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标题: 突然想到让deepseek来解释一下递归 [打印本页]

作者: 密银    时间: 2025-1-29 14:16
标题: 突然想到让deepseek来解释一下递归
本帖最后由 密银 于 2025-1-29 14:19 编辑 ! T! r( V* |6 `9 C( V  J

$ G8 `! h, o0 o7 R3 M/ J解释的不错) _8 W  s* E0 E/ \8 E; u
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递归是一种通过将问题分解为更小的同类子问题来解决问题的方法。它的核心思想是:**函数直接或间接地调用自身**,直到满足终止条件。
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6 D5 N4 @; ^; b! ^3 i0 _$ ?2 [- y, h 关键要素
& A6 t* ~' L' f" C7 o! P6 R4 c1. **基线条件(Base Case)**
9 N' Y, T9 y. X5 G   - 递归终止的条件,防止无限循环+ B- G, N0 M0 P. B4 J% A2 o$ _
   - 例如:计算阶乘时 n == 0 或 n == 1 时返回 1. |4 J4 \$ s' a, v

7 Z1 J2 Q: m; \8 W1 h2. **递归条件(Recursive Case)**+ r5 h* F7 D& q
   - 将原问题分解为更小的子问题+ l( \: X  }* I3 C9 ~7 u
   - 例如:n! = n × (n-1)!7 a  a# b  m6 j4 o; B* q  d' w& j: R8 b

+ B  ^. d; K5 I9 a2 u% K+ O2 Q 经典示例:计算阶乘! q6 B0 g' z4 I7 _4 {
python  z& a2 i& J: J2 b1 f
def factorial(n):
/ t4 {# b" e8 @/ H2 j9 o/ A    if n == 0:        # 基线条件
. I# u6 A5 ~# m1 Y# v2 ]        return 1
' Q. M5 r- O+ \( q0 C# l    else:             # 递归条件
) q  h! w5 u0 H( j; d        return n * factorial(n-1)- ]9 x7 Z2 B5 N- ^7 g; L) v
执行过程(以计算 3! 为例):
. n6 g/ z9 H) x5 v* n3 i4 e) Zfactorial(3): t8 r( B0 u& ~' K& b* O
3 * factorial(2)
' B) J7 W/ }3 ^0 K1 p6 s) o6 \3 * (2 * factorial(1))- o0 i$ f; e# N* H
3 * (2 * (1 * factorial(0)))
3 g( U4 w& D9 C' W: [8 n3 * (2 * (1 * 1)) = 6
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递归思维要点+ Y8 D% V+ Y! O0 l" O
1. **信任递归**:假设子问题已经解决,专注当前层逻辑6 _; L6 W* p6 @  u/ f2 R
2. **栈结构**:每次调用都会创建新的栈帧(内存空间)+ ~& f# o/ F* v" q8 Y
3. **递推过程**:不断向下分解问题(递)
- _( h; E7 Y+ {- k2 q# X' Q4. **回溯过程**:组合子问题结果返回(归)
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注意事项3 C6 Y4 i, O" k: _* B2 F7 W- [8 K
必须要有终止条件. k$ x. B1 W' X1 @" C7 V5 L
递归深度过大可能导致栈溢出(Python默认递归深度约1000层): F5 N. [* m9 A& K
某些问题用递归更直观(如树遍历),但效率可能不如迭代8 x9 a3 f' U$ e( T0 i; x$ o
尾递归优化可以提升效率(但Python不支持)
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递归 vs 迭代
6 S) e" x1 x! m7 I6 @) \|          | 递归                          | 迭代               |, Q3 s' S) }' d/ B
|----------|-----------------------------|------------------|
+ [0 n7 N- o) f, ?% p8 a| 实现方式    | 函数自调用                        | 循环结构            |+ Z$ B8 b- @. G0 g  Q8 O5 W
| 内存消耗    | 需要维护调用栈(可能溢出)               | 通常更节省内存         |# z0 r9 u$ Q1 j
| 代码可读性  | 对符合递归思维的问题更直观                | 线性流程更直接         |
: x  D# k2 u, I% \. ~4 s+ u, k| 适用场景    | 树结构、分治算法、回溯问题等               | 简单重复操作          |3 U2 O4 q; n+ b
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经典递归应用场景
3 Q/ x2 |" D9 n1. 文件系统遍历(目录树结构)) S2 G; Q2 V( ]9 X$ a+ d  G7 c
2. 快速排序/归并排序算法* c# X6 j2 Q: j& J9 h8 {& A; t
3. 汉诺塔问题
) d2 q2 o7 P0 k+ D4. 二叉树遍历(前序/中序/后序)
+ m8 x  X* B& C2 }4 D) W7 P1 M5. 生成所有可能的组合(回溯算法)2 P8 o6 K& `/ o* Y+ {, m
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试着用递归思维想象:你站在一面镜子前,镜子里有无数个逐渐变小的你在照镜子,这就是递归的直观体现。但记住每个"分身"最终都要有结束的时刻,这就是基线条件的重要性。
作者: testjhy    时间: 2025-1-30 00:07
挺好,递归思维要点与我能够回忆起来我当时写递归程序的思路很一致,,或者被它唤醒,9 V7 c# V; i, U  N5 P) |( [$ \8 u/ G
我推理机的核心算法应该是二叉树遍历的变种。3 l6 A; N+ H8 V$ w4 q
另外知识系统的推理机搜索深度(递归深度)并不长,没有超过10层的,如果输入变量多的话,搜索宽度很大,但对那时的286-386DOS系统,计算压力也不算大。
作者: nanimarcus    时间: 2025-2-2 00:45
Recursion in programming is a technique where a function calls itself in order to solve a problem. It is a powerful concept that allows you to break down complex problems into smaller, more manageable subproblems. Here's a detailed explanation:( M/ w3 _0 [% B9 p
Key Idea of Recursion
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  V" g) ~$ c2 sA recursive function solves a problem by:
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    Breaking the problem into smaller instances of the same problem.) w& R: V% l0 f

