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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑
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: y+ D/ r9 E  U/ r7 f解释的不错8 k, |( C8 U7 ?$ a0 y' r) I) \
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递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。- x3 C2 h' R+ m( ?) |

* v, e, q# g! V: } 关键要素
" {# ^# }. W5 N) Q1. **基线条件(Base Case)**
  g" L7 P; `1 k  y! I   - 递归终止的条件,防止无限循环5 c' u$ E: H3 b' S
   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1
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2. **递归条件(Recursive Case)**8 Z& }2 [3 d. @: f! y2 F
   - 将原问题分解为更小的子问题
" L( P/ w! ^$ X/ f   - 例如:n! = n × (n-1)!
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经典示例:计算阶乘
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) u9 u7 R* ]% k1 C; J. Adef factorial(n):% `; I1 s' ]8 {7 C( u. Q
    if n == 0:        # 基线条件0 W2 F! @+ T9 M. M2 U
        return 1
7 Y; F" l# U) }4 D9 r- d    else:             # 递归条件
; J: q, b# K# n' z! S9 z+ R        return n * factorial(n-1)
, \% {2 Y; X. b: H$ C执行过程(以计算 3! 为例):# X7 T6 A* E2 Y3 s
factorial(3)
5 U4 W+ c' L0 v! I) p# i. H, v3 * factorial(2)
/ [* ?' f' `% R  n- T2 P0 D3 * (2 * factorial(1))- O( o& A. ?- A% u! _  R/ i
3 * (2 * (1 * factorial(0)))+ K$ _& |% w+ x2 o& l9 f5 q
3 * (2 * (1 * 1)) = 6
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7 U$ E4 m& n  x, i( h6 c2 T' H8 o% O 递归思维要点4 d$ V. ~1 f  E6 {# u5 D
1. **信任递归**:假设子问题已经解决,专注当前层逻辑
) _% E& x, O5 M7 P2. **栈结构**:每次调用都会创建新的栈帧(内存空间)5 h7 r- H) V# s7 B! n( w) z. d: |
3. **递推过程**:不断向下分解问题(递)7 Q- b" M7 q; [# }+ Y
4. **回溯过程**:组合子问题结果返回(归)
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注意事项9 W1 h+ ^5 o( |7 G2 H
必须要有终止条件
; D" w( u; h" S6 a' s: f; ]递归深度过大可能导致栈溢出(Python默认递归深度约1000层), [) U; a( @2 z3 }+ B( z( C! q
某些问题用递归更直观(如树遍历),但效率可能不如迭代2 b: H) ?: @1 S: G- S9 N, u
尾递归优化可以提升效率(但Python不支持)
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递归 vs 迭代- k. r& U. W/ e
|          | 递归                          | 迭代               |% v; U" q, X, E  U, i3 m5 T
|----------|-----------------------------|------------------|
8 L9 Y" W- n& Y0 B; Z. ]| 实现方式    | 函数自调用                        | 循环结构            |& i5 [6 j" @. b! y. @) B  @
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |  V7 ^. x$ G6 S
| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |( w2 B! h" ]' Y6 B- ^) y4 V
| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |
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9 W* h6 ~: V$ M! h. n  z 经典递归应用场景
( Q" V8 T: T& U9 Y5 I1. 文件系统遍历(目录树结构)6 S& k! u+ t- ]8 E1 v, Y
2. 快速排序/归并排序算法; ^& e. g! a: k& {+ \
3. 汉诺塔问题& d; i! E7 m) E  H' w  S
4. 二叉树遍历(前序/中序/后序)% m. J4 R2 ?  I5 O2 s9 {
5. 生成所有可能的组合(回溯算法), h6 @$ \- q2 C5 r. F" z

& R5 P3 u! `! s+ q& X试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,
: w: w9 {7 m$ ]# b2 e! p我推理机的核心算法应该是二叉树遍历的变种。- }- o+ A& w$ B/ F$ E) j
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:8 U1 V5 }! m* z6 Y9 k# i6 C7 h
Key Idea of Recursion/ i! m6 @- M6 m
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A recursive function solves a problem by:$ v" h# _: w2 w

6 ~# f3 j  a' ~; j# l    Breaking the problem into smaller instances of the same problem.
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    Solving the smallest instance directly (base case).
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    Combining the results of smaller instances to solve the larger problem.
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Components of a Recursive Function
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  [6 j& Z, }8 w8 Q    Base Case:# ?) V/ c  v2 y; X' b( z! m: \
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        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.+ o+ f8 ?8 F8 B& x! R5 E! r

