TA的每日心情 | 擦汗 2016-4-17 12:18 |
|---|
签到天数: 1 天 [LV.1]炼气
|
本帖最后由 tingsanguo 于 2014-5-2 14:01 编辑
- U- R* ~4 \* p& o水风 发表于 2014-5-2 01:57 ![]()
- [* _0 M0 q1 J! _9 }再次重温自己与数学天才们之间的差距有多大了。解出来了,我还看不懂思路 ...
( j: r9 q9 l! }9 c2 n
2 z2 ?" Q ?5 K2 Q+ x- hfixed point f(X) = X = (1-n), where n is the number of people who divide the coconut.% q! z0 g2 ?, f( ^
/ u9 e# U, G: a% z3 U' S$ a. `! m% `The least number of coconut before dividing is Z = [n^(n+1) + X], i.e., always divide (n+1) times.
* ^6 }" T- N- N- J; g) s) H8 K3 B2 e. w6 p; y& W
After being divided (n+1) times, Z becomes 1, since X is fixed point.* P4 j, b9 v1 b. {
; Q2 ^1 M! r1 P) l0 ]- _8 Gn n^(n+1)+X, n^(n)+X, n^(n-1)+X, n^(n-2)+X : q4 f* @$ t; G
1 1
& F* m4 ~; N( F% R; e$ y; V( b. g2 7 3 1
7 v3 \9 h& ~) g4 K: p/ w) V$ Y6 W- c3 79 25 7 1
4 b% T" V7 r! K% G. b" ?4 1021 253 61 13 1
5 ]2 P, |5 Y2 H) g: o5 15621 3121 621 121 21 1. @! J3 b! y4 o4 M( I+ d
8 y+ l' l/ q( P/ h- I$ t
+ a; E3 @' V) v% s/ ~: L) G' p |
|