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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    0 N0 E7 C9 `7 b: P1 _  \# [# d9 C% F2 M7 `$ v
    解释的不错
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    ; J' Y& K7 v5 O/ @' [" {递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。. l! j8 W. R# j" U% _4 Q

    4 M# }$ Z9 F" p9 g1 v8 ?: P8 L 关键要素
    9 m7 c2 {  @; T9 a8 g; _1. **基线条件(Base Case)**: x, Z- v- v  x2 [. e% I
       - 递归终止的条件,防止无限循环  q: _8 G- m- ~. o  }
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1/ w/ v) [' r( [# f

    ) b* ~: f! ~8 H. l% L7 w  h, a' D2. **递归条件(Recursive Case)**
    3 {0 x  _, Z7 L7 \0 b; d   - 将原问题分解为更小的子问题- o: W- Z8 C- v7 |
       - 例如:n! = n × (n-1)!
    $ Q% T; L$ A2 F! o1 [, P3 S8 }. Q
    $ j/ l4 X$ Q# @; G8 f  m 经典示例:计算阶乘) {$ f* w! D0 a# K" M$ `  J
    python
    7 V1 k" z7 Z0 bdef factorial(n):
    & ?- ~8 R, v3 f, V    if n == 0:        # 基线条件
    * N1 _) K1 n4 v1 Y5 J  l5 R& c# y$ ?$ M        return 1+ w1 B! z( r. R
        else:             # 递归条件
    7 ~9 T% Y+ I; m  M        return n * factorial(n-1)  y5 C4 }8 a% L; M. z
    执行过程(以计算 3! 为例):9 ~$ f3 s; \  F& w
    factorial(3)
    ) d! z! `, I+ g2 j0 A3 * factorial(2)
    4 p" r: Z7 e7 O6 p& A) {3 * (2 * factorial(1))3 ]- \' X, I/ G1 l  v# ^
    3 * (2 * (1 * factorial(0)))! l# v7 H: _+ u) p$ z0 d& e9 D
    3 * (2 * (1 * 1)) = 6. r) e3 s, @" D3 H

    # U1 K. T% f$ w6 b" _) e 递归思维要点6 J9 u# @/ v" ~) D4 S) x$ E6 x  t2 Q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    ! L0 Z# c) y/ z6 \. r5 W0 |% d2. **栈结构**:每次调用都会创建新的栈帧(内存空间)& O, \1 A% x4 P. q, N, r( N
    3. **递推过程**:不断向下分解问题(递)8 B* g/ h7 p* c5 H+ c
    4. **回溯过程**:组合子问题结果返回(归)
    9 J( c1 |, t$ k, N7 U2 p: X
    * D+ i8 w  S. ] 注意事项
    , e/ d: |% ]. [! D; r+ t5 l) I必须要有终止条件
    & s. d  |+ R8 x' k/ Y递归深度过大可能导致栈溢出(Python默认递归深度约1000层)( G$ z9 N6 K9 B2 h! o
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ( {  m# _6 |  r& E, m尾递归优化可以提升效率(但Python不支持)
    / z- F9 j2 ]) k
    - H5 ~+ S/ V! p* A8 ^; `7 Q 递归 vs 迭代
    - E: o( o0 h+ t) g2 G|          | 递归                          | 迭代               |7 b$ s( O2 s, J
    |----------|-----------------------------|------------------|( s7 L: y* ^5 m6 c9 a! ~4 E: B; G
    | 实现方式    | 函数自调用                        | 循环结构            |8 v0 K/ q* `7 v- l2 _% O
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |" I' T" z4 J8 I3 b9 ]) N8 v) v2 @
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    4 C! A; o; A/ u5 @| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    $ k) s# j/ S4 X4 M- X7 W8 m
    1 `7 O  h2 B1 w. i4 [ 经典递归应用场景4 I# {: T; N" ?* x( W' O
    1. 文件系统遍历(目录树结构)
    , N! F3 }* ^5 F. W- [2. 快速排序/归并排序算法
      K- l5 X. T7 V2 f3. 汉诺塔问题( a4 [/ u! m5 D, a2 S
    4. 二叉树遍历(前序/中序/后序)
    4 d$ v. S- [* ?# ~, N# V! n0 W( T5 ?5. 生成所有可能的组合(回溯算法)" _: N8 l* W9 j! c- V

