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[科技前沿] 突然想到让deepseek来解释一下递归

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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 % G' @% L" x4 y& ?0 r

    9 J0 `( ^! R  R$ x! V* U7 Q( }解释的不错
    ' i9 v2 c! M6 m2 n6 i/ R8 _4 L
    9 [- g. T) [4 {7 ?. G% D9 ?递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    - J7 e# G" @7 U& ^' ~' w
      W4 h9 r& e1 O- k5 u4 F 关键要素
    ' `2 f' ?# n& T+ _1. **基线条件(Base Case)**
    9 x$ B$ a* _) z- Q   - 递归终止的条件,防止无限循环  X5 L, l) }  r( h( ^! a: U
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 12 D* H# Z' g# Q& ]
      d+ ~0 B, @4 |2 Z" {% E, I
    2. **递归条件(Recursive Case)**1 q: l2 b; q' ]7 S; q
       - 将原问题分解为更小的子问题
    2 e' \. Q1 Y7 z; R5 y$ ]5 {/ R  {9 c   - 例如:n! = n × (n-1)!
    / B' d* H7 }. S6 s  l, m6 y1 e. N' F' j' f. ^! b# q
    经典示例:计算阶乘
    8 D3 Y1 g4 M/ @  n; N# J. Apython2 d6 J: H+ A% @7 W0 p. @2 D
    def factorial(n):; ^& C) [4 B" M) y2 B6 y6 b
        if n == 0:        # 基线条件
    & f8 Y$ t1 v' q5 b+ k, d0 e3 g        return 1( l& e4 H; d6 g- C: W6 p; {8 i
        else:             # 递归条件& H2 h& n/ u) f; O
            return n * factorial(n-1)
    4 b/ ]. i6 l3 i! T2 m, ?执行过程(以计算 3! 为例):7 w: Y) q4 @! q7 K
    factorial(3)
    ) c* ?* G3 c5 R3 * factorial(2)
    / U7 |1 f' g& d4 {! v3 * (2 * factorial(1))3 @7 b& m* d( s2 F
    3 * (2 * (1 * factorial(0)))7 y( P0 M' _- M+ K+ E' ^
    3 * (2 * (1 * 1)) = 6
    9 z) W1 f/ Z3 o' K$ E4 V% I- Y5 X, ^0 J8 \- Q# z) \0 r/ G
    递归思维要点! q) s9 D4 K  c( @  |2 q
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    7 f1 ^, w! o' `2. **栈结构**:每次调用都会创建新的栈帧(内存空间)- x' j. a9 f0 ~; W1 s
    3. **递推过程**:不断向下分解问题(递)9 |) F* G, |; N8 Z3 b
    4. **回溯过程**:组合子问题结果返回(归), s5 \$ \2 S: f( M, J; x+ L
    " p' B  O5 j" o) e& f! M/ b
    注意事项; ], s$ f7 O) R6 u
    必须要有终止条件
    4 s5 _7 N8 E6 W递归深度过大可能导致栈溢出(Python默认递归深度约1000层)/ l+ `: e6 `0 a7 o4 |1 L
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
      r6 y. p- t1 L) \" {7 l尾递归优化可以提升效率(但Python不支持)9 K/ j) C, Y3 z6 \

    & \  H# t+ ]5 n( {7 U 递归 vs 迭代' u1 _9 j" N- ?. R9 \! V
    |          | 递归                          | 迭代               |% U; C: G- H) S1 r  U$ ?" L
    |----------|-----------------------------|------------------|
    - R7 J& O" {: t3 _* f' N6 z% c| 实现方式    | 函数自调用                        | 循环结构            |9 t4 q& k* m8 W% m
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |4 U# V( l; H, I( P
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |8 D! g% a" q0 D; u2 S" w- I% {: i
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    4 ~5 V. m; E- F0 n9 {% Z# T: I  a% G8 i" V3 [0 |
    经典递归应用场景1 x" r2 C, P* D
    1. 文件系统遍历(目录树结构)
    : s, ?* [4 ?3 J9 L2 e2. 快速排序/归并排序算法6 l* x- |8 m& p6 K% f- u7 f4 _
    3. 汉诺塔问题
    $ e! y& R# J/ c8 F. p& V4. 二叉树遍历(前序/中序/后序); Y; M+ L* ~! H) u; R2 T4 h; J. R5 }
    5. 生成所有可能的组合(回溯算法)
    ) h, d: H. G  e6 L0 d0 p
    2 K0 b! [! r! M试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    # R* j& T/ z6 m" ]我推理机的核心算法应该是二叉树遍历的变种。& g$ c3 U3 k( E+ ], Z: r6 s
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:$ a( ?1 C. v9 K4 D# g# F' ~
    Key Idea of Recursion0 a5 L/ Z' T+ `1 v1 B
    3 K" V, Y1 y: ]5 R9 ~3 \  Z
    A recursive function solves a problem by:- q# M4 C" j  M5 E5 {* T) P+ P) X% V
    : q8 C3 w8 A( d4 ~
        Breaking the problem into smaller instances of the same problem.
    1 V# y3 k9 `( C* G" r! ?/ \$ U2 |5 k+ I0 U) H
        Solving the smallest instance directly (base case).6 x5 ?) i* m# d* R# N  E

