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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
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    ; O8 N1 u" G! z8 O4 c- O0 [解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    8 |/ K/ e4 {6 d0 Q2 M
    . N0 Y) v- x, ^ 关键要素
    6 v2 F0 T6 x$ J; P4 E0 J. N5 Z1. **基线条件(Base Case)**
    % }! v. L/ G3 g4 T$ H2 P4 P   - 递归终止的条件,防止无限循环
    4 ], p- L7 K5 e* D7 G9 x   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    % M3 x0 o- u# ]: O  b# J+ N& u6 S6 O3 b$ V- m5 u- [  V
    2. **递归条件(Recursive Case)**
    2 |' |! k0 L; G; s  E  G   - 将原问题分解为更小的子问题1 U) u7 i2 k7 p; Q, M; r! h2 |
       - 例如:n! = n × (n-1)!
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    ! N9 d7 J6 l. Y) K& P 经典示例:计算阶乘
    * C. A6 ~7 m0 t  g+ apython
    ; S$ m0 U7 Q$ {8 idef factorial(n):, J3 H3 p8 c, V& G4 o3 U
        if n == 0:        # 基线条件
    5 |/ s' p! N( }, x: ]' u        return 1- l" I, k4 \0 s
        else:             # 递归条件  X3 [2 {# T' k' t3 v9 z# Q# P( {
            return n * factorial(n-1)
    3 O" ~6 x3 Z5 R1 S% b执行过程(以计算 3! 为例):/ R1 o1 R8 D: o/ e- k4 z) @
    factorial(3)$ v) }( L4 `, P
    3 * factorial(2)
    ; k8 Q9 s  K4 ]4 R3 * (2 * factorial(1))
    6 S7 N2 N" P9 [9 c0 e3 * (2 * (1 * factorial(0)))
    ( X; [" \+ X) X9 t" u8 e3 * (2 * (1 * 1)) = 61 ?+ |( A, `" R8 x: y

    2 E* L7 L# \  D# S' m 递归思维要点/ E+ P- Z. |, i! j  O2 ?, |* b
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    # w1 Z! u4 `* w2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    6 q1 j* P+ K6 ~9 y3 P  P3. **递推过程**:不断向下分解问题(递)- ]0 T4 Q) b4 }, M/ `
    4. **回溯过程**:组合子问题结果返回(归)% c! p/ H, t9 {" y5 g. n1 p9 x: z
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    注意事项
    2 ~5 Q! z8 d1 W& G* ]$ H+ R% q) c必须要有终止条件
    1 {0 D  w6 z. \$ u" r递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    3 e; Z" E+ C# M% D' z某些问题用递归更直观(如树遍历),但效率可能不如迭代
    7 X7 ]# Q+ n  W4 ^尾递归优化可以提升效率(但Python不支持)# E4 a& k. ~: b& ^7 l* W+ `

    * H0 n2 U) y; n$ Y# W# W, I 递归 vs 迭代! G0 ]  Z" ^9 J* W
    |          | 递归                          | 迭代               |8 J; ]+ i/ X9 o: f
    |----------|-----------------------------|------------------|6 ~( O6 B! O, a! c2 d
    | 实现方式    | 函数自调用                        | 循环结构            |, U4 O' w" J7 @9 K
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    . y) H5 i7 K$ j| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |! v! W! i) |/ O" _4 W+ o  T
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    ) w! S9 d% p/ U8 D4 b/ D" n0 ]+ z: Q
    经典递归应用场景! w& g$ U4 W  A4 ~! [
    1. 文件系统遍历(目录树结构)( h# a2 g; ?; r( k3 |! T
    2. 快速排序/归并排序算法
    5 m) n0 w. h  G" z5 y0 @3. 汉诺塔问题6 F' o' r+ F5 y2 R5 \  m( ]
    4. 二叉树遍历(前序/中序/后序)& y; m3 q2 x5 h$ n) z
    5. 生成所有可能的组合(回溯算法)4 |1 v$ U1 \8 x- w: [/ @5 J