    - `+ G. L3 T$ X" F$ |- W+ l试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    5 小时前
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    2 D1 A8 m+ K7 k1 d! @1 ]* {我推理机的核心算法应该是二叉树遍历的变种。5 k" S' Y9 _+ Z' R4 k8 h3 I# l
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:) `- @6 p' W( Q) U
    Key Idea of Recursion! d" p. s1 i( x+ D
    , T& j. ^5 \8 G+ |; w
    A recursive function solves a problem by:
    # J, v% H8 f2 f7 H1 u
    : g: X5 i- I9 q" X    Breaking the problem into smaller instances of the same problem.5 k- g2 G1 z8 ~6 e' s/ _& R

    6 s5 N' U, F$ C# k* O4 ?' i% t2 u# r    Solving the smallest instance directly (base case).
      x/ m) i" o( [* M
    ; @! K$ r7 d% Q8 t/ E0 H" H    Combining the results of smaller instances to solve the larger problem.
    3 Q! P0 K" h5 T7 T) s4 ^, J: B* t& ]5 @9 n1 v
    Components of a Recursive Function
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        Base Case:8 a2 X6 {( C' X- N# g; V/ V' f

    - m  J/ P4 F& m        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    * D/ X3 z7 F4 C% N+ {
    " W0 h. C& p( `  \) u0 i2 @        It acts as the stopping condition to prevent infinite recursion.3 ^4 z9 f8 o# h

    / I3 N% m, Q$ z% a        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    9 P) B0 W$ x( l9 ^: U7 S: U: w; n% j9 K( ]0 v9 s
        Recursive Case:: G) G8 r% @( K* V1 W! t
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            This is where the function calls itself with a smaller or simpler version of the problem.
      E' E- Q& V6 z* J: t. x, P. R' n5 J! R9 Z$ s! W& X0 d
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    : x) d7 i* x; ]/ o1 ^: |6 v/ S" x. u, }, \
    Example: Factorial Calculation
    4 J; A2 g- e# m$ P4 {6 \& X, d  _: _/ L, T$ f1 ]; Q
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:8 X: n3 q8 A! m) w+ d

    : W1 H5 X% K; p/ k9 S! U    Base case: 0! = 17 T$ N/ ]. n) _% x' s: z' c
    . v( O' @) c0 `7 t; o% r- j
        Recursive case: n! = n * (n-1)!
    7 h7 \4 Z+ z: R
    : {3 z7 E- H1 i4 E4 _% w" YHere’s how it looks in code (Python):. w3 {2 n' b) _: A/ V
    python- U/ \' @( I0 b8 K6 x
    6 T; U4 {% f: w+ R
    ; F2 ]9 n$ r! g2 \' v
    def factorial(n):: J* L4 u+ X  k* t5 H, a
        # Base case
    / x$ O0 l* R9 K; i' X. w    if n == 0:" T" [5 q- I( s5 y3 S
            return 1( \3 V( f* S& a0 s! n* g
        # Recursive case
    ( ]. M, Y2 p. I$ C: D) y- l    else:. @8 C, Q4 E8 |) c. u2 h
            return n * factorial(n - 1)
    6 I$ |- ~" E% _6 a- a  g: q
      [" Y) B$ m5 I# R# F# Example usage0 ?5 Q5 Y+ U, U
    print(factorial(5))  # Output: 120
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    How Recursion Works7 {, L' F+ [) V  c) ^2 R
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        The function keeps calling itself with smaller inputs until it reaches the base case." T1 J0 T* \" c6 q# S( D/ i
    9 p+ G9 |2 b- c
        Once the base case is reached, the function starts returning values back up the call stack.. x3 I* j" m/ ?0 o4 u/ G! V6 U

    / [! k* b. c6 {) o( d    These returned values are combined to produce the final result.! a7 M* X/ N) V* F# A

