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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 , O3 j0 b4 F, w

    $ Q) D4 W7 {0 o/ U+ J/ k; X解释的不错/ ?% Q. R- ?! s- t' w; ?
    / ^: Z( q9 N$ X' E  n; j
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    / @- O: E% [' V- \7 {
    5 A3 U; |  u7 z8 B  Q 关键要素( G- O9 ]* c5 N4 }3 }" a' B" y
    1. **基线条件(Base Case)**' {8 y# e) C' o& K5 a
       - 递归终止的条件,防止无限循环) [% L' Z. t# b$ {- p; a! M
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    4 Y2 L: @7 d8 q
    2 x! l" X- N) k! f) V2. **递归条件(Recursive Case)**& _8 A: Y3 O$ M" i5 s
       - 将原问题分解为更小的子问题4 @- G5 u& v; S2 }8 n/ L& C% d
       - 例如:n! = n × (n-1)!
    $ o7 S1 u! b5 y& Z% d  ]; p5 d4 m. }
    经典示例:计算阶乘
    / T7 L7 o$ F5 g6 V, H9 {/ p( lpython/ X, \, l8 j( Q/ C
    def factorial(n):! _3 a6 V0 o, [
        if n == 0:        # 基线条件
    0 l1 _5 S2 X* u& o0 f$ w        return 1
    2 {) q3 \; S9 m% X7 H; n    else:             # 递归条件, \! N- W- D" U4 H+ M
            return n * factorial(n-1)7 B* x2 `8 X& r7 t
    执行过程(以计算 3! 为例):
    ( {* g9 B9 [/ z7 g$ m- lfactorial(3)  A" L7 I# Z: r- i
    3 * factorial(2)1 y. ^& J8 _; E) J" U% ^+ v
    3 * (2 * factorial(1))( J5 H9 `$ e! U
    3 * (2 * (1 * factorial(0)))
    , o7 w2 c3 Q2 U# R3 T' |5 G8 _0 T! v* O/ i3 * (2 * (1 * 1)) = 6
    % S& F; c; V7 k1 k8 k& k  ~: u' l# y
    递归思维要点( C# g2 F3 h2 F% k& E+ Q1 U4 p, i
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    ( v6 x" {* C7 d) w# i6 O+ `2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    1 B9 A$ Q5 v% b7 E* R9 [2 ~3. **递推过程**:不断向下分解问题(递)
    % _5 u' e- b4 I9 X) w4. **回溯过程**:组合子问题结果返回(归)
    " |4 j5 X/ A8 ^
    : @% G% w/ k0 k& Q 注意事项
    , I( u8 B2 z3 N$ {7 Q0 Q0 _0 z" `- Y必须要有终止条件
    ! Z/ \# P: u8 F  u! }递归深度过大可能导致栈溢出(Python默认递归深度约1000层)  O+ S2 x* T) s6 H
    某些问题用递归更直观(如树遍历),但效率可能不如迭代9 ]+ r, L) j: P% f7 t
    尾递归优化可以提升效率(但Python不支持)
    & P  v7 e9 r; v, A3 A
    6 ?4 A& Z7 I  c 递归 vs 迭代; e7 y) t0 ]& y4 W% C) b
    |          | 递归                          | 迭代               |) u" k5 n/ u0 M# {1 g3 D2 Q8 W
    |----------|-----------------------------|------------------|, t, s- I, o9 i/ `! `" a
    | 实现方式    | 函数自调用                        | 循环结构            |
    $ _- ]  W4 C" A8 X) F2 |9 U| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    $ y8 z3 g2 m/ w, Q$ f8 s| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    2 R8 Q. d6 h3 X, R| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |  v; q! g# K- U2 d6 L  v' {8 A

    ( G- U# v# \, R7 U 经典递归应用场景- Q% }1 {/ }1 b9 u; W7 X
    1. 文件系统遍历(目录树结构)
    3 n: w- [& S8 j, u) F. p' V2. 快速排序/归并排序算法8 e, Z; U& E8 E
    3. 汉诺塔问题
    7 F  W* U$ \; d; Q" R) {- d4. 二叉树遍历(前序/中序/后序)* n4 H  z4 k8 O( ~
    5. 生成所有可能的组合(回溯算法)
    ' y$ @6 o7 X7 o$ n3 o" S/ P7 I, T, K2 P# o
    8 d8 n# A, K1 a试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,/ p8 `7 r8 {- u0 c
    我推理机的核心算法应该是二叉树遍历的变种。4 Y+ C9 b- @! i: P+ V1 _
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:* b, _. n$ o% ^# p! x6 a0 |# o# c
    Key Idea of Recursion# `. I' _* J5 A2 \
    # H6 a# s. o# x
    A recursive function solves a problem by:1 s8 v. K& V/ F2 R2 ?

