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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    6 T2 d$ G* ?& E7 _! |* ~, }' q* U1 k2 v: E# U( B3 y
    解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    : M4 L! u4 i; |  ^
    - d: r" j. N2 O9 h 关键要素
    " f, V# W9 J( ^" t4 G3 r" A9 B2 s1. **基线条件(Base Case)**
    9 o, r; {9 o8 Y5 m. p   - 递归终止的条件,防止无限循环* M; X9 g9 y) u- m$ y% C  r
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    / s, N3 i8 W7 w) P# z( ~$ k
    9 l+ J# T8 P( R4 a0 H+ H8 c2. **递归条件(Recursive Case)**
    9 x9 |* d2 C9 S) O2 b# C# j5 c   - 将原问题分解为更小的子问题* j! a% s, B9 Q7 c- \9 T
       - 例如:n! = n × (n-1)!
    . \- E+ N6 c6 F, Q, L8 d% g
    8 ~) [+ t6 T0 |' e3 t7 x% Z 经典示例:计算阶乘4 I7 t7 X& x. e- m$ u
    python9 Y8 x$ g, l+ _& w
    def factorial(n):/ |" t6 W: x0 a5 F" [
        if n == 0:        # 基线条件4 z5 q6 J1 Y. P6 H
            return 1! y: P# X/ m- k% o. }) r1 }1 }
        else:             # 递归条件, Z: Q. v* {) B; X) y7 u0 _0 w- h
            return n * factorial(n-1)2 o! Q. L/ \2 G, n* [! M
    执行过程(以计算 3! 为例):
    2 v9 T/ I# X: G8 ^; x8 V0 Pfactorial(3)
    % T6 \( h! C! p3 i" G2 m3 * factorial(2)) C, I. c5 `& Z* c
    3 * (2 * factorial(1))
    & R( ^5 ~4 {8 `3 E& T( N3 * (2 * (1 * factorial(0))): N7 r9 h* `3 C6 c" o" G' p( M, x
    3 * (2 * (1 * 1)) = 6
    & o* H' f+ h- A% Y  d' ~5 ~+ A7 Y* `7 ~8 v5 Z
    递归思维要点
    & Y9 s8 w# j+ R2 h( m1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    ! _3 L) M4 N9 a8 M2 L$ n2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    - C8 J. W$ }" u3. **递推过程**:不断向下分解问题(递)& J  Q9 {/ l$ q0 b. s
    4. **回溯过程**:组合子问题结果返回(归)4 I# \) h8 Q: u* n! L+ `5 t% N

    . K: E/ u! h1 Q 注意事项
    0 B) F3 a' w* D! @3 `1 C) V必须要有终止条件. e7 r  k2 ~, K$ H! x7 H
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    $ I. Y7 w( D& F: f: Y, z6 ]/ f# R某些问题用递归更直观(如树遍历),但效率可能不如迭代
    * W) s5 a! V6 ^; ?1 W尾递归优化可以提升效率(但Python不支持)0 p$ s! K3 N5 c% f# `  s8 H, x

    ) q+ r  K& C* I0 \2 _ 递归 vs 迭代
    & D3 @, v! R. m, |$ i|          | 递归                          | 迭代               |8 o2 [3 t0 ?+ i  e4 b6 |, g( w* c
    |----------|-----------------------------|------------------|6 o2 I6 Z& o3 ]
    | 实现方式    | 函数自调用                        | 循环结构            |* |; {0 v9 s7 D- w3 w  z
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    $ k1 s, ^& z/ S3 \! o0 n4 J8 Z| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |% E. t: w* K3 z2 @2 g: }# @& M$ D
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |- i+ C: O4 k" w5 p

    8 ^  ]# R: e0 X 经典递归应用场景
    ' [- s, o' G; |: Z/ y9 \7 ^1. 文件系统遍历(目录树结构)
    6 A5 n8 ~& Y9 e9 G- m2. 快速排序/归并排序算法
    1 F4 C# `( y3 U9 ]" F2 S9 h* d: ^3. 汉诺塔问题7 e0 S6 C! z( m- A  W$ x4 I
    4. 二叉树遍历(前序/中序/后序)
    + A6 Q, g4 G) L# u: ]' f& q5. 生成所有可能的组合(回溯算法)  y4 e6 l) }- U, \  R

