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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 # n9 k4 S+ H4 k
    ( _! o8 _4 K9 M0 }* J/ @3 R
    解释的不错
    9 y0 Z) f& v0 p  p5 ?7 L1 z+ y+ B2 d0 G
    1 A' V) @! T" z% ?& A! V# {递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。1 h% l. |" b. ]6 G6 B' p

    7 V, q& U* y3 K6 M# a- {2 Y 关键要素; J8 M7 [# Z3 w$ U& r4 o
    1. **基线条件(Base Case)**
    ) j9 _0 ]$ X( z( O4 i. Y3 U" r   - 递归终止的条件,防止无限循环
    ' u/ N4 ]3 n7 b8 p( m! }   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1% i8 \% I8 ~4 w' D

    # T  {2 Z1 K6 A1 i, c2. **递归条件(Recursive Case)**' B  ]4 q: s1 J1 ?' I
       - 将原问题分解为更小的子问题% Q! p) l" M0 e! Q2 J+ \% ~
       - 例如:n! = n × (n-1)!% Y  \  q" n; x3 f8 X& M

    1 |$ f( t+ i. Q, i9 s3 K5 Q 经典示例:计算阶乘% o" w- Y  Y7 g/ L
    python/ m9 t4 j, z1 i; r- Y
    def factorial(n):
    2 Q/ I5 ^. u4 V! ]7 j    if n == 0:        # 基线条件
    & S9 T$ e) p5 f' e$ S3 ?. s        return 17 N; c/ Q" N4 U
        else:             # 递归条件
    , h9 D: r! W8 a9 Q6 v7 ]        return n * factorial(n-1)" O; ~5 H9 r- L7 Q
    执行过程(以计算 3! 为例):9 e$ |6 T& \6 U( A& Q6 Z
    factorial(3)# j  h3 e$ y: R/ x$ m. M' _
    3 * factorial(2)
    1 g+ y) M8 z4 \3 * (2 * factorial(1)); i( S( N8 c" p; i6 p$ L* H. \" G8 a
    3 * (2 * (1 * factorial(0)))
    5 g+ X8 M8 n, p9 O9 N9 q3 * (2 * (1 * 1)) = 60 P. w  [( W  x" F4 f! W- a

    2 y% n7 O6 s* g' [& T! U" | 递归思维要点
    ; s" q) [0 X% I1. **信任递归**:假设子问题已经解决,专注当前层逻辑; M$ o& C' b7 q( X
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    $ X, o' v5 m: T1 W' h! V3. **递推过程**:不断向下分解问题(递)
    8 }1 ^( r% }7 ^/ O- m5 r% L5 Z3 |4. **回溯过程**:组合子问题结果返回(归)
    3 J/ l5 b5 G; ]1 \. u& y5 e: B$ q* `
    注意事项
    7 s5 k6 J) Q* I必须要有终止条件+ w% j. }2 f* p# _5 A+ ?
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)* S0 b+ [, T" y( ?9 u/ ^9 g5 W: @+ k
    某些问题用递归更直观(如树遍历),但效率可能不如迭代- p- \& X" M: O; o
    尾递归优化可以提升效率(但Python不支持)
    9 W/ j2 _. `  a6 {# i* l
    , o) b7 v4 k$ O* T. K6 O 递归 vs 迭代
    6 ]% Y0 B& _" E' p0 \0 D8 Q|          | 递归                          | 迭代               |- v; D, L- H# U& r7 x. D
    |----------|-----------------------------|------------------|
    ) y! q4 O3 O  b+ y/ N% b| 实现方式    | 函数自调用                        | 循环结构            |
    5 v3 l+ U$ T* t$ A) Q5 y, N1 [( X| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |6 W0 [9 c4 N+ l5 _& h
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |  I, `; k( k- k2 g: ]
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    ' u3 _6 X& S% t5 R
    * `* k! F8 R1 F" ~+ H. A# N 经典递归应用场景& e8 n# }4 m) R% a, o3 C: `& p
    1. 文件系统遍历(目录树结构); b1 Z& m  G& Y; F4 Q
    2. 快速排序/归并排序算法9 `( q3 {$ E5 X$ }3 d2 z$ \2 L7 R
    3. 汉诺塔问题& ]2 ^6 X2 N4 \( `4 R2 n2 u8 I
    4. 二叉树遍历(前序/中序/后序)+ L7 M6 \! ^5 w5 j3 N6 b: ^! g
    5. 生成所有可能的组合(回溯算法)1 P# g! z  h4 r: v$ I
    0 @; ^# n3 r: t* Y, R
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    郁闷
    昨天 07:20
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,6 L% q2 T2 ^: m! j8 m$ H
    我推理机的核心算法应该是二叉树遍历的变种。
    * [5 [, ?% w" |. ?# C; a另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:$ s- q0 h7 v$ i4 y) s2 y) u
    Key Idea of Recursion) T% ^3 ?% D( h
    $ [5 u4 Z; X4 W  h- a/ @7 F* ]0 u1 u
    A recursive function solves a problem by:
    , Y6 ]7 J" S% ?5 t9 e& j- F
    6 @2 F* w$ Y% v. G/ ~# Z  ]    Breaking the problem into smaller instances of the same problem.
    0 k& [  q# I8 S$ i3 J8 y& N3 }; {  h( P8 m+ ?+ N
        Solving the smallest instance directly (base case).3 [8 m  n2 P: [% j+ x
    3 t: v+ c8 ]( R' S8 Y+ W. q
        Combining the results of smaller instances to solve the larger problem.
      B) ^) v3 K; V" @+ A
      R# W6 P! [7 P  |$ L: @% VComponents of a Recursive Function
    " U# \1 t) P" i. k+ P- z3 B% x: e
    % B2 e; R: f: b, _    Base Case:4 X3 ^# a. D* |- ?$ N

