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[科技前沿] 突然想到让deepseek来解释一下递归

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  • TA的每日心情
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    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    发表于 2025-1-29 14:16:55 | 显示全部楼层 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 . e0 F3 z* K$ r8 U  r* S
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    解释的不错" {) d; l1 {9 i6 f: x

    ( O+ T3 q$ F/ r$ G" F( z- b* e递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    # f/ g6 D) w4 }9 G4 p+ `0 _* F
    ) z, x, e% N4 \2 ^  f) v' q/ o7 T2 D 关键要素
    * ^) M, q$ x) B6 h6 e# N1. **基线条件(Base Case)**7 s. S& U* l! F0 R
       - 递归终止的条件,防止无限循环7 L2 |% S8 o2 E$ q3 ^7 H6 |
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    & h1 b. q) Y4 N, H# L
    / ^! V9 F6 d( q# E/ c0 t: ~1 J% C4 X2. **递归条件(Recursive Case)**
    # A* E; f8 l  P; s# L1 ?" `/ ]   - 将原问题分解为更小的子问题$ F1 j/ v: k6 q
       - 例如:n! = n × (n-1)!( n( x, f; F' l8 @- J. L

    ( p+ b7 F" k5 O3 L! x 经典示例:计算阶乘1 U- m4 k2 j9 v9 `" Y/ Y$ n9 @
    python9 I, P7 r1 r& K* T, F; J
    def factorial(n):- `: v: x+ u; k
        if n == 0:        # 基线条件1 k+ t- H( `! |
            return 19 ~7 d; A1 R! a* e* b$ T: j2 J5 U
        else:             # 递归条件+ h  D; u# Q" m& H
            return n * factorial(n-1)$ ]( d+ K$ p) r! k# s
    执行过程(以计算 3! 为例):1 U+ M9 k! s( d8 ?
    factorial(3)
    5 i- X5 a1 m% W+ n' H. y0 ?( E+ b3 * factorial(2)6 j7 t! j8 Y  v3 U& H/ X8 S2 Y
    3 * (2 * factorial(1))0 Y0 Y6 d% \4 P0 k
    3 * (2 * (1 * factorial(0)))
    3 f6 F/ d+ ?9 o! a: |3 * (2 * (1 * 1)) = 6% l$ ~$ `( M; K, z* X& Z
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    递归思维要点
    ) p/ a# ^4 c0 L" |- d+ ^/ W1. **信任递归**:假设子问题已经解决,专注当前层逻辑! O3 G# i( x  Z" g
    2. **栈结构**:每次调用都会创建新的栈帧(内存空间)
    ; g% N3 w$ V; e7 i- e) ?2 Q2 @3. **递推过程**:不断向下分解问题(递)
    5 Q$ a) ?1 P8 E* ]4. **回溯过程**:组合子问题结果返回(归)# Q1 F' {" h8 Q% p* V) U' H& l

    4 t2 B0 G0 m5 L4 F 注意事项& U7 U% i: b8 P" r6 ^
    必须要有终止条件
      n/ K' \+ f% p/ ?! m$ _) g- O递归深度过大可能导致栈溢出(Python默认递归深度约1000层); W- ~3 d2 C& b9 ]
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    9 D9 Q/ }+ P/ J" d9 J& w  C尾递归优化可以提升效率(但Python不支持)
    ' H; B% G- A' m  ?) n* }
    " W) c4 ?" B( I" z# F 递归 vs 迭代% y. A# F- [# w( N, N
    |          | 递归                          | 迭代               |; Z" `' P& P( V# E! w, J! F- a4 \
    |----------|-----------------------------|------------------|
    * M# K( A9 t! E' D! t+ z! |% c, _2 ~| 实现方式    | 函数自调用                        | 循环结构            |
    , z# y' _# n/ W| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
    " p- W  _6 e0 Q* M7 m- z| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    8 I$ u6 n5 A- z, s- d; S* ]4 j| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |8 N/ Z- f: ?+ X1 x: N
    . m8 {+ `+ x& o4 p! r: k' D
    经典递归应用场景
    6 Y& ^) L# [6 ]$ j3 n- y1. 文件系统遍历(目录树结构)
    # m; S; f7 j. e% x2. 快速排序/归并排序算法) ~/ I  G1 y  V. W1 f
    3. 汉诺塔问题( R4 D% k5 k3 F/ G2 l, ]. T& @0 ?
    4. 二叉树遍历(前序/中序/后序)
    * u6 N* b5 d* \& {# l2 |5. 生成所有可能的组合(回溯算法)
      u+ Q: A: h, ]) M  \
    " G. P- E* l! ]% A1 A+ \试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

