设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2283|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 * p3 c  z- k+ g9 E( Y) V% e! Z

    6 ]8 D& r8 J3 l/ K5 L! j7 c3 @解释的不错
    . f) k2 N! u% @! J
    7 I$ I$ y) i% Q) A) J递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    # y+ D9 `7 B- G' ~7 f5 R4 L2 ]2 T" ]" z8 H* ~, P
    关键要素1 R- @' N+ q5 L
    1. **基线条件(Base Case)**5 a. w8 g7 E5 l
       - 递归终止的条件,防止无限循环
    . s  O7 P- `( [' v/ [( [   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    7 a& B0 z" V) B# V# a! f
    . u  p8 {2 w2 @/ N" V0 g2. **递归条件(Recursive Case)**
    # J2 ]" i2 `1 C1 \  s   - 将原问题分解为更小的子问题
    + j+ c# H4 _0 K   - 例如:n! = n × (n-1)!5 Q2 G% U, r6 @0 `2 i

    / l: ^- ^5 M5 p0 N 经典示例:计算阶乘; f" c6 a) n; q
    python
    . k. q4 g( t2 gdef factorial(n):
    : j* [& o# F  C% ^* _    if n == 0:        # 基线条件1 H3 i- y6 j1 G6 U8 D! P$ u
            return 1
    2 u' T& j9 x$ y% C3 [2 z+ V    else:             # 递归条件- V0 {8 ~0 ]0 h" `
            return n * factorial(n-1)
    : T3 C% X8 I  L# }8 Z# I执行过程(以计算 3! 为例):
    6 \2 F, f- }4 u3 \factorial(3)
    / t6 O" n4 r9 @3 * factorial(2)* ?6 J+ ^9 ~2 u8 H. Y- }" m7 M
    3 * (2 * factorial(1))% w) r- |$ t# J) E. w0 }" A
    3 * (2 * (1 * factorial(0)))
    ! q& P: R% V+ y3 * (2 * (1 * 1)) = 6+ `5 O$ {4 [& h/ @, ]  {
      x, t; n" _7 \; N- q* f0 j7 t' u
    递归思维要点! J+ R) f1 B5 t) j) Y$ U! L4 t- _
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑. m/ m: d* {( H
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)6 Y6 ?  X0 d& ]9 A+ S+ c
    3. **递推过程**:不断向下分解问题(递)
    - E3 E& L  p* c4. **回溯过程**:组合子问题结果返回(归)4 |, L9 ~- u9 m- ~

    3 [8 ^3 M4 M9 D# i4 H3 C 注意事项* v! H2 B" i: ]5 o3 s; l
    必须要有终止条件3 d) o7 X0 o6 t; P4 U  c  B
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层). Q' a! I7 @0 n6 ~) e
    某些问题用递归更直观(如树遍历),但效率可能不如迭代% F+ `" Z( a7 O7 E
    尾递归优化可以提升效率(但Python不支持)" X0 l7 I* e9 S% ~! I

    0 W9 V' g  |8 J4 A 递归 vs 迭代1 M/ e+ \$ B$ g7 ?
    |          | 递归                          | 迭代               |
    : M& \6 m% e( z5 a6 B/ ^|----------|-----------------------------|------------------|3 e1 U6 n3 j) q4 M9 Z" Y, V, j; B
    | 实现方式    | 函数自调用                        | 循环结构            |
    3 O! a5 G& T) ~9 k| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
      ^# i/ t& g6 ^0 B9 h| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    4 A6 x" a2 V/ z+ M: X6 {3 n| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    2 j& h3 |; }6 Q. b3 \( w6 ~0 H- d5 `! J4 f' z4 x5 a
    经典递归应用场景
    ( _# S: W! Z9 O5 S4 b1. 文件系统遍历(目录树结构); R. i, d; \2 D& A1 [( n- d, N
    2. 快速排序/归并排序算法4 }3 `- T2 M" i" ]6 ~2 p
    3. 汉诺塔问题
    " ~4 }1 @% f" Q9 ~, y3 R$ q4. 二叉树遍历(前序/中序/后序)
    / C2 \+ w; K/ h8 z! u5. 生成所有可能的组合(回溯算法)
    ) o9 e( A. g" L+ ?% x5 Y5 _5 n: X1 U9 O; g* q
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情

