设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 3211|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 9 J( ?8 b3 Y# Y% _( h! {

    : t( R0 ^0 _6 }; n解释的不错
    # ~+ E0 P  ~1 l4 @7 A' O
    : g( W7 Q- \3 B3 H: f  N递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。" w  C% C; n/ d* u# n$ O: ?# l( l

    . K* Q2 x% _2 m0 P- i 关键要素: G) u( _3 T$ r4 n7 p, _
    1. **基线条件(Base Case)**4 @2 G  b% W* m- e( `
       - 递归终止的条件,防止无限循环
    # `- ^& ~' D3 p+ r% X   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    , y& B; A6 [8 S6 E
    8 X, G! J" F4 T8 {& K: q! a2. **递归条件(Recursive Case)*** ~; ?5 Z2 p+ V4 M
       - 将原问题分解为更小的子问题
    + V& x; v) T# W$ `8 s   - 例如:n! = n × (n-1)!
    $ h( k; s9 |3 m5 a
    : R: c+ r3 {7 G. Z/ s4 Z  Y( d 经典示例:计算阶乘) p- W4 S) D" u/ w" e, Y6 T1 n" r
    python' @: `3 [- j* }/ ?# Y
    def factorial(n):
    # i& d+ X) o/ J$ r# L3 v    if n == 0:        # 基线条件# o3 `! h7 h# x8 D. r# z, c. W0 B0 G
            return 1# Y9 m# x! U  G& [9 s3 ~, Q
        else:             # 递归条件5 p* V; V! V1 w3 R  y
            return n * factorial(n-1)' R8 ^; k/ |, ]) v$ K
    执行过程(以计算 3! 为例):
    3 C2 g3 l' P' q/ t8 w+ `factorial(3)
      d% H) o' a; u+ T3 * factorial(2)
    ' s! P( E9 N) k$ l! n0 O3 * (2 * factorial(1))
    : h; [9 f6 G' W( `4 M* @3 * (2 * (1 * factorial(0)))
    4 w+ A# D. z! m6 q# k4 L2 f9 ?3 * (2 * (1 * 1)) = 67 h$ a' S; b# A, n
    ' {( a8 D0 F4 @# K& j) i2 U
    递归思维要点
    # X6 r5 ]. A, X2 ^% H" |& S1. **信任递归**:假设子问题已经解决,专注当前层逻辑: M/ W9 q) d, }' G
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    " ~5 E0 j) R# w/ o1 I2 ]3. **递推过程**:不断向下分解问题(递)) l# A: }% L2 Q8 x1 d4 d
    4. **回溯过程**:组合子问题结果返回(归). m. d; G1 f- S

    8 t  b3 i0 r& v, G- Y3 o7 G$ p" [ 注意事项+ ^; F  ?5 N0 r6 q" {8 ?. n: e
    必须要有终止条件' d4 I6 N$ V1 T9 \; ^6 u) ^* r
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
    ( s$ f# v! w: f某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ; u; _1 {" j7 L; x尾递归优化可以提升效率(但Python不支持)
    1 x) B/ _% q5 H9 j0 ]7 g% j7 D2 H, k8 H
    递归 vs 迭代! h" L* v4 S9 r* |) r3 e, V
    |          | 递归                          | 迭代               |
    5 t; f) x  o* P0 Z4 b4 o|----------|-----------------------------|------------------|
    * y9 k' F& }: u5 ^# M  l6 Z: U% U1 d| 实现方式    | 函数自调用                        | 循环结构            |
    0 P5 d! N+ _$ K& R% h| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    , O9 K  x4 l2 G3 M  i  ^| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |, k% z/ q7 e% T- f
    | 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |- V9 ^# c& l8 u# m/ N- o

    1 c: ~- w" d; V/ } 经典递归应用场景% e) L/ ~, D, t# R9 o
    1. 文件系统遍历(目录树结构)  {+ {, y; e- D' {
    2. 快速排序/归并排序算法, c, k9 `+ ~1 {3 e9 I
    3. 汉诺塔问题# B* I; [4 \2 @; i
    4. 二叉树遍历(前序/中序/后序)& ?4 U, B, S1 I+ t( M& S
    5. 生成所有可能的组合(回溯算法)) N2 _0 d; r( O8 D# ]+ t$ t
    % y" d) ~8 y. [6 T
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    难过
    9 小时前
  • 签到天数: 3337 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    8 g; q4 _- Z, ^# O3 K% V* g我推理机的核心算法应该是二叉树遍历的变种。
    ) S3 L. B0 Y) w( V3 x另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:, l7 r6 o) y' T& C( j# p
    Key Idea of Recursion7 S: T  u6 l# H" _) ?4 v" s