    $ Y  O2 S  P5 K. e0 J$ s& n2 a" x    Breaking the problem into smaller instances of the same problem.' N, Y: C" y6 b( @

    3 @5 d5 d  p2 y( l! e    Solving the smallest instance directly (base case).
    , K4 r3 r. m- C, U* ]2 B1 P$ }2 O: a* K0 }3 f
        Combining the results of smaller instances to solve the larger problem.
    $ D, m& I6 v9 L& n) X
    6 i3 `) @+ q1 z$ t8 SComponents of a Recursive Function
    + E& m  }8 Q3 D( [
    + v, @' o! k+ T, X: O7 [4 m/ p    Base Case:
    % n: N5 E1 q/ @! s$ |
    . I( G4 W% w5 h5 H0 Z        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    , a; m6 X; B  ~' h/ _& l- {
    3 a9 W6 d! b- L  i        It acts as the stopping condition to prevent infinite recursion.
    8 b6 Q: g- L1 @" D  }* d* p: G8 o: I6 \/ _
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.2 j" O$ D. E7 V; u

    # [8 E+ z/ G% T4 r+ o    Recursive Case:
    " x% K; V; y7 y- h+ ?0 B6 ]8 g$ J% ]4 f- E
            This is where the function calls itself with a smaller or simpler version of the problem.
    & O; y, I& V& {9 R+ a
    3 e0 Q" N( b, `/ m, P/ g  Z8 |        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    9 G8 D1 f. K+ N- P' `5 e! r, G
    ( L! H2 ^- y, j% D% ~Example: Factorial Calculation
    1 h2 M& J0 @2 z' N" b5 G6 i# x' i9 r' P( s
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    ) Q# f! \  Y' Y7 t  U5 _0 m9 h4 H
    3 J- E% p4 G& i( ~% b; X    Base case: 0! = 1. R; L! ^% Q2 w) y
    ! s4 L7 y$ [7 s, s) L
        Recursive case: n! = n * (n-1)!% a( v6 ~$ }5 q! Z: Z+ C
    2 d! d9 w6 I0 i: \
    Here’s how it looks in code (Python):0 V& e- E) H/ |% _6 ]/ C, p0 J
    python) v' I/ W6 {/ S/ |

    ! v% d6 t* X" A4 l% E3 G- ~4 e% i3 F
    def factorial(n):8 b; U) ]# W8 `8 P
        # Base case
    1 }  f5 M1 U+ o' N0 o6 j    if n == 0:- B2 X1 S& _3 z2 ~# B: k" p3 _8 p
            return 1. v- M: X# Z- O8 }  J* e
        # Recursive case
      c6 R# R& t  `    else:; o7 s9 p1 z9 R& K* Z+ s
            return n * factorial(n - 1)$ D5 Q+ s. B: E8 Q6 _8 i! @
    ( [* a5 j# O6 G) o6 M
    # Example usage! ]: H6 L$ Y3 Z* z
    print(factorial(5))  # Output: 120" s$ ]; }( j: p3 V3 m

    * _6 {4 X  R. k! A$ T8 THow Recursion Works- |) Z# B8 \- p! L; Q9 c

    " c8 J1 i' U- u- y+ I    The function keeps calling itself with smaller inputs until it reaches the base case.
    ) g: d& S& r) h
    9 C/ n4 T6 D8 G    Once the base case is reached, the function starts returning values back up the call stack.
      [. l2 s6 q- }. u/ F, E
    $ g2 e5 d* b( M  [    These returned values are combined to produce the final result.
    ) Q; D/ U( R- ]1 E: t" k' c9 \$ b
    For factorial(5):6 {; Z0 C5 M7 e, f( H1 v2 S
    & v6 a3 H; c! u5 Q7 E) a+ P) z

