设为首页收藏本站

爱吱声

 找回密码
 注册
搜索
查看: 2596|回复: 3
打印 上一主题 下一主题

[科技前沿] 突然想到让deepseek来解释一下递归

[复制链接]
  • TA的每日心情
    开心
    2025-9-8 05:08
  • 签到天数: 3 天

    [LV.2]筑基

    跳转到指定楼层
    楼主
     楼主| 发表于 2025-1-29 14:16:55 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    本帖最后由 密银 于 2025-1-29 14:19 编辑 $ E# N4 |  B- q& O& R$ p

    - P6 i! U4 n: O1 ]解释的不错- Z" @" _0 Y; W3 l" P& L: R

    0 b. K$ _& z" C: C  P" {递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
    ! d6 K) e8 y/ a  ]! ^& Q7 h: f
    * R& d) ?4 Y7 I6 C0 `8 P 关键要素) q; ?8 r+ d: d
    1. **基线条件(Base Case)**% _: J7 K6 V: k( @* q9 C( m" E
       - 递归终止的条件,防止无限循环2 k4 _1 f& G8 W, V( h4 e, W
       - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
    2 _: Q- f1 W& m. ^1 T6 u( S3 n1 m1 l8 j" M3 g9 p7 c/ R
    2. **递归条件(Recursive Case)**
    5 H- S4 C0 L! q7 l& }5 b   - 将原问题分解为更小的子问题7 i+ r+ e) h) s0 |1 r1 t5 o
       - 例如:n! = n × (n-1)!; Q( x/ u* M  Y. X
    , ^+ f8 `) q9 P3 I
    经典示例:计算阶乘
    % _, W1 y* w) @! m" |python
    % H; A& C; l. P2 `: a* _0 z9 i0 c2 ddef factorial(n):
    1 i" s' S$ ?; @; R5 `4 v8 W# u    if n == 0:        # 基线条件
    ; [/ W- |/ m: t/ m" z; s1 T; |' R  S) N( ?        return 1
    ! g5 j2 \+ U5 p  [' ]* G    else:             # 递归条件: L. b4 Z# `9 Z
            return n * factorial(n-1)$ s; Z" a* l- L" d& _3 w
    执行过程(以计算 3! 为例):0 r' g9 ]) d. Y4 M( @6 m$ f4 u, V
    factorial(3)" Z4 m6 E* P7 H$ T+ ]. f8 [$ e
    3 * factorial(2)
    % c& ^# w' W  ?+ f9 H8 X  H# n. R3 * (2 * factorial(1))6 D* ?. y+ Q0 z" }0 g& a2 w$ Q
    3 * (2 * (1 * factorial(0)))
    * L4 @+ |: \0 t6 @+ s0 H' }3 * (2 * (1 * 1)) = 6- H3 U; U0 s2 @4 @: ~
    5 u  ^; `7 ]' E: [
    递归思维要点+ X. R: m  p7 h9 I) ^- m- U. u
    1. **信任递归**:假设子问题已经解决,专注当前层逻辑
    5 C6 R' w# W7 j( M3 j) P% p2. **栈结构**:每次调用都会创建新的栈帧(内存空间)- Z) e+ a9 e5 \/ |! Q; B3 }3 c1 t. Z
    3. **递推过程**:不断向下分解问题(递)
      r& n6 Y! v) F4 y' G3 K4. **回溯过程**:组合子问题结果返回(归)
    3 r' w: T4 ~/ E1 C4 p) H( s" J; U+ I/ Z
    注意事项  _# h& q( z( ?0 R
    必须要有终止条件7 `; F' m' P& f/ y7 ]
    递归深度过大可能导致栈溢出(Python默认递归深度约1000层)- f. _0 ]. l+ L( ^, H' g2 D* a  X3 ]
    某些问题用递归更直观(如树遍历),但效率可能不如迭代
    ' D6 ]5 ?5 B3 `; _8 v尾递归优化可以提升效率(但Python不支持)" Q8 ]% i! y6 y+ K8 C

