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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ! n3 ^2 i2 g3 B/ J. V0 V( ]1 \

    1 n; _5 H3 B( |; J0 n解释的不错0 c# b7 Y4 @6 E  S
    7 d4 W( E5 X6 x2 C8 o0 y8 d3 w
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    , @: z3 [, u& m2 U9 o0 p" ]4 u9 r/ s% I  m2 t# C" q+ s
    关键要素
    " \, i+ {$ a. p, a1. **基线条件(Base Case)**
    . K  ?2 Y; k% g* {   - 递归终止的条件,防止无限循环; `# n- y! n+ h- ?# `
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1! Q2 i3 h. C* G' d! i+ U6 S7 {7 Y

    : H& S( O7 A7 x- W% O# g2. **递归条件(Recursive Case)**$ |- b+ E0 t: n2 B+ b$ l$ [
       - 将原问题分解为更小的子问题- i7 u. r8 n4 U' H
       - 例如:n! = n × (n-1)!3 D- H+ {) z+ t+ j9 @4 y+ e/ J( J# w
    0 W+ H; F: s  v4 g1 m
    经典示例:计算阶乘' P( I5 X0 ~, e6 f4 \
    python! _, r( Y+ {* V# |2 n# M) S& p, L+ F
    def factorial(n):0 \, G7 u6 G4 `% ]# \
        if n == 0:        # 基线条件
    $ W2 g" B+ l4 Q' n        return 1( t( `, F5 N8 R3 W8 [! d$ e
        else:             # 递归条件
    # `7 t& ~$ @. c& _, I1 h% |        return n * factorial(n-1)
    ! ~. ]' z3 a# \7 o$ j' M; ?执行过程(以计算 3! 为例):
    2 h  |: d9 d" U- v: r3 }factorial(3)
    8 K  I1 ^( W' u, q0 y- J+ d3 * factorial(2)3 `* f# C! q8 ~% }* b! s* K! Z( `- F
    3 * (2 * factorial(1))
    ! ^. J! u2 u* O# C0 J$ m0 g3 * (2 * (1 * factorial(0)))/ w8 q" e1 N& y# K
    3 * (2 * (1 * 1)) = 6
    " e3 y& E3 F' ~% [; E) a4 {
    / J8 M0 q2 {: g; k1 V, _7 g& R 递归思维要点# ~1 Y3 S: F' J9 X# O
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    & S5 S, |+ o) N. M9 X* g2 u8 N2. **栈结构**:每次调用都会创建新的栈帧(内存空间)" I8 p& z( e4 P
    3. **递推过程**:不断向下分解问题(递)* I' F$ O$ m+ D# K
    4. **回溯过程**:组合子问题结果返回(归)
    0 _7 g4 p9 N8 |
    , j% d9 N8 h6 [0 {% I" ]! w 注意事项/ O# F* i+ Y$ \  h+ H
    必须要有终止条件+ ]6 V( e* |+ x, c) @
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层); H3 n& a* [8 o% _9 y7 e; n9 n* f
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    + w) ?6 e  q6 }/ n/ F. ^. [/ L. m+ `尾递归优化可以提升效率(但Python不支持)
    * B3 F7 f7 b( \+ j) U. F. K6 [- O& k7 j
    递归 vs 迭代# Y! ?- i: R/ o# i/ q8 o0 l
    |          | 递归                          | 迭代               |2 K; p9 c/ {# n- b6 V
    |----------|-----------------------------|------------------|
    7 h/ {7 o4 t- v2 G) `6 h| 实现方式    | 函数自调用                        | 循环结构            |
    1 |/ n9 u4 n  Z2 g. @) k' O| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    ; w; h1 F6 M. `- U5 B6 ~- j& d| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |" Y! O9 |# d) y9 C* ^4 ^. @$ T
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    2 b, r3 s  {' ]' ^4 }+ D, y4 g2 D; V. W. N: V" n5 S" L$ o6 A
    经典递归应用场景
    ! V: X+ n1 I# C# @1. 文件系统遍历(目录树结构)" b; z3 _8 ]0 W/ P* ~
    2. 快速排序/归并排序算法
    : p; j( h7 o, y, `$ m/ p& S3. 汉诺塔问题3 w; V" q8 A) o  D
    4. 二叉树遍历(前序/中序/后序)
    4 Y$ m! _4 @9 c9 i- N: I5. 生成所有可能的组合(回溯算法)" P$ a1 |/ ?' Z

