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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

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     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 ! K3 k7 L- h/ f8 h4 [
    4 x3 J7 P9 _4 e' H8 [4 b( f% r" }
    解释的不错' ~2 L- ~8 t# A" n4 I. ~6 x9 _
    ' m) `8 T, h  H' Z0 {& n
    递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。/ G2 X1 p+ ~) I5 Q

    . b$ E5 h! J, U 关键要素  t7 @9 Q- T+ `& ~
    1. **基线条件(Base Case)*** o! R7 @& t. Q* P4 |; g9 Z+ J
       - 递归终止的条件,防止无限循环
    ; B8 T8 k2 O( h" B! y/ J% D+ S   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1" r2 n( B4 W6 v/ ]+ Y! l3 S, v" j, `
    ' R5 z: e) N& S
    2. **递归条件(Recursive Case)**
    4 @4 q; p1 `9 m) u5 E   - 将原问题分解为更小的子问题
    3 B  r# Z- i$ y# [/ ^   - 例如:n! = n × (n-1)!
    & a/ K) ?' t' N' T- d  }* H
    $ z5 `/ n0 I5 S# M 经典示例:计算阶乘
      {, f, V/ S* l0 b) j3 H/ tpython8 ~" h* B* b6 F, ?
    def factorial(n):; E- I9 ?6 u# v# c0 V) F4 A7 {" K
        if n == 0:        # 基线条件
    , V" c& P- d- G        return 1
    5 Q* {1 K6 q' x" B+ V( c; [    else:             # 递归条件
    ( W  C& J$ t: l" q: n        return n * factorial(n-1)
    1 I3 l& f7 b# |8 X6 _& T执行过程(以计算 3! 为例):; N" i0 s9 y- z' T6 W  b+ S8 A
    factorial(3)8 `+ g/ R! d; C7 }- Z4 T: G! P
    3 * factorial(2)  ?7 a3 ]% }" f( }7 x# q4 ^
    3 * (2 * factorial(1))' C! s# V. e2 f/ g& x1 e. N% M9 u
    3 * (2 * (1 * factorial(0)))
    $ x8 W0 X* X! v* K/ H) e3 * (2 * (1 * 1)) = 6( B: W. L9 `9 Q- f3 X% ]

    4 b; C7 H8 K; [& d( u" `0 i 递归思维要点
    , z! }0 l# G+ L1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    / g0 v# F: n" R! W2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    * V2 f, |7 e% Y6 {4 j) G8 K3. **递推过程**:不断向下分解问题(递)
    * R0 `% S( n, k( s! A4. **回溯过程**:组合子问题结果返回(归)
    . s& f8 R, F, |7 v8 m: L; l# j4 e
    , k" H. c. a# P7 X. [( N3 M) w0 j 注意事项
    ( s2 i: O3 a1 T# k. i3 g必须要有终止条件6 l  ?2 o, Z& }; S" \: _9 m
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)2 ?9 m& [' }( a9 T& _% j
    某些问题用递归更直观(如树遍历),但效率可能不如迭代( t- V  r( J0 h  F4 e
    尾递归优化可以提升效率(但Python不支持)7 A" @5 c- C5 B. m0 X! D+ a( A. r, C

    ! Y) z3 A. o, o9 w+ r/ u) M 递归 vs 迭代
    . q* k3 t8 i: n$ F) ]" }; q|          | 递归                          | 迭代               |
      e5 A. |1 X' D8 M|----------|-----------------------------|------------------|
    ) Q2 @0 k* b: w! L: }. B7 S| 实现方式    | 函数自调用                        | 循环结构            |
    & Y  s, r' y6 k3 E- ~| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |9 |' x8 \2 z4 c0 N( P
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    4 C4 w6 ^1 r. A; A( i| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |: K+ n7 J0 u% p, [  A! p

    , Q1 S/ w7 L& a0 A3 ^  M, _ 经典递归应用场景
    1 F9 w" U. l3 n9 h/ ^1. 文件系统遍历(目录树结构)8 C5 `! g9 C& T; F# U# K3 X' u
    2. 快速排序/归并排序算法
    " |8 t4 M1 R8 t! |" m/ h( Z3. 汉诺塔问题
    & |, G2 l1 F! A: [; u& F, i! B. @4. 二叉树遍历(前序/中序/后序)" a3 `' ?# i$ E/ @/ w! |7 U' Z3 b4 p4 g
    5. 生成所有可能的组合(回溯算法)
    1 N2 L/ T7 i* ~5 a! `1 {% r2 }- ^" Y9 ?; L3 a; \
    试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,9 J) i2 k3 ^- l
    我推理机的核心算法应该是二叉树遍历的变种。
    3 a& b  Q/ o! c5 {- n. l另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:6 K" a1 p# N1 J8 {; G& y
    Key Idea of Recursion8 L8 E2 e% Z, w9 h" B

