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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 , i, ]2 {& V1 ~+ o+ B
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    解释的不错
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    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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    4 S5 ]) Y, }: ^) u( M4 z' Q4 r3 w 关键要素( M% p) v# E# Z
    1. **基线条件(Base Case)**
    ( `% |4 c) G. c5 X& `% ~   - 递归终止的条件,防止无限循环
    $ c' f; _" F& |, ]% l8 y8 ~   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    : U8 B5 F  b1 A2 h: H) F/ z5 ^# U! Q; o$ l6 b3 W
    2. **递归条件(Recursive Case)**9 w8 r7 w$ C& l1 G4 P! t9 [6 F3 v
       - 将原问题分解为更小的子问题' g! v" ^! Z+ r, v7 f
       - 例如:n! = n × (n-1)!
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    7 R: g4 U$ |  n/ @" p9 ~& v 经典示例:计算阶乘
    3 |( g' Y& C' j  b7 l  {; npython* x% N: x' W  |" e- o
    def factorial(n):
    ' T4 k4 n. E  \4 A( ]    if n == 0:        # 基线条件
    6 _2 `. W0 _8 H- j. e$ @- t; W        return 1. }- |0 @$ i3 d  X
        else:             # 递归条件
    0 ?. X& I9 [0 z1 v0 m2 v- \        return n * factorial(n-1)
    % g1 E3 _8 ^. P9 E% R执行过程(以计算 3! 为例):$ R# l- d# Q* m
    factorial(3)* ~) u0 m2 [$ @
    3 * factorial(2)4 ?& H$ f) p& t2 Q4 g* o! R8 b' V9 X
    3 * (2 * factorial(1))
    , D, ~; K0 h$ Z6 q3 * (2 * (1 * factorial(0)))( r6 S; Y) q0 u3 F+ p
    3 * (2 * (1 * 1)) = 6
    ; I0 ]! U4 {8 ^2 E( M* z7 u) X5 z5 Y# K/ x
    递归思维要点( L/ K3 U9 u, Y( \
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    $ b) }" ^. ]* I4 O5 f4 p2. **栈结构**:每次调用都会创建新的栈帧(内存空间)$ u7 X& v( b+ P! x4 E
    3. **递推过程**:不断向下分解问题(递)) D2 S, l( n& Z1 U5 P. r* y* Q) d1 O
    4. **回溯过程**:组合子问题结果返回(归)
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    注意事项
    # f6 L) V/ s- {! T- E* }) i9 Q必须要有终止条件& e3 s% V# K: r3 H& r3 I: K! }
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    & h9 c, l' E9 M+ l某些问题用递归更直观(如树遍历),但效率可能不如迭代
    " m$ I5 f* l' G) q& t尾递归优化可以提升效率(但Python不支持)
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    递归 vs 迭代
    5 G9 i9 K+ ?/ p* E|          | 递归                          | 迭代               |  ^% m) R5 d5 t) m/ R: \
    |----------|-----------------------------|------------------|
    - ^( z# U" F( q2 G7 G| 实现方式    | 函数自调用                        | 循环结构            |
    ; O( i( h9 l( F/ `$ r0 |3 v| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |/ x5 J: j; Q' q8 @2 E/ R  L6 @
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    ! u8 f4 I4 m+ m| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |2 \9 ?! J/ M- W! H+ b3 N' j: b, Y$ o5 U

    : e3 c: T" I: m: e2 U- M 经典递归应用场景
    0 r3 o' u, }: z3 q# w1. 文件系统遍历(目录树结构)
    4 g8 K% U$ a& I1 Z1 b1 W7 B2. 快速排序/归并排序算法. ~, a# t7 I& t9 [9 v, q! Z7 d
    3. 汉诺塔问题4 p! g  ~" @( [0 o; _
    4. 二叉树遍历(前序/中序/后序)- m  k" l; Z8 k" M& B5 {& k9 F) w
    5. 生成所有可能的组合(回溯算法)
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    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    昨天 07:13
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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,0 k! n: b) O6 Q! S" c7 x$ t( H8 ~/ [
    我推理机的核心算法应该是二叉树遍历的变种。
    8 @! P% j* j0 [! [* V另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:  Z+ @1 D* K: i
    Key Idea of Recursion
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    " X. ?, U7 ~: g4 i  k( W; C- LA recursive function solves a problem by:) y; o+ D; U* k! s2 L" ]0 D6 H" v
    9 G7 n3 y9 `  T6 d- F* h
        Breaking the problem into smaller instances of the same problem.
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        Solving the smallest instance directly (base case).
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        Combining the results of smaller instances to solve the larger problem.
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    Components of a Recursive Function
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    ( O) t& R+ g4 ~: [7 Q( n% F: }! c    Base Case:
    ; B0 x# t! Y' ~6 I# j
    8 A; P! z/ L% o+ }        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.1 x; w7 b  Y" K8 ?) E
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            It acts as the stopping condition to prevent infinite recursion.
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            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.8 |1 `- H% b- j  h0 E' f5 A

    3 f, O! J, R) f, T* F( ~8 x8 y    Recursive Case:. Y- r- j, ?6 X
    9 d0 O  R0 X: E) W. K
            This is where the function calls itself with a smaller or simpler version of the problem.' w9 B; _7 |$ v/ v0 u

    , ]" n& M4 A6 S+ h  ]+ d+ ~        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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    4 P) ^* C$ {, T- m% P5 DExample: Factorial Calculation
    9 @0 O0 u; {7 T' p3 \$ A
    + `0 j( C$ c. vThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:: g- M0 m: @2 N2 H5 Q
    2 r- {; G* {- V% T/ X2 S+ c
        Base case: 0! = 1. h. F, o4 L' H+ z. R0 ]4 x; p

