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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 ; R# Y) z5 r, V

0 P% ~# `% K% N) ^: `" Y3 X解释的不错: J& P* l6 f/ C9 g6 m

8 v# ~$ A: U+ Y# M, Y5 Y递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。: q- y* ^, v1 ]2 [2 u
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关键要素$ w2 z" r% Y. H
1. **基线条件(Base Case)**
4 [, ^( {! l; R/ c0 S$ o" Y0 ?   - 递归终止的条件,防止无限循环
3 ~  \% [4 p& R' ~   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 17 u4 ?$ t) x; p$ C
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2. **递归条件(Recursive Case)**
2 L) m( z6 f1 ]+ ?* S   - 将原问题分解为更小的子问题
/ D" v: l. g! A$ z   - 例如:n! = n × (n-1)!
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4 V6 m: c3 r- S, M1 T$ P; G8 T 经典示例:计算阶乘
5 ~& E1 t  Z" g) L7 V, p% V: S& A+ rpython
0 j/ s# M; v$ Y& |1 y) ]def factorial(n):3 L' E4 g; s! q1 p0 Y
    if n == 0:        # 基线条件
7 B5 T- L2 O3 O# g5 ]- H        return 1& X( x! ~& ~& z  c3 D# ?/ o
    else:             # 递归条件
& a/ u! L( {, K( Z1 N4 v: q        return n * factorial(n-1); D! U: D4 b& e5 n8 ]- f0 v
执行过程(以计算 3! 为例):
! p1 D. w' k1 i7 M; P  b# Pfactorial(3). u; }- p* B5 L5 D( _2 V( t
3 * factorial(2)# M6 M* y. z. V. B- V
3 * (2 * factorial(1))) c  {) `4 y2 K+ U1 }4 k% h5 @
3 * (2 * (1 * factorial(0)))
4 W1 L5 |! \( A8 y# D  u3 * (2 * (1 * 1)) = 6+ a- j5 H/ a. s
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递归思维要点
5 u7 l5 p* Q. m1. **信任递归**:假设子问题已经解决,专注当前层逻辑) k. [: v6 |5 A) `& s& |. j
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)4 O: ?0 J6 p- I# x. D% F+ @" w6 G
3. **递推过程**:不断向下分解问题(递)
: a1 Z! c( g  R! x4 c4. **回溯过程**:组合子问题结果返回(归)
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注意事项
* g) L3 O0 u! A: V9 g- |必须要有终止条件0 R# d( I) L. E3 g! H% @* y3 y( N1 Q
递归深度过大可能导致栈溢出(Python默认递归深度约1000层)
+ T6 J- a; n. n" O某些问题用递归更直观(如树遍历),但效率可能不如迭代+ ~: X0 b0 _- F
尾递归优化可以提升效率(但Python不支持)
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) |. C* T7 U6 f 递归 vs 迭代
5 _% H) F4 i4 A1 Y6 q|          | 递归                          | 迭代               |2 o5 R/ O8 ^$ B1 G
|----------|-----------------------------|------------------|* P& R) P5 X2 g
| 实现方式    | 函数自调用                        | 循环结构            |
" t. w# Z/ J5 @+ F! x| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |
* H; v  F  s/ o& i| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
& e& o8 t- t) z( }| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
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经典递归应用场景2 |: n* P8 a3 ?& R
1. 文件系统遍历(目录树结构)5 }1 I* d- ^4 i4 |. ^1 l; I2 b
2. 快速排序/归并排序算法
$ L$ C8 G7 ^  T! n) x7 m5 H3. 汉诺塔问题
# t5 _, n$ i- l4. 二叉树遍历(前序/中序/后序)
+ i( N2 W' D" K! A. G) _* |1 I! `( ^2 J5. 生成所有可能的组合(回溯算法)" q0 o. ~7 o8 u8 V2 ]
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试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,8 j$ e$ ^6 g) i
我推理机的核心算法应该是二叉树遍历的变种。$ r( e) a1 r9 ~
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:
$ X' @) A/ e; Y: G8 F! }Key Idea of Recursion
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9 I: d$ E: g1 |; H, _# i/ hA recursive function solves a problem by:* F* `% m, }& J4 w1 M

9 k- j/ t% k1 t    Breaking the problem into smaller instances of the same problem.
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4 s8 \: h" ~0 ~# Y7 Q    Solving the smallest instance directly (base case).# C. j5 }# n+ h6 U# @
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    Combining the results of smaller instances to solve the larger problem./ b' T3 H! M4 p7 C- }
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Components of a Recursive Function
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    Base Case:
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' h3 a4 G: K) X1 q        This is the simplest, smallest instance of the problem that can be solved directly without further recursion., g) d: D- ]0 A: o1 a9 F
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        It acts as the stopping condition to prevent infinite recursion., i4 V3 ?( ^: V6 R
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        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    Recursive Case:
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2 {& U. Q1 p" a        This is where the function calls itself with a smaller or simpler version of the problem.
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        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).' L' z6 ?" H0 d* k

  |  d( a+ U! n: PExample: Factorial Calculation
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! B: w& W. @) nThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
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    Base case: 0! = 1! g) @! z" g  h: Q" A- T

