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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑
    % D4 B6 B, a8 n7 S; x+ t8 M; E
    5 i* y& k+ R% {解释的不错2 s0 i0 V( c) y

    $ t) ]8 t5 z3 y1 c递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。. \) D3 W7 w: X7 K( C  D' N
    2 ^5 a# m% f2 I3 K0 K' F
    关键要素% m3 Z; U: _$ ~+ X; ~$ A9 L
    1. **基线条件(Base Case)**$ N" L$ Z, B1 `+ D0 `: W9 ~
       - 递归终止的条件,防止无限循环
    . S  A' l+ T- Q6 U! z4 f# N! V# S   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    2 D; A' b, R3 O4 i% x, u5 C: o8 g8 ]5 I- Q
    2. **递归条件(Recursive Case)**
    " l0 I5 n% N$ g9 z   - 将原问题分解为更小的子问题
    0 R# A% Q# y, F- o! w   - 例如:n! = n × (n-1)!+ E& t+ x  g" Q/ l" C) X
    8 w3 ]) @% G- H# R/ ~4 v
    经典示例:计算阶乘
    ; J7 `4 a+ j/ Ppython6 d6 V% w2 `6 n; Y" ?3 r" r! t
    def factorial(n):% L# \2 @' E3 L, Q% f) K
        if n == 0:        # 基线条件$ J- W. _) x4 V- `+ r
            return 1# S9 d% \' u8 C% u1 K
        else:             # 递归条件8 a2 G5 p1 c% H( y' x
            return n * factorial(n-1)1 ~' w: N, g* j3 @
    执行过程(以计算 3! 为例):/ ]/ x3 z7 D. d" z0 N
    factorial(3)  O+ a( [/ a% d
    3 * factorial(2)1 j, \5 q4 q& E& ^/ d+ k: J
    3 * (2 * factorial(1))
    - q# l- L. K2 A8 N3 * (2 * (1 * factorial(0))): R# G- L) ~* T& R2 w4 M* r$ b
    3 * (2 * (1 * 1)) = 6
    6 I  z- P9 c% O- s9 i/ R8 f- G0 L$ R- P0 n0 v
    递归思维要点
    ) B% H, l# `' B# r6 S1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    # G3 a8 w0 q# a$ f/ o7 L2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    : w9 F7 c( D* Z; p3. **递推过程**:不断向下分解问题(递)
    - Z! Z8 G9 u' o, D0 ~# E# i4. **回溯过程**:组合子问题结果返回(归)* U4 W4 d0 D7 H0 N
    6 z; L) Y( }" ~& F+ d* y1 V! i
    注意事项
    0 ?3 u" d& [  |6 K% s' w必须要有终止条件
    7 \! B6 U; z% q8 J. r/ f递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    7 K& ]. ~9 s  A5 v5 s* l某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ! E' J- @" B! O& @! d: `尾递归优化可以提升效率(但Python不支持)
    , A* B3 g2 O- `6 e
    - S; T# s( C! p) T/ O) n 递归 vs 迭代
    : W1 G6 d6 \% v0 |- h|          | 递归                          | 迭代               |0 w/ [3 ^/ `4 W: I; ?
    |----------|-----------------------------|------------------|
    2 _- ^  {( T! G3 g5 c4 ~. w| 实现方式    | 函数自调用                        | 循环结构            |
    " C- E/ j- y5 E, E8 G6 ~| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |; c* p( }2 \- M: j. u3 v
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    9 Q; m7 n( H0 q" ?) Y3 a1 V0 Y$ m| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |8 s; N# ?& Q0 R* d
    , f. d1 g0 w7 E$ ]- o8 o! \
    经典递归应用场景. C! R* v4 [, [; f+ O  v' y; {
    1. 文件系统遍历(目录树结构)- v# I( {5 E  [* p
    2. 快速排序/归并排序算法
    : Z9 v" F) c7 L  l3. 汉诺塔问题. h" C$ \6 ]+ o* t( u% P
    4. 二叉树遍历(前序/中序/后序)5 `9 s' T) _4 T4 V. [+ y
    5. 生成所有可能的组合(回溯算法)4 S4 [- D9 g% k0 R7 ]# U! n
    . ^) w8 |) i$ y9 i; o6 n
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    3 N! F9 D2 a4 P+ ^5 q$ R6 J我推理机的核心算法应该是二叉树遍历的变种。$ a2 s3 Y7 y7 q/ z. z/ I& u
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:. ~3 I5 r& t! M. w4 I
    Key Idea of Recursion
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    / L0 f' U  k$ dA recursive function solves a problem by:2 ]) ?% Y3 \7 ~3 z
    ' n7 f6 Y. i2 G0 G3 N! F: A
        Breaking the problem into smaller instances of the same problem.
      U7 H7 _# O/ T6 v: l+ ]+ e4 C$ I7 g2 H5 B
        Solving the smallest instance directly (base case).
    0 k4 ]! Z3 i9 R! i: C3 ~# ^& V& \" l& ~# X- ?1 y3 W6 a+ `3 n
        Combining the results of smaller instances to solve the larger problem.3 {7 X# l" E. N* m  d% f
    ) v, D8 Y6 n( o1 `- e
    Components of a Recursive Function
    2 w' g5 N- F' e0 ]5 a; ~- Y  T/ {, S0 Y
        Base Case:
    . r2 \0 H& R; P9 t0 G' L0 g1 X% u& v% _9 A; t  t. B" z
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    9 H2 K5 k. ]9 G$ f! e
    2 {% ^- i: d- [3 c        It acts as the stopping condition to prevent infinite recursion.
    # h  J' n2 h, a0 \* b( J2 v/ _5 Y! Q  O& m7 W
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    2 N" \' B  f/ n3 M# y( p% ?! q
    ) x! g* w4 p" h) Q    Recursive Case:
    7 n3 Q8 `8 C  c$ `8 M' Z- }
    0 D: H' g8 L. B: ~/ g        This is where the function calls itself with a smaller or simpler version of the problem.% N( L  }% i6 J. _3 v, d
      S% f" \& v, Y3 ?4 {+ N
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).9 q* M/ C- ^8 [# u7 W

