标题: 突然想到让deepseek来解释一下递归 [打印本页] 作者: 密银 时间: 2025-1-29 14:16 标题: 突然想到让deepseek来解释一下递归 本帖最后由 密银 于 2025-1-29 14:19 编辑 % c8 P& I Q @7 C : N7 c% B: n w. F解释的不错 0 w+ C9 `% A6 |2 @+ y: U& H, P) {! |" E9 ~: u
递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。5 H o9 L/ Q a6 }7 P5 d8 \
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关键要素 ( K0 A7 [! f+ U# Z0 h1. **基线条件(Base Case)** 4 g( r# C1 v; H2 b5 ^ - 递归终止的条件,防止无限循环 5 k; r. B7 W/ x# I3 \) A) Y - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1& e) i% v, f, C3 \! Q8 G) y
, d% w1 V9 a, R2. **递归条件(Recursive Case)*** \+ e ~; j5 S5 c2 e% p1 K
- 将原问题分解为更小的子问题+ s G# F0 E6 R V
- 例如:n! = n × (n-1)!5 Y, g$ g9 W/ s- ]# U/ s
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经典示例:计算阶乘 5 D. m' i6 F1 T$ [7 S, |& Gpython 2 p- n1 w; H" Q* X Q9 a1 idef factorial(n): 1 F/ S6 B- _1 V, X if n == 0: # 基线条件/ b y7 h" ?4 y7 T
return 1 ) e) l1 T( W+ X+ f6 d/ l else: # 递归条件 $ Z* q$ C$ N" k* d" {! h% M+ P return n * factorial(n-1) 4 n& f3 ^% {2 f8 `% }2 k+ Z执行过程(以计算 3! 为例):5 S: C! a8 J, G5 B+ M
factorial(3) 8 J R" n5 W: @% A/ [$ Z3 * factorial(2)6 `$ c# N! q: z [
3 * (2 * factorial(1))* w/ G& ?; L/ l) z, r) u% M
3 * (2 * (1 * factorial(0))) " g0 d* U1 i! S8 x# N3 * (2 * (1 * 1)) = 6 # q4 l; K0 H/ I+ A; ^9 \$ w3 K4 `
递归思维要点 . g) A. v3 m1 P( E: ?; f1. **信任递归**:假设子问题已经解决,专注当前层逻辑! A b! J0 f# x
2. **栈结构**:每次调用都会创建新的栈帧(内存空间) m* e _5 E5 [, F1 b7 f
3. **递推过程**:不断向下分解问题(递)7 c4 y' Y% ~% F* G7 y
4. **回溯过程**:组合子问题结果返回(归); a# t1 @* U9 V R1 z
+ N. X& e8 A' E: \3 _. X/ \1 R 注意事项6 X k) Y* V0 d9 ~8 n
必须要有终止条件 , S* ]) k" G o7 ~, O& M递归深度过大可能导致栈溢出(Python默认递归深度约1000层) . x8 P( h! t# l( n, d$ L某些问题用递归更直观(如树遍历),但效率可能不如迭代 ! d+ K4 P4 l$ V% p1 q4 E. p尾递归优化可以提升效率(但Python不支持) : a7 E7 s: P8 M, ]: x3 V( o/ t) |( m& j
递归 vs 迭代 3 q8 N/ A, h! H% e5 w& {: M| | 递归 | 迭代 | 5 {. _! Y, G T2 w% Z. b9 q& n|----------|-----------------------------|------------------|5 |. H2 [$ s, b, `9 V+ ]2 e' @$ Z; E. Z
| 实现方式 | 函数自调用 | 循环结构 | + L8 P$ ?# f) \) E| 内存消耗 | 需要维护调用栈(可能溢出) | 通常更节省内存 |1 p: y7 ]: g5 \* O
| 代码可读性 | 对符合递归思维的问题更直观 | 线性流程更直接 | 3 y. {& `; Z& o9 |: C4 @3 m| 适用场景 | 树结构、分治算法、回溯问题等 | 简单重复操作 | 7 y6 I4 v# L# ?( V E8 f7 B# P/ g8 l9 H5 t: n; M2 v
经典递归应用场景# Y4 _, ]$ e9 M* @0 \/ O' f
1. 文件系统遍历(目录树结构) ' M( x+ g2 Z( R4 V; U Q* N2. 快速排序/归并排序算法7 ^$ ]5 |0 m. _/ }0 b7 o
3. 汉诺塔问题5 \: H( @9 Z; y* b2 o1 W
4. 二叉树遍历(前序/中序/后序)( f5 r& D% s9 t3 r; L
5. 生成所有可能的组合(回溯算法) # q! v. A6 R7 J! _ / k) o8 k% ?0 @0 Q试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。作者: testjhy 时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,( S4 @/ i: d4 D, q) Y
我推理机的核心算法应该是二叉树遍历的变种。8 e; R( [" c1 }; ^- H6 @
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。作者: nanimarcus 时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:* Y5 I6 v0 N. S: C7 z0 _
Key Idea of Recursion$ O R' n# R5 ~3 p" x+ m" b% ?! J
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A recursive function solves a problem by: * Z4 I; g0 H: G8 _9 N* h% c# V- Q0 m( `" d
Breaking the problem into smaller instances of the same problem.; T( P& X) s1 F
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Solving the smallest instance directly (base case). 4 J) a# B5 ?2 ^; i9 q * f- J9 Z& D# ^0 r" x Combining the results of smaller instances to solve the larger problem.: ]: }# G0 y. i# E5 B
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Components of a Recursive Function % g5 X" y' L5 b5 H1 r) C( ?, R8 B$ A3 n: @! ]' X* h. }- E
Base Case:+ E. ~4 m7 o9 x; M' D0 |: {) A+ ~5 |
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This is the simplest, smallest instance of the problem that can be solved directly without further recursion. : u6 X* V& x( Z7 ^' m) {3 X + |9 p( [! L) i4 `) U It acts as the stopping condition to prevent infinite recursion.( L- F9 A$ C* D9 J0 v) U% V6 c+ b# n
, O) V* L0 j# D Example: In calculating the factorial of a number, the base case is factorial(0) = 1.1 r/ W. Q5 }9 c8 ~
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Recursive Case: ! t/ A; Y- s# O( I. g9 y5 H& n+ r& W& s
This is where the function calls itself with a smaller or simpler version of the problem.. x2 Q' S3 W7 m3 v1 _7 e; i