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  • TA的每日心情
    郁闷
    昨天 06:54
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    [LV.Master]无

    发表于 2025-1-30 00:07:50 | 显示全部楼层
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    + y# ~6 M' l; U* |4 j我推理机的核心算法应该是二叉树遍历的变种。5 c0 t; a; }5 C; S/ l9 t) }
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
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    发表于 2025-2-2 00:45:59 | 显示全部楼层
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:- E0 b$ z) h+ M0 z$ t9 N5 ?
    Key Idea of Recursion, @1 Q& y$ D, P, Y* R# J

    5 c, L4 @1 @6 x! s/ oA recursive function solves a problem by:9 [; n3 K+ s& j( Y

    7 ~" w. S, j2 e1 V2 V! G. Z    Breaking the problem into smaller instances of the same problem.
    7 j4 I/ X7 a5 n
    5 @+ @) R/ q% v& ?0 p; ]' f( L    Solving the smallest instance directly (base case).+ L  M3 C$ a4 m

    9 O" j& ~# q5 R% A: ]) b, L. Z0 g    Combining the results of smaller instances to solve the larger problem.
    3 R- Q* m9 Y/ \3 _3 _& E# n4 H1 M4 _# r! _4 X
    Components of a Recursive Function; i( }6 B- c0 E7 N5 T

    7 Z4 [9 F) p# p! \5 Y4 }    Base Case:6 M4 ]# j+ T! T5 z

    ; x5 @/ \5 @& n% w( ~5 C        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    $ Y6 L( j5 d- b  y2 U( I3 ?" }% m; }
    5 ?* o' d# A' i9 m1 Z        It acts as the stopping condition to prevent infinite recursion.
    # w5 `  j$ u, e' G( E% F
    & w' E' n4 }8 K! i5 `4 q: |9 y2 e. b        Example: In calculating the factorial of a number, the base case is factorial(0) = 1., ^1 s* ?0 i9 V  k5 s3 s2 _1 |
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        Recursive Case:
    " w8 V/ Q* t( o) \: ?
    3 n% P5 |& b/ {8 Z# V        This is where the function calls itself with a smaller or simpler version of the problem.
    $ c) ?/ D: x* R% @9 ]5 A$ P: ~9 L. t. e$ c
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).1 u; g1 ^. A; f

    $ i  a/ m# h: n/ h2 v! R, M& kExample: Factorial Calculation
    ! C; b4 M3 _# W2 g6 F. e3 a0 u2 e
    $ y3 @, x; T; d# L& PThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:6 u% [- C4 ^8 _
    0 O* s( P, w/ i* ^5 A1 Z
        Base case: 0! = 1* z1 D" B9 ~. l+ g# |, o

    * E% D: J7 `/ M6 v/ S$ ~    Recursive case: n! = n * (n-1)!3 Z  r) W1 f/ v3 F+ Z: U1 Y7 E. z6 j

    % @, o) N% h3 Z6 G8 c- O) O& pHere’s how it looks in code (Python):
    , R) I) T4 y6 V! T1 Wpython9 I0 Q! x% j+ F- z4 i( s
    / G) O# B- q7 S. S
    / h! x' x: `4 J- P8 R+ c1 l
    def factorial(n):
    ; E( _2 ~' H$ P4 S    # Base case+ u6 u* d, \, W+ ~: C8 E8 w
        if n == 0:
    ; X  _5 Z% l* |, F9 {( K5 o        return 1
    . J, H% J( p) s& B5 B* n' m, m    # Recursive case
    % y7 |4 y  U5 F( ?& j" G$ V    else:& L9 z& W( s1 v, g
            return n * factorial(n - 1)( E' K! h. I+ t3 H5 y2 l. E. L& a

    ) {2 k, ~5 T" L7 @+ w! u# Example usage" _0 |; R" E/ G7 u) F2 j$ e
    print(factorial(5))  # Output: 120
    " ~: i- N$ U! t7 f
    4 P1 Y) Q! ]- _! w$ t8 e+ oHow Recursion Works( h  _+ _2 q+ d
    ! t  o7 \; X9 H3 ~! w1 W
        The function keeps calling itself with smaller inputs until it reaches the base case.
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        Once the base case is reached, the function starts returning values back up the call stack.
    6 s1 t9 e* x  d+ P% d, s. E" i& z
    # L# g  p: t& X3 P5 K    These returned values are combined to produce the final result.
    $ i1 F. \2 s" p' b  ^2 {
    ( z$ u: }% R8 W3 nFor factorial(5):1 a( q7 l( p& ~- y  v5 a

