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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ; G% g2 q5 f* {# i4 J  T- W
      Y8 C' n8 q+ C" @- e9 G! p
    解释的不错  u/ E: R; ?$ p* e5 U# K; H

    7 Y. j& y' e, m" B& q6 n7 c  U递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。+ x3 n7 ~. d3 z8 C! B& n

    8 |: h6 T* |7 h8 s 关键要素
    3 \! W. {9 O6 p1 l# ]1. **基线条件(Base Case)**
    1 U" ?9 |2 {, h) i+ F$ V0 W   - 递归终止的条件,防止无限循环2 Z- I) F% x0 f$ q. ]( @
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    $ i) e1 u4 d, R! j; o: u! u
    & d* `! T/ M$ T2. **递归条件(Recursive Case)**6 E7 {/ g3 p& r+ \6 s' F4 M
       - 将原问题分解为更小的子问题
    0 f: L( x) F& t, `  q2 S   - 例如:n! = n × (n-1)!
    $ t! H0 |( p8 p, O6 Z; o, k: f) Y4 s6 e; h& N- S; Q
    经典示例:计算阶乘# z$ w) [7 |6 T: \0 }* ?: X4 y/ \0 x  c
    python: M9 p8 q7 z2 \
    def factorial(n):  I, q3 z: `1 }  o1 x( ^: N( p# d
        if n == 0:        # 基线条件
    ) W' P! C; q! z. ~        return 1/ H5 g3 V6 Z7 V% e) p3 f  @
        else:             # 递归条件
    ; n* Z4 R1 V/ j8 t4 b% x        return n * factorial(n-1)
    / M/ S' d- I! b! |1 y  }执行过程(以计算 3! 为例):
    - J0 x4 ]0 K1 Z( afactorial(3)$ E6 u8 P4 j* ^0 u- }0 h  m4 t/ Y+ F
    3 * factorial(2)$ r9 B0 f7 z0 b7 H+ Z% k
    3 * (2 * factorial(1))
    0 f5 X4 }" y& [3 * (2 * (1 * factorial(0)))0 z; _) t( d. g* X
    3 * (2 * (1 * 1)) = 6
    0 ]+ J  z5 L- u) j6 i5 r/ `2 j
    " O; x8 f9 C% c+ Z0 O 递归思维要点5 V7 T( t, b5 N: Z6 \; s
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    4 U$ ^, e* A5 D; q! ?$ t1 {: R2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    7 i9 F2 Y% H; p3. **递推过程**:不断向下分解问题(递)
    : x& f  k1 j6 N7 q4. **回溯过程**:组合子问题结果返回(归)6 R- M8 _3 x& j' Z2 E. q/ S$ X

    ! c' C: J/ i8 O/ r" J5 N8 D0 K* l 注意事项) l9 X" C8 T- v( V* d. y5 \  b
    必须要有终止条件
    & }# f/ h) E; L递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    & v5 h/ C1 I" ]1 V1 d) e某些问题用递归更直观(如树遍历),但效率可能不如迭代
    , w7 z+ {/ X- q( \8 T- ~( O尾递归优化可以提升效率(但Python不支持)
    . M! K/ G. L4 |! P  R- h& I5 {: s
    ; G$ g7 Z0 l! j 递归 vs 迭代
    0 y" P$ p. }9 U- e|          | 递归                          | 迭代               |
    ( t' R8 T3 X. l|----------|-----------------------------|------------------|
    7 c; p* B: d  I4 z, r| 实现方式    | 函数自调用                        | 循环结构            |: ]$ g/ d) Y6 ]* v3 J. _
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |# J9 x: |6 E  m# V4 t1 N/ {. {
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |0 e* ]; _+ g& |$ s5 l
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    & |; b  w/ V6 _: I/ i' s3 }* y- u  L9 ]( Z# [( Y0 Y
    经典递归应用场景
    ; F! \  F9 r/ G2 ?2 c1. 文件系统遍历(目录树结构)% W: v; C/ H% W; A. B
    2. 快速排序/归并排序算法
    5 b8 n1 `- C0 P5 c5 A7 f' ?. \) A& p3. 汉诺塔问题
    1 X1 V# B2 o: H. L1 y4. 二叉树遍历(前序/中序/后序)
    8 u, j7 ~, C# K$ q4 ^5. 生成所有可能的组合(回溯算法)
    , I$ `, _% _, R
    : ]; C1 P% h' \6 O试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,- c+ w, S1 H; M) I! m3 [8 y8 [. ~
    我推理机的核心算法应该是二叉树遍历的变种。
    & O8 w6 k* Z8 e8 |4 ~+ p7 ^; e. P另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
      _* ]4 K8 e. U) d2 N, tKey Idea of Recursion
    : k! _$ k, T; U9 x# x4 ^# G! k, l/ I" s
    A recursive function solves a problem by:* E6 |1 q8 G2 \  e

