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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑   X0 |' l- Z; N  p% P2 C
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    解释的不错
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    ( r/ p% @' _/ c5 m递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。8 Q5 ~! f; g! H( L$ i

    $ M, J6 Y; t& i- x 关键要素
    ' g) H' a+ _0 \/ p) A* O7 y% B1. **基线条件(Base Case)**% u1 _5 b6 ~0 l) k
       - 递归终止的条件,防止无限循环
    1 C5 R% d. |2 N1 q$ x2 I   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1+ a, d" |) m% C' J% z

    * B4 L/ b4 _8 c2. **递归条件(Recursive Case)**3 b3 i* E3 T0 |5 p& D9 N# \7 Y7 N
       - 将原问题分解为更小的子问题
    $ R. v' ]% ^  o6 N   - 例如:n! = n × (n-1)!5 v* Z( W1 Q, ^$ J7 [' ?, J
    ; o2 {9 |/ ]2 @% p$ j$ k$ Q
    经典示例:计算阶乘
    7 C( y3 J( J+ D; O+ S& B/ N- rpython0 n+ w/ \1 }* |. a- g
    def factorial(n):7 L8 ]( n& M9 }: t
        if n == 0:        # 基线条件( d; O9 ~' E# ~8 `
            return 15 ]2 `) c! {7 {' R1 R, A5 j: V
        else:             # 递归条件
    / @/ K" X7 Y" C- q2 X# c        return n * factorial(n-1)* p; u# `% j* A" K& [; z
    执行过程(以计算 3! 为例):
    # d+ ~) s5 `2 [- o. x7 P& ifactorial(3)' u3 ~2 K. M* Y4 P' ?  W  F! v: X8 `; p
    3 * factorial(2)4 O, w: h1 S3 Y1 N
    3 * (2 * factorial(1)); ?5 F$ M( K, k. Y
    3 * (2 * (1 * factorial(0)))
    , B: g7 R, E) R7 z, R3 * (2 * (1 * 1)) = 6
    " o* U9 i" P4 `% S6 b! n1 ?* F% s; s
    递归思维要点
    , C6 _+ R( w; X( w1. **信任递归**:假设子问题已经解决,专注当前层逻辑$ d, j. p# ~) D( c6 i
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)/ t+ J; H+ D1 r* `5 R- a1 I! i, i7 Q. ~& }
    3. **递推过程**:不断向下分解问题(递)) v$ R5 _  i# a3 u$ F9 J$ I
    4. **回溯过程**:组合子问题结果返回(归)
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    / t5 |6 U2 k. B 注意事项
    7 X( ~# D4 G2 u( O* ~. i( ]& x必须要有终止条件4 d' C7 B( s# s0 ?, p. [5 C( d7 k0 `
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    . C% T/ n3 j& Q2 o6 |某些问题用递归更直观(如树遍历),但效率可能不如迭代2 A1 n5 x; _# _
    尾递归优化可以提升效率(但Python不支持)
    - g. J1 T' Z) W# z- y" }. \
    / ^( d3 F: {$ a* G! b 递归 vs 迭代
    $ A; a5 Y, P, j. S|          | 递归                          | 迭代               |- R: `( [2 x9 u: h3 y! a" F
    |----------|-----------------------------|------------------|
    5 c& X7 S3 {: r0 E| 实现方式    | 函数自调用                        | 循环结构            |  U) C4 d2 i9 @+ T1 m% _
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    9 w' i$ l$ o: C& }| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    0 k% h! N8 _) @! E9 o7 g& k! G| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    # f( p: ]' D2 Y- m8 u* J( \: @
    % ?7 G' |1 h! B# a2 \ 经典递归应用场景
    7 t" k1 O) O' P* L5 W! a4 s$ d* |$ Q1. 文件系统遍历(目录树结构)
    " V+ F: K! u9 j2 j2. 快速排序/归并排序算法# s: N/ N/ T% z0 Z3 O# y0 {8 l* d
    3. 汉诺塔问题
    0 w. o9 e7 i3 l/ O# b2 _4. 二叉树遍历(前序/中序/后序)2 X% |! y8 @6 v& ]7 t4 {  H$ j% d
    5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,7 Q6 h( _5 r! {! K3 T
    我推理机的核心算法应该是二叉树遍历的变种。1 s5 t6 ]4 _5 c, X7 |
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
      {: S4 Y. S0 w8 ^- nKey Idea of Recursion
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    8 ]' H/ w9 b4 b  YA recursive function solves a problem by:8 u4 Q5 u& J/ K0 l
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        Breaking the problem into smaller instances of the same problem.* X+ K* ^9 h6 C  d9 ?/ |
    ; o. o1 ~/ S+ l. D+ Q
        Solving the smallest instance directly (base case).5 a* s2 Z% C6 }$ F7 Z0 a. ?' l

