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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    . O9 t0 J4 R) M5 N' ~9 x1 z# f: \8 c8 t7 f4 P. m
    解释的不错
    % T! D: f/ W! }8 T% u' Q
    3 N8 P2 H. s& n7 p递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。5 o0 r; C: i5 u5 j. [

    # U) L7 V1 E# q% j# F9 f6 g/ B 关键要素1 L! i9 p# Y2 }  W# K
    1. **基线条件(Base Case)*** V6 y2 M. ^: G! ^
       - 递归终止的条件,防止无限循环
    " D; C" U" s& c7 U* v5 E0 d: K- M   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1/ l) T7 W( @, A  x2 y/ R( P1 s

    , o5 c& ^9 P' K* d2. **递归条件(Recursive Case)**$ M( a' |* u. Y5 T; v" o8 f/ n3 T$ f
       - 将原问题分解为更小的子问题( @/ L% D! |$ }. M5 i
       - 例如:n! = n × (n-1)!- P! g5 r/ D3 p4 B7 w# N9 ?

    % \& v; q6 C& k$ z+ X0 \! V5 M 经典示例:计算阶乘
    9 T) T+ I* d7 H. y' @0 Gpython
    / @6 G# T9 t" e/ l! Kdef factorial(n):
    ; D9 |3 t2 _  T; P6 \8 e2 T    if n == 0:        # 基线条件
    5 e) ?4 o  d% y; O        return 18 ~6 u1 U* }; y2 p- P; `  \
        else:             # 递归条件4 H7 @0 Y  l; n8 W+ @- H
            return n * factorial(n-1); C8 o$ V# L% n4 l! ^' _1 d
    执行过程(以计算 3! 为例):4 ~( @0 I, j; I4 n' A
    factorial(3)
    1 q) n# m( S! F& @4 X3 * factorial(2)
    1 g5 ~- h9 A! \6 t2 u/ g3 * (2 * factorial(1))3 `7 y% m% e; ~. H7 w' ?# i
    3 * (2 * (1 * factorial(0)))& j8 Y$ g* z5 q" W
    3 * (2 * (1 * 1)) = 6
    . Z4 }# Y; ]7 R: x; G/ T# X; L2 n6 {; c9 {" I; g' V% L) P
    递归思维要点
    # x0 z1 E$ \, {% w1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    " E* m6 d7 A6 T/ v% T0 x2 L2. **栈结构**:每次调用都会创建新的栈帧(内存空间). j" q* q! z% f# t
    3. **递推过程**:不断向下分解问题(递)/ G: f; h, B; W' t* o% C
    4. **回溯过程**:组合子问题结果返回(归)5 g9 \; P  z( f  ^" D; z
    ' {0 _/ L1 y, F
    注意事项6 J$ A, w: u. \- d
    必须要有终止条件
    2 y; J- {. Q* u- Y# G递归深度过大可能导致栈溢出(Python默认递归深度约1000层)) q! A: r- |. `4 B* {* q
    某些问题用递归更直观(如树遍历),但效率可能不如迭代9 y2 Y* U" f% M" W- c
    尾递归优化可以提升效率(但Python不支持). j, j3 _, H, v9 v7 D
    ) Q. @0 _+ P1 n4 c
    递归 vs 迭代: u7 @- b& V0 u- Z
    |          | 递归                          | 迭代               |
      L; [! i" }* s: l. v$ a4 T& [0 {& T|----------|-----------------------------|------------------|# ~% {/ \; i1 b& }  C( B: E8 O; X4 V
    | 实现方式    | 函数自调用                        | 循环结构            |: g- J6 M+ Q/ f4 f+ N
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |/ A" J$ A+ o9 ?! y7 p
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |0 w! B9 Q: ^- A: v
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |+ W# q8 i; S% R" q

    4 Y( J8 f% i0 C 经典递归应用场景: X( v; q* L1 v0 w7 u
    1. 文件系统遍历(目录树结构)
    . m$ [7 P) V& q' t- m1 H% |: F4 j2. 快速排序/归并排序算法5 q0 h# x2 p( t9 r1 L1 K1 F+ H
    3. 汉诺塔问题4 w& C; l( }3 C# Z3 D( J* H
    4. 二叉树遍历(前序/中序/后序)( a* ~2 l4 V: E6 n
    5. 生成所有可能的组合(回溯算法)# ?* Z% q. v% o& c) t" r5 L: W