    ) C8 M  o0 c' xA recursive function solves a problem by:
    + _+ Z: J8 e$ s. k. h1 S9 u: Y4 v5 y( H  }/ A
        Breaking the problem into smaller instances of the same problem.
    & a( V  r6 E0 R& j3 h3 U% G$ V: q# u  v5 u2 R$ [6 M; j, j2 T
        Solving the smallest instance directly (base case).
    4 l1 r8 F- U0 ^, K: G$ R
    - G1 S6 }" w4 r9 h    Combining the results of smaller instances to solve the larger problem.8 J: g& Y) @% N8 k3 L: h8 Z* ~
    + Q. |! h! ~0 b' H! \
    Components of a Recursive Function" j" z: D7 N0 T" |

    5 n% |7 Q; e+ C4 o9 b& }    Base Case:8 W7 S! C# A& U9 g
    * `' c3 P/ h. U( Q* b
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    7 ?) A$ O- G% r7 b  U' C: T2 E3 W. t- y+ i( `" G9 h, l- [
            It acts as the stopping condition to prevent infinite recursion.# W$ C" e# z! Y3 _+ f
    " `; g0 w: v/ f) {' e" @
            Example: In calculating the factorial of a number, the base case is factorial(0) = 1.: A2 z0 I. l% o* n# i! W0 f

    ( ?6 K0 k" }/ }' G5 H    Recursive Case:
    7 N; c3 D+ P) k7 _/ _% \3 J8 V' U; [! ^
            This is where the function calls itself with a smaller or simpler version of the problem.- M; Q1 t! R) B8 c
    7 g5 F3 k9 v0 h. Y  m7 |+ w
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
    4 V9 U# ], x. a# r( J" j% M7 x
    Example: Factorial Calculation* n5 [/ L( M" j- ^3 k' `
    / s: l/ R1 `% n9 J# o
    The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
    0 T* G* P' @$ M/ n9 ?0 B6 L8 _& B5 i, o. Y1 w; c" Y
        Base case: 0! = 1
    ' w5 R9 K$ H, N$ B4 p5 W& t% m( i" m- m1 w8 _
        Recursive case: n! = n * (n-1)!
    ! `0 K9 p3 r& k, ]( C7 q6 Y: x1 k. U( ?- j- _
    Here’s how it looks in code (Python):6 K: ]4 _$ u8 A5 [; R! J1 e
    python
    6 ?! v3 c6 }/ W" Z4 z
    ) N7 I' y2 x7 |4 V. \9 Z% B1 E: T& W2 ]0 _; \9 r2 A
    def factorial(n):
    7 E$ v* m2 I9 }* w% p! S0 z) n    # Base case/ c: l0 [1 N9 x0 @
        if n == 0:
    ' k- T6 K" W  ?( e. K        return 1
    / q( N" C% f" x6 i    # Recursive case
      J- q- R% N7 x# {  J3 h; Q$ _    else:: s$ s# T8 ?# E8 q9 a
            return n * factorial(n - 1)% f6 t/ U# ^* u& I+ W0 G" T+ r
    # {! j$ L: U" _9 f
    # Example usage) O/ T: G; u- B% Q; U0 ^
    print(factorial(5))  # Output: 120# _9 p! b* M* y5 T+ s9 A
    / y6 g# T6 }; y+ X$ E
    How Recursion Works
    5 z% N! Q; e. `  g+ r
    ' N) A* ^' O; f* u    The function keeps calling itself with smaller inputs until it reaches the base case.7 @+ g: r8 R+ ?# [4 a* \  v* @

    5 a% R1 A- n: F, d    Once the base case is reached, the function starts returning values back up the call stack.! g4 p- `: O4 p

    * r9 o  C* \: [) T, S    These returned values are combined to produce the final result.
    $ U* U, f( h# ?! k2 |3 q) \0 a% _( m! X( A
    For factorial(5):+ |. T" N# Y. ~* y) x, Q7 M# S