    / p8 {* R, @3 l% {. G6 a/ N& i    Combining the results of smaller instances to solve the larger problem.
    9 w9 D" ?& g5 f4 B: V! G
    2 j7 b1 ~% J: x$ ^0 uComponents of a Recursive Function
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    & t$ w1 i+ q( w2 }. J7 E    Base Case:! G& T+ j6 B& h* q( a) I6 j) L
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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    * k3 o: v9 x9 Q7 O6 o8 W, y        It acts as the stopping condition to prevent infinite recursion.4 _* l4 Z& y3 B3 U9 L  V
    ) d/ [: T: e. r7 O. Y
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.- ]+ F/ \2 _, a! q

    , s* L1 Q9 R- C    Recursive Case:
    * I* m3 N# R( i2 F) _( b
    ; d) u0 [# H. \% a8 W, Y        This is where the function calls itself with a smaller or simpler version of the problem.2 E8 I- W  @6 z5 }

    , ^$ e, E& }" K' V* _        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1)., g/ c- K7 a% m- y

    + t( J: T8 G/ A5 F) e3 K8 ~0 q: lExample: Factorial Calculation+ K5 S3 y) d0 A

    0 N, C4 `! t" H; F( B1 f1 B! ^% mThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:' _! `! \: O( _) }/ I) A) {; M4 h

    * x  R" s4 b( k4 B% U& l    Base case: 0! = 17 \1 _8 \  r& m) f! g* q9 j
    & a5 P9 v  |1 n% _7 Q) D0 v
        Recursive case: n! = n * (n-1)!
    1 n- A+ `. }! J3 ~' B6 g$ T- v! r; k1 A6 X/ B9 C$ J
    Here’s how it looks in code (Python):
      X& Y/ ~% w6 K9 s5 {python% }( W. F6 w1 j5 C

    * i1 S. V$ p4 X4 a! y# S7 N# c) ]) I! T, G7 @2 k2 D5 i
    def factorial(n):
    ' }4 l" i* ]4 ?2 b7 U    # Base case2 a; S0 \/ E/ I, ^7 v+ d
        if n == 0:8 ~. L# x6 P) Z1 K1 u9 n0 H5 ?
            return 1
    # y( D: T4 k" l- W8 Z) B+ Y    # Recursive case0 E* c" Z' E7 m( y1 ^
        else:
    , l3 D" z& M) W6 O- m        return n * factorial(n - 1)
    2 `4 M: U8 h* [% P+ S, g5 H( l" c# K6 T
    # Example usage5 o2 |3 U4 y( g! w/ A* `
    print(factorial(5))  # Output: 120
    4 T. J: }7 b5 n/ I6 e3 T8 C$ }
    9 x3 V* s7 |! a  b; iHow Recursion Works
    6 k6 x4 h+ T8 _
    & e7 S( Y, A/ N7 K    The function keeps calling itself with smaller inputs until it reaches the base case.
    * U) ?8 I! k& u0 j: b& }' O8 x) I2 D1 N% f6 P! s0 W# J& s4 K
        Once the base case is reached, the function starts returning values back up the call stack.
    . `6 ?8 I) U# t; {3 ^! {! Y+ }9 b& C0 a7 l! p* g; g( s
        These returned values are combined to produce the final result.- k( ?$ j& r% z. j" x; o# S5 `
      V/ g/ a% k$ ?9 ^" C2 N6 j
    For factorial(5):
    ! W5 a& u+ f) [3 n+ E
    , T9 l3 J* O! ^0 |  N* V2 ?- [, l  P% U. @5 [; w9 V: N
    factorial(5) = 5 * factorial(4)
    6 t# d+ a# H# O" ^  Q5 M1 D8 {factorial(4) = 4 * factorial(3)3 \+ P1 F& x# ~' H0 t8 _" n1 W3 b; u: O
    factorial(3) = 3 * factorial(2)# R) y% u9 }# u- v3 x' ?
    factorial(2) = 2 * factorial(1)$ t6 B/ B& i. Q" z
    factorial(1) = 1 * factorial(0)
    ! M9 V: }/ Q* j7 j, g/ Z6 rfactorial(0) = 1  # Base case' O# w; Q/ V. c: Q5 o$ J  v5 |; S) I" N