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Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1). - M9 b9 H% B! N4 c/ G4 C* @: S4 G7 Q" P
Example: Factorial Calculation 3 b: F# }9 C' d2 U2 [9 b) q3 y0 d2 q7 ?( @# P
The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:, u: V/ H. N& U5 f
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Base case: 0! = 1& z! m/ ~# U. i0 y' Z: e, j
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Recursive case: n! = n * (n-1)! 7 Q; V! T3 _$ \" q- b2 a% H0 k" n v
Here’s how it looks in code (Python):, P; J0 C z$ e. o1 V5 R& o
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def factorial(n): 8 {: l& v8 |. _9 |; l/ M9 X! I. Q # Base case 5 I0 v b* R" _ if n == 0:2 A7 F2 R5 o" P
return 1' g' s& }* B. {; h0 G/ v
# Recursive case P0 D* x4 `3 i" H- k: I+ s
else: & \" i9 M7 O' U, P return n * factorial(n - 1) $ v; b2 J# X( [, e' x) w: t ( {! ?" T) }( D5 R# Example usage 4 M3 J: i! J8 ~2 fprint(factorial(5)) # Output: 120 1 T& U* z* n) M7 c. W" a& D1 `
How Recursion Works; K& T1 S' s8 z7 G2 n. F4 h B
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The function keeps calling itself with smaller inputs until it reaches the base case. . O6 I+ a, [' v$ \* b % p8 V7 z2 \# Q, D! C5 d3 O Once the base case is reached, the function starts returning values back up the call stack. % d6 ]' x% F6 j+ |3 W( R% P* ?6 Q4 z
These returned values are combined to produce the final result.) Q& v& r" A- B2 q1 V1 r( S
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For factorial(5): % m3 O$ J0 a9 U) W" t0 z/ r% S: G4 o& k# P, ]$ s, A
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factorial(5) = 5 * factorial(4) 9 D8 |9 ~* V% q- a. Zfactorial(4) = 4 * factorial(3) $ ?9 j( _ Z% X5 }7 ^factorial(3) = 3 * factorial(2)0 h7 H8 e# g; v: _4 U3 h% N
factorial(2) = 2 * factorial(1) 3 U, |/ |- N. z( k* V- z( ufactorial(1) = 1 * factorial(0)$ o1 `5 ~, x6 g) L' |7 t3 w
factorial(0) = 1 # Base case+ d3 `3 f5 @4 r" X! O L1 I8 }
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Then, the results are combined: " g) ]# p% T- I# H3 g! A9 k' a' P: }9 i4 S2 Q# B5 | j0 X% A }
. u2 Z, J- X# E- hfactorial(1) = 1 * 1 = 1+ R0 n' {4 d" _: [
factorial(2) = 2 * 1 = 2 7 d+ s9 [7 {4 U; v$ k4 P* V8 ofactorial(3) = 3 * 2 = 6- b7 c( L5 E3 H
factorial(4) = 4 * 6 = 24* Z& L6 V0 ^1 m5 O8 o& r
factorial(5) = 5 * 24 = 120 , f0 C; K. k; d, d4 b N- ?3 h- k2 O0 X
Advantages of Recursion0 Q$ r# M9 q) r5 |9 i8 b
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Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).7 t* N9 ~, ]3 z1 u: I( B4 B/ y; x
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Readability: Recursive code can be more readable and concise compared to iterative solutions.+ ?1 ?2 E, J7 |) C. a6 p. o/ s
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Disadvantages of Recursion$ s8 t+ }7 j3 W) c: u1 z6 G
7 M( {# L; @% I, ] Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion. * y, o- E( Q' R* T+ b$ j8 _: ^: ?4 X1 J$ M/ j( p- G) ~5 a
Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization). ' D7 j; h! P3 K1 T/ u7 v; R5 x1 Q6 N) |5 O2 A% e
When to Use Recursion2 [ W; j/ c4 w1 D$ p" T
. ]& A0 O% g l; I% o$ N* B/ ^ Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort). ) W z6 i! f# V: U% C6 `8 k% L5 P# f! B2 V
Problems with a clear base case and recursive case.$ d K v/ X G+ \! U4 z
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Example: Fibonacci Sequence % J; x0 ^% ?5 O3 q+ S( ~& h( n" E/ {! l( |1 ]/ |) P" G
The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones: 7 O3 s. I/ w- I% o- f3 p3 ~. [( @$ B5 |( _" y1 h* `
Base case: fib(0) = 0, fib(1) = 1 5 I$ \0 J; Y; X) e6 ]9 l# L' d ) W5 q( c0 B- a E2 N$ m8 l Recursive case: fib(n) = fib(n-1) + fib(n-2)' @4 U: s, q2 d8 Z
7 g# D K* X1 [* s+ uTail Recursion4 E {$ U6 k7 ?" u6 _( |
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).8 ^7 O! `) D: S
8 J6 [; F5 {) h8 z9 S: a& U& zIn summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.作者: nanimarcus 时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。