    6 \, o4 W9 X' M# v5 B* H; D    Combining the results of smaller instances to solve the larger problem.. ~# w' d/ g1 x- T0 U2 F

    3 v+ y; p- U) c% FComponents of a Recursive Function
    & M% m7 [" G% |0 ?- J9 S6 E4 W! R# E$ B+ P- @. E, Q/ _
        Base Case:. b7 V5 h' w7 e! ^+ R5 Q- c# r3 p
    8 m1 ~5 `; T" b/ w+ S1 z! H
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    6 v2 w# D6 l8 i1 v* C9 @% p4 c% V; w. @
            It acts as the stopping condition to prevent infinite recursion.
    " {. k4 k. {, b% d' ~( T0 l- j, ?# i. f5 U8 d) j3 b
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.# e2 l& P1 _6 D# ^1 ^+ `% x

    2 g# O. O8 ]- D5 R    Recursive Case:: S7 {0 X  a( {) A3 c
    , j; Q+ y- z) I4 _
            This is where the function calls itself with a smaller or simpler version of the problem.
    ! Q& C) F9 a8 }/ [# B
    , Z# Z6 x/ X3 i+ a+ [2 G* t        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).6 b% \; V! ^  ~$ @. p/ e9 |9 G

    ( }. P" t3 e+ K: d' e* q% q' }Example: Factorial Calculation
    3 _3 ?3 ^' v9 l% @: L* D0 l( ]8 R* ^6 g: ]# t7 p7 ^# Z
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:% ?$ F; V- a# _# U; V: V' I; \9 a
      U; @+ ]2 x1 Q! C: c# b4 o7 w3 @0 }" _
        Base case: 0! = 1
    0 o2 B) I' B* c; m. X2 w0 f! L2 C- b- [/ p" w* V" i: `" `
        Recursive case: n! = n * (n-1)!
    4 M5 v! s/ T8 B. c% P" y+ L
    & `+ k9 Q$ m. B) j; ]5 RHere’s how it looks in code (Python):
    + X- [+ i0 V5 o5 C2 S) [) ^- Tpython
    ' f$ K1 f5 L* s1 e; N
    7 |3 J- Z  M/ _- E" E. E" q$ l( k6 j$ ]% I4 K( H8 D1 U
    def factorial(n):6 @9 u' D+ h* e/ }) y. J& Q
        # Base case) Q9 F. a" x2 n2 i% R
        if n == 0:: f- k$ F9 A; A/ u
            return 1  E9 G  U% `+ A+ u* P  {
        # Recursive case) L$ U& R( x% \1 B* D; w6 r( S- A
        else:
    7 N4 G' ?0 D; ^# T7 h' Y/ [        return n * factorial(n - 1); N0 x9 E( w7 r; {
    , }9 J& B) g- \  J
    # Example usage+ `2 O/ l4 x$ l! L% S
    print(factorial(5))  # Output: 1205 ?: \, ~6 w7 I% h$ f6 T9 I$ p7 p
    + E  T: w8 ]2 v. ]* o" C
    How Recursion Works) @+ r+ h0 a5 f* ^' a7 J9 p* o

    7 l: |, ^# n0 H. I# s8 j4 y, C! S    The function keeps calling itself with smaller inputs until it reaches the base case.2 z/ P4 E; C7 S' n7 @  u9 Z8 ^- |
    ! j$ T1 M8 r* d, S  B
        Once the base case is reached, the function starts returning values back up the call stack.! g6 R$ e0 T) m$ x. x
    / O" H) h2 U9 Q
        These returned values are combined to produce the final result.
    5 C# S, `# x" y/ ]; W" b, j# y2 Y' L0 Q4 [, e+ f9 O
    For factorial(5):. {" G* _. |6 l6 y# F