    . H( K, X! c  VThen, the results are combined:
    % z9 N: z5 {4 v3 e4 `2 e: C5 N0 i1 R, \% u

    8 _7 O, j1 \' v8 X4 \" O' kfactorial(1) = 1 * 1 = 1
    - I+ h" M& y- n' V6 F6 m9 |8 ufactorial(2) = 2 * 1 = 2
    4 V& u- d; G5 @5 |. G5 @; F9 cfactorial(3) = 3 * 2 = 6/ d  w5 j, U/ U0 Q5 O2 y& q" I
    factorial(4) = 4 * 6 = 24  \7 O, _* S7 D* ?" x: j
    factorial(5) = 5 * 24 = 1204 H  W5 N8 L; a3 A

    4 b$ T5 `+ m9 Y. MAdvantages of Recursion' `; h( g+ E  v1 U! \
    ; @9 @4 C2 O: u7 d
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    7 d' J/ N. a2 \" Q/ X' W9 N) f; y$ J6 n4 q/ m- l% b
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    % ]8 D3 _% R$ c- ]
      z. Y. {7 M8 c/ \Disadvantages of Recursion0 |! C, r$ \: V* E' w. X, u
    2 A$ Q2 D4 \9 j$ m" P: X7 E
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    & U" C7 Z- d+ T* n2 p- [5 k$ j  [' e& n
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).0 x0 r' K0 N* e/ E! q1 }

    7 q- G: C! c. j8 M  c3 d1 [# s, AWhen to Use Recursion
    ' W+ ^' D: O# k- w1 `( B/ t8 _( H" X7 b( H' ^
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort)." v0 ~- {. F' x5 Q- s+ J

    * P  ^! Y4 P$ r8 f, |- E# F. M    Problems with a clear base case and recursive case.
    $ @1 {! a) F  z5 |
    . {. i4 ]0 a$ Z" NExample: Fibonacci Sequence4 _; u- C! T$ g

    + Q) }# S) ^9 b6 T' PThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    0 o3 q  L# f* e& @, o! _9 E6 W, z$ m' K8 Z
        Base case: fib(0) = 0, fib(1) = 1" G+ }" z+ x- f7 R  g

    2 k' ^: d6 Q' a9 p* f    Recursive case: fib(n) = fib(n-1) + fib(n-2)0 H* i5 W, ]; Q$ C4 H/ u; K$ E: K
    8 r2 U7 s  T3 d: \9 @" K
    python9 p! v' U! i+ r* N6 J5 r
    " @* a+ {& @1 b! G+ N% a) P
    # Y. f$ B8 h* r) y1 L$ E/ m# H, v" a
    def fibonacci(n):; v4 R- ]; E; ]0 }# J+ a
        # Base cases
      R3 M0 h7 l$ W+ Y" Q$ }    if n == 0:
    * }5 D* `) y" l3 R; p, [        return 0/ Q8 D8 h: C# C8 _
        elif n == 1:" i+ k! D: B9 N
            return 1
    6 e9 {% ]7 H$ B, b4 h    # Recursive case9 O* o+ m2 j* c% l1 Z
        else:" ?. m, h8 A" q. V, Y' M5 @7 ]
            return fibonacci(n - 1) + fibonacci(n - 2)) T# {8 E! X6 m9 F, ]* F
    : b% h1 A( W- W# d. ]
    # Example usage" }$ V. I$ L3 j8 d+ F  G: U
    print(fibonacci(6))  # Output: 8  P5 Q1 M+ d2 {6 Q% D2 l
    : d- r5 D: x' B% v
    Tail Recursion
    ' M1 t6 K4 r8 m$ A- b, x" X" Q  H2 [/ A7 S2 j8 g+ X/ k
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    : R) p+ m  J: z* i/ Z3 Z0 n; i; n3 W+ I, @0 N, V7 r
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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