    8 P4 M+ z+ P- L9 c  {0 l5 m试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,2 W- R* O; L2 |7 c8 F3 s( r/ ^
    我推理机的核心算法应该是二叉树遍历的变种。
    4 u$ v% ?& P( q# m7 R! o+ Q7 M另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:% D/ r7 j4 T( x( s. o1 L# r% q3 c
    Key Idea of Recursion
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    5 l9 v, w9 \. K) M/ l0 dA recursive function solves a problem by:
    6 {  J) s) n9 T" f5 _2 P4 D! c8 I8 E0 h
        Breaking the problem into smaller instances of the same problem.; ~6 B; y% X  o( b" c5 A$ |* e

    " ~: L- N7 m/ e    Solving the smallest instance directly (base case).
    ; c, Z# k# }% c, D( k" M6 O/ D/ ^
        Combining the results of smaller instances to solve the larger problem.
    : @1 B: I% B  j5 m3 v( \9 |" {
    - X+ Z' E. r3 Y) g% vComponents of a Recursive Function/ V" C2 \" L! ~# P- j7 A

    / x3 V. B6 ~* c    Base Case:& r6 r0 N, {: l3 [, C' s
    # s6 A5 w& I' V! f
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    & U$ @$ n% A8 y# q7 ~3 Z9 U5 z' m) [& B
            It acts as the stopping condition to prevent infinite recursion.$ y- {1 b- ~; J$ H
    7 g) L6 O' n+ `" x
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    8 y. t7 C- W# g; o# }4 Q
      G& L6 z/ ^5 e8 W" E  B    Recursive Case:
    4 b( V3 ~4 H# ^2 c$ t* Z) J1 o3 @1 w
            This is where the function calls itself with a smaller or simpler version of the problem.
    * Z; v% Y& I  }- ]
    ) t' Y+ p7 ~! C3 q$ R' J& R        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    " B( d8 @9 ~  k* n/ ~
    8 D+ I  f# Y0 b3 {( JExample: Factorial Calculation
    : v5 G+ T; p- S( a5 l
    " ~/ c( P2 T% p' [) |The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:' W! Y9 M0 m, _; v! R8 i* l
    ! `3 T% B, D* \2 Z* j, u! c2 }
        Base case: 0! = 16 W* V! @) j5 {: t' l
    5 b9 c, P2 l5 m( ?( ^8 m
        Recursive case: n! = n * (n-1)!% e  Y) Q( x" K4 q

    * G2 S" {2 B/ l" |4 C. IHere’s how it looks in code (Python):0 A  D8 D: M% T5 `+ ~! ~. l0 U
    python$ D) R4 g  O7 a) L7 A3 W

    ; ^# U( ~, g# N9 H; {' w3 N8 S8 e$ B* W9 a$ n: a
    def factorial(n):
    5 P6 r" w! T; j$ G! |    # Base case
    % M5 e: s1 Y" K6 r# \( R, u    if n == 0:
    / B/ j, b- I3 e        return 1
    1 Q+ F7 c' _' ]4 ?) T0 u: h# G    # Recursive case2 i/ Q- e+ j. \; g! n  w+ @2 M
        else:
    ! s0 @1 q/ m; |. f( q" g        return n * factorial(n - 1)3 d' k! Z6 D: P  ~2 n; e+ q

    0 k6 r4 B; J) @5 M5 W6 [- U# Example usage/ i" f, Y# P% [: s% P
    print(factorial(5))  # Output: 120: u  u8 v" L+ Q: g1 q; b
    . E$ J- A- D. g8 I: l# [
    How Recursion Works
    + x  Q7 g  V  C+ R  D6 r4 K# ?& }5 Y: }! `$ Z  w# d/ O; B# ]. z
        The function keeps calling itself with smaller inputs until it reaches the base case." K* V0 p  B5 k: u8 C5 ?0 r% Q; n

    ( D) [( h8 A* Z) R+ [9 f) i    Once the base case is reached, the function starts returning values back up the call stack.
    * r! v' v7 [2 a* ^' i) W2 I6 b" i% C/ W& @; ^
        These returned values are combined to produce the final result.
    ! r) T& S( G. n
    2 A" T* u8 ~& z. |) PFor factorial(5):" z9 I/ W0 r2 i* }3 e' c# n6 f