    5 B: v0 p3 x& W/ s! p) m7 d  Z1 U4 O, t8 N0 @# |  K
    factorial(5) = 5 * factorial(4)
    ' L+ D7 I% n, N7 W0 F$ S8 `factorial(4) = 4 * factorial(3)
    3 R* D+ I4 i: B2 ~: X8 Kfactorial(3) = 3 * factorial(2)
    # u2 o" f8 L4 G; f6 ]# l+ a/ C$ Gfactorial(2) = 2 * factorial(1)
    7 C) M+ t. k! Z& x1 l9 Wfactorial(1) = 1 * factorial(0)
    " r/ q) c  v# c2 A* Kfactorial(0) = 1  # Base case. C! G7 u  }# f4 Z4 X

    1 a1 i/ F  {0 @1 i% `Then, the results are combined:7 c3 g* d, N( m) N- K" O8 J

    9 R6 n: r3 ~+ N* N, a
    ; l7 U7 s4 K( C7 Mfactorial(1) = 1 * 1 = 1* e, W$ k4 R; j
    factorial(2) = 2 * 1 = 2; Q0 V9 ]: i- \
    factorial(3) = 3 * 2 = 6% [! `+ N8 M. {( Y5 b. d3 B
    factorial(4) = 4 * 6 = 24
    0 B: @6 L2 {  R, P7 {' ?factorial(5) = 5 * 24 = 120
    , b% E% W0 I: s' f" u( d$ E) F7 h
    Advantages of Recursion0 J1 L6 l/ Z. T# w
      P0 g* ^& Z) I
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    ( P7 C# {: I" }" E. f6 U
    9 l7 H% W8 ~; N3 H/ Z; B! F6 Y    Readability: Recursive code can be more readable and concise compared to iterative solutions.
    6 |# B  O; Z2 U% O0 x! O: \1 M
    3 |" B" m3 _; c1 ]) ADisadvantages of Recursion7 K$ \$ Z9 }9 q5 y5 d7 |
    ; O7 f# o5 n, z% o" |" U
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.$ D4 y. R4 b8 I* m( m
    2 [; m' r" d! ~+ W" F
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    2 a0 d& a2 Q0 v0 |0 N
    4 [: _  R% O- B4 d. F' C- lWhen to Use Recursion( Y( X' |9 I. G1 i5 [6 L
    4 T9 ~; I( c( n( ]
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).! `& N0 k0 q% C9 q0 B
    % c1 H; J/ u+ f
        Problems with a clear base case and recursive case.; \2 X0 Q4 }+ ^6 p* g

    5 q; ~  A4 o" A6 Y1 I' CExample: Fibonacci Sequence
    7 N* b" |/ {4 s/ K1 O! i; z
    ! {- H) h+ z0 EThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    + n. p' S. I/ p$ H
    , p. r% c- b! Y- e    Base case: fib(0) = 0, fib(1) = 1
    . {- X* k5 g8 E& O! @4 C, i) j- h  q7 w: t% X& @* i  F% s
        Recursive case: fib(n) = fib(n-1) + fib(n-2)& s  ~0 h9 `; \$ j, {, R: Z& s

    0 m3 l4 e2 h" C# f9 L0 ]% ?' f" \& T* M) \python/ A  @0 T- I4 I4 z
    0 U& h+ ?9 T1 f2 ?
    3 w; s' {8 B1 H0 z4 m9 X- e8 w
    def fibonacci(n):
    ! i2 w& D1 m' p# Q' n! e    # Base cases
    $ E% Z/ a& C: B# Z: N0 Y8 c    if n == 0:( [* U7 m8 j. {/ E
            return 0  H; w6 Z7 P, J8 O
        elif n == 1:
    ( T) F* f6 h- j; N, y3 S        return 1
    & {1 d) E" w6 @% w    # Recursive case/ L3 f, m1 @: q5 g# W, s& S
        else:: V" ^- U# J/ q: b
            return fibonacci(n - 1) + fibonacci(n - 2)
    ( W" a6 ~/ e4 r
    & [0 I8 X$ O" H" u' K! F9 u# Example usage
    2 ^/ o" \) P" Y/ P# w5 Yprint(fibonacci(6))  # Output: 89 ^( N! @: U$ p& F! ?+ O% F

    ; b4 w+ w) x9 ?) tTail Recursion3 {9 u: F* x# y* J9 N

    8 p( g+ J& Y2 a5 ]Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
    6 B, O4 i% Y8 P1 w7 O
    ' M$ Y5 t8 f! uIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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