    9 V; Z8 g5 L# U& U$ ~0 D6 i        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.1 w& ]4 f" }3 B. z* V! }& v, d
    * T- i1 p" k* G
            It acts as the stopping condition to prevent infinite recursion.
    : c0 H/ ^0 B7 S4 _8 v3 c& P' S6 P* m% H1 I- @" A- y
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.' d3 O( G+ E0 o. k( w& u! _; b

    * K7 ^( q9 b+ K8 n    Recursive Case:
    $ Z6 `- V& P5 I9 K, \" `9 U+ c2 X5 c  n
            This is where the function calls itself with a smaller or simpler version of the problem.
    + r3 H7 N% b2 ?/ \0 m
    : @6 Y8 s/ _# u7 Y; s: K& {2 v1 S        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    . W* V, m2 W! f4 U" X& H5 v8 F1 y0 S% ?# t5 f3 l
    Example: Factorial Calculation5 \( W/ s: a$ i7 E, t8 ?# @

    8 N& C' u& `6 s" |The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:7 i+ q: k# A# Z6 H/ N
    , S, [0 J/ n- s% n/ X% H+ |4 T
        Base case: 0! = 1
    + R3 b0 d9 g- l
    2 h) G6 E- _: I1 C6 q& ^/ D    Recursive case: n! = n * (n-1)!! g& K& n" q! ?1 J. C
    9 d* f7 n9 w9 T
    Here’s how it looks in code (Python):! N4 j: h) d9 S% j4 d
    python) t% N* e6 M" ^; Y9 W; S6 n

    0 p7 f( W' }* z$ j
    1 N" T" P4 ]: e  e- Qdef factorial(n):
    ! Q- B) r. l# z# t  W+ _4 T    # Base case1 h8 M7 K0 z2 u2 \( ]% O6 n, {9 S
        if n == 0:$ z6 n/ T: Z3 ?  j
            return 1) w# w8 _  m" W" x" L
        # Recursive case
    & F/ l- p) [) i) h+ e    else:
    . d7 V' R% _5 ~        return n * factorial(n - 1)8 p9 }* f: H. ^+ k# O  k
    ! c8 y0 t2 l/ h1 e+ `
    # Example usage, `5 V4 V* f# Z8 X% X
    print(factorial(5))  # Output: 120
    ! t# m" u% I/ ?) R; f) s7 @7 @( g* f& @6 s( P
    How Recursion Works
    + |* k( Q+ F& V2 {
    . R$ }% u) v6 U, J' q! X) j9 N2 y0 J. U    The function keeps calling itself with smaller inputs until it reaches the base case.  P8 `7 B% D3 k; [0 u# N

    2 g5 p; Y1 O7 g7 o    Once the base case is reached, the function starts returning values back up the call stack.8 I' S5 M; q7 S6 J

    ' f0 g8 }$ g; B+ E9 t! q    These returned values are combined to produce the final result.$ v( ^3 h3 H- M/ ^/ h