    & z  }2 d5 ^$ J  z1 ~- I: a  r" |" `试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    : a8 ]  ?/ _% N0 v- J我推理机的核心算法应该是二叉树遍历的变种。
    1 c% H# L' h3 F- M! o# X另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    & E8 m" X5 E2 KKey Idea of Recursion
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    A recursive function solves a problem by:" o; Y9 ^3 c7 c( V6 L. p
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        Breaking the problem into smaller instances of the same problem.
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        Solving the smallest instance directly (base case).
    8 R8 ]! e  ^3 I) Z, [0 g
    1 ^2 G2 V$ L  {( k    Combining the results of smaller instances to solve the larger problem." t! s7 U5 m8 z5 G# n9 i7 h
    9 ?% @! c. W' `/ x5 i
    Components of a Recursive Function# A, i' N- ?: n1 y! ~

    * i8 v8 [9 Q* ^    Base Case:' F* g- k8 O: w+ w
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion." [! U' ?( C  v5 L1 Z
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            It acts as the stopping condition to prevent infinite recursion.
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    1 @! P5 W' u2 t9 h        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    - K, h" }7 ^+ S9 O4 W2 b: H3 h    Recursive Case:6 V7 f! n( b9 E3 ~4 W/ A
    2 c% R' Y: {7 I$ v& F
            This is where the function calls itself with a smaller or simpler version of the problem.1 F' p0 P3 k" G3 C. W2 R' X5 ]$ ^

    # L% A/ T5 K: e. @. Q: Y& h        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    5 K! a: c: s& g) i4 T4 p# O& K; @$ J) g, e9 _! r; W
    Example: Factorial Calculation
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    . p, K  a, w/ x: C6 QThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:- e$ _/ ~; b7 K4 y: S4 @
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        Base case: 0! = 1' f% }: l6 O4 L% g' d

    * W; W, B# U0 I' F    Recursive case: n! = n * (n-1)!
    0 V% V7 V. F/ A) w$ j3 J6 D. p7 k* f) a+ \# t8 h7 e: [
    Here’s how it looks in code (Python):
    4 Q4 o: ?( a6 C3 Vpython
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    9 [3 ^: C+ j8 V& M' \* ]' [/ Sdef factorial(n):) Y! N( Z7 X, r8 d4 T  Q  P
        # Base case
    $ L2 H* @! g- q; K    if n == 0:* v5 q3 n4 s) j% G5 Y! x
            return 1) I& T  E9 W1 N9 _# h2 B; S
        # Recursive case
    1 m8 _! A+ \+ w- k    else:" z; l+ `0 N* o5 _$ D5 [( O
            return n * factorial(n - 1)
    * i- Y7 Z' w, Y# q2 S7 p5 [8 T. q
    . a: O* T: w9 A8 _' G# Example usage
    # h# `$ G# v; Gprint(factorial(5))  # Output: 120
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    " w4 f- c+ I/ @7 L% i6 f) KHow Recursion Works
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    # ~5 ~7 J8 i: H  B1 j9 t    The function keeps calling itself with smaller inputs until it reaches the base case., S) A, w- n. `

    ( u  k9 b2 h: K3 b1 ^; ~7 ^    Once the base case is reached, the function starts returning values back up the call stack.
    ' _3 Y  O# j3 K0 J- A) D
    . I. Y- E  e3 P' d0 m* W4 J    These returned values are combined to produce the final result./ G, y4 O# U" J& O5 Q