    1 s% d# s! O+ K5 w, B3 t试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    郁闷
    14 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,  T+ y; T. K# ^4 t
    我推理机的核心算法应该是二叉树遍历的变种。; h9 P# a. m5 P7 ]& p+ ~1 B
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:0 ?% \( x9 \2 a2 I) c
    Key Idea of Recursion
    3 f, {& r  V/ B0 }/ x2 `( X, N6 v5 {  O4 Z8 ?
    A recursive function solves a problem by:" v6 R2 s  r: q0 C% A

    , f( ^3 ?( m1 G' I* Z$ y+ y1 {    Breaking the problem into smaller instances of the same problem.
    + Z6 _: x9 }, f% e
    ) @2 J9 e  Q) G' ~    Solving the smallest instance directly (base case).
    9 j6 A" h! l( m% v* X
    * J; e. D- @; `# m1 l: j; }    Combining the results of smaller instances to solve the larger problem.
    3 H, F  {6 @; B5 [+ y: C7 n" r- g# K3 q  _! V: W" D  \$ u
    Components of a Recursive Function- H! W- s' \0 \3 p% k) _' L6 O: [, T
    8 T1 I6 Y) O0 }. U8 H
        Base Case:
    ) B' F6 Y2 X' P0 s! c' R7 P8 j
    / |# w  I$ P( Q9 u: y4 @7 h/ _6 c        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.; J: a0 i, C# H. ]' U
    ' |0 M$ B' t  \$ W- ?0 f5 i
            It acts as the stopping condition to prevent infinite recursion.
    % `3 A4 G& s& T) a1 ]0 i2 `% I
    : `$ O8 R/ k0 |3 L. j2 u        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    1 c. |' [4 k. a6 f8 I5 W5 L5 z* p% F9 n% J' F8 `! p2 f8 b( C
        Recursive Case:
    2 ?/ R' j$ M1 H! J: n- {: n& ^
    # T' \7 s* G4 K' c4 v8 o        This is where the function calls itself with a smaller or simpler version of the problem.$ ]9 G' w- B& E0 |9 G& R2 U: n6 J: ]

    + }9 N3 O8 `1 s' R        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    ! G  c& j* h, N. Z1 s% P; J$ P$ T: }$ j3 t
    Example: Factorial Calculation) F0 Q2 a$ N" b

    + T7 e7 _. O- u9 y! r! f# I& {The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:7 ]( z: i1 @7 c/ w. Z! Y
    2 {/ @! z, g( @# ~5 M+ o
        Base case: 0! = 1
    0 H  V+ ?3 x1 u
    . w+ p. D; K2 |! N9 f9 V+ r    Recursive case: n! = n * (n-1)!
    ' j5 R' |2 J3 @/ D
    : E; w1 F0 O% y% XHere’s how it looks in code (Python):0 x" A+ U& Z/ K. E# X3 g- x( i, y
    python9 k9 G. k8 n7 H; s+ J

    * }9 w( Z7 T4 ~% d/ _9 x* W0 G- e' Y8 `5 u+ `
    def factorial(n):7 i6 h9 |( @# i4 y* G! b
        # Base case3 L0 A& F4 q4 ~
        if n == 0:
    7 k4 u( U% T( V2 [' }# H        return 1
    5 c9 k  P) y1 {  p: b7 }& G7 f    # Recursive case
    & T: b7 K" o: I5 u2 s9 o" K/ J- C  a! L    else:5 `7 k# x2 G# d, [7 T
            return n * factorial(n - 1)
    2 {7 Z: C/ Q" B) w+ c1 L% `9 j, a. t  W) z' J% ?% K, A/ m
    # Example usage+ x0 a: ~: g7 P& L9 _) B$ R8 D
    print(factorial(5))  # Output: 120
    $ R: B% ^, M1 m! d
    # [/ H2 C3 C6 _5 h1 m/ A0 L0 yHow Recursion Works) V+ Z9 p  r3 `% w& Y) y7 F
    5 C! g9 R% n: C8 c! @6 |' r1 y
        The function keeps calling itself with smaller inputs until it reaches the base case.
    ( L7 u# u4 S9 o9 A: i
      `5 W% q) }( ^$ H' _    Once the base case is reached, the function starts returning values back up the call stack.: E: x' s& y6 ]+ b( @  N% }

    3 V* W, {7 G& N* j2 Z- Z' G4 e* W    These returned values are combined to produce the final result.
    $ `& i5 I6 s3 w, v' h* P7 r/ C/ G) e. I+ t0 r, i+ k9 t, V
    For factorial(5):, p4 }% m; J8 `3 y
      r) ]9 o$ Q* K2 A5 q" z" R