    . p) \$ T8 N! T2 j' _Example: Factorial Calculation$ R( F: ?/ k: S( r6 c& K0 m
    ) i5 ]- T% @: Z1 O* z( X
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:% h  ]$ n" `0 s  ?, B4 c3 Z

    / x7 }4 X" b0 ]' W4 p    Base case: 0! = 1
    . a  b* [+ S; c; m! c2 N) O" |( D2 L- N  H5 d' \
        Recursive case: n! = n * (n-1)!) E, f* v+ \) }7 C- ~) T% a  \
    0 N# d' n# `4 j
    Here’s how it looks in code (Python):7 k6 S- ]5 d) @, K" g
    python7 H$ {  f. x, s/ P7 @

    % |, J- o! L& i: C$ z/ E5 _  o: v0 ?* S2 j$ _
    def factorial(n):  m# ~4 e% g# }+ ^6 B4 _+ J. x
        # Base case% C: p" }( ?! M( e. |! A2 H
        if n == 0:  {* c5 C8 Q( z1 L
            return 1
    , E8 {+ c7 S" E5 a0 d  \6 Y    # Recursive case* T4 N, D  S& K, B
        else:
    % P8 g$ m% m* \1 Z9 u7 q        return n * factorial(n - 1)
    " J/ W% |/ z6 a; @6 Y) N* r6 o: j1 L6 o9 _( U  B" o9 A
    # Example usage
    3 N9 k6 ]( ^9 H0 c6 i$ `- a2 Hprint(factorial(5))  # Output: 120
    8 a: R6 s2 v) T  l: v' d3 l, j$ q5 o# N# P
    How Recursion Works, ^5 D3 F" q1 K; W3 i' k" l" T
    5 `# _& Q4 _8 S" n2 q  ~
        The function keeps calling itself with smaller inputs until it reaches the base case.4 `' t8 O( C3 \# _$ ?8 U0 q

    6 u* \* q) L! N% |+ r8 q8 ~    Once the base case is reached, the function starts returning values back up the call stack.  n7 d' k# e  I7 b5 t

    ( G% b4 N6 H) \) z( q! U    These returned values are combined to produce the final result.) v" |3 N( w; \