    - q9 ~. c5 ?' y) w+ UA recursive function solves a problem by:
    * u6 X) I; v" v( I% w$ T4 U7 ?  \& q* e7 i* C
        Breaking the problem into smaller instances of the same problem.
    5 E6 T7 J9 F/ ^6 S5 F, {* K- J0 I# y( h) B* R! y6 D
        Solving the smallest instance directly (base case).$ N$ @8 ^' W( Y. }; ]  g& k: g
    ) B* L! K; w: g9 p
        Combining the results of smaller instances to solve the larger problem.
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    Components of a Recursive Function! u; a, `" I0 s. N3 d2 U8 Y
    # ~! ^+ |1 \1 A& {1 r1 o+ j
        Base Case:; l% Y' O4 y* ]8 U
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            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.3 a1 J) ?9 U" @9 e, m: p1 Z

    * g9 W8 n1 {: l6 b2 L        It acts as the stopping condition to prevent infinite recursion.! f* S0 K/ g( ~+ Y) o- c

    0 j* t7 X1 e1 w  z5 W        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
    ) S: A8 ^) w( j' L  S7 C1 F! a/ u; v8 R
        Recursive Case:
    4 b1 Q0 Y- a  x* Q( Z: i$ w0 d3 H9 _6 }' P( ~
            This is where the function calls itself with a smaller or simpler version of the problem.9 |/ P/ r7 A9 R/ D$ v1 b: O

    ) Z' M$ C4 u# y  v! R3 x        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).( x: A% C$ K" f4 [

    0 e& x' ~. W& L7 XExample: Factorial Calculation% ?5 T$ o. [+ h' P3 A

    . p  f8 z' {8 f/ ~+ W! I  PThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:1 i; e) i* a6 M. g, @( |1 c, g

    3 M2 ^% [+ T. {7 l; I    Base case: 0! = 1; m& s" r1 g7 u& W1 x! S/ T

    ) N9 E8 @: p& R2 j    Recursive case: n! = n * (n-1)!# T: h) L5 b8 k6 k  b

    : k( M/ y# H9 ?; @Here’s how it looks in code (Python):2 G* M7 V7 B# t: z
    python! q& m& G- C; W0 }% B- |

    ' K  d' s8 w! A, p# a) |( P, a6 H2 Z' K) A/ ^
    def factorial(n):* l. _% P9 U9 n0 \- G) j  k& p
        # Base case: ]4 ?1 f% q$ l" ^( H
        if n == 0:) M7 V0 x# E, `4 K8 S8 O2 v
            return 1
    0 x% d  `% j# \7 z- Y# D( i; a  {    # Recursive case+ T+ T; K8 L; l3 V+ h% ~8 m& i
        else:$ K9 W% X" A& J8 W8 t: {* x
            return n * factorial(n - 1)
    8 `, t+ z% {& P! s. Y, C* s8 y+ N& t3 W, Z8 Q
    # Example usage' j, J- l' B1 ^6 j4 q, ]: Z3 F
    print(factorial(5))  # Output: 120. S/ e* u. w9 y) |7 O
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    How Recursion Works: Z* P+ Y4 t3 c& R! t( Y

    $ p4 {, K0 k1 L! I9 Q, O    The function keeps calling itself with smaller inputs until it reaches the base case.' b( d3 b: K6 M; e0 }/ q8 y( `
    - i# o9 u* \$ g* G- ^8 H! X. ~
        Once the base case is reached, the function starts returning values back up the call stack.$ f1 A: z4 E: m( ]6 P
    1 z4 ~( [. P* K/ P9 r: j
        These returned values are combined to produce the final result." {: Z; Y* B2 T* e
    * P8 @% d: p* P/ H  k: o* G' {
    For factorial(5):3 a- C( i7 o# Z! `