    . _+ S, F6 k! I6 N$ w6 Y    Breaking the problem into smaller instances of the same problem.# o! y/ A) h. ^* v1 z8 j

    * U" f9 O2 F% ?& n& T$ ~, J5 c    Solving the smallest instance directly (base case).
    4 ~' O: a# j( W3 V
    ) \3 ]; i, {, ~6 @5 T) S    Combining the results of smaller instances to solve the larger problem.
    6 H& h' o/ M7 b9 Q
    - q: q, |( |* S. BComponents of a Recursive Function
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        Base Case:, y& ?) `' X9 \' w7 S

    , [# W9 s/ ^2 y1 ^' M* [+ Q        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    ; K9 m7 |; a* W6 `) Y  f2 Z. o( D7 }3 j) A* f
            It acts as the stopping condition to prevent infinite recursion.
    / n; m" V; `5 U2 t* W, O- Y* m1 S5 @, W  @1 d  S+ s8 m; O7 U
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.- t. M* P: Y9 T

    ) N; W  H6 Q3 y    Recursive Case:
    3 [2 Z5 ?* `6 M! R4 S4 J# L
    : a  N" _6 d2 q# F( d& `, v' O        This is where the function calls itself with a smaller or simpler version of the problem.- V9 _- Q9 S( }3 S  W8 `) s
    5 c2 N2 m# f. N3 |" S; A' f: k
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    3 H# g* E) E; u0 g  L
    3 m0 y$ Q0 F# N" J  D1 qExample: Factorial Calculation0 p0 f7 O7 a" ?6 `3 H+ P7 @$ J9 l. i

    7 H9 P- O9 A7 m) IThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    $ Y4 r. h1 A. o' Q4 q1 j! n. P1 \* ~( \3 {; r9 C
        Base case: 0! = 1* M# r/ Z1 b9 J3 f9 l
    ; A6 Y% N& I7 [0 D; Q2 g4 R# b: m$ f
        Recursive case: n! = n * (n-1)!. g0 g( q. o9 O* A$ F
    $ y7 P5 c4 k" u; R+ v$ t
    Here’s how it looks in code (Python):
    ' L/ c% B( Z2 W2 v. J* mpython
    ) F+ q7 g- p7 U4 A4 E( b. B, h( I
    ( x" w" k' ^7 j& k& C5 m2 J- T0 o
    def factorial(n):( ^+ U+ {0 Z' _& R
        # Base case/ u: D$ R$ }6 h  f% c% z! C& _1 M. R
        if n == 0:
    $ P/ s9 ]1 G" B3 D) Z        return 1
    # w3 m, Z/ D$ O& z9 ], [' ]    # Recursive case
    6 T3 @. h) X3 }5 m2 H3 U    else:; K3 s/ l4 ~" \, y9 \
            return n * factorial(n - 1)
    , a, |4 F* M* F% f; C  w* t
    0 P$ a% O4 s1 X) z5 x: ]0 \# Example usage
    $ r  r8 B" p1 f0 X1 bprint(factorial(5))  # Output: 1206 \0 E5 g( g9 c( a+ d, B1 Y
    ( X% u8 f+ U+ a
    How Recursion Works7 ?5 n% d. Y$ J: [) w4 X& M$ ^$ X( I

    : E$ Z1 Z( Z' U# L7 L# C/ S    The function keeps calling itself with smaller inputs until it reaches the base case.' U; C5 d! ]1 b# M
    : Q, C8 z( i% g$ W$ t! @# S8 k
        Once the base case is reached, the function starts returning values back up the call stack.
    ; D2 d8 v3 J! B1 @
    4 _& d( N# Y2 q9 Q0 L, x    These returned values are combined to produce the final result.
    % r) k/ `2 R3 z! D6 T$ X' f! F( l6 V6 v' A
    For factorial(5):" i9 B) a4 n: [; {/ V# o7 j% R

