        elif n == 1:4 B6 e+ n" Z" {6 x0 N
            return 1; q  B- l! A! {. U7 y) y" x$ B
        # Recursive case  F9 o. |' Q% o0 @; `$ v$ j+ p4 p
        else:
    9 ^: o) E! B" r6 m6 j& M* J! t- J" Y        return fibonacci(n - 1) + fibonacci(n - 2)5 O# g3 A2 v! u+ X( d+ b* K
    # V, i+ ]9 }8 T- s
    # Example usage" Y( A' o! R/ {. ?" x0 R
    print(fibonacci(6))  # Output: 8
      I) f- t1 {( z% H' ]6 N! Q% H2 P- Z; @
    Tail Recursion% E$ [+ S: G2 @/ @& o

    ( q8 |, s; X. x! f: ]& D6 r7 ITail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    * ?& l. y7 N" E' j, W5 l) e" s; [; o& d7 J- j- Z
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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