    . @- b* ?- ?. [' N3 r( H 递归 vs 迭代
    4 H$ T0 r" l7 h- C  w( d& m|          | 递归                          | 迭代               |
    1 p# B# i" Q) v# }% V  Q|----------|-----------------------------|------------------|" w: g' @5 G9 a4 N$ @
    | 实现方式    | 函数自调用                        | 循环结构            |1 [3 M+ P* w4 }: y
    | 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |0 n9 c0 u/ T3 v/ g) ]1 U$ y
    | 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
    0 [$ \- j; k4 h, Q- z* w. O9 H| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
    6 s7 S2 N% u3 f! q8 ?8 B. p, g' }! _1 M9 V. s, z
    经典递归应用场景  Z4 d+ c. O9 C$ q
    1. 文件系统遍历(目录树结构); @1 Q. J) e; V' P! |, W& h8 e6 m6 Y
    2. 快速排序/归并排序算法
    * {8 G9 y! l* [/ t% F& E3. 汉诺塔问题
    8 S( |1 E% A; V# h/ x% }4. 二叉树遍历(前序/中序/后序)
    7 N4 E4 v9 J4 F; L3 D9 |5. 生成所有可能的组合(回溯算法)
    + c% ^% P5 A. t  ~+ m% A1 R9 j
    ; a4 p- Z- p+ M0 I' `试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。

    评分

    参与人数 3爱元 +26 收起 理由
    pcb + 4
    老票 + 16 涨姿势
    住在乡下 + 6 给力

    查看全部评分

  • TA的每日心情
    慵懒
    昨天 09:26
  • 签到天数: 3225 天

    [LV.Master]无

    沙发
    发表于 2025-1-30 00:07:50 | 只看该作者
    挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
    6 g" w8 ~' Q$ L) L$ X5 d我推理机的核心算法应该是二叉树遍历的变种。: f  T# T& C0 s2 j2 I( R5 K+ u
    另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    板凳
    发表于 2025-2-2 00:45:59 | 只看该作者
    Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:1 i+ G# n) n' p, q3 y4 Z# w
    Key Idea of Recursion
    ; v% U. Q  p% b: R6 S7 s
    ' O8 v; k+ o7 K" |! Q; JA recursive function solves a problem by:& [( Q" B; v7 l) l
    ( ?' B8 y, k" n: m* U- |. H+ _
        Breaking the problem into smaller instances of the same problem.
    & s+ r$ w2 T) K0 W# t8 [
    ! [4 y' t& Z; q' g0 N; r4 m    Solving the smallest instance directly (base case).5 P% w  L3 |6 b5 Y; `. B
    % R! B! t: u8 B9 q$ X. s" U
        Combining the results of smaller instances to solve the larger problem.
    + X3 Z$ `6 T0 \4 F- `9 w$ \+ e+ |# J( g7 l
    Components of a Recursive Function6 w1 m0 y7 U1 g$ y% N
    6 i! l1 C% F, V
        Base Case:# L$ w4 p+ T. w4 J, _$ }' i
    / T5 Y7 u9 |- j* _, T
            This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
    2 @) }+ _3 S0 Y/ w2 _- w: I
    + D* v9 D8 k- K- _% L        It acts as the stopping condition to prevent infinite recursion.
    ( \3 X3 F1 c' [
    4 D0 ^: S; K* k) b' E5 C( P        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.7 g& s1 G( P/ w7 A; m

    0 S% c& z8 |& [9 `7 r( K1 s    Recursive Case:
    6 q1 ]8 d$ n, Y2 F0 o
    " e, A$ ^9 {6 R9 P        This is where the function calls itself with a smaller or simpler version of the problem.
    " ~4 o8 W3 E; g+ U/ A) e% H3 M, {+ z9 y" w1 i: F
            Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).2 C" f) a" E3 ?0 m