    1 _* X( K7 I% K0 X7 WFor factorial(5):
    & `0 x5 X" A% S+ \4 s& V- l6 f- R) [' ]! q' C1 @/ x1 X* e2 O4 y
    ; D. x3 K" `4 |" s' E
    factorial(5) = 5 * factorial(4)- q2 n3 d$ N! {5 b' Q- ]1 S
    factorial(4) = 4 * factorial(3)
    ) C2 [" b" Q: k0 @8 E. d2 vfactorial(3) = 3 * factorial(2)
    - X; m! R9 V3 E0 nfactorial(2) = 2 * factorial(1)
    + G! D+ _9 I, Z  Ufactorial(1) = 1 * factorial(0)1 h, k/ z9 B" @
    factorial(0) = 1  # Base case
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    ' b' ^/ Y1 j  h) NThen, the results are combined:. y7 y! p" p( E. T( ]
    ' G! R( V1 e8 q" ^
    5 d' N% l1 {+ ~5 q
    factorial(1) = 1 * 1 = 1
    - S- ]+ ]6 V; Z7 B: I7 tfactorial(2) = 2 * 1 = 2
    , D) _& i/ j1 afactorial(3) = 3 * 2 = 63 Y  E$ a  o2 Z9 @! p2 M" ?
    factorial(4) = 4 * 6 = 24
    9 ~" k9 J+ W8 T4 @' [" ]# Bfactorial(5) = 5 * 24 = 120
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    0 X1 R5 b$ E. |/ L! xAdvantages of Recursion3 y6 h( \6 W/ N3 v- n5 B* L+ l$ I
    ; t% [7 {1 P+ ^& D6 Y3 t6 ^' f
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms)./ z) F$ D. Y+ |" {* }: a

    4 b, W3 Z- T; k, p/ d) R5 y7 z    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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    0 k' _5 L4 v' m# z; q- vDisadvantages of Recursion& }& D& c! j) _, N

    ) f0 O2 p- b+ g    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    ' H/ Q0 q% B$ H, D! f" Y, Q% t( z6 Y+ V' \; ~+ p; y
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).; |) [, z& z, P& n# H
    8 M$ z# J2 J- f6 n
    When to Use Recursion
    / H6 e* ?" S0 r2 A2 [- j. y
    * Y* p( |7 L# `8 F% T    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    0 r) d: G' b; G% V2 R  J9 f1 v9 F' p% P8 Z& t
        Problems with a clear base case and recursive case.
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    ! k* s9 U; [0 _# N9 Z( P! i1 @$ `Example: Fibonacci Sequence% K% \4 n; Y; K# e# s9 ?

      f7 v, S/ J4 s0 ?3 ]: WThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:: X# c  k, [  ]

    ' I6 [, N3 x1 k( t( b    Base case: fib(0) = 0, fib(1) = 1
    5 h8 w1 a. V" T5 s
    8 j% k+ `& Q; f0 h$ V2 n3 s    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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    - N# V4 t- c' _' c1 Rpython' `9 K* Y7 R1 H9 ~8 B5 e
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    8 h$ @  k7 G& G+ E1 U
    def fibonacci(n):$ o0 D' G$ c: L- x
        # Base cases
    ) {5 r* d" e  e1 L9 i3 \    if n == 0:
    ' J  W3 j+ H) R% |2 D        return 0
    0 C* O) H) c4 t1 q! p    elif n == 1:+ a( x1 @: X3 s& ~, D
            return 1. x6 I* n1 a7 {& p1 e
        # Recursive case
    - G% M8 j9 y4 c+ T8 g    else:
    5 q2 F1 X3 U5 f        return fibonacci(n - 1) + fibonacci(n - 2)8 l2 ]3 k9 u6 D* m7 t: ?' v

    " ~- R, l- Z" q  i: w3 \# Example usage
    $ ^; l1 p9 ]; L# l, Y9 _$ Lprint(fibonacci(6))  # Output: 8: r9 H& |& s" ^, |, s& F0 e

    6 R4 j  Q& {/ Y- o$ wTail Recursion+ m( r& h9 f+ M: O% e
    . W, [4 b6 G% U1 k, A5 N9 _/ ]3 f
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    0 s1 N1 x2 H  @1 W& P: r; T3 ^
    4 {; _0 l( W2 w9 S2 BIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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