1 i+ j- W  t; }; s, p    Solving the smallest instance directly (base case).
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# F3 g; F. [  c  J    Combining the results of smaller instances to solve the larger problem.: y+ A4 S$ o2 a: Y
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Components of a Recursive Function  Q" p. @. E) b! [1 a4 `8 [) s

1 X& m- w# l' h; L! x% M    Base Case:) P! t8 T% S; {" F2 M. i  m0 W

8 l2 |* Q* z$ n" |+ ]0 m        This is the simplest, smallest instance of the problem that can be solved directly without further recursion.
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        It acts as the stopping condition to prevent infinite recursion.8 }! P6 O1 P6 B; h4 Z9 ^: f

% g/ q, ?5 x  l3 R! j4 ?        Example: In calculating the factorial of a number, the base case is factorial(0) = 1.
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    Recursive Case:$ @6 m5 e! n; u8 f/ R6 g
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        This is where the function calls itself with a smaller or simpler version of the problem./ _1 V$ `- k, R: H
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        Example: For factorial, the recursive case is factorial(n) = n * factorial(n-1).
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Example: Factorial Calculation
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' p7 u4 m* G' p: iThe factorial of a number n (denoted as n!) is the product of all positive integers less than or equal to n. It can be defined recursively as:1 R* i! A! ~6 k. A. ?1 A

2 N: ?1 A6 {9 y    Base case: 0! = 1
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    Recursive case: n! = n * (n-1)!
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/ @. k$ R/ d# W3 z/ Q2 }( J/ ^# }5 oHere’s how it looks in code (Python):* [! n7 j2 W* N( X1 X) R1 N
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def factorial(n):2 ?) r4 @" j% C; S/ j$ I
    # Base case
' [/ w/ z+ U* G+ N( D7 b; x    if n == 0:1 \$ N$ p' Y; i: X# g! Q
        return 1% b! q3 _$ [- ?$ {: w# U
    # Recursive case
' B6 m% O4 r8 B7 W; P0 h& V    else:
; `* }7 ^4 I$ g        return n * factorial(n - 1)
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: g* r8 N  _# j  U" _& o7 W# Example usage, \, W. ^, N" @# D/ I: y) O
print(factorial(5))  # Output: 120( p, ~) Y7 e9 l, E6 q
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How Recursion Works1 Q9 S3 ~2 t$ B' F

4 {/ N6 Z* v7 L- j6 c( P    The function keeps calling itself with smaller inputs until it reaches the base case.
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" a9 Q0 }& i; r- X) p& |/ S    Once the base case is reached, the function starts returning values back up the call stack.
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    These returned values are combined to produce the final result.) C3 O+ M: ~2 d% U% K# i$ a  M# w