    7 [$ {8 E# @. Y5 B$ O: p% i& }# N
    1 b; u6 `6 z; ]- Y' Y, _) X; G3 Gfactorial(5) = 5 * factorial(4)
    ) f+ y- d& g, G, ]; Pfactorial(4) = 4 * factorial(3)( A" [4 _* b) D- N) i& j! f
    factorial(3) = 3 * factorial(2)
    7 D: J5 b* ^1 N' m1 `factorial(2) = 2 * factorial(1)
    3 U) U! K% y, Q: ifactorial(1) = 1 * factorial(0)& l2 B, v0 V6 b3 ^
    factorial(0) = 1  # Base case
    ( e/ \1 ^$ x7 B  j8 m- ]3 h  m: a8 y4 I/ t& E1 o; {* \2 _  d
    Then, the results are combined:
    3 t# d( L8 v* B; Z7 b0 z7 ?8 W2 E  I4 i7 |( T( A5 o) x
    0 J+ I$ ^) ?2 O& [) o6 z
    factorial(1) = 1 * 1 = 1
    : O7 [$ t+ B; T4 l- a: Bfactorial(2) = 2 * 1 = 2
    - E3 ^% Z2 v; \% ]# @, cfactorial(3) = 3 * 2 = 62 K0 ~0 D5 [" k* E. F  Q& d, o# x! S
    factorial(4) = 4 * 6 = 24
    6 h6 P2 V& N7 n. Mfactorial(5) = 5 * 24 = 120
      L: q. n9 E, N0 W3 F5 d' @$ k8 |. L9 i
    Advantages of Recursion
    $ Z% H/ Z3 d% U- v) G1 J, |0 a2 A! T3 f5 o  I" j+ ~
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).* u: {, ]$ [  E/ }2 P6 }  G

    . B5 u+ o* H1 }1 W# m* e; V+ X# ~. S) w    Readability: Recursive code can be more readable and concise compared to iterative solutions.6 U! o' K6 ^4 k0 u* w6 o* a

    + h- W* D2 O0 o! {# N4 CDisadvantages of Recursion) H8 y8 v! o$ k8 _4 r

    : G3 G, v& _3 `/ @- s- i1 H! q    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.6 G; c$ r) c" r/ {9 v9 s0 q

      ^& m( G3 P' ?2 i* t, ?6 j! y    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).& _  H; g7 u) _7 D0 b

    2 h0 [2 n0 [) W" A. Z8 y3 {When to Use Recursion# J  H+ Y5 L" f* v$ |; a

    5 l: h; x: a, K5 W- k    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).5 @' X, L+ _1 f& H8 k8 Q& j

    1 `5 K( m& }6 K& f, w    Problems with a clear base case and recursive case.
    1 ^& G: l$ t* a. h# R- J
    7 x+ j! e4 k7 f* y. @) BExample: Fibonacci Sequence/ O8 p( g# L# o# v2 V/ U
    - N8 W) a- @  i% ]
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:; ^! h8 ~8 R+ @) w+ y

    # B6 s0 \: j) [( T+ K    Base case: fib(0) = 0, fib(1) = 1. U$ m0 ]2 Y$ a* H1 @9 I, n' l

    ( z4 \6 T' ^, p& s. a    Recursive case: fib(n) = fib(n-1) + fib(n-2)0 O1 R. ]9 Q3 P9 F- E' e' p

    9 c& j, D5 @& k( f$ o0 a/ apython; o3 c2 Y8 L: ~: F9 i8 C& o) i; d3 u
    ) _# M, P& S% W: Z
    * G, [; H! Y) j. N) G6 h; S- |* M! I
    def fibonacci(n):8 [) n- r  R3 R+ M' L
        # Base cases) ]5 r" x' g1 F) p2 A/ {' U2 a  w* R
        if n == 0:
    : J! e2 m5 _' h6 _. v        return 0& g3 |1 u, N& |9 z( ?9 l# W- l
        elif n == 1:1 F! S# v" |9 [0 b. Y" k
            return 1
    , c; s% e! D8 b% X' D    # Recursive case! K; \( l& o. N% D
        else:
    % g& V5 [: `, k1 s  H        return fibonacci(n - 1) + fibonacci(n - 2)5 l7 `6 Z6 L9 ^& `8 @

    9 n5 p: v3 j# A7 ], W& M. Y# Example usage
    ' _% @; h2 h3 |+ s0 ^, n& q5 i" Vprint(fibonacci(6))  # Output: 8
    7 w; @/ T- z* ?9 M% M2 ^& G
    0 v; y; y  w4 m( lTail Recursion
    / }9 @, e6 ^4 [$ L) u% e1 j
    / E# y( x& g* |" L  A7 |Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).& c* v/ o# I1 V/ a0 U5 a4 {8 H2 N
    % N& Q& h9 ^6 r. t+ }
    In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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