    7 小时前
  • 签到天数: 3202 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    ! z" _: W5 I7 l! p我推理机的核心算法应该是二叉树遍历的变种。
    5 v! R9 E  k; Y" m另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
    9 X; g5 a' x- a7 ?$ m- v6 SKey Idea of Recursion
    ; Q; ~- X% t( p* @* A
    8 [+ i) _' f. D* p6 LA recursive function solves a problem by:8 v5 J) y9 J0 b$ p7 i
    , ]! A  }# [: T& q
        Breaking the problem into smaller instances of the same problem.2 ]8 p* W* R# P+ C

    / T; p4 S/ ?. a. \& U9 Z" v7 `, \    Solving the smallest instance directly (base case).
    / f0 }+ v" L8 x: {7 P
    $ c! k5 I' m# Y! v# H/ W8 u    Combining the results of smaller instances to solve the larger problem.
    0 r# y1 }3 U, n
    ) W1 V# f0 x% V7 v6 l9 bComponents of a Recursive Function
    / E2 V+ d4 v! M4 z/ E/ L, |$ v& o( ~% `1 T, h2 w8 d0 w
        Base Case:
    / I7 ]+ _5 G$ `
    : F% J1 q% u4 T$ f        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.0 V1 S2 `# Q, T- i& k2 ?
    . k/ v9 X! o  \9 @9 D; S8 y
            It acts as the stopping condition to prevent infinite recursion.
    ; G$ |- B; P$ e! D% n
    : @+ d, t# K; |        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.6 }9 c; \  m+ M

    - M1 r; @: M, K/ ^  n    Recursive Case:
    7 u' Q6 g7 `5 e7 ~# P
    3 V6 g! n# \6 x2 o        This is where the function calls itself with a smaller or simpler version of the problem.8 P1 C( i) ]- c+ H& x
      z+ T2 {( X* L) l) t
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    4 Z  t8 @5 X# s
    , h9 e1 H1 m2 U: SExample: Factorial Calculation
    6 }( k" }7 J8 [  f' D0 {2 |+ }
    4 h5 k! q1 A- T* S' Y6 IThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    ! l* a% g) z. @" x' ?& i& @: S9 }2 _- j# }  o0 n
        Base case: 0! = 1
    2 t8 J3 [- e8 k* f* y$ K8 L9 P0 i
    + F# |. s6 }+ m    Recursive case: n! = n * (n-1)!0 ?9 Y# h. S2 s& w1 N
    2 u+ h! d. s! ?
    Here’s how it looks in code (Python):+ W1 a8 S" f1 I+ I$ }) C+ L: i
    python6 W% Z# I2 r! I4 A" x' _  a

    ' N; p2 f! h- r4 y8 w5 }5 o, E
    def factorial(n):) L) ~" l5 d7 T. l
        # Base case' F8 s) o+ Z1 f2 s6 ^8 Z! m2 a2 O6 c
        if n == 0:; T- o$ T3 ~/ E* P
            return 1
    . P" J/ Z0 Y% t2 g6 X    # Recursive case
    ! x% }( p* N5 S    else:
    6 v; u  v# {! ^* z; \" N+ X3 z        return n * factorial(n - 1)
    8 L) d) `5 M3 H2 Q% F. S* i* E' K0 B- _
    # Example usage) t' K3 ]. u# o& ^3 m  d  Y/ n
    print(factorial(5))  # Output: 120
    2 [# {7 d! m4 F% v" W/ q: y: c0 _; E  ]. P
    How Recursion Works  `/ s1 P+ ^* }4 V/ h$ w( d

      l; [6 _- q# _/ \- _2 `& D    The function keeps calling itself with smaller inputs until it reaches the base case.
    ; R: S8 W' y9 U5 @8 I) f# W6 w- W  T: P! z3 f& ~" a
        Once the base case is reached, the function starts returning values back up the call stack.$ S$ a! Q* X; R0 J' Z; u

    8 Q% t" b* B9 l1 ?* E% Q    These returned values are combined to produce the final result.. B( ?: Q4 A2 [4 e3 T9 ]0 u

    2 |9 Y1 t/ N% YFor factorial(5):
    # W' c1 d$ x# O7 u& O' t1 [
    : t) j6 _  {+ H* A5 ]# d/ f9 u2 U( B- o% F6 i
    factorial(5) = 5 * factorial(4)" J8 w; E1 Y7 I6 ?- ^
    factorial(4) = 4 * factorial(3)2 ^0 `" {( l% n4 b' L" u% o
    factorial(3) = 3 * factorial(2)! u5 M( a' V, a, g' T4 M/ L9 f; n
    factorial(2) = 2 * factorial(1); y9 l+ E2 v, u8 {2 j
    factorial(1) = 1 * factorial(0)
    + ?$ G0 Z& L8 f' ?$ g9 N) ]factorial(0) = 1  # Base case9 D% Y. j1 z4 Q7 Z