    ; D3 k/ j% N( }7 pFor factorial(5):3 u- t' \. B& B( L: i

    # l% H+ M# t& n2 F2 O% J; o, F/ q' X* N  N- }
    factorial(5) = 5 * factorial(4)' o4 ]2 p) G) [
    factorial(4) = 4 * factorial(3)& ^. T8 [0 r; G, |( V
    factorial(3) = 3 * factorial(2)9 ?4 S' x) ^# ^/ b7 {; Z: f4 [8 U2 W
    factorial(2) = 2 * factorial(1)- R* [3 t& \3 ]) N
    factorial(1) = 1 * factorial(0)
    ) P: G1 k  p' L1 r# F2 N9 Gfactorial(0) = 1  # Base case
    & n8 A6 S1 F' a* o' p4 S, c
    % ?0 W/ i' M, i$ O* T# Z8 h8 D( DThen, the results are combined:$ r& m9 C9 {0 S# B4 @

    9 V6 P9 g2 W- z% a
    4 W0 H% M" s9 D+ ?+ [, d8 ofactorial(1) = 1 * 1 = 16 X. A  [3 L5 n: d* E. T: l
    factorial(2) = 2 * 1 = 2+ [" M8 T- t0 D9 k, s
    factorial(3) = 3 * 2 = 6
    % I* U0 A( y# y6 o3 _9 Ifactorial(4) = 4 * 6 = 246 d+ |7 p& I: c$ x4 K! b  M
    factorial(5) = 5 * 24 = 120
    # k2 q, W& q9 g8 P" ^7 y2 n( A7 H/ s4 Q
    Advantages of Recursion
    - \* @' V7 @6 F/ a9 }! x; I8 ]) o9 S
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    , M# B3 ~, [- w1 U; ^9 I8 o8 e) ]/ {, I5 C* K
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    ; Z7 V! ^+ E, S- m; |
    3 V# a( w5 g, |) x; B" VDisadvantages of Recursion- U' V3 K! M# x: \) d4 G/ y% K

    2 _& O) {5 h( Y& n& g; _& P! g/ a    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    $ O) k+ K% T8 p1 r
    ( [$ L; j$ ^7 j    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).2 {, Q5 w0 R/ E2 r) _
    2 @* p; I! ~7 Z" s
    When to Use Recursion
    * q4 }" B  N' I2 X+ s
      E0 q7 t% M( ]: y    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ( W$ b) p+ A) l7 `4 Y
    ! n* Q0 }" M( }8 ^! Y    Problems with a clear base case and recursive case.
    8 y; J) E2 s! B- B7 U" M6 b/ A  _* \  t+ n; y+ B3 @8 Z
    Example: Fibonacci Sequence
    # b) c6 o& Q6 I) C* o& Q; Z  Y
    + U1 z6 t) _- |& A! {The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:1 V% Y  l/ e, M+ n* b- c  j
    5 W8 @5 g7 M8 C4 F& B" K9 ]
        Base case: fib(0) = 0, fib(1) = 10 w* o5 V! N! I
    ; o3 F% s# u3 L+ a
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    5 x2 E7 q( \" ^1 b7 e6 N3 _; Q. {6 p) E5 L4 x: M
    python1 ]$ u$ v  n6 y& O8 ?
    3 N: W0 A* ~, N& l5 _. o% C$ x, A

    ! W% Z9 O5 B$ c" G* [3 n' a) gdef fibonacci(n):; A. z' `* O+ M* s5 h
        # Base cases) I, B3 p  j0 u  U7 ~$ A* F6 k
        if n == 0:; s' i& b+ i/ x( L' i6 Q. M0 o
            return 0
    ; S. d  t2 P5 F6 w; x, O* s    elif n == 1:
    8 w$ \) [3 M+ _. [  ^7 j        return 1( s1 y2 [$ K1 m' M$ s- t2 ~
        # Recursive case
    ! @( X+ z8 C( @, M, u5 k* @' n. H    else:
    # `3 {1 J3 Y4 P8 d        return fibonacci(n - 1) + fibonacci(n - 2)
    / |% k8 B  ^- w/ r* u
    ) w& c( ]3 i! f# Example usage
    , h# r: s! G! S  }# \! Q" v: Fprint(fibonacci(6))  # Output: 8
    - A8 ]9 t+ a, \% C% Y, v9 T4 E8 k
    . h+ U$ B. z+ }  D- f  [+ E3 d, xTail Recursion
    5 s5 q+ c7 H* Y9 m/ G9 e1 b7 K# a7 N9 ]) {4 R5 x- k  x0 a2 q
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    5 v  q. }9 [9 J4 F2 {
    * m1 P% ~( K0 J0 X* WIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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