' O8 o2 L% m6 C; j+ I7 |& L4 i    Recursive case: n! = n * (n-1)!* C& f& |) |5 @+ D
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Here’s how it looks in code (Python):
' C- u* e& L2 Q  j! H$ @python
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def factorial(n):
: D7 j. G0 A  ?$ e9 Y    # Base case
/ g7 J! Y$ H) \$ [; f6 n0 H    if n == 0:
6 {$ g1 S% R5 z" s; o% S        return 1
' w! @! r$ {& K- G" q2 q9 w7 J    # Recursive case. ?8 X8 `. N9 g- J2 D
    else:
% n$ @/ B) H' w3 C" m! b* i5 _        return n * factorial(n - 1)! Q( N! {( y) H4 b0 P, a
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# Example usage
! T6 W' S" h: B) l) D2 Mprint(factorial(5))  # Output: 120" v4 [9 @. k2 I+ h# J: w

9 O  K2 ]) J' T( M( K  zHow Recursion Works, K) [5 ^7 F6 p
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    The function keeps calling itself with smaller inputs until it reaches the base case.
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    Once the base case is reached, the function starts returning values back up the call stack.
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    These returned values are combined to produce the final result.
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For factorial(5):1 t( c! |0 k3 h: w7 ?* B5 Y
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factorial(5) = 5 * factorial(4)
, p1 V4 H$ c% H0 W0 J; W( ?factorial(4) = 4 * factorial(3)
6 f1 ^: l; m' |+ H7 M& M* u% |factorial(3) = 3 * factorial(2)
8 y- Y2 n6 k* }' T2 z/ N* Bfactorial(2) = 2 * factorial(1)
% t2 k5 `/ `3 G' y2 b/ ~, Ufactorial(1) = 1 * factorial(0)2 ^) d* E2 O7 I8 S" x& {
factorial(0) = 1  # Base case3 q# I. q) r& Y' Q7 m( S
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Then, the results are combined:
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" A- b8 A' Z# \$ Y  B# X% }1 I  Yfactorial(1) = 1 * 1 = 1
  P; x! t) Y1 K$ n; E) a& x* lfactorial(2) = 2 * 1 = 2( A0 {$ }4 a$ H  P/ u8 N
factorial(3) = 3 * 2 = 6
0 p" f0 I! Z, s0 Afactorial(4) = 4 * 6 = 24
: ?" x. m, A- R3 _3 d# R8 Y9 kfactorial(5) = 5 * 24 = 120, y8 ]0 y( `) L1 {) R

1 K; }) B- D) t+ g4 R7 I5 Z5 d9 S( OAdvantages of Recursion2 `7 W. p, W* J( @

( O1 Z: w9 h' L3 U4 w+ U  d/ a    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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3 Z! e* J% r* w    Readability: Recursive code can be more readable and concise compared to iterative solutions.: [! F" ?+ w6 ~% W

/ C3 _5 J5 c$ L8 |; n; T" jDisadvantages of Recursion6 j- @6 S, e2 g5 T

! S1 f% z; e4 ]! L$ d; }    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.* {* l- o4 n" k' R5 B+ b! ~1 W/ S

: ~- Z0 k; `% i: I3 |0 q/ h    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).
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When to Use Recursion- A+ O  n, c* {( \5 g

# {2 t) Q1 W0 T  F. w# s    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).0 j& w# w" y  m9 }. c

) {! _3 j$ _& t- a* E, a1 \    Problems with a clear base case and recursive case./ j# L2 y' ?0 X( n) \2 r, c
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Example: Fibonacci Sequence' l& O( I$ p" U* ^

' x0 Q1 J9 X/ o4 \( J0 zThe Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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2 |' ?+ e# {; s5 y    Base case: fib(0) = 0, fib(1) = 1
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    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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python
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def fibonacci(n):; s; P$ K# h8 v' Q
    # Base cases& u# q4 P. M5 f: D2 C
    if n == 0:4 @6 `2 K2 d# ^, b+ T4 O0 u. `
        return 0' J9 A; t4 `- C- O# j% C+ C! }/ H& Y
    elif n == 1:
4 x- w0 }; l$ v3 F  ]2 m% i/ ~/ q5 H        return 1
, C* @  |5 m8 b# [" a( c    # Recursive case2 x; }( v, N3 [9 a8 X
    else:* [7 C0 A1 {- H7 p; U! x
        return fibonacci(n - 1) + fibonacci(n - 2)& P/ @" Q  N1 S4 f8 P5 k- ]

% r2 Q* \: q  Y- v# j& S# Example usage
) n( s$ m/ N! e# P& M# @print(fibonacci(6))  # Output: 8. g: V' d) b/ o* y' s: m

6 [1 T; ~' ]$ L# nTail Recursion, \6 H; n$ w5 D" u2 e- j6 }! P0 g
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).! `- s/ {1 @& n9 _$ t7 K

$ b# S- u& K. H* XIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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