    ( [. B9 s( C) k6 B/ S, Z    Recursive case: n! = n * (n-1)!9 A* R9 K# }* E$ h3 ~
    ) p8 w( ~- T) W
    Here’s how it looks in code (Python):' O1 @0 C% j4 O  E) @
    python
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    ' U( j9 a1 ]! S2 n8 bdef factorial(n):
    9 P) B+ A* L; @0 }- B( m5 k    # Base case$ w. I: U, v& k8 t! ]& F0 @& @% j
        if n == 0:+ b9 L2 H' C; p5 E# Y
            return 1/ ?6 x$ q. B; f4 L$ @
        # Recursive case
    5 g, |# s& `# c2 v! y    else:
    0 j( j! m3 P' |3 u        return n * factorial(n - 1)
    6 E7 _% M7 T0 E- [. A5 G& ?8 Z3 h- n2 ]5 P) \7 }$ V5 V, c$ {0 ]
    # Example usage  Q7 l# ^/ _3 F9 Q* s. \! x
    print(factorial(5))  # Output: 120
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      J% x9 d/ F0 V1 G4 @! gHow Recursion Works
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        The function keeps calling itself with smaller inputs until it reaches the base case.
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        Once the base case is reached, the function starts returning values back up the call stack.1 N4 ?* H& \! m8 f  V
    ; D2 C3 f# h# E5 s. w" F% P
        These returned values are combined to produce the final result.
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    For factorial(5):
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    1 j' Y. }& U6 {5 w& W- V1 s9 v+ h0 L
    factorial(5) = 5 * factorial(4)1 V0 v' t# v( s# y$ K" Y" ^2 @
    factorial(4) = 4 * factorial(3)
    . w6 D0 {6 P- a8 [factorial(3) = 3 * factorial(2)
    ) k  Y* `/ `+ _* q  efactorial(2) = 2 * factorial(1), w4 G6 o; a& u$ p; }3 T8 S
    factorial(1) = 1 * factorial(0)7 M' m' L  I( {! J
    factorial(0) = 1  # Base case
    0 V: e- h# J: g3 B  X/ N7 k0 w0 s. I" r
    Then, the results are combined:
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    " T9 K9 m% b) w4 z6 c+ m  Y! D7 U0 i, h. D
    factorial(1) = 1 * 1 = 1
    % @$ h, l, n, B1 t! t& }factorial(2) = 2 * 1 = 2
    ) Y+ ]$ B9 D' d2 c8 B# _factorial(3) = 3 * 2 = 65 @# w$ L: R' _9 n' B
    factorial(4) = 4 * 6 = 242 ^( x1 ~" \% t; x$ p
    factorial(5) = 5 * 24 = 1201 @8 I" a% n: B3 r/ a

    * X, w) d3 {, o0 vAdvantages of Recursion
    * ^/ ~* ^5 N4 J7 E- ?# {- ]0 m
    - y8 N4 B" f1 ~+ k0 Y  s    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
      W0 B9 M; w& }0 M
    " m7 f2 x0 L7 }' p$ \    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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    Disadvantages of Recursion3 y: i4 v1 H0 t

    , k6 q; V# V. ?4 |    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    " m: q- Z0 b. r8 J6 m  ?6 h" q- W" g8 T8 `
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).$ P. }# ^, O* q6 g/ r

      H5 y9 v: l4 e* `: j) R  @0 `When to Use Recursion7 h: f1 ~8 n8 \
    2 W7 D. H9 j, k" b; G
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
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        Problems with a clear base case and recursive case.6 D" `7 M/ R  O. x" c0 Z1 D
    2 g, \& L0 ]( H. T# H
    Example: Fibonacci Sequence
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      [# Y& Y) s7 w! rThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:. s, g6 [8 N3 N' X

    0 [. ^* U! W: c7 L  k9 I    Base case: fib(0) = 0, fib(1) = 15 ?$ a) T" H6 p" K. a* N
    4 R  @4 o0 R( P( g
        Recursive case: fib(n) = fib(n-1) + fib(n-2)2 A& l. x/ y1 j8 c* W8 w

    8 m+ D3 I  ]% o0 l+ Dpython( ]: Y; U1 @+ O* |  w& t

    8 S# x4 W' p5 S9 Y, @) [; }
    9 K! G7 a. b! f5 [3 Y# W8 wdef fibonacci(n):' D$ a, R) p8 [5 X4 j; r
        # Base cases- F5 T; T; a( ^# _$ H7 }2 {' A
        if n == 0:
    & M  a0 N$ [. [! N. g" V3 q        return 0
    ) C3 a5 q! J- Z. C    elif n == 1:. c, H* F3 ~1 d+ z, Q- u6 h
            return 1/ C& f( l4 w# l! {/ X. F+ x
        # Recursive case
    1 R( s4 C* {# M. [) H/ b' |# w    else:) b; u1 a9 a# i! Z8 v
            return fibonacci(n - 1) + fibonacci(n - 2)
    % F$ p! G# N; M# |  Q
      \7 E7 O1 D1 q8 p. {) P( h# Example usage
    . k# u; x' K9 o( ^+ t. _print(fibonacci(6))  # Output: 8
    % B7 N# A6 U7 A6 y& E% {
    ' k) X/ B2 S/ r1 |Tail Recursion* t% p" P9 }) ]) K9 _  A
    # Z; J9 E2 j9 M! ^! v# V. ^
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    : w3 ^% L& [1 t! ?$ S+ L% L0 X" O: o! n7 y/ c+ S3 N, Z$ L+ I
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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