    & ]2 K( M- [; _1 F9 Nfactorial(5) = 5 * factorial(4)
    - _+ z/ ]8 I3 c) Kfactorial(4) = 4 * factorial(3)
    6 q0 e$ Y! u/ ~. A$ zfactorial(3) = 3 * factorial(2)% d* j% M- d( [8 f* b$ s
    factorial(2) = 2 * factorial(1)
    ' v/ k' U7 {, U  A; p) O( _factorial(1) = 1 * factorial(0)
    . n! m, Y' q' N" G. a/ Cfactorial(0) = 1  # Base case0 O/ j/ _/ p( P

    ( y+ Y- C9 K/ |+ fThen, the results are combined:. F1 Y, Z: o3 E. E1 t1 ^9 Q% W

    $ j9 h9 x2 P3 Z' s1 F2 u" |% h' H3 G, U' o* p* W* {
    factorial(1) = 1 * 1 = 12 e, k9 P( f; D" u/ w
    factorial(2) = 2 * 1 = 2. `! T7 A8 c/ ~; U  Q8 ~' C' L3 b1 g: i
    factorial(3) = 3 * 2 = 6
    # C( T, ~! d* {! K5 Lfactorial(4) = 4 * 6 = 24" l: M; L6 [- H+ l7 w  m
    factorial(5) = 5 * 24 = 1205 M( H+ N+ N7 ~2 G- Q

    " W! M5 H! K$ j2 Z: C, wAdvantages of Recursion2 K' u+ p9 P! r: x, d0 A! S

    5 U* I5 y8 T2 i    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).% M' R3 E) h5 a1 H) @

    9 x) L" z6 r# S    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    . ]8 c2 _' V, @  C7 ?  c
    7 J  @$ i2 |; k* C2 E8 N, uDisadvantages of Recursion6 N, A. C4 U' @1 F) @( \1 i
    & ]% p+ K& O: [4 y( Z
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    ' W: p4 g' h% R6 S# o# u
    # w) q5 v5 e! n4 x    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    7 a4 r' B! h) Q5 Z1 l2 p6 i0 f/ {$ x9 l0 F/ U! \
    When to Use Recursion
    2 C5 w0 K" n, g$ a5 E- m' ^7 {: T% s$ B3 `
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    , ?! q+ _+ H, p5 p5 g* s. n1 V. I5 c1 T" U
        Problems with a clear base case and recursive case.
    4 Y' a- v% d7 S3 R4 w6 S
    ( W' ~8 @. f5 R) tExample: Fibonacci Sequence
    1 P$ T2 f) f. e, Z0 B$ ]. k2 Q2 P8 s7 c) c
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    % ], J- l9 {' w1 b8 S. u" y% O) P- ?$ q- o  W$ J
        Base case: fib(0) = 0, fib(1) = 16 B2 k! ?1 ]( U1 U/ b' s0 [1 }9 R
    1 T/ g" G! H- @9 Z
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    , `: Z+ ~1 Z, x# n9 S, i. e( g! H2 M6 u2 Q8 r! E0 Y" o2 x
    python
    : R9 e  v: x/ P/ F; Y4 L
    # Y9 ]+ t. ~. m. A6 C% r9 A/ P3 ?
    1 x9 j  Z. G, a. q- gdef fibonacci(n):' W0 F2 i" Z. u
        # Base cases( Y. q, r  d6 x0 l; G
        if n == 0:9 L. C" B8 b. H$ Z
            return 0
    5 h/ W$ J# Q4 n    elif n == 1:
    9 t4 j1 r( k. @! ]4 ?        return 1
    ! s! x* e, @3 E1 {+ h) m/ K    # Recursive case
    5 \& y8 \- E4 n3 Z* w1 x6 [    else:! J0 j8 a) J% T; m
            return fibonacci(n - 1) + fibonacci(n - 2)
    ; C1 c# x- ~: v" j) W, S' f. F8 V, B$ U3 f% P3 @: Z1 G: R
    # Example usage% ~/ b1 I. e* J3 s
    print(fibonacci(6))  # Output: 8
    % m* s- d8 E. W3 l$ h9 V
    ; _4 E1 Q9 D" q% @  |: RTail Recursion
    ! v2 k1 W" x% S; @! B
    ( u  M: f+ G% g7 ^2 M! dTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).* b( H0 {1 R/ I5 N7 H

    / ]5 {# i9 t$ k$ w7 KIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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