    5 Q3 v7 O' d8 G6 W( q  x' M0 hfactorial(5) = 5 * factorial(4)+ X* F  T% z+ L% ^: g3 H( |4 e% e
    factorial(4) = 4 * factorial(3)) B7 i; S& o. B+ s
    factorial(3) = 3 * factorial(2)& H3 K5 t2 s! B8 F/ p, i1 {% D
    factorial(2) = 2 * factorial(1)
    5 B3 W" s5 S8 a- r  k1 V- F2 Rfactorial(1) = 1 * factorial(0)* {1 u, M7 H  `  {  x# w9 g
    factorial(0) = 1  # Base case
    $ y' x% Z& r7 \2 e  d$ m( o* q# h4 g. w1 A* X
    Then, the results are combined:
    ' y; K9 V! v7 [' ]  E: u. N  [, u: Y! v* p# d# M
    ) f" ]1 |5 j( t/ d( d# Z3 f* i
    factorial(1) = 1 * 1 = 19 x# Z7 c1 L, N9 v1 Y
    factorial(2) = 2 * 1 = 2
    1 r* y9 {" E$ m4 ?& Y! Cfactorial(3) = 3 * 2 = 6
    $ Z  x+ e* u+ q0 Yfactorial(4) = 4 * 6 = 24
    3 W: X+ ~% k) G, G, H0 a- Hfactorial(5) = 5 * 24 = 120* U& k6 \( C5 O" d1 |3 b2 n1 {
    6 Z) s9 p( K+ Z6 m1 A
    Advantages of Recursion' H, ]( {6 k* i: k1 ]* i; X
    + f" Y& v- P+ s; q" \2 E
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms)./ A$ ^' d% @* H6 ^) n

    , E1 @8 f" v1 \1 H& f" |# Y+ j    Readability: Recursive code can be more readable and concise compared to iterative solutions.( B0 ~' q6 I$ B
    ( ]- {$ h3 A( b  ~) J# S
    Disadvantages of Recursion
    & @% I! M1 Z; n
    ) \4 u4 Z* U) ^    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.1 h5 j* h+ q  }8 ]
    * z9 X% V1 n. ]) ^
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    + a5 |: J$ J/ f0 H/ V
    ; C7 C) e4 L( F9 R! jWhen to Use Recursion
    ! F/ F. p) G3 S
    ' u; I& h, `, Y0 u1 M, z    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).+ ^$ Y8 v( O2 r% h' k; k& I
    + e& |9 Q' b- n3 y# s, n9 z/ e
        Problems with a clear base case and recursive case.
    8 h! U- F: c) a/ ], T8 C6 S3 r" x9 v0 ~% h# o- i, k0 u
    Example: Fibonacci Sequence- q7 K) T, w0 j, C4 H; l
      k* Z' F% B+ q) p8 E' k
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:' W- l" E$ M" n* h
    % n  Y7 }% K! }$ ~/ ], X( D0 C: t
        Base case: fib(0) = 0, fib(1) = 1/ @  G/ X+ K4 K& k  C+ x4 V3 Y

    # M- S8 }' }( }6 H7 I; a5 ^! d2 Y    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    $ G  S, |8 ?: h! S9 ^8 Q  X0 s
    * x( u9 E! c. g, U: f4 k: npython3 v. B* S3 S9 M: w; F/ h; m

    % b* U0 E6 n  m+ c& ^
    ! ]* D, G! F8 X  B% \7 m. ~0 gdef fibonacci(n):4 l; k4 v& W  e/ }- l; E
        # Base cases
    ' N3 c$ n  Y0 A    if n == 0:4 z  d" A6 h6 U6 g  |5 G1 H# w
            return 0( z1 b, G( }" l& j5 P
        elif n == 1:
    / Q& ~# \/ m9 B" g# K, s% ]7 {        return 13 @, y/ {  b0 d  S" a, M' z! o. L/ B
        # Recursive case
    & y- E$ v" Q; t4 ^1 H3 F. V    else:
    2 I' x& s5 y4 z  D# W        return fibonacci(n - 1) + fibonacci(n - 2), g, N- q4 E' d( J8 r

    $ s8 J7 ~- \" x$ E, A- d# Example usage
    5 U( J% O+ [+ o1 Jprint(fibonacci(6))  # Output: 88 s5 c/ V3 z+ d" @) z2 T
    - p, o8 T- A0 G) l  O/ D, v1 v
    Tail Recursion
    1 i) i0 Z1 e1 U& F7 d! R4 I0 }) e4 x+ j% j) y3 d! s
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    9 z/ N" L8 h, E! p
    ' ^# U! E3 ^! n4 `' Z" rIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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