    ; [' F9 r! P! s( A( }4 YFor factorial(5):* l) {/ N5 t3 V6 Z0 A

    * X" f+ E9 P3 k7 T. I
    $ \, j4 _' s9 _2 Gfactorial(5) = 5 * factorial(4)
    3 I% h, P: m5 A1 a! ifactorial(4) = 4 * factorial(3)* [5 N. F. [, p+ [
    factorial(3) = 3 * factorial(2)
      y. T5 A0 M6 i9 Q8 \& E! E% ufactorial(2) = 2 * factorial(1)" B- b6 Q8 b3 N6 V" q* v
    factorial(1) = 1 * factorial(0)
    ' |2 G) u; c6 j- a; Afactorial(0) = 1  # Base case
    , L. b9 s1 v4 h/ o, f! B
    8 D% k: {+ G. Q# v7 `2 |# ~Then, the results are combined:
    + C8 A$ ?& X- r' {2 t( m) }
    1 X- t: a1 i; U/ y5 ^
    ! G* u" u( |- o  Vfactorial(1) = 1 * 1 = 19 i8 f* b# S4 ~' n& E5 d
    factorial(2) = 2 * 1 = 2
    2 S( R* h" _' dfactorial(3) = 3 * 2 = 6* s# e* n$ S; z% ~. Y
    factorial(4) = 4 * 6 = 244 C  J3 n# \7 U* }0 }
    factorial(5) = 5 * 24 = 120
    8 T; \1 `( R0 i1 p- }) U. Z; x3 Q5 u- c  [# I! J$ H1 U4 _
    Advantages of Recursion: ~" M' L0 m3 Z# I- v0 t
    # k. s$ s; E! n) c5 H# V
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).7 k( |8 J  s7 |% I& |& ?# C
    * j; v: Y( Z: b( A: `9 x
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    1 m0 t/ i- k' T8 L6 Y" V- W+ _5 f
    Disadvantages of Recursion# S+ u% `, u" F; r4 L! `

    , M9 V8 E$ U, T- r7 N( N+ F1 k    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.% y' g( H) q7 r' I; b

    7 L4 t, _9 ]0 T    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
    ( y( f, k" v2 L/ q2 p2 U# q1 m: u1 {
    When to Use Recursion5 {6 w9 V) R3 F1 Z6 x  k; `% {

    1 v4 c3 K4 [% O1 R) t    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    9 B+ i  K1 @1 ]8 t
    , m; ^3 b( `- c    Problems with a clear base case and recursive case.0 v/ m" Y4 W8 Z5 H6 r+ }3 K5 ~
    ) j. t- ~( N4 }4 e0 m" g" {
    Example: Fibonacci Sequence
    ! }/ A9 A3 g& v% D! l8 p2 i; o5 ~
    ! n: r7 x) @# B+ h8 E2 k' C, lThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    . Z1 L2 G  X9 w3 |/ Q; A( ?. O2 ^. R9 U, ?
        Base case: fib(0) = 0, fib(1) = 1
    : H4 W% G8 I3 _, q" I; z4 y6 D7 R- t$ j" ~1 W0 r* ~
        Recursive case: fib(n) = fib(n-1) + fib(n-2)1 G( W$ w1 ~- w( V% p, k
    ! O9 x4 e( |% g, X( C$ p- l  q
    python2 E" a# j& X* @; n! V! s
    . o& f* J7 `, {4 x* A9 W9 i8 u& G
    / M/ u" M$ q8 G5 `5 A: ~
    def fibonacci(n):
    + A1 K/ T0 G- N% a8 R. H    # Base cases
    9 M6 ?) C0 A- ?* F( s3 [    if n == 0:! _* a. C; b: _4 ?
            return 01 x1 [/ `4 L5 D
        elif n == 1:
    * m% {& k6 K6 ^8 C        return 1
    ; w9 J% s. ?: T8 K) o    # Recursive case
    6 ^+ s" M5 D8 X9 _9 W4 Q7 a; b    else:9 G6 n2 B8 |* K
            return fibonacci(n - 1) + fibonacci(n - 2)2 b0 I% N; {4 X2 u/ Z' t% A! k2 D( ?

    ; C; D( P9 o# g+ N$ b/ r# Example usage
    % u" d4 L$ h2 F& n5 }0 d5 ?print(fibonacci(6))  # Output: 8
    7 s9 n7 g- s6 M; L4 }* W2 G. r8 O6 L! k! y  x
    Tail Recursion
    8 N1 B! t2 v& ]$ e4 k+ w2 w/ Q7 a
    6 x! g6 R9 d) ^8 ETail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).) M2 j  a' n# x2 V6 n

    0 `$ T, I, y0 o" X) eIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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