    4 y4 p6 m: ^! B8 r) uExample: Factorial Calculation! Z! s: x2 J5 R+ G) F# l0 _$ V% H

    $ k0 {1 ~7 o+ V* G+ g2 EThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:  o  }0 o* `0 {! O4 a9 o0 o, J

    " [# I4 k+ ~8 s' s* K4 L    Base case: 0! = 1
    3 `0 Z' d' l  A  R8 E+ V/ j0 q" J0 p. x8 I$ L
    $ W4 r1 p) M& {& ]: n1 v    Recursive case: n! = n * (n-1)!
    # r" f9 b" g5 [5 ^7 u+ G2 J3 y
    ' L8 ?5 ^2 b+ u! t3 DHere’s how it looks in code (Python):
    9 W6 u$ {/ n5 a9 Ppython
    ! E) z$ K3 N1 t7 R" k
    # ^) v+ b8 C' l- Y3 @$ S1 a8 R1 x2 t8 g* F4 T' w! z, S( i+ ]
    def factorial(n):
    9 H. T0 D% L% b; W0 U9 T7 A    # Base case
    + e/ e; \1 I; p7 e9 }    if n == 0:
    $ g/ v, h8 w) r        return 16 p: r, G; R9 w" i; n( r7 o
        # Recursive case
    * p/ r# a% [# F4 S& ^* K) k    else:
    2 M8 s) q  s- Y# P  ]$ y/ i+ F) _        return n * factorial(n - 1)! i! e& C* D$ r/ n; M/ t6 o, I

    ( c# E# p; g% H! ]2 d0 p# Example usage$ t* s* }0 R  m  U6 I" X
    print(factorial(5))  # Output: 120  V( T: y/ Q! ?8 v2 R

    / [; ^" \5 s( yHow Recursion Works3 i: T6 |, C8 e

    0 ~8 S! u  x. R    The function keeps calling itself with smaller inputs until it reaches the base case.
    ) r+ C7 h: O( \5 s
    & D% A9 ], `$ `! B; \    Once the base case is reached, the function starts returning values back up the call stack.
    4 w4 v3 X0 @1 V9 |' _% A* d
    4 M5 ~5 a/ u' s# j' r" s4 O! b    These returned values are combined to produce the final result.
    4 |. X3 T2 U& U6 K6 F( W# ^% d" g) o4 S6 ]* V
    For factorial(5):
    , x( s, r6 P) ~7 T" \
    $ f; n0 g1 m$ Y/ y) g% @& k6 K0 P: [; m; @0 t3 S
    factorial(5) = 5 * factorial(4)
    1 U4 {2 g0 H) y3 F) C- ?factorial(4) = 4 * factorial(3)
    3 j0 k' j3 S+ V. cfactorial(3) = 3 * factorial(2)! |% }- k. R0 t7 `9 w% X
    factorial(2) = 2 * factorial(1)
    8 s8 b/ c0 j, Q+ }+ k2 Tfactorial(1) = 1 * factorial(0)% W! R) U9 ]% S1 V/ J- }; ?; J; E
    factorial(0) = 1  # Base case" P( A) ?( m9 Y( X4 j2 v% T