    2 Q8 O3 {6 q- Q8 P
    / L" w' T$ x' u% Z! s- e; H9 d' t) lfactorial(5) = 5 * factorial(4)
    * C7 ?( W3 Q% Ofactorial(4) = 4 * factorial(3)
    . @. c  Z+ i% _+ _0 I* qfactorial(3) = 3 * factorial(2). L  b. {+ Y5 h- o5 D; Q& I/ B2 _
    factorial(2) = 2 * factorial(1)
      N/ @5 F9 d9 _( V' ^6 a, R* O$ Ufactorial(1) = 1 * factorial(0)
    5 @1 T' F% s' v: t7 u* \: r. Afactorial(0) = 1  # Base case& M2 [6 j6 Q* x$ G
    / H1 Y* Q$ W' H# _  s: i4 m. [
    Then, the results are combined:* M) ~# R; E. D, Y

    ' H8 B6 Q/ w3 S# u/ s) s( Z. ~! P" r9 f9 s. y8 Q
    factorial(1) = 1 * 1 = 1
    ! @2 E5 E; ^9 L1 mfactorial(2) = 2 * 1 = 2# J2 O! ]( `3 U# o
    factorial(3) = 3 * 2 = 6% g$ u$ ^# J7 L& r9 h3 b; U
    factorial(4) = 4 * 6 = 24
    9 p  \7 q7 i% U& l9 qfactorial(5) = 5 * 24 = 1203 X8 w0 S' u! ]0 P0 b& m# ?1 G% ~

    8 m/ y/ y- u; @& L- E& n$ gAdvantages of Recursion
    % D5 s, M9 s% w, L+ @& |$ [, @- k. _. g5 v* P) `; z. d" U, H% `7 y
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
    6 Y- A0 d1 D! v
    : i9 @4 d$ m( M) R    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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    Disadvantages of Recursion; Y2 B, C8 S  T. X2 U6 X* N
    & l2 b/ z5 u4 n0 p& ~
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.$ Z( U2 e# I$ z9 \& H7 x0 F
    ( X: ^$ B2 u, _
        Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).# ]1 j; {$ m% {0 }( G/ t
    , E3 \7 M; I1 y* B5 u
    When to Use Recursion4 _' r- `3 H" Q

    3 I. E4 F, G4 U3 g7 k# ~    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
    ( Q- D4 D' l3 s7 I) ^5 o* U" K# M) S1 |, Q
        Problems with a clear base case and recursive case.
    ! ?! `3 d7 g) ^" Z) N
    9 ]- E1 g( d7 O# F& l, q6 ZExample: Fibonacci Sequence
    9 d2 `1 S; V7 z$ \6 p. E, f. c) @( s  f  }
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
    8 G0 @& z1 a0 {" o% X* ^5 j
    " o9 }3 j# @7 V% E    Base case: fib(0) = 0, fib(1) = 1! S" ], K: G2 k' B" C
    : i6 S: w, v# k
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    2 |: }& g9 v6 n" Z3 ]4 g) M: D% B; x! J
    python
    5 d) t4 b4 Y* C1 S2 |* t2 y! X# d$ U0 }$ R8 _4 z8 E8 |

    * U8 o/ L/ J, l9 v8 d% U# [5 A; Bdef fibonacci(n):- v, Q+ g- Z! j9 ]! K
        # Base cases
    2 W) N5 s: I) L    if n == 0:8 Q# U/ \1 q- a. S4 W
            return 07 H  D2 z4 g6 a7 o8 X; y- r
        elif n == 1:& v: t0 _' c. x0 h8 d5 h- i
            return 1
    * ~* e" B( B* I# z  i3 M' E* o    # Recursive case
    5 }3 s! r% i0 u6 l    else:+ }% [1 s3 O) i! X6 o8 w
            return fibonacci(n - 1) + fibonacci(n - 2)
    5 G- E+ H- d$ a/ ?- |/ A# U, o) [4 `( l- {
    # Example usage
    ; h, t6 M5 n% x7 H" rprint(fibonacci(6))  # Output: 89 s; `+ v% }& T7 o
    , w+ d) `; u: |
    Tail Recursion; w- G. c3 G6 ], e& H: C
    - w3 s: |9 E2 b' Y
    Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).( a6 z9 ?# q* d+ D: q

    2 ^; }7 p8 ?" C! UIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
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    发表于 2025-2-2 00:47:27 | 显示全部楼层
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
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