    ' r5 d9 d# K3 {5 B$ SFor factorial(5):
    ; p+ G2 N2 x) Y3 f% H) x6 T5 [4 I; M
    & a3 X2 h; K$ I6 Q
    factorial(5) = 5 * factorial(4)
    . E5 c$ D! X) V+ O" e8 ufactorial(4) = 4 * factorial(3)
    ; v8 b$ e9 D# Kfactorial(3) = 3 * factorial(2)
    8 P4 v  I1 u+ s, h( s5 \/ O# E! H& Sfactorial(2) = 2 * factorial(1)( c) d7 _: e4 Q# \, F0 U' ]8 J
    factorial(1) = 1 * factorial(0)
    ( b6 l2 `) f/ r, |factorial(0) = 1  # Base case* F4 f6 r7 O0 f
    5 U. d5 Q% E1 j8 m7 d4 u: z
    Then, the results are combined:* ^, Q. J* d( a# J( w5 m0 S1 q7 u+ o
    9 B( g5 H' n5 O) p! }
    $ i$ J9 u& ~2 p: v; Z9 O- m$ ]
    factorial(1) = 1 * 1 = 15 ~! _" w4 i4 E1 G9 |6 S
    factorial(2) = 2 * 1 = 2% ?8 R& o; `. R' f: }7 k4 L
    factorial(3) = 3 * 2 = 60 y: c/ b4 x8 p; c9 G  Y" w9 `' M
    factorial(4) = 4 * 6 = 24
    1 y3 X' ^2 B7 h$ O0 m, @* L& mfactorial(5) = 5 * 24 = 120
    : I- M$ h4 ]: w; V
    % v8 ^; h$ O. _2 K6 x7 |7 |9 _' yAdvantages of Recursion; x8 W+ l8 v# G+ Q' X) q* F

    3 Q- x# H% F0 @" J  O0 Q- X    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    2 A0 d* c- T- L" S( {% R" _4 E5 W& P7 d4 d2 v4 c
        Readability: Recursive code can be more readable and concise compared to iterative solutions.5 l5 [$ W, ]) e5 s# @% k9 F

      n! a2 a1 n+ D6 f! qDisadvantages of Recursion9 n1 ]* O) v" y, u9 }

    $ v: K0 R* v0 w( X! X    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.% {2 B, v1 Y. ~4 Z

    8 N- Q& u/ @' E0 J  r    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).: T6 c% R0 [+ A& `+ m
    6 ^$ R  ~6 X' t3 `
    When to Use Recursion
    ( O1 Z+ x3 T  v% Y1 f  _* f' S* G; P& h! ]
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    4 W- ]# X  U) X( m, C8 }: p+ F& O# ^. _. d7 u
        Problems with a clear base case and recursive case.7 d$ {$ X* P* g$ F8 M
    . T9 ~4 q$ F4 q
    Example: Fibonacci Sequence9 A6 h( [) Y# F1 S

    & G% f& K0 u5 l* ]- D2 Z# ?The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:3 h: B: |) {/ k& d# d: S3 }4 \

    / |+ n8 G  f& c, M    Base case: fib(0) = 0, fib(1) = 1
    + A' q0 j3 ]5 F3 q. N# A. y% H+ o0 R2 y. C( x0 W
        Recursive case: fib(n) = fib(n-1) + fib(n-2)8 d! v# {3 h7 S5 _- ^1 v7 T

    % ~( H+ O5 N7 H; j) Fpython1 C1 ?& ^5 \  b+ [
    ( W& a1 @0 ~- q- P, n, z

    - }% K2 y/ x% T1 ]def fibonacci(n):
    - o; m; r' h4 I! X: E# d    # Base cases- m7 {$ l, N: p4 _# j
        if n == 0:$ Y/ \( M+ h9 H, y1 v. |" |7 m
            return 0
    2 r' q; s* O' H! v! L% D    elif n == 1:8 l2 L" ]! C/ ~2 R- Z
            return 1
    * Q6 _+ O& b1 K* U: H& W    # Recursive case& V: S9 |4 q. ?% \! }
        else:, [9 v" Z! \' D0 i9 f
            return fibonacci(n - 1) + fibonacci(n - 2)$ K: V& l; n, l  R& q# \
    6 T6 E3 ?) F: }! m3 o
    # Example usage+ e% ]" E% t& X6 b8 j
    print(fibonacci(6))  # Output: 8# T' ]+ p# B7 m. I
    1 X; l; a: k0 h+ C) u
    Tail Recursion
    & e; v& P) o, r* e
    / J' x4 B, r  Y) ITail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    " k, O/ A5 I. Q; Z6 `5 T( C7 X# R0 B
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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