: G% s, b  u! R/ m0 `' I% Y        It acts as the stopping condition to prevent infinite recursion.
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/ `& @' \6 e( E& |0 @        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    Recursive Case:
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        This is where the function calls itself with a smaller or simpler version of the problem.7 K( b' {1 z; b- e
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        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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Example: Factorial Calculation
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The factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:
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    Base case: 0! = 1) c4 y7 q) m7 O5 L. r) d
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    Recursive case: n! = n * (n-1)!) D. X# U( x: h! I- K: I# N3 G& [
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Here’s how it looks in code (Python):
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def factorial(n):
8 g5 m4 j9 @1 C6 ?    # Base case8 u+ A4 v" X. e  T& ^
    if n == 0:7 t( F2 u; ?9 @" K& t1 U
        return 13 ?% M. T: Q4 H
    # Recursive case
; h# m3 c; n$ J3 I$ k* K5 d9 T% Y    else:
) T7 r: N2 T3 t7 \! V/ y/ i        return n * factorial(n - 1)
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# Example usage
% C/ U4 M. l+ ?5 _4 Vprint(factorial(5))  # Output: 120# L: @+ a' x% X( A1 |
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How Recursion Works
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5 K; Y! S' a8 B, B- K4 f    The function keeps calling itself with smaller inputs until it reaches the base case.
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- e8 H+ y4 P* G    Once the base case is reached, the function starts returning values back up the call stack.3 O- e+ M3 F9 [7 A
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    These returned values are combined to produce the final result.8 C" T; F2 s( X* U8 w1 e3 n
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For factorial(5):
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factorial(5) = 5 * factorial(4)
5 V: e$ @* ^3 I" ]5 {) k) ffactorial(4) = 4 * factorial(3)$ d: D4 d2 D' x; e- [
factorial(3) = 3 * factorial(2)( y+ B$ z  P: v; k; c9 U; j3 D3 \
factorial(2) = 2 * factorial(1)
; p% ^6 G& R! E9 X4 s# ]' M! E& _factorial(1) = 1 * factorial(0)
. M$ C4 y* X; vfactorial(0) = 1  # Base case
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Then, the results are combined:
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& H5 @6 y+ p" ]% B! Zfactorial(1) = 1 * 1 = 1$ e: @% J  \+ h
factorial(2) = 2 * 1 = 2  y; I' \; G0 l, m9 L
factorial(3) = 3 * 2 = 6
" f' L2 A8 X9 S% Sfactorial(4) = 4 * 6 = 24
% E+ G' d! k- ~/ R/ X( |9 y  Bfactorial(5) = 5 * 24 = 120
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Advantages of Recursion$ }' }5 ]+ G$ t2 Q0 c2 V. I5 V- p
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    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).% [. ~* B6 ^9 E$ |
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    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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( d4 i3 M" G' ~2 sDisadvantages of Recursion
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6 `; J' x1 Z; E2 ]% f! N- O: D3 V    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).2 y1 |; E1 h6 h# ^$ S5 D' u( d
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When to Use Recursion
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+ \! u9 v% _) J$ n3 a- F. k6 I$ j    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).- h7 V% d" y8 P
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    Problems with a clear base case and recursive case.; Y) U0 V% W0 ]# r  |
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Example: Fibonacci Sequence9 t  W6 L' c8 Y5 A
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The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:
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+ h! S! U7 C' [$ [1 X7 F    Base case: fib(0) = 0, fib(1) = 1
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. ]( `+ h# y6 y" V- C" F: }  \    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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+ h% I) A0 t& F2 R/ q) \def fibonacci(n):
/ x! p# S2 p6 L( t; ]5 l    # Base cases
6 |" @# S- `* `, |) ^    if n == 0:
4 _- n7 m3 j3 q& I2 Z( L        return 05 e3 y  D7 i, w8 l/ X
    elif n == 1:0 a1 ~3 U8 y2 ?5 k+ E! a& t3 C
        return 1  j& F6 s3 \% |0 d& t9 x5 Z1 H$ G
    # Recursive case7 U8 s. ^1 [4 v  `, \' P7 Q. o
    else:* t9 _" ^$ C" a& C9 o9 i
        return fibonacci(n - 1) + fibonacci(n - 2)
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# Example usage
  a" E$ [( w: ]8 F$ }8 @( jprint(fibonacci(6))  # Output: 8- n* R" y* P6 E1 v7 `: W

$ J( R: D1 i# h( y: }/ y9 R9 ITail Recursion
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
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In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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