    $ J. T  G: O; y7 \8 ?, D% U* r7 D* l8 ^# d0 g
    factorial(5) = 5 * factorial(4)
    2 K& V5 \, N/ K8 \! ?* Hfactorial(4) = 4 * factorial(3), F" |* w  l; \
    factorial(3) = 3 * factorial(2)
    ; H. G* N: A5 ?: M/ yfactorial(2) = 2 * factorial(1), w* D. l% i/ ~! |8 \
    factorial(1) = 1 * factorial(0)
    6 _) T% A  K6 x! \. Q, lfactorial(0) = 1  # Base case2 @7 A- P) c4 r9 O3 g
    5 R$ n6 t( p: L. G, ]9 D% ~
    Then, the results are combined:
    ) g: i$ y+ F+ b1 p+ l& g5 b* }# K: U/ i
    & \- m  |# B6 u! E0 |
    factorial(1) = 1 * 1 = 1
    ' n5 z/ F" ^% nfactorial(2) = 2 * 1 = 2, a/ l: K9 A4 j
    factorial(3) = 3 * 2 = 6
    ( f% ~6 h, G2 zfactorial(4) = 4 * 6 = 242 u' ~3 b5 D- M+ V4 D  c
    factorial(5) = 5 * 24 = 120  j. S$ h8 z! G* V" Y

    9 m1 ]4 R. c7 M7 I2 c9 XAdvantages of Recursion7 t$ Y* x: w+ c: [, V$ O( N
    7 f0 X8 b( \4 ^4 Q7 F) e7 [
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).3 G/ B& N. {3 V8 Q7 P, z4 A

    6 ?1 @" G) r5 x. L    Readability: Recursive code can be more readable and concise compared to iterative solutions.
      g! m- D( r/ Z3 Y8 h/ V1 P/ c7 d& u2 D# w# V3 ~
    Disadvantages of Recursion
    1 h" g3 r3 J6 O
    ! D2 d% e7 s) b& U0 \! S    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    & v! s6 k, M: E& u; h" P9 E; V3 @" {" W$ Y' _* C$ e' N% j. T
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).. c+ h: U6 I2 ]) D# ~& H
    4 `4 C9 S8 ~: h4 J# T
    When to Use Recursion
    ! W* b6 g% }" T4 ~4 v) T  n, l" Z( ^0 ^, Z# }- P& x+ X2 Y& ~7 o; }
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).1 {9 ~4 b4 a0 [# r; r( L

    * f3 z/ S; D7 J, N5 D3 @' C    Problems with a clear base case and recursive case.8 i; Q" ?* K# a
    # G8 w9 c+ ?0 y5 h% L$ u$ p
    Example: Fibonacci Sequence
    8 j+ o7 T9 }. z- o( j1 l9 C3 y. L8 g! K5 O  C: P" X; n7 |
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:; M6 u, a- z/ Q, c  `" R
    ( u  ?* ~) Y( i
        Base case: fib(0) = 0, fib(1) = 1
    # |6 V5 A* P- f! d/ y. `# \
    # S8 l" e. v2 h* p, W  M, I. y' r3 `    Recursive case: fib(n) = fib(n-1) + fib(n-2)
    / T$ |2 h1 d1 v. k3 H/ M+ X% _( e3 i  P& ^! E* K
    python
    ! V, L/ F* l& l& Z4 l
    ; ^& ~1 K1 `. d, ~$ K5 F, z4 u# z4 y& ]5 h4 N' M$ A
    def fibonacci(n):
    3 v3 f2 I  N$ F& k    # Base cases0 ], ]+ H, x" r" `) w7 j- ~
        if n == 0:
    & D0 \# e( M1 K! c3 H5 N3 C" x. r        return 0
    ; T7 F- e' p' x- S& v* J, l    elif n == 1:! u% i' Q( H2 d
            return 1
    ; L5 A! o5 t4 }5 `1 P3 v& N    # Recursive case( j7 r7 {4 m% t- }! I
        else:
    1 _5 @9 c0 e* B- G* [& G+ g3 I) w        return fibonacci(n - 1) + fibonacci(n - 2)
    3 T- }, f; o: [- x( E5 }, H5 n/ ?0 D6 r/ B5 w7 z3 }
    # Example usage
    2 @$ p3 b8 s8 g$ a4 n1 \% g, nprint(fibonacci(6))  # Output: 8
    ' m* d2 ~" d! B7 \9 ]( T
    , ~) }9 e5 g0 ^5 x: dTail Recursion
    3 p( h; v* C6 ?3 U0 y6 Z
    , f+ k& d3 b6 }6 d5 y0 [Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).& P/ q+ k! m; I6 S
    ; W1 t- [9 P! m, _; r, s  P7 u
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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