    ( a3 P7 g7 ?! e+ H# n5 }9 X# C8 }9 x8 k* ^
    factorial(5) = 5 * factorial(4)
    + Y5 w' P) e& F/ W! u; yfactorial(4) = 4 * factorial(3)
    * s5 v* T! v) A$ q$ Kfactorial(3) = 3 * factorial(2)
    ( P4 D2 B) n+ M: Wfactorial(2) = 2 * factorial(1)6 `/ {/ Y$ V" h
    factorial(1) = 1 * factorial(0)
    $ z% M  u$ `, K% K5 i$ {* U7 {factorial(0) = 1  # Base case( G- m; z; E9 g" i# b* X3 W
    * e- l5 l; D7 k& u
    Then, the results are combined:: x! X5 c6 v3 [( A0 X
    # T6 S3 T, o0 h6 |: L8 k# A3 H6 u

    8 o8 C( N( T- C& Gfactorial(1) = 1 * 1 = 1" Y; r2 W- j/ {# g' d/ j4 l/ y
    factorial(2) = 2 * 1 = 2
      s; B3 C1 [5 a9 S1 ?5 `4 ^factorial(3) = 3 * 2 = 6
    / F+ p* c/ D# V4 Z# Qfactorial(4) = 4 * 6 = 24$ I1 x2 {5 l( v% U  p
    factorial(5) = 5 * 24 = 120
    5 R3 m; `0 j. {2 w6 V& W- g! a6 M4 \# d1 F$ }4 f
    Advantages of Recursion
    ' D* O; V, ]) K$ v9 H) Y& H" _2 `8 |6 F- B2 R8 m5 K
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    ) _2 x/ b) _3 O  s' O* b7 r8 X2 H7 `1 Y( M; \+ O
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    - g7 M3 C- r4 b) w! p1 ?5 I! q& M
    Disadvantages of Recursion( ?0 Z+ h7 X9 \
    * \  R" i( n$ {4 \: ~
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    0 E4 G1 I6 i( o1 F, h: g2 d6 W: W. y- Q* G; E4 O, o
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).2 H' y9 |3 V: u# N
    6 g5 i6 `4 P/ S1 J1 l: ~  X# L
    When to Use Recursion* @- }8 z" F4 M! `
    6 u7 R( M7 U5 I/ m$ F) t9 |
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    0 _- a' I* |# _: r3 _, V. \8 `3 \/ E0 X) B' n. F3 u8 }
        Problems with a clear base case and recursive case.
    " [6 O+ w1 L0 @! G- D2 y- N$ T0 o/ q2 s: C* @, W' b; ^
    Example: Fibonacci Sequence& G* t3 E# f% F$ T6 l* i; z8 D" R  [

    : {- p" y& `& Z  p( }0 o8 ?The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:% d# J" B5 ~7 Q6 E7 z3 p# W

    ' c' ^( B5 k- E7 f* @/ @3 n- [3 H  p    Base case: fib(0) = 0, fib(1) = 1
    ; y8 f9 R; k, m" M( v
    + i" F0 I2 p( F8 u1 T    Recursive case: fib(n) = fib(n-1) + fib(n-2)0 D4 \5 _1 H; e6 k2 y# y; N

    , K9 Z) _, ]2 M  c& kpython  p+ \5 ^. \5 c$ g: s; q$ _
    . B6 ?) i3 u! B7 r- R6 A

    3 }' o) V3 f1 z6 e  Edef fibonacci(n):9 \% ]. C. Z( ~
        # Base cases% p& A) ~$ H# P, V
        if n == 0:
    8 ?& @6 C2 e! M8 b        return 00 K& Z7 ?2 j& g5 B7 M0 n* g
        elif n == 1:
    ) x9 ?+ d3 Z& x- m# v; j0 z/ B2 D        return 1/ M0 g" W: i3 n7 H% a0 A/ Q) A: |
        # Recursive case
    4 b7 P$ y. _6 c- k% i9 f/ W2 r    else:
    3 _. [! J- ^( p9 v4 M5 D) Q        return fibonacci(n - 1) + fibonacci(n - 2)  r- ]$ Z* ^& Z9 d
    , ?' N( P% l7 Q, Z7 o* b, s# L$ Q
    # Example usage9 F8 R$ R4 ?% s! n) u# {) \% T5 A4 L
    print(fibonacci(6))  # Output: 8, n) U  t! p/ _0 k" d( Z, D: H
    % c" g0 `! P1 }6 \# G
    Tail Recursion
    5 V+ Q; V. G7 {  T& K
    7 q# m6 G. f( D$ p8 C( ^Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).3 _0 }8 A/ y3 }, L& h0 u
    5 L9 l5 o0 v# d0 b# S* N
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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