    - G/ q4 I# e/ z  b( ~7 B( i- [$ k4 t' \
    factorial(5) = 5 * factorial(4)
    " v+ e  E+ X: h5 G7 A# p8 _factorial(4) = 4 * factorial(3)
    - E8 @% `' f  O6 r9 Y- ?: Pfactorial(3) = 3 * factorial(2): ]% }7 P+ T  s* a0 O3 T
    factorial(2) = 2 * factorial(1)
    " w$ N- Z" w& t' A4 U$ [factorial(1) = 1 * factorial(0): v: m+ X& b6 J" Q+ c
    factorial(0) = 1  # Base case& V4 k1 U$ G5 q
    5 G; S! T+ p4 m8 O
    Then, the results are combined:
    8 D# I9 S6 A  m* \
    5 i( u: t! y+ D' R8 f, A) t& u  w) X  H/ E* }+ g
    factorial(1) = 1 * 1 = 1- {; @: \& [7 q( S
    factorial(2) = 2 * 1 = 2% p: {) G/ H, m6 v4 ^, Z. Q' D  l
    factorial(3) = 3 * 2 = 62 C9 @1 t( w0 g  P; @  n: m
    factorial(4) = 4 * 6 = 24
    9 I/ W: [( C2 ^3 G, F( e! Dfactorial(5) = 5 * 24 = 120& ^; X! Y$ e* [9 ^

    * s( ?, v* Q$ y  G) L  [) ~: R  t+ u, LAdvantages of Recursion
    9 |) Y+ E- p4 j5 {9 F8 c$ R. w
    % r9 s0 i) s2 F- b5 D: \1 j+ [    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    " m$ c; X& R, z! E8 I: {: F0 W4 Y& [4 m! V
        Readability: Recursive code can be more readable and concise compared to iterative solutions.0 v7 ?7 Y% ^0 W, T/ }7 l3 u

    7 Q' S& s" k. t5 B$ {9 A* UDisadvantages of Recursion! N/ Z5 Q3 {# J& a- K3 u
    ) ^9 \6 Y) A5 U" K, q& m* P
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    2 n4 x6 S5 {# Y! {7 w; y
    6 ^% v. ^: V1 l$ a    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).8 L. R8 R7 E* _( J7 p2 u
    8 \; o' o( N" }" E+ V6 }
    When to Use Recursion9 @! N+ R; z+ E, X" r) i# u: r
    0 a- M3 }9 f6 A* z' S1 I. @
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    6 f3 {" N) ~  t# O8 h: l4 R3 j/ S
        Problems with a clear base case and recursive case.) `5 x) L* ?. d! w0 y

    1 _6 H5 S4 ?0 Y' t0 _3 TExample: Fibonacci Sequence5 @3 x; y& I5 Y+ g6 A. J

    5 ?( ^$ ~  O$ V9 HThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    " M1 x4 I, g* q# t
    ; Z6 w( n4 T( }! `8 _    Base case: fib(0) = 0, fib(1) = 1
    , L0 j, D% L8 N4 S4 J0 Z7 P/ T) N$ E5 _1 E
        Recursive case: fib(n) = fib(n-1) + fib(n-2): y* x8 {5 n. }3 t* W! P# T
    9 o$ x, `, s% u! G% V2 x* p
    python! E; H- _, X. |' v

    # A+ ]7 c( S' S6 {4 X0 x' C$ ^3 v, O) B: ^
    def fibonacci(n):
    5 H; A7 l4 O; V/ M9 x    # Base cases- v2 j+ s% `. t/ w9 z; m
        if n == 0:& j3 [9 `/ W+ y4 Y; I3 i
            return 0
    9 t. z0 |" L2 X/ c3 }7 ^( F    elif n == 1:
    8 l4 ]4 f7 O. a0 d( E7 R% Y8 n        return 1$ U! Q, m( Q' R2 L* y
        # Recursive case2 ^) a' m3 P4 r7 d' a+ F) _
        else:
    3 V6 z& m# i/ K) c3 R6 s: S1 c6 f        return fibonacci(n - 1) + fibonacci(n - 2). I4 w; z# j! C8 j$ y+ v5 \, K/ K
    " l4 U( `( W; L, _& V* o5 [+ p$ Y' [
    # Example usage
    ! k( z9 e( Z* B# G' ^% u( X7 A# Tprint(fibonacci(6))  # Output: 81 r; l2 ^, L6 O, ]# \( \2 O8 [

    + \* [2 v& s) E0 C- X* a3 ]4 jTail Recursion
    ; y+ b7 V; x+ C) {$ A
    5 g! M* k1 i+ ~& P; LTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).' N* S& O6 h, K* ~' n: u

      K7 ?9 x. u" y; I' M, r& |In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-9-1 14:55 , Processed in 0.065697 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表