      V3 \8 F5 ]( u  G+ A* W7 m试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,, x/ L7 O2 R+ N8 c
    我推理机的核心算法应该是二叉树遍历的变种。
    # O4 M0 [: p! r# l1 k! P' z另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    6 c5 H. o2 Z2 h% p- }% r- }Key Idea of Recursion% I8 b7 w6 d5 P  p% H1 `
    9 O' _- ?) i9 ~6 U4 o" Y
    A recursive function solves a problem by:. |) }: P; O5 x3 J# @5 O

    $ ~) }1 t0 F+ P    Breaking the problem into smaller instances of the same problem.
    ( q2 H2 p: Z" B! @
    7 ?. A/ x5 y$ E/ `5 o0 }8 n( V    Solving the smallest instance directly (base case).
    6 `: H+ Q0 C4 _/ d  Y% \, K0 s& V  j2 r; U2 S5 \6 a
        Combining the results of smaller instances to solve the larger problem.
    5 ]3 E" }3 k- F) }: N$ L
    ) y. |* s) R, }$ ]: ~1 IComponents of a Recursive Function
    ) {' {$ D3 j8 J! F: q- D/ F- L) O! S3 m+ x1 c! T( h- Z
        Base Case:
      m/ W0 _6 E4 f; ]
    * y. L0 l; V4 f9 {- u" z        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.; d- H/ ~, m) q% v' r$ V7 K

    ) B! X; a' E0 q8 j4 i        It acts as the stopping condition to prevent infinite recursion." h3 s1 }9 T' X  T7 X8 N/ n, A$ M

    % {' V/ a  K  t% X        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    8 B. C3 c' Y. i0 n4 L9 ^) a; Z3 N3 n6 z$ F& W& t* p0 J: o# U
        Recursive Case:6 t9 P: n: @# r2 Y2 `5 U! S

      Z9 n/ s) I  ^/ \& m% t( w        This is where the function calls itself with a smaller or simpler version of the problem./ x  C& u0 P# F# C
    & p4 }5 m3 E4 _, J- \
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).5 k# t- u/ {" M( r# A
    ! X( C$ D  d9 o' y" W
    Example: Factorial Calculation+ {) i/ e) `8 a7 x
    ( F5 j7 l% |' f  H
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    1 t( n* w1 I' D1 @! s% y. U& d' \
    0 u$ ~* \( B& \6 a    Base case: 0! = 1' C# u# |; I8 U% S, v' r) X
    + g! b% \1 y0 F/ r+ A$ l( |
        Recursive case: n! = n * (n-1)!
    ' f4 E* `2 }7 v0 n  k$ E. Z. [3 `) t- `  u2 j" m
    Here’s how it looks in code (Python):4 e; W, L- }$ n8 y  E
    python
    ( z  U9 j' t/ Q1 I& t# b( ?) n; h6 \

    ( N+ ?& T# y. G; ~% edef factorial(n):" ?  o2 s1 ~" x# @# _& Q. a; ^# l
        # Base case9 e7 R3 ]; B! G- h+ ~+ C
        if n == 0:
    5 N* \8 s- l2 @- p2 C: T        return 1/ j  r0 s4 |) @/ l6 I. g3 j6 y
        # Recursive case
    7 U3 Q( D& M' X' C' r' d4 w7 b    else:! {2 F7 R# \+ i
            return n * factorial(n - 1)
    * W2 m! ~' @6 s* u
    - r: f; k" o/ k* f9 _# Example usage6 z3 \" w% ~& F7 _* x- M
    print(factorial(5))  # Output: 120: [  k0 L4 i8 r2 I- v9 V

    & j  I- z9 r- z% Q5 F! G" uHow Recursion Works
    / w. T5 q9 l1 X" L( O% `1 e2 g. p7 o1 j: x
        The function keeps calling itself with smaller inputs until it reaches the base case.
    ( l2 B' n) L  [% ~; |8 D; \
    0 G! J1 ~: C; `" t% d    Once the base case is reached, the function starts returning values back up the call stack.. k6 d0 _' x" P" Z1 J) m, o0 a. c
    ) z& ~) [" y; E0 [
        These returned values are combined to produce the final result.
    + V! ?8 f- r/ X! i
    * F9 l* O( l9 K) MFor factorial(5):! k- f, I! L; k' p" H