1 d) i. e; e, k5 U! w3 A8 v' B+ {For factorial(5):
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factorial(5) = 5 * factorial(4)9 S! P+ }, h0 D. w: y
factorial(4) = 4 * factorial(3)
1 M0 O* r# N& w: \factorial(3) = 3 * factorial(2)
% t- ?& a7 q7 P# ^. |factorial(2) = 2 * factorial(1)
- m  E! V5 o) I2 z8 ~# ufactorial(1) = 1 * factorial(0)/ `5 {* z. y9 w, j! i. H6 _
factorial(0) = 1  # Base case
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Then, the results are combined:
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% s1 l$ k1 `& {$ l& c% R. v9 w9 }0 afactorial(1) = 1 * 1 = 1& k5 W6 {5 C* E$ X
factorial(2) = 2 * 1 = 2( e1 p+ A' ]1 x
factorial(3) = 3 * 2 = 6
& }3 ^9 l( X* [5 j3 t8 Mfactorial(4) = 4 * 6 = 24
# c$ G! l! i# A( o& _  `factorial(5) = 5 * 24 = 120/ o/ `6 l+ {5 J3 W& ^7 X9 c
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Advantages of Recursion. `( _2 {: J' H

) N: V7 l1 w6 }" d& Y    Simplicity: Recursive solutions are often more intuitive and easier to write for problems that have a natural recursive structure (e.g., tree traversals, divide-and-conquer algorithms).
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2 _4 q7 s6 O* ^) \8 r; k+ l( R    Readability: Recursive code can be more readable and concise compared to iterative solutions.
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. N' f. H7 c7 H# R2 l' HDisadvantages of Recursion
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3 F$ m* E/ a# w" l* G, j    Performance Overhead: Each recursive call adds a new layer to the call stack, which can lead to high memory usage and potential stack overflow for deep recursion.
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    Inefficiency: Some problems can be solved more efficiently using iteration (e.g., Fibonacci sequence without memoization).4 F! {6 r7 e/ V2 j' w
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When to Use Recursion
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  X% A* n# a+ N" c1 v    Problems that can be broken down into smaller, similar subproblems (e.g., tree traversals, sorting algorithms like quicksort and mergesort).
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    Problems with a clear base case and recursive case.
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Example: Fibonacci Sequence
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The Fibonacci sequence is another classic example of recursion. Each number is the sum of the two preceding ones:' B* E) K6 d+ S4 Y1 ?! o

& ^9 D& {6 ]& g; {8 C6 E! d    Base case: fib(0) = 0, fib(1) = 1
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    Recursive case: fib(n) = fib(n-1) + fib(n-2)
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python
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def fibonacci(n):
' i( _( j8 f% u$ r$ Z! i9 v4 |    # Base cases
5 |( P5 {7 @7 T9 Y+ @: ^    if n == 0:3 y" F/ C6 y8 s
        return 0- U) r- E( \- o) Z6 d8 U
    elif n == 1:. c' B! ^* Y; h9 _
        return 1; m( U% a- G) `
    # Recursive case) e! b( H' }0 B3 ~+ ?/ Q
    else:
# s- e$ Z8 R& q1 D- G0 k        return fibonacci(n - 1) + fibonacci(n - 2)& z3 [( Z. W  T. @

. m+ r- f; t7 i2 X. a1 f# Example usage
4 {! y0 h& k8 G' R- e/ u# yprint(fibonacci(6))  # Output: 84 q7 S) A: g3 S6 N8 t

5 _5 P; N* T+ nTail Recursion# x% W, A/ X" l$ k% o
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Tail recursion is a special case of recursion where the recursive call is the last operation in the function. Some programming languages optimize tail-recursive functions to avoid stack overflow, but not all languages (e.g., Python does not optimize tail recursion).
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In summary, recursion is a fundamental concept in programming that allows you to solve problems by breaking them into smaller, self-similar subproblems. It’s important to define a base case to avoid infinite recursion and to understand the trade-offs between recursion and iteration.
作者: nanimarcus    时间: 2025-2-2 00:47
我还让Deepseek 给我讲讲Linux Kernel Driver 现在的开发流程,让一个老同志复习复习,快忘光了。




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