    9 W3 {3 @/ g2 m+ dThen, the results are combined:
    / q( H7 }8 m2 R. U9 R$ _6 B
    8 ^0 C( S# h3 M* o/ n$ K/ }9 c
    & O2 V  A/ q+ l) A# A* h2 Rfactorial(1) = 1 * 1 = 1- x( y  G. X' L8 F' X# |" X  u5 q: `
    factorial(2) = 2 * 1 = 2; p# G/ m0 c  g. d& s8 y5 f
    factorial(3) = 3 * 2 = 6
    & @2 U( p/ Z2 d9 ]  Y( p# Wfactorial(4) = 4 * 6 = 24. [" c$ l$ h- _; {6 U! |
    factorial(5) = 5 * 24 = 120
    % s, v2 h* a# P, `1 @$ h# q6 U
    ; e& a- _4 ]9 y6 J- F- r1 J/ JAdvantages of Recursion
    , h- h3 e7 s6 R# c* G) [# q/ n# C5 D3 ?; v4 ?+ [) a: O
        Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).) Z2 N4 J* n: W  K1 R
    ; \2 F' J8 ^0 A6 [6 K9 r
        Readability: Recursive code can be more readable and concise compared to iterative solutions.
    8 _. C- i: d; \+ l% v# M& G2 @' I0 ~$ ~
    Disadvantages of Recursion' a. `# H1 q- V9 ]  O6 [! C
    ) }( c1 p+ s3 N  s# D
        Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
    $ m" E1 a$ m. G0 h' ~1 T3 e3 L/ I# N
    . l+ `+ H; O  y5 O    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).0 a$ @) V- L$ H+ c$ V4 B/ X. L; n
    . ?3 ~1 n/ E9 `; d- S
    When to Use Recursion' C* ?. Q) X9 t* |# e4 |* `
    $ T% a/ B4 p5 y) @5 f- Y- ~
        Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).1 ]8 }. O' }2 X. n! y' O
    6 E4 r: m0 d7 d
        Problems with a clear base case and recursive case.
    8 n: ~' ~) m+ K" h) N
    # x' k% l: f: F, Q. ~Example: Fibonacci Sequence
    - P5 A" h# C' q" T0 P' G, J8 _/ R. Z2 d7 U+ g% h( [9 t2 d
    The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:$ B& G) V5 `7 A# X
    % L/ [  \, ^/ J0 d7 s+ R
        Base case: fib(0) = 0, fib(1) = 1
    , ?2 j4 d6 f' b7 M6 L: y0 L. g8 y0 V+ ~' d
        Recursive case: fib(n) = fib(n-1) + fib(n-2)
    0 `7 y4 n3 v0 u$ h' U: Z+ g
    , L" R8 P0 `0 }1 o6 H2 Fpython* |! X/ t# r4 h' _' K) h0 E" Q' N
    ( {* |# x" S- X

    2 p$ ~* j/ |9 Y; kdef fibonacci(n):
    ( h% p! f2 g. w3 D$ [    # Base cases; D9 C+ F( B% I8 a! H8 r. S" K
        if n == 0:
    ! B! w8 f) J. }4 k; W8 x        return 0
    2 m% R' |8 M. e3 Y1 ?" e2 _    elif n == 1:( q* o, b5 D+ M
            return 1
    : j- A, N( J7 y9 q    # Recursive case& H) s2 s2 @" _, {8 m
        else:5 G5 [5 B6 f. r( ^2 L. w! U; g
            return fibonacci(n - 1) + fibonacci(n - 2)
    % _& [; h2 {) b- F' j) U( ~. ^/ k8 a; i
    # Example usage! f2 t) i1 w# R9 p& e- q; D# Q4 D
    print(fibonacci(6))  # Output: 8# |' v- m( T" q7 m

    ' b$ J8 G, c- g2 R+ d9 {- @% XTail Recursion
    & H; c& r' T5 H  z6 ~( I
    ; F7 l1 l2 Q2 L9 r* zTail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).% p7 [) @" I( Z

    ) n4 `1 e4 |: W* A. u! QIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
    回复 支持 反对

    使用道具 举报

    该用户从未签到

    地板
    发表于 2025-2-2 00:47:27 | 只看该作者
    我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。
    回复 支持 反对

    使用道具 举报

    手机版|小黑屋|Archiver|网站错误报告|爱吱声   

    GMT+8, 2026-4-29 12:34 , Processed in 0.060574 second(s), 18 queries , Gzip On.

    Powered by Discuz! X3.2

    © 2001-2013 Comsenz Inc.

    快速回复 返回顶部 返回列表