    * ^/ W+ T2 u* N1 a
    3 j+ f7 D' ?$ P4 y, l4 ?1 {; @factorial(5) = 5 * factorial(4)) k$ A4 I- i: Y
    factorial(4) = 4 * factorial(3)8 M8 z# K8 C6 m1 V
    factorial(3) = 3 * factorial(2); J) R* I7 F; f
    factorial(2) = 2 * factorial(1)
    ! R  h9 ]& V- b" }factorial(1) = 1 * factorial(0)
      ~  J! S9 D# p3 F3 R9 x1 P1 Cfactorial(0) = 1  # Base case
    6 g: V- f3 s% l5 }
    : V, t  r! B' T2 Z6 X0 ~$ M+ I" _Then, the results are combined:
    6 P, W$ _5 k- z5 j) G7 D
    6 [( l' {9 C. j/ B
    ( y% H0 L% A' F' n; `- }- t; J2 [factorial(1) = 1 * 1 = 1* \0 g# D# p) z
    factorial(2) = 2 * 1 = 2
    : L7 {2 N- K; _" V; G/ K6 j: a$ \factorial(3) = 3 * 2 = 6+ t. z# r- j& |/ `7 \2 S  M
    factorial(4) = 4 * 6 = 24
    2 A7 o5 A7 m1 vfactorial(5) = 5 * 24 = 120" Q  J  x+ g) }& X. C0 n8 Y

    3 W8 x0 T" \$ D2 K% z' N! WAdvantages of Recursion
    8 o/ J5 q3 ~. G3 b( p  T. t; b6 u3 J7 W# ?5 V3 |
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).8 f$ E. }. O# H6 U: v7 m- _

    % f2 p* X7 G5 s1 h: w$ Y2 s& p' i0 B    Readability: Recursive code can be more readable and concise compared to iterative solutions.. J- U7 F& Q4 E% f

    9 l  P/ {9 b5 p$ F. hDisadvantages of Recursion
    , {) A; k" G, A; N7 ^; f6 s
    ; ]# W0 g  |9 b+ O7 b4 e& l& w    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.% {( q3 s9 y7 y, v9 L9 ^% s  E

    . S' Y9 y3 h6 J! e  m, h+ t    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).- H! G% t4 X  t1 M, y" m. z0 M

      h! g, h/ X) v7 {When to Use Recursion
    1 w$ g) T* k/ E5 I. m
    . R! H' d; T) i    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).  ^9 l9 Q$ Y6 d$ ~3 t1 B5 z
    5 H( {7 Y2 w5 Z5 u2 o! A$ g
        Problems with a clear base case and recursive case.
    0 i- i( Y* `2 w1 @4 |; \% ~+ h
    2 \! {/ d. w7 o5 W& JExample: Fibonacci Sequence' C% t4 Y0 _+ s1 R0 U4 m; M6 a

    ' U& O  N  L4 b# A/ L+ aThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:) F: ^' Z; L/ A+ K+ R
    / A1 [' S& V# U7 h# w
        Base case: fib(0) = 0, fib(1) = 1
    0 \+ x3 q/ k" z2 v; _' |! P1 m( c' R5 \0 c4 c9 v: F% o
        Recursive case: fib(n) = fib(n-1) + fib(n-2)  V1 W- Q6 ^3 P6 V6 o

    , v9 u" L! R0 T1 l1 Rpython
    # {, t' F, K3 T2 u4 m/ G+ E' J0 z% \0 x: n. P
    8 F" v' ~8 y$ h/ d
    def fibonacci(n):7 ?( S, [+ C, V+ M
        # Base cases9 v5 G7 o! n8 W
        if n == 0:) ]- [9 O3 a% B; Z" f: j: ^( X
            return 0
    % T4 _% D/ ?0 P    elif n == 1:# h1 j# S* F9 B* Q
            return 1
    8 i/ }0 q1 s& Y4 O. V# W    # Recursive case& `7 k) D: X- c! R
        else:+ Y  E. o, n. I* [
            return fibonacci(n - 1) + fibonacci(n - 2)$ r/ [9 {8 G; w" c

    % L8 c, p: t* q( z, x* \; h, A# C# Example usage: e+ m- e& }2 \
    print(fibonacci(6))  # Output: 8& t/ ]. i! f; Z3 v7 _
    9 Q5 B, X* R9 b* q
    Tail Recursion
    . o' ^4 `/ A5 L' e/ ]8 r: C* ?
    " M. W& G( o& t( v& d! ?: STail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).! R  `0 M9 k8 ]$ }! x0 I6 V
    6 l( q5 E8 O0 q3 W' s
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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