    : f. Z) G/ W* h7 h( FThen, the results are combined:: d2 I) E* G: _1 V. Y6 F8 T4 M

    6 x2 V1 w% x( h5 S0 ?) P5 `5 l7 e
    factorial(1) = 1 * 1 = 1, O9 n: e& K$ C( h- P+ j
    factorial(2) = 2 * 1 = 25 l& ?1 S! K) `$ h5 b# m$ o
    factorial(3) = 3 * 2 = 6
    . A( h0 M0 }. k: {( j9 Q7 ffactorial(4) = 4 * 6 = 242 Z) K$ Y5 A8 h! Y& d8 Q
    factorial(5) = 5 * 24 = 120
    % S3 I. ^( b- H! ~/ K: E! ?% G% Z2 S6 B8 c2 q% Y8 @4 T
    Advantages of Recursion
    ! M. H7 Y, g9 b- G# L
    $ w+ b& w# f1 z! ^6 x; g    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).% a: @( u- F; O, L+ y

    0 z7 f5 L; k" m; v6 V    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    ; p& d+ H/ V6 a& `* t' E- E* }( `1 |7 O$ s2 {! Y" s* C4 s
    Disadvantages of Recursion
    7 t5 \9 @$ G3 _* r6 R/ k) k  q0 u8 m2 `. C6 }* b: g
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion./ q$ ^+ J2 W$ |$ G
    1 V: L; D% J" b) E
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).: L$ m2 H- ?  C2 o# y+ I
    + f' X( }  M8 m2 t  d
    When to Use Recursion& K( x" [+ ?$ ]9 e; V+ C

    6 Y5 J5 P( e; Z& F  z. d1 c    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ; F! j: h) u8 d" R: J
    3 G# |2 `0 K$ u% q2 g5 Q! M% Y5 f    Problems with a clear base case and recursive case.$ n4 e1 o# F4 ]/ R5 C7 j
    + Q  G- b. A4 |$ B) \) h5 V
    Example: Fibonacci Sequence* {6 S0 N3 r. P$ F! m8 O' {
    4 l5 {+ w5 }' k: a$ N; ]
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:) M$ F) R" _! J' [$ U9 S. w
    . n' y5 U  G# K* P2 `& V
        Base case: fib(0) = 0, fib(1) = 1
    1 }2 @: W, z0 ?5 Z( {7 }" @% u
    - x. \# D2 ]- E1 E    Recursive case: fib(n) = fib(n-1) + fib(n-2)& l$ o$ t- u5 u' S7 ]0 V1 d

    $ f' _5 A( C. `" [python
    1 P4 B* m$ e3 U2 [. H- S9 Q
    . J0 s4 A2 u4 S+ T6 P; r0 e$ U! V6 Y$ }
    def fibonacci(n):  S) X1 |; C/ g; ]0 U
        # Base cases) E2 ^- \9 X6 l/ \/ j: Z
        if n == 0:
    ( p" I! T+ n) ]$ x; J        return 0
    2 Z' S5 u/ e# M2 x9 q! @* q" y2 K" P& G    elif n == 1:' M9 J( Y3 C/ k, D" `
            return 1! D6 \4 w& F, H0 u  Z
        # Recursive case
    1 J$ D" Z# A! ^5 C    else:* V4 c( W9 ~' T  v& h, B
            return fibonacci(n - 1) + fibonacci(n - 2)7 e0 y2 z4 T: i" t* j2 r

    ) _4 k5 u8 l  v  _1 L1 s! a- C# Example usage- f0 L3 n. b+ ?4 V7 \+ B
    print(fibonacci(6))  # Output: 8( _3 _# k( h" {2 q2 o& |

    - F0 K  _* e! `+ V1 \" {3 `Tail Recursion
      M& G& t7 `+ Z; h6 u
    6 z3 T, E# P9 M0 Q1 I# f0 w. O# I% oTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion)." `9 \( @3 ~2 B2 |1 F7 o7 ^) |1 a! p

    6 K! v% ^9 X9 t. h- vIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-3-15 14:29